EDIT****Other aim:
And I would love to iterate through every excel row and save each row as separate .xml file (filename = invoice.text)
any help appreciated
->>> the problem is, that the 2nd created .xml file has also data from the first row inside. Can anybody help me? Highly appreciated
help is appreciated, I want to give ROOT name attributes and the xml a version "" and save each excel row as a separate .xml file
I already setup the excel with openpyxl.
EDIT
Code edited
from lxml import etree
import openpyxl
# Create root element with namespace information
xmlns = "http://xml.datev.de/bedi/tps/ledger/v040"
xsi = "http://www.w3.org/2001/XMLSchema-instance"
schemaLocation = "http://xml.datev.de/bedi/tps/ledger/v040 Belegverwaltung_online_ledger_import_v040.xsd"
version = "4.0"
generator_info = "DATEV Musterdaten"
generating_system = "DATEV manuell"
xmlRoot = etree.Element(
"{" + xmlns + "}LedgerImport",
version=version,
attrib={"{" + xsi + "}schemaLocation": schemaLocation},
generator_info=generator_info,
generating_system=generating_system,
nsmap={'xsi': xsi, None: xmlns}
)
####open excel file speadsheet
wb = openpyxl.load_workbook('import_spendesk_datev.xlsx')
sheet = wb['Import']
# build the xml tree
for i in range(2,6):
#consolidate = etree.SubElement(xmlRoot, 'consolidate', attrib={'consolidatedAmount': str(sheet.cell(row=i,column=16).value, 'consolidatedDate': str(sheet.cell(row=i,column=2).value, 'consolidatedInvoiceId': str(sheet.cell(row=i,column=13).value, 'consolidatedCurrencyCode': str(sheet.cell(row=i,column=12).value )})
consolidate = etree.SubElement(xmlRoot, 'consolidate', attrib={'consolidatedAmount': str(sheet.cell(row=i,column=16).value),'consolidatedDate': str(sheet.cell(row=i,column=2).value), 'consolidatedInvoiceId': str(sheet.cell(row=i,column=13).value), 'consolidatedCurrencyCode': str(sheet.cell(row=i,column=12).value) })
accountsPayableLedger = etree.SubElement(consolidate, 'accountsPayableLedger')
account = etree.SubElement(accountsPayableLedger, 'bookingText')
account.text = sheet.cell(row=i,column=21).value
invoice = etree.SubElement(accountsPayableLedger, 'invoiceId')
invoice.text = sheet.cell(row=i,column=13).value
date = etree.SubElement(accountsPayableLedger, 'date')
date.text = sheet.cell(row=i,column=2).value
amount = etree.SubElement(accountsPayableLedger, 'amount')
amount.text = sheet.cell(row=i,column=16).value
account_no = etree.SubElement(accountsPayableLedger, 'accountNo')
account_no.text = sheet.cell(row=i,column=19).value
cost1 = etree.SubElement(accountsPayableLedger, 'costCategoryId')
cost1.text = sheet.cell(row=i,column=15).value
currency_code = etree.SubElement(accountsPayableLedger, 'currencyCode')
currency_code.text = sheet.cell(row=i,column=12).value
party_id = etree.SubElement(accountsPayableLedger, 'partyId')
party_id.text = sheet.cell(row=i,column=20).value
bpaccount = etree.SubElement(accountsPayableLedger, 'bpAccountNo')
bpaccount.text = sheet.cell(row=i,column=20).value
#doc = etree.ElementTree(xmlRoot)
#doc.write( str(sheet.cell(row=i,column=13).value)+".xml", xml_declaration=True, encoding='utf-8', pretty_print=True)
doc = etree.ElementTree(xmlRoot)
with open(str(sheet.cell(row=i,column=13).value)+".xml", 'w') as f:
f.write(etree.tostring(doc, pretty_print=True, xml_declaration=True, encoding='utf-8').decode('utf-8'))
# doc = etree.ElementTree(xmlRoot)
# with open("test1337.xml", 'w') as f:
# f.write(etree.tostring(doc, pretty_print=True, xml_declaration=True, encoding='utf-8').decode('utf-8'))
# convert into elementtree and write it directly into a file
#doc = etree.ElementTree(xmlRoot)
#outFile = open("test1337.xml", 'w')
#doc.write("test1337.xml", xml_declaration=True, encoding='utf-8', pretty_print=True)
#doc.close()
Please help sitting like hours on that.
