I tried multiple times to make this work without results, here's the code
import os, sys
try:
with open("syscore.lib", "r") as confFile:
readConfFile = confFile.readlines()
fileExist = True
except:
fileExist = False
if fileExist is True:
method = "r"
else:
method = "w"
for _ in range(2):
with open("syscore.lib", method) as confFile:
try:
readConfFile = confFile.readlines()
except:
confFile.write(os.system("python --version").replace("Python ", ""))
print(readConfFile)
The problem come again in a similar way down here
import os
test = [str(os.system('python --version'))]
test1 = os.system('python --version')
print('PV: '+str(test1))
print('Python Version: '+test[0])
Can anyone help me with this?
Thanks
As noted in the relevant thread here, os.system() returns the process exit value. 0 means success. If you want to capture the printed output, use os.popen() instead:
import os
python_version = os.popen("python -V").read().strip()
And the output is 'Python 3.6.6'.
Hope this helps.
if you only want to get python version then try,
Python 2.7.12 (default, Nov 12 2018, 14:36:49)
[GCC 5.4.0 20160609] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.version_info
sys.version_info(major=2, minor=7, micro=12, releaselevel='final', serial=0)
>>> version = "{}.{}.{}".format(*sys.version_info)
'2.7.12'
>>>
you will get in python3,
Python 3.5.2 (default, Nov 12 2018, 13:43:14)
[GCC 5.4.0 20160609] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> "{}.{}.{}".format(*sys.version_info)
'3.5.2'
>>>
or you can use,
>>> import sys
>>> sys.version
'3.5.2 (default, Nov 12 2018, 13:43:14) \n[GCC 5.4.0 20160609]'
>>>
Related
The problem is that I can not import class from another folder. Class that I want to import in LoginPage.py.
# login.py
from selenium import webdriver
import time
import unittest
from Selenium.POMProjectDemo.Pages.LoginPage import LoginPage
class loginTest(unittest.TestCase):
#classmethod
def setUpClass(cls):
cls.driver = webdriver.Chrome(executable_path='D:\python\Selenium\chrome_driver\chromedriver.exe')#, options = webdriver.ChromeOptions())
#options.add_experimental_option('excludeSwitches', ['enable-logging'])
cls.driver.implicitly_wait(30)
cls.driver.maximize_window()
def test_01_login_valid(self):
driver = self.driver
driver.get('https://vk.com/')
login = LoginPage(driver)
login.enter_user_name()
login.enter_user_password()
login.login_button
#classmethod
def tearDownClass(cls):
cls.driver.close()
cls.driver.quit()
print('test completed')
#Loginpage.py
from Selenium.POMProjectDemo.Locators.Locators import locators
from auth_data import vk_password,vk_login
from POMProjectDemo.Locators import Locators
class LoginPage():
def __init__(self, driver):
self.driver = driver
self.index_email_id = locators.index_email_id
self.index_pass_id = locators.index_pass_id
self.loginButton_id = locators.loginButton_id
def enter_user_name(self):
self.driver.find_element_by_id(self.loginField_id).clear()
self.driver.find_element_by_id(self.loginField_id).send_keys(vk_login)
def enter_user_password(self):
self.driver.find_element_by_id(self.passwordField_id).clear()
self.driver.find_element_by_id(self.passwordField_id).send_keys(vk_password)
def login_button(self):
self.driver.find_element_by_id(self.loginButton_id).click()
Error:
ModuleNotFoundError: No module named 'Selenium'
The way python figures out import paths is to first look at entries in sys.path and check if the module you are trying to import is accessible from any of the paths. It will stop at the first path under which your module is found.
e.g.
