this is my first question.
Im trying to learn some python, so.. i have this problem
how i can get data from this url that shows info in XML:
import requests
from bs4 import BeautifulSoup
url = 'http://windte1910.acepta.com/v01/A23D046FC1854B18399D5383F36923E25774179C?k=5121f909fd63e674149c0e42a9847b49'
document = requests.get(url)
soup = BeautifulSoup(document.content, "lxml-xml")
print(soup)
output:
Output
but i wanna get access to this type of data, < RUTEmisor> data for example:
linkurl_invoice
hope guys you can try to advice me with the code and how to read xml docs.
By examining the URL you gave, it seems that the data is actually held a few links away at the following URL: http://windte1910.acepta.com/depot/A23D046FC1854B18399D5383F36923E25774179C?k=5121f909fd63e674149c0e42a9847b49
As such, you can access it directly as follows:
import requests
from bs4 import BeautifulSoup
url = 'http://windte1910.acepta.com/depot/A23D046FC1854B18399D5383F36923E25774179C?k=5121f909fd63e674149c0e42a9847b49'
document = requests.get(url)
soup = BeautifulSoup(document.content, "lxml-xml")
print(soup.find('RUTEmisor').text)
Related
I am trying to webscrape a government site that uses frameset.
Here is the URL - https://lakecounty.in.gov/departments/voters/election-results-c/2022GeneralElectionResults/index.htm
I've tried using splinter/selenium
url = "https://lakecounty.in.gov/departments/voters/election-results-c/2022GeneralElectionResults/index.htm"
browser.visit(url)
time.sleep(10)
full_xpath_frame = '/html/frameset/frameset/frame[2]'
tree = browser.find_by_xpath(full_xpath_frame)
for i in tree:
print(i.text)
It just returns an empty string.
I've tried using the requests library.
import requests
from lxml import HTML
url = "https://lakecounty.in.gov/departments/voters/election-results-c/2022GeneralElectionResults/index.htm"
# get response object
response = requests.get(url)
# get byte string
data = response.content
print(data)
And it returns this
b"<html>\r\n<head>\r\n<meta http-equiv='Content-Type'\r\ncontent='text/html; charset=iso-
8859-1'>\r\n<title>Lake_ County Election Results</title>\r\n</head>\r\n<FRAMESET rows='20%,
*'>\r\n<FRAME src='titlebar.htm' scrolling='no'>\r\n<FRAMESET cols='20%, *'>\r\n<FRAME
src='menu.htm'>\r\n<FRAME src='Lake_ElecSumm_all.htm' name='reports'>\r\n</FRAMESET>
\r\n</FRAMESET>\r\n<body>\r\n</body>\r\n</html>\r\n"
I've also tried using beautiful soup and it gave me the same thing. Is there another python library I can use in order to get the data that's inside the second table?
Thank you for any feedback.
As mentioned you could go for the frames and its src:
BeautifulSoup(r.text).select('frame')[1].get('src')
or directly to the menu.htm:
import requests
from bs4 import BeautifulSoup
r = requests.get('https://lakecounty.in.gov/departments/voters/election-results-c/2022GeneralElectionResults/menu.htm')
link_list = ['https://lakecounty.in.gov/departments/voters/election-results-c/2022GeneralElectionResults'+a.get('href') for a in BeautifulSoup(r.text).select('a')]
for link in link_list[:1]:
r = requests.get(link)
soup = BeautifulSoup(r.text)
###...scrape what is needed
Hello I am trying to use beautiful soup and requests to log the data coming from an anemometer which updates live every second. The link to this website here:
http://88.97.23.70:81/
The piece of data I want to scrape is highlighted in purple in the image :
from inspection of the html in my browser.
I have written the code bellow in to try to print out the data however when I run the code it prints: None. I think this means that the soup object doesnt infact contain the whole html page? Upon printing soup.prettify() I cannot find the same id=js-2-text I find when inspecting the html in my browser. If anyone has any ideas why this might be or how to fix it I would be most grateful.
from bs4 import BeautifulSoup
import requests
wind_url='http://88.97.23.70:81/'
r = requests.get(wind_url)
data = r.text
soup = BeautifulSoup(data, 'lxml')
print(soup.find(id='js-2-text'))
All the best,
Brendan
The data is loaded from external URL, so beautifulsoup doesn't need it. You can try to use API URL the page is connecting to:
import requests
from bs4 import BeautifulSoup
api_url = "http://88.97.23.70:81/cgi-bin/CGI_GetMeasurement.cgi"
data = {"input_id": "1"}
soup = BeautifulSoup(requests.post(api_url, data=data).content, "html.parser")
_, direction, metres_per_second, *_ = soup.csv.text.split(",")
knots = float(metres_per_second) * 1.9438445
print(direction, metres_per_second, knots)
Prints:
210 006.58 12.79049681
I want to get the ticker values from this webpage https://www.oslobors.no/markedsaktivitet/#/list/shares/quotelist/ob/all/all/false
However when using Beautifulsoup I don't seem to get all the content, and I don't quite understand how to change my code in order to achieve my goal
import urllib3
from bs4 import BeautifulSoup
def oslobors():
http=urllib3.PoolManager()
url = 'https://www.oslobors.no/markedsaktivitet/#/list/shares/quotelist/ob/all/all/false'
response = http.request('GET', url)
soup=BeautifulSoup(response.data, "html.parser")
print(soup)
return
print(oslobors())
The content you wanna parse generates dynamically. You can either use any browser simulator like selenium or you can try the below url containing json response. The following is the easy way to go.