Thanks so much
I recommend using etree elements and subelements and convert them later on into a element tree. This provides more flexibility while creating the xml, especially when you want to iterate over an existing data structure:
from lxml import etree
# Create root element with namespace information
xmlns = "http://xml.datev.de/bedi/tps/ledger/v040"
xsi = "http://www.w3.org/2001/XMLSchema-instance"
schemaLocation = "http://xml.datev.de/bedi/tps/ledger/v040 Belegverwaltung_online_ledger_import_v040.xsd"
version = "4.0"
generator_info = "DATEV Musterdaten"
generating_system = "DATEV manuell"
xmlRoot = etree.Element(
"{" + xmlns + "}LedgerImport",
version=version,
attrib={"{" + xsi + "}schemaLocation": schemaLocation},
generator_info=generator_info,
generating_system=generating_system,
nsmap={'xsi': xsi, None: xmlns}
)
# build the xml tree
consolidate = etree.SubElement(xmlRoot, 'consolidate', attrib={'consolidatedAmount': "1337.01"})
accountsPayableLedger = etree.SubElement(consolidate, 'accountsPayableLedger')
account = etree.SubElement(accountsPayableLedger, 'bookingText')
account.text = 'amazon'
invoice = etree.SubElement(accountsPayableLedger, 'invoiceId')
invoice.text = "1"
# convert into elementtree and write it directly into a file
doc = etree.ElementTree(xmlRoot)
with open("test1337.xml", 'w') as f:
f.write(etree.tostring(doc, pretty_print=True, xml_declaration=True, encoding='utf-8').decode('utf-8'))
The generated file looks like this:
<?xml version='1.0' encoding='UTF-8'?>
<LedgerImport xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xml.datev.de/bedi/tps/ledger/v040" generating_system="DATEV manuell" generator_info="DATEV Musterdaten" version="4.0" xsi:schemaLocation="http://xml.datev.de/bedi/tps/ledger/v040 Belegverwaltung_online_ledger_import_v040.xsd">
<consolidate consolidatedAmount="1337.01">
<accountsPayableLedger>
<bookingText>amazon</bookingText>
<invoiceId>1</invoiceId>
</accountsPayableLedger>
</consolidate>
</LedgerImport>
Related
I wrote an xml file with ElementTree. The problem i'm facing is that I want to write multiple logs in the same xml file.
The code:
import xml.etree.cElementTree as ET
#XML
root = ET.Element('LOG')
DATE = ET.SubElement(root, 'DATE')
DATE.text = "child_1"
TIME = ET.SubElement(root, 'TIME')
TIME.text = "child_2"
CC = ET.SubElement(root, 'CC')
CC.text = "child_3"
AMOUNT = ET.SubElement(root, 'AMOUNT')
AMOUNT.text = "child_4"
tree = ET.ElementTree(root)
#Generating XML
tree.write("file_name.xlm")
#Print
print(open("file_name.xlm").read())
Current output example:
<LOG><DATE>child_1</DATE><TIME>child_2</TIME><CC>child_3</CC><AMOUNT>child_4</AMOUNT></LOG>
Output that I want:
<LOG><DATE>child_1</DATE><TIME>child_2</TIME><CC>child_3</CC><AMOUNT>child_4</AMOUNT></LOG><LOG><DATE>child_1</DATE><TIME>child_2</TIME><CC>child_3</CC><AMOUNT>child_4</AMOUNT></LOG><LOG><DATE>child_1</DATE><TIME>child_2</TIME><CC>child_3</CC><AMOUNT>child_4</AMOUNT></LOG>...