>>> sys.path
['', '/home/bhakta/dev/sonar/controller/venv/lib/python37.zip', '/home/bhakta/dev/sonar/controller/venv/lib/python3.7', '/home/bhakta/dev/sonar/controller/venv/lib/python3.7/lib-dynload', '/usr/local/lib/python3.7', '/home/bhakta/dev/sonar/controller/venv/lib/python3.7/site-packages']
Let's say you have a module called "some_module" in /tmp
➜ ll /tmp/some_module
total 4
-rw-rw-r-- 1 bhakta bhakta 29 Jan 11 11:39 __init__.py
➜ cat /tmp/some_module/__init__.py
def foo():
print("Hello")
➜ python
Python 3.7.10 (default, Oct 19 2021, 17:50:56)
[GCC 4.8.5 20150623 (Red Hat 4.8.5-39)] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.path.append("/tmp")
>>> import some_module
>>>
>>>
>>> some_module.foo()
Hello
Now, lets say you have
➜ ll /var/tmp/some_module
total 4
-rw-rw-r-- 1 bhakta bhakta 45 Jan 11 11:43 __init__.py
➜ cat /var/tmp/some_module/__init__.py
def foo():
print("From var/tmp Hello")
And you do:
➜ python
Python 3.7.10 (default, Oct 19 2021, 17:50:56)
[GCC 4.8.5 20150623 (Red Hat 4.8.5-39)] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.path.append("/tmp")
>>> sys.path.append("/var/tmp")
>>>
>>>
>>> import some_module
>>>
>>>
>>> some_module.foo()
Hello
Notice that python found the first system path (/tmp) where some_module was found.
Thus:
➜ python
Python 3.7.10 (default, Oct 19 2021, 17:50:56)
[GCC 4.8.5 20150623 (Red Hat 4.8.5-39)] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.path.append("/var/tmp")
>>> sys.path.append("/tmp")
>>> import some_module
>>>
>>> some_module.foo()
From var/tmp Hello
I'm following the documentation and using the latest PyMuPDF (1.18.13). However Pixmap.tobytes() isn't working for me:
zoom = 2 # zoom factor
mat = fitz.Matrix(zoom, zoom)
pix = page.getPixmap(matrix = mat)
stream = pix.tobytes(output="png")
AttributeError: 'Pixmap' object has no attribute 'tobytes'
Example of documentation:
What might be the issue here?
I am PyMuPDF's maintainer.
What is your configuration? I just tried your code on Windows and Linux each with v1.18.13 and it work.
Python 3.8.5 (default, Jan 27 2021, 15:41:15)
[GCC 9.3.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import fitz
>>> fitz.version
('1.18.13', '1.18.0', '20210505063222')
>>> doc=fitz.open("v110-changes.pdf")
>>> page=doc[0]
>>> pix=page.get_pixmap()
>>> b=pix.tobytes()
>>>
Windows:
Python 3.6.6 (v3.6.6:4cf1f54eb7, Jun 27 2018, 03:37:03) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import fitz
>>> fitz.version
('1.18.13', '1.18.0', '20210505063222')
>>> doc=fitz.open("v110-changes.pdf")
>>> page=doc[0]
>>> pix=page.get_pixmap()
>>> b = pix.tobytes()
>>>
My python code shown below is not retrieving any dates before the year 1900. I learned that this is a limitation of datetime.strptime().
I have tried to follow some of the workaround mentioned in similar posts , Is there any way to use a strftime-like function for dates before 1900 in Python? but they seem a bit complicated for me to follow. I also learned that there is a patch available to fix this issue. https://bugs.python.org/file10253/strftime-pre-1900.patch
I tried to install the patch in Pycharm by copying the patch to a text file, but I am getting the following error message. Any ideas on what I need to do to run the patch successfully to get dates before 1900 ?
Pycharm Patch Error Screenshot
My Code:
from datetime import datetime
import csv
with open('train.csv', 'r') as f_input, open('sample.txt', 'w') as f_output:
csv_input = csv.reader(f_input)
csv_output = csv.writer(f_output)
for row in csv_input:
for date_format in ['%Y']:
try:
converted = datetime.strptime(row[3], date_format)
csv_output.writerow([row[0], row[1], row[2], converted.strftime(date_format)])
except ValueError:
pass
I realize this isn't what you asked, but I'll put it out there anyway since I'm assuming that if the answers to the linked question are too complicated to follow, the idea to patch your problem away successfully is probably unrealistic.
The limitation you are seeing is present in Python2:
Python 2.7.12 (default, Nov 20 2017, 18:23:56)
[GCC 5.4.0 20160609] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> from datetime import datetime
>>> d = datetime(1899, 1, 1)
>>> d.strftime('%Y-%m-%d')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: year=1899 is before 1900; the datetime strftime() methods require year >= 1900
It is somewhat rectified in Python3.2, and fully rectified in Python3.3 and onward:
Python 3.5.2 (default, Nov 23 2017, 16:37:01)
[GCC 5.4.0 20160609] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> from datetime import datetime
>>> d = datetime(1899, 1, 1)
>>> d.strftime('%Y-%m-%d')
'1899-01-01'
Parsing works too:
>>> d = datetime.strptime('0113-01-01','%Y-%m-%d')
>>> d
datetime.datetime(113, 1, 1, 0, 0)
>>> d.isoformat()
'0113-01-01T00:00:00'
>>> d.strftime('%Y-%m-%d')
'113-01-01'
So if that is an acceptable option, you could switch over to Python3.3+ and you won't have this issue.
