Develop Reference

Python TkInter create a button to open a specific directory

I want to create a button that opens the special directory like "C:\Users\", But as I searched, I did not find any code except the following code:
from tkinter import *
from tkinter import ttk
from tkinter import filedialog
gui = Tk()
gui.geometry("100x100")
def getFolderPath():
filedialog.askdirectory()
btnFind = ttk.Button(gui, text="Open Folder",command=getFolderPath)
btnFind.grid(row=0,column=2)
gui.mainloop()
What is the correct way to solve this problem?

Use os.startfile("C:\\Users") to use the system file explorer to open the directory.

How I used tkinter button to Import files

I would like to run a python program and when clicking a button in a (tkinter) window become import files form any direction and store it to another direction and in database .
import tkinter as tk
from tkinter import filedialog
def UploadAction(event=None):
filename = filedialog.askopenfilenames()
print('Selected:', filename)
root = tk.Tk()
button = tk.Button(root, text='import files', command=UploadAction)
button.grid(row=1,column=1,padx=10,pady=10)
root.mainloop()

Getting folder path with Python Tkinter tkFileDialog

Using Python Tkinter I am trying to get the directory path of selected Folder. I do not want to load a file or navigate to a file but get the folder path like
How can I do this?
from Tkinter import *
from tkFileDialog import askopenfilename
def callback():
name= askopenfilename()
print name
errmsg = 'Error!'
Button(text='File Open', command=callback).pack(fill=X)
mainloop()
Update
from Tkinter import *
from tkFileDialog import askopenfilename
from tkinter import filedialog #for Python 3
def callback():
name= askopenfilename()
directory = filedialog.askdirectory()
print directory
errmsg = 'Error!'
Button(text='File Open', command=callback).pack(fill=X)
mainloop()

You can use askdirectory from filedialog as follows:
from tkinter import filedialog #for Python 3
directory = filedialog.askdirectory()

Ok Looks like I find the solution on my own. Putting here which might help someone else in future.
import Tkinter, tkFileDialog
root = Tkinter.Tk()
root.withdraw()
dirname = tkFileDialog.askdirectory(parent=root,initialdir="/",title='Please select a directory')
print(dirname)

Tkinter not working in cmd (working in IDLE)

I am trying to display a directory selection dialog box (for getting a path and then for saving downloaded stuff).The code runs fine in IDLE but when i try to run it in CMD i get this error
NameError: name 'Tk' is not defined
I am using tkinter for gui.
Code Snippet
from tkinter import filedialog
root = Tk()
root.withdraw()
filename = filedialog.askdirectory()
Using Python 3.4.3. Any help/suggestions?

The statement from tkinter import filedialog only imports the filedialog module from tkinter. If you want the usual Tkinter stuff, you have to import that too. I'd recommend import tkinter as tk and then referring to it with e.g. root = tk.Tk() so you don't just dump everything into the global namespace. Or, if you really just want the root object, use from tkinter import Tk.
from tkinter import Tk
from tkinter import filedialog
root = Tk()
root.withdraw()
filename = filedialog.askdirectory()

Removing TK from Window Title Python tkinter

I re-used a code I found here to set the transparency to the TK icon, but it leaves the TK there in the invoked window. I created a second window, and I am able to edit that title. But why can't I edit the code I found from an existing post. I looked everywhere but the new window I made, the title can be edited, why not the other window with Tk in it?
from tkinter import *
import tkinter
import tempfile
ICON = (b'\x00\x00\x01\x00\x01\x00\x10\x10\x00\x00\x01\x00\x08\x00h\x05\x00\x00'
b'\x16\x00\x00\x00(\x00\x00\x00\x10\x00\x00\x00 \x00\x00\x00\x01\x00'
b'\x08\x00\x00\x00\x00\x00#\x05\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00'
b'\x00\x01\x00\x00\x00\x01') + b'\x00'*1282 + b'\xff'*64
_, ICON_PATH = tempfile.mkstemp()
with open(ICON_PATH, 'wb') as icon_file:
icon_file.write(ICON)
root = Tk()
root.title("rename")
tk = tkinter.Tk()
tk.iconbitmap(default=ICON_PATH)
label = tkinter.Label(tk, text="Window with transparent icon.")
label.pack()
root.mainloop()

First of all, you should not create multiple Tk() applications in the same program.
The issue occurs because you create the new window (Application) using Tk() , but you are renaming the title only root application. This does not rename the title of tk application. That you create.
If all you want is for the title to be renamed for the window with the label - Window with transparent icon. . You should use tk.title() (instead of root.title()) . Example -
import tkinter
import tempfile
ICON = (b'\x00\x00\x01\x00\x01\x00\x10\x10\x00\x00\x01\x00\x08\x00h\x05\x00\x00'
b'\x16\x00\x00\x00(\x00\x00\x00\x10\x00\x00\x00 \x00\x00\x00\x01\x00'
b'\x08\x00\x00\x00\x00\x00#\x05\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00'
b'\x00\x01\x00\x00\x00\x01') + b'\x00'*1282 + b'\xff'*64
_, ICON_PATH = tempfile.mkstemp()
with open(ICON_PATH, 'wb') as icon_file:
icon_file.write(ICON)
tk = tkinter.Tk()
tk.title("rename")
tk.iconbitmap(default=ICON_PATH)
label = tkinter.Label(tk, text="Window with transparent icon.")
label.pack()
tk.mainloop()
And you do not need multiple tkinter imports, it does not do anything. Importing tkinter (or any module) once caches it in sys.modules , and any time you try to import it again, you get that cached module from sys.modules .
If you want to create more windows in your application you should use Toplevel widget for that . Example -
import tkinter
import tempfile
ICON = (b'\x00\x00\x01\x00\x01\x00\x10\x10\x00\x00\x01\x00\x08\x00h\x05\x00\x00'
b'\x16\x00\x00\x00(\x00\x00\x00\x10\x00\x00\x00 \x00\x00\x00\x01\x00'
b'\x08\x00\x00\x00\x00\x00#\x05\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00'
b'\x00\x01\x00\x00\x00\x01') + b'\x00'*1282 + b'\xff'*64
_, ICON_PATH = tempfile.mkstemp()
with open(ICON_PATH, 'wb') as icon_file:
icon_file.write(ICON)
tk = tkinter.Tk()
tk.title("rename")
tknewwindow = tkinter.Toplevel(tk)
tknewwindow.title("rename1")
tknewwindow.iconbitmap(default=ICON_PATH)
label = tkinter.Label(tknewwindow, text="Window with transparent icon.")
label.pack()
tk.mainloop()