What you want is just not how xml works. xml documents have one root node, and just one. The closest you can get is by wrapping your <LOG> entries in a container:
<ALL_LOGS>
<LOG>....</LOG>
<LOG>....</LOG>
</ALL_LOGS>
Here is the data from the xml file,
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
<SOAP-ENV:Header />
<SOAP-ENV:Body>
<ADD_LandIndex_001>
<CNTROLAREA>
<BSR>
<status>ADD</status>
<NOUN>LandIndex</NOUN>
<REVISION>001</REVISION>
</BSR>
</CNTROLAREA>
<DATAAREA>
<LandIndex>
<reportId>AMI100031</reportId>
<requestKey>R3278458</requestKey>
<SubmittedBy>EN4871</SubmittedBy>
<submittedOn>2015/01/06 4:20:11 PM</submittedOn>
<LandIndex>
<agreementdetail>
<agreementid>001 4860</agreementid>
<agreementtype>NATURAL GAS</agreementtype>
<currentstatus>
<status>ACTIVE</status>
<statuseffectivedate>1965/02/18</statuseffectivedate>
<termdate>1965/02/18</termdate>
</currentstatus>
<designatedrepresentative></designatedrepresentative>
</agreementdetail>
</LandIndex>
</LandIndex>
</DATAAREA>
</ADD_LandIndex_001>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope
I want to save in a dataframe : 1) the path and 2) the text of the elements corresponding to the path and only for a the elements that contains a value. So I would like to have something like that :
Path Value
0 Body/ADD_LandIndex_001/CNTROLAREA/BSR/status ADD
1 Body/ADD_LandIndex_001/CNTROLAREA/BSR/NOUN LandIndex
2 Body/ADD_LandIndex_001/CNTROLAREA/BSR/REVISION 001
I have this little code that does not work ! It returns an empty dataframe, however I can see by the print(d) in the loop of the function that it takes correctly each elements. I don't really see what is wrong ? Anyone can find why it is empty and not working ?
from lxml import etree as et
from collections import defaultdict
import pandas as pd
import os
filename = 'file_try.xml'
namespace = '{http://schemas.xmlsoap.org/soap/envelope/}'
with open(filename, 'rb') as file:
root = et.parse(file).getroot()
tree = et.ElementTree(root)
col_name = ['Path', 'Value']
dataF = pd.DataFrame([],columns = col_name)
def traverse(el,d):
if len(list(el)) > 0:
for child in el:
traverse(child,d)
else:
if el.text is not None:
d = d.append({'Path': tree.getelementpath(el).replace(namespace,''), 'Value' : el.text }, ignore_index = True)
print(d)
return d
df = traverse(root,dataF)
print(df)
df.to_excel("data_2.xlsx")
Try this.
from simplified_scrapy import SimplifiedDoc, utils
rows = []
rows.append(['Path', 'Value'])
xml = utils.getFileContent('file_try.xml')
doc = SimplifiedDoc(xml)
body = doc.select('SOAP-ENV:Body')
def getPathValue(node, path):
path = path + '/' + node['tag'] # Splicing path
children = node.children
if children:
traverseNodes(children, path)
else:
rows.append([path, node.text])
def traverseNodes(nodes, path):
for node in nodes: # Traversing child nodes
getPathValue(node, path)
traverseNodes(body.children, "Body")
# print(rows)
utils.save2csv('data_2.csv', rows)
Result:
[['Body/ADD_LandIndex_001/CNTROLAREA/BSR/status', 'ADD'], ['Body/ADD_LandIndex_001/CNTROLAREA/BSR/NOUN', 'LandIndex'], ['Body/ADD_LandIndex_001/CNTROLAREA/BSR/REVISION', '001'], ['Body/ADD_LandIndex_001/DATAAREA/LandIndex/reportId', 'AMI100031'], ['Body/ADD_LandIndex_001/DATAAREA/LandIndex/requestKey', 'R3278458'],
...
I find my mistake by looking on the answer of #yazz.
Here is the code :
from lxml import etree as et
import pandas as pd
import os
filename = 'file_try.xml'
namespace = '{http://schemas.xmlsoap.org/soap/envelope/}'
with open(filename, 'rb') as file:
root = et.parse(file).getroot()
tree = et.ElementTree(root)
col_name = ['Path', 'Value']
data = []
def traverse(el,d):
if len(list(el)) > 0:
for child in el:
traverse(child,d)
else:
if el.text is not None:
d.append([(tree.getelementpath(el)+str(el.xpath('#Ccy'))).replace(namespace,''), el.text])
print(d)
return d
df = pd.DataFrame(traverse(root,data), columns = col_name)
df.to_excel("data_2.xlsx")
I have a directory that contain several xml files that I would like to able to treat all of them, one by one and export them as CSV files.