Is file a keyword in python?
I've seen some code using the keyword file just fine, while others have suggested not to use it and my editor is color coding it as a keyword.
No, file is not a keyword:
>>> import keyword
>>> keyword.iskeyword('file')
False
The name is not present in Python 3. In Python 2, file is a built-in:
>>> import __builtin__, sys
>>> hasattr(__builtin__, 'file')
True
>>> sys.version_info[:2]
(2, 7)
It can be seen as an alias for open(), but it was removed in Python 3, where the new io framework replaced it. Technically, it is the type of object returned by the Python 2 open() function.
file is neither a keyword nor a builtin in Python 3.
>>> import keyword
>>> 'file' in keyword.kwlist
False
>>> import builtins
>>> 'file' in dir(builtins)
False
file is also used as variable example from Python 3 doc.
with open('spam.txt', 'w') as file:
file.write('Spam and eggs!')
As others suggested, type in Python 3 it is not defined by default:
Python 3.8.10 (default, Nov 14 2022, 12:59:47)
[GCC 9.4.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> file
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: name 'file' is not defined
The color coding in VS Code and possibly other editors probably refers to Python 2, where it is defined by default, it is the type returned by open():
Python 2.7.18 (default, Jul 1 2022, 12:27:04)
[GCC 9.4.0] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> file
<type 'file'>
eduardo#camizao:/$ python2.7
Python 2.7.3 (default, Sep 26 2013, 20:03:06)
[GCC 4.6.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import urllib
>>> url1 = 'http://www.google.com'
>>> url2 = 'https://www.google.com'
>>> f = urllib.urlopen(url1)
>>> f = urllib.urlopen(url2)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/urllib.py", line 87, in urlopen
return opener.open(url)
File "/usr/lib/python2.7/urllib.py", line 211, in open
return getattr(self, name)(url)
File "/usr/lib/python2.7/urllib.py", line 355, in open_http
'got a bad status line', None)
IOError: ('http protocol error', 0, 'got a bad status line', None)
>>>
When I try to connect to an https site, using urllib I got error above.
Proxies are correctly setup. Debugging python code, I have noticed in urllib.py that an import on ssl library is not performed. So, https calls are also not performed. Can anyone help me, please? I do have to use urllib, instead of urllib2 or another one. Thanks in advance.
It's not something wrong with the way you are writing it at least:
$ python
Python 2.7.4 (default, Sep 26 2013, 03:20:26)
[GCC 4.7.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import urllib
>>> url1 = 'http://www.google.com'
>>> url2 = 'https://www.google.com'
>>> f = urllib.urlopen(url1)
>>> f = urllib.urlopen(url2)
>>> f.read()[:15]
'<!doctype html>'
>>>
So that's what it's not. It must be something with your environment or your config then. You said you are using proxies?
EDIT:
I'm able to open it via an open proxy (won't include said proxy because who knows if it is sketchy - substitute with your own proxy:
$ python
Python 2.7.4 (default, Sep 26 2013, 03:20:26)
[GCC 4.7.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import urllib2
>>> proxy_handler = urllib2.ProxyHandler({'http': 'http://some-sketchy-open-proxy'})
>>> opener = urllib2.build_opener(proxy_handler)
>>> opener.open('https://www.google.com')
<addinfourl at 140512985881056 whose fp = <socket._fileobject object at 0x7fcbba9b1ed0>>
>>> _.read()[:15]
'<!doctype html>'
>>>
Try it that way (note that I used urllib2, not urllib) with your own proxy URL. Hope that helps!
EDIT 2:
Using only urllib:
$ python
Python 2.7.4 (default, Sep 26 2013, 03:20:26)
[GCC 4.7.3] on linux2
Type "copyright", "credits" or "license()" for more information.
>>> import urllib
>>> proxies = {'http': '189.112.3.87:3128'}
>>> url = 'https://www.google.com'
>>> filehandle = urllib.urlopen(url,proxies=proxies)
>>> filehandle.read()[:15]
'<!doctype html>'
>>>