import requests
url = 'https://www.oslobors.no/ob/servlets/components?type=table&generators%5B0%5D%5Bsource%5D=feed.ob.quotes.EQUITIES%2BPCC&generators%5B1%5D%5Bsource%5D=feed.merk.quotes.EQUITIES%2BPCC&filter=&view=DELAYED&columns=PERIOD%2C+INSTRUMENT_TYPE%2C+TRADE_TIME%2C+ITEM_SECTOR%2C+ITEM%2C+LONG_NAME%2C+BID%2C+ASK%2C+LASTNZ_DIV%2C+CLOSE_LAST_TRADED%2C+CHANGE_PCT_SLACK%2C+TURNOVER_TOTAL%2C+TRADES_COUNT_TOTAL%2C+MARKET_CAP%2C+HAS_LIQUIDITY_PROVIDER%2C+PERIOD%2C+MIC%2C+GICS_CODE_LEVEL_1%2C+TIME%2C+VOLUME_TOTAL&channel=a66b1ba745886f611af56cec74115a51'
res = requests.get(url)
for ticker in res.json()['rows']:
ticker_name = ticker['values']['ITEM']
print(ticker_name)
Results you may get like (partial):
APP
HEX
APCL
ODFB
SAS NOK
WWI
ASC
https://en.wikipedia.org/wiki/Economy_of_the_European_Union
Above is the link to website and I want to scrape table: Fortune top 10 E.U. corporations by revenue (2016).
Please, share the code for the same:
import requests
from bs4 import BeautifulSoup
def web_crawler(url):
page = requests.get(url)
plain_text = page.text
soup = BeautifulSoup(plain_text,"html.parser")
tables = soup.findAll("tbody")[1]
print(tables)
soup = web_crawler("https://en.wikipedia.org/wiki/Economy_of_the_European_Union")
following what #FanMan said , this is simple code to help you get started, keep in mind that you will need to clean it and also perform the rest of the work on your own.
import requests
from bs4 import BeautifulSoup
url='https://en.wikipedia.org/wiki/Economy_of_the_European_Union'
r=requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
temp_datastore=list()
for text in soup.findAll('p'):
w=text.findAll(text=True)
if(len(w)>0):
temp_datastore.append(w)
Some documentation
beautiful soup:https://www.crummy.com/software/BeautifulSoup/bs4/doc/
requests: http://docs.python-requests.org/en/master/user/intro/
urllib: https://docs.python.org/2/library/urllib.html
You're first issue is that your url is not properly defined. After that you need to find the table to extract and it's class. In this case the class was "wikitable" and it was a the first table. I have started your code for you so it gives you the extracted data from the table. Web-scraping is good to learn but if your are just starting to program, practice with some simpler stuff first.
import requests
from bs4 import BeautifulSoup
def webcrawler():
url = "https://en.wikipedia.org/wiki/Economy_of_the_European_Union"
page = requests.get(url)
soup = BeautifulSoup(page.text,"html.parser")
tables = soup.findAll("table", class_='wikitable')[0]
print(tables)
webcrawler()
I need to get the text 2,585 shown in the screenshot below. I very new to coding, but this is what i have so far:
import urllib2
from bs4 import BeautifulSoup
url= 'insertURL'
r = requests.get(url)
data = r.text
soup = BeautifulSoup(data, 'html.parser')
span = soup.find('span', id='d21475972e793-wk-Fact -8D34B98C76EF518C788A2177E5B18DB0')
print (span.text)
Any info is helpful!! Thanks.
Website HTML
3 things, your using requests not urllib2. Your selecting XML with namespaces so you need to use xml as the parser. The element you want is not span it is ix:nonFraction. Here is a working example using another web-page (you just need to point it at your page and use the commented line).
# Using requests no need for urllib2.
import requests
from bs4 import BeautifulSoup
# Using this page as an example.
url= 'https://www.sec.gov/Archives/edgar/data/27904/000002790417000004/0000027904-17-000004.txt'
r = requests.get(url)
data = r.text
# use xml as the parser.
soup = BeautifulSoup(data, 'xml')
ix = soup.find('ix:nonFraction', id="Fact-7365D69E1478B0A952B8159A2E39B9D8-wk-Fact-7365D69E1478B0A952B8159A2E39B9D8")
# Your original code for your page.
# ix = soup.find('ix:nonFraction', id='d21475972e793-wk-Fact-8D34B98C76EF518C788A2177E5B18DB0')
print (ix.text)