Individually, It works perfectly with the script below:
import xml.etree.ElementTree as ET
import csv
tree = ET.parse('D:/scripts/xml/download_xml_1.xml')
data_out = open('D:/scripts/csv/output_1.csv', 'w',newline='', errors='ignore')
csvwriter = csv.writer(data_out)
col_names = ['Fichier','No. de document','Titre']
csvwriter.writerow(col_names)
root = tree.getroot()
for elem in root.iter(tag='Document'):
row = []
filetype = elem.find('FileType').text
row.append(filetype)
documentnumber = elem.find('DocumentNumber').text
row.append(documentnumber)
title = elem.find('Title').text
row.append(title)
csvwriter.writerow(row)
data_out.close()
But I'm going crazy to find the solution to do it, one by one and this where I am so far:
import xml.etree.ElementTree as ET
import csv
import os
for my_files in os.listdir('D:/scripts/xml/'):
tree = ET.parse(my_files)
data_out = open('D:/scripts/csv/'+ my_files[:-4] +'.csv', 'w',newline='', errors='ignore')
csvwriter = csv.writer(data_out)
col_names = ['Fichier','No. de document','Titre']
csvwriter.writerow(col_names)
root = tree.getroot()
for elem in root.iter(tag='Document'):
row = []
filetype = elem.find('FileType').text
row.append(filetype)
documentnumber = elem.find('DocumentNumber').text
row.append(documentnumber)
title = elem.find('Title').text
row.append(title)
csvwriter.writerow(row)
data_out.close()
Any help would be greatly appreciated.
Simply generalize your process in a defined method that receives a file name as input. Then, iteratively pass file names to it. Also, consider with context manager to open text connection without need to close.
import os
import csv
import xml.etree.ElementTree as ET
xml_path = r'D:\scripts\xml'
csv_path = r'D:\scripts\csv'
# DEFINED METHOD
def xml_to_csv(xml_file):
csv_file = os.path.join(csv_path, f'Output_{xml_file[:-4]}.csv')
tree = ET.parse(os.path.join(xml_path, xml_file))
with open(csv_file, 'w', newline='', errors='ignore') as data_out:
csvwriter = csv.writer(data_out)
col_names = ['Fichier', 'No. de document', 'Titre']
csvwriter.writerow(col_names)
root = tree.getroot()
for elem in root.iter(tag='Document'):
row = [elem.find('FileType').text,
elem.find('DocumentNumber').text,
elem.find('Title').text]
csvwriter.writerow(row)
# FILE ITERATION
for f in os.listdir(xml_path):
xml_to_csv(f)
I need to parse a directory of xml files into one large csv file, I need certain attributes under the element 'Param' (attributes are 'Name' and 'PNum'). There is another XML file in the directory called Content.xml which I can get all the names of the other XML files and set them as the FileName. The issue is that I cannot figure out how to get these attributes in each XML file as each XML file has a different organisation and some don't seem to have these attributes in the first place.
I have written code that works for one of the XML files in the directory that outputs a CSV file with all the relevant information.
import xml.etree.ElementTree as ET
import csv
import os
FileName = '------.xml'
tree = ET.parse(FileName)
root = tree.getroot()[4]
csv_out = open('CsvOut', 'w')
csvwriter = csv.writer(csv_out)
count = 0
for child in root:
generation = []
parameters = []
if count == 0:
csv_head = ['Generation', 'Parameter Name', 'Parameter Number']
csvwriter.writerow(csv_head)
count = count + 1
gen = FileName[:-4]
generation.append(gen)
parameters.append(generation)
name = child.get('Name')
parameters.append(name)
num = child.get('PNum')
parameters.append(num)
csvwriter.writerow(parameters)
csv_out.close()
I rather simple and you can do it in two steps:
First, enumerate all xml files in the directory
Perform your code over these files
import xml.etree.ElementTree as ET
import csv
import os
from glob import glob
# create csv writer
csv_out = open('CsvOut', 'w')
csvwriter = csv.writer(csv_out)
# write the header
csv_head = ['Generation', 'Parameter Name', 'Parameter Number']
csvwriter.writerow(csv_head)
# iterate over the xml files in the current directory
for FileName in glob("*.xml"):
tree = ET.parse(FileName)
root = tree.getroot()[4]
for child in root:
generation = []
parameters = []
gen = FileName[:-4]
generation.append(gen)
parameters.append(generation)
name = child.get('Name')
parameters.append(name)
num = child.get('PNum')
parameters.append(num)
csvwriter.writerow(parameters)
# after iterating, close the csv file
csv_out.close()
I am parsing through many xml files and putting certain information into a csv file. Because my xml files are named: "1.xml", "2.xml", etc... I am using a for loop to cycle through my different Xml file titles. However, based on the range that I use on my for loop, my csv file contains different data. For example, when my for loop range is 1:200 my csv file includes info from my xml files 1 to 199. However, when I change my range to 1:300, my csv file only contains info for my xml files 217 to 249. The info actually stored on my csv file changes based on what I put in as my range for my for loop. Has anyone else had this error and do you have any solutions?
My code is below:
import xml.etree.ElementTree as ET
import csv
from pathlib import Path
# open a file for writing
data_labels = open('DataLabels.csv', 'w', newline='')
missing_files = open('MissingFiles.csv', 'w', newline = '')
# create the csv writer object
csvwriter = csv.writer(data_labels)
csvwriter2 = csv.writer(missing_files)
data_head = []
data = []
missingfiles = 0
missfiles = []
MediaId = "Media Id"
#data_head.append (MediaId)
Family = "Family"
#data_head.append (Family)
Species = "Species"
#data_head.append (Species)
Genus = "Genus"
Content = "Content"
ClassId = "ClassId"
#data_head.append (Genus)
data_head.append(MediaId)
# Family = member.find('Family').tag
data_head.append(Content)
data_head.append(ClassId)
data_head.append(Family)
# Species = member.find('Species').tag
data_head.append(Species)
# Genus = member.find('Genus').tag
data_head.append(Genus)
csvwriter.writerow(data_head)
for i in range (1, 190):
#print (i)
data = []
inputfilename = str(i)+ ".xml"
my_file = Path(inputfilename)
if my_file.is_file():
data_labels = open('DataLabels.csv', 'w', newline='')
tree = ET.parse(inputfilename)
root = tree.getroot()
MediaId = root [2].text
Content = root[4].text
ClassId = root[5].text
Family = root[6].text
Species = root[7].text
Genus = root[8].text
#print (vote)
#count = 0
#for Image in root.find('MediaId'):
#print (child.tag, child.attrib)
#name = child.find('MediaId').text
# print (Image.find ('MediaId').text)
##csvwriter.writerow (data_head)
#data = []
#if count == 0:
# print ("count is zero i'm in loop")
# MediaId = member.find('MediaId').tag
# count = count + 1
#else:
#MediaId = root.findall('MediaId').text
data.append(MediaId)
data.append (Content)
data.append (ClassId)
#Family = member.find('Family').text
data.append(Family)
#Species = member.find('Species').text
data.append(Species)
#Genus = member.find('Genus').text
data.append(Genus)
csvwriter.writerow(data)
data_labels.close()
#print (data)
else:
missingfiles = missingfiles +1
missfiles = []
missfiles.append(inputfilename)
csvwriter2.writerow(missfiles)
print ("missing", missingfiles, "files")
data_labels.close()
missing_files.close()
print ("done")
Open the csv in append mode ,else you are just overwriting the same file.
I think you need to divide your script in small readable functions.
First, you can create a function to parse a XML file:
import xml.etree.ElementTree as ET
def parse_xml_file(xml_path):
""" Parse an XML file and return the data. """
# type: (str) -> list
tree = ET.parse(xml_path)
root = tree.getroot()
return [
root[2].text,
root[4].text,
root[5].text,
root[6].text,
root[7].text,
root[8].text]
This function parse a XML file and return one record containing a list of values.
Then, you can create a function to iterate a list of XML files (existing files) dans populate the CSV file:
import csv
import io
import os
def populate_data_labels(xml_path_list, work_dir="."):
header = ["Media Id", "Family", "Species", "Genus", "Content", "ClassId"]
with io.open(os.path.join(work_dir, 'DataLabels.csv'), 'w') as fd:
writer = csv.writer(fd)
writer.writerow(header)
for xml_path in xml_path_list:
writer.writerow(parse_xml_file(xml_path))
This function use parse_xml_file() to extract each record.
You can create a function to log the missing files. You can use CSV format (or a simple text file):
def populate_missing_files(missing_files, work_dir="."):
header = ["Filename"]
with io.open(os.path.join(work_dir, 'MissingFiles.csv'), 'w') as fd:
writer = csv.writer(fd)
writer.writerow(header)
for xml_path in missing_files:
writer.writerow([os.path.basename(xml_path)])
Finally, you can write a function which search the XML files and call the previous functions:
def parse_work_dir(work_dir="."):
all_files = [os.path.join(work_dir, "{0}.xml".format(idx))
for idx in range(1, 190)]
existing_files = (path for path in all_files if os.path.exists(path))
populate_data_labels(existing_files, work_dir)
missing_files = (path for path in all_files if not os.path.exists(path))
populate_missing_files(missing_files, work_dir)
Usage:
parse_work_dir("/path/to/your/working/dir")