I run the following openpyxl command to wrap text in all rows after row 9. It works fine but throws a deprecation warning. I'd love to figure out how to use documentation such as https://openpyxl.readthedocs.io/en/stable/ to determine the current, non-deprecated, way to wrap_text. But I always find the documentation confusing and unhelpful to me. For example, if I search for wrap_text I get this: https://openpyxl.readthedocs.io/en/stable/api/openpyxl.styles.alignment.html#openpyxl.styles.alignment.Alignment.wrapText
But that tells me nothing about how to wrap text. Do I simply not know know how to use the documentation? Is there some great mystery I am to unravel so I don't have to endlessly google how to use openpyxl? How does one look at such documentation and figure out out how to wrap_text in a cell?
Here is the code:
from openpyxl import load_workbook
from openpyxl.styles import Alignment
file1 = "C:\\folder\\inputFile1.xlsx"
wb=load_workbook(file1)
ws = wb.active
for rows in ws.iter_rows(min_row=10, max_row=None, min_col=None, max_col=None):
for cell in rows:
cell.alignment = cell.alignment.copy(wrapText=True)
wb.save('C:\\folder\file1_wrap.xlsx')
here is the deprecation warning:
C:\Users\Jcurran\AppData\Local\Continuum\anaconda3\lib\site-packages\ipykernel_launcher.py:10: DeprecationWarning: Call to deprecated function copy (Use copy(obj) or cell.obj = cell.obj + other).
Remove the CWD from sys.path while we load stuff.
How might I figure out the way to find the information required to use the current (non-deprecated) approach to wrapping text in cells via the documentation at https://openpyxl.readthedocs.io/en/stable/?
I am using Jupyter for my environment. Shift tab or tab doesn't give me anything useful.
Any suggestions? I crave self sufficiency but can't grasp how to navigate the documentation for answer. There must be some clue somewhere? Some source code perhaps that I do not know how to locate?
I learned that I did not have the latest openpyxl version. pip install openpyxl installed 2.5. I upgraded it to 3.0.
Now when I look at https://openpyxl.readthedocs.io/en/stable/index.html it makes more sense :-)
I now know that the "Working with Styles" section of the openpyxl 3.0 documentation is the place to go for formatting data.
So I click that, and go to https://openpyxl.readthedocs.io/en/stable/styles.html
That page shows me this:
>>> alignment=Alignment(horizontal='general',
... vertical='bottom',
... text_rotation=0,
... wrap_text=False,
... shrink_to_fit=False,
... indent=0)
and I could use that info to wrap text with this line:
cell.alignment = Alignment(wrapText=True)
Now things are starting to make sense for me. :-) Thanks!
Related
Is there a way to make excel visible with openpyxl module in python 3.7.5?
Did some reasearch on documentation and other resources but did not find any answer.
https://openpyxl.readthedocs.io/en/2.6/api/openpyxl.workbook.properties.html
openpyxl.__version__
> '2.6.0'
My objective is to obtain the same result as with use of win32com.client
xlApp = win32com.client.Dispatch('Excel.Application')
xlApp.Application.Visible = True
Tried setting visibility = 'visible' and minimized=False within parameters of openpyxl.workbook.views.BookView object
Also tried setting different parameters within 'sheetview' as specified in this topic:
Set workbook view with openpyxl?
Yet with no success. I believe that there is possibility to do so but i couldnt dig to the answer.
Would appreciate getting some help with the package as documentation does not include detailed descriptions.
I have the -current- latest version of pandas, openpyxl, xlrd.
openpyxl : 3.0.6.
pandas : 1.2.2.
xlrd : 2.0.1.
I have a generated excel xlsx- file (export from a webapplication).
I read it in pandas:
myexcelfile = pd.read_excel(easy_payfile, engine="openpyxl")
Everything goes ok, I can successfully read the file.
But I do get a warning:
/Users/*******/projects/environments/venv/lib/python3.8/site-packages/openpyxl/styles/stylesheet.py:214: UserWarning: Workbook contains no default style, apply openpyxl's default
warn("Workbook contains no default style, apply openpyxl's default")
The documentation doesn't shed too much light on it.
Is there any way I can add an option to avoid this warning?
I prefer not to suppress it.
I don't think the library offers you a way to disable this thus you are going to need to use the warnings package directly.
A simple and punctual solution to the problem would be doing:
import warnings
with warnings.catch_warnings(record=True):
warnings.simplefilter("always")
myexcelfile = pd.read_excel(easy_payfile, engine="openpyxl")
df=pd.read_excel("my.xlsx",engine="openpyxl") passing the engine parameter got rid of the warning for me. Default = None, so I think it is just warning you that it using openpyxl for default style.
I had the same warning. Just changed the sheet name of my excel file from "sheet_1" to "Sheet1", then the warning disappeared. very similar with Yoan. I think pandas should fix this warning later.
#ruhanbidart solution is better because you turn off warnings just for the call to read_excel, but if you have dozens of calls to pd.read_excel, you can simply disable all warnings:
import warnings
warnings.simplefilter("ignore")
I had the exact same warning and was unable to read the file. In my case the problem was coming from the Sheet name in the Excel file.
The initial name contained a . (ex: MDM.TARGET) I simply replace the . with _ and everything's fine.
In my situation some columns' names had a dollar sign ($) in them. Replacing '$' to '_' solved the issue.
I have to read informations from a .mpr file (in order to complete a dataset). Does anyone know how it works ?
I tried with pandas, open(), but on the net i got anything ..
Thanks a lot !
There's a package on GitHub called galvani that you can use. Install from source (it seems that their pip install galvani is not updated)
Then simply do:
from galvani import BioLogic as BL
import pandas as pd
mpr = BL.MPRfile('path_to_your.mpr')
df = pd.DataFrame(mpr.data)
df.head()
You will see your data
Why do I receive this warning message every time I run my code? (below). Is it possible to get rid of it? If so, how do I do that?
My code:
from openpyxl import load_workbook
from openpyxl import Workbook
wb = load_workbook('NFL.xlsx', data_only = True)
ws = wb.active
sh = wb["Sheet1"]
ptsDiff = (sh['J127'].value)
print ptsDiff
The code works but I get this warning message:
Warning (from warnings module):
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/openpyxl/reader/worksheet.py", line 320
warn(msg)
UserWarning: Unknown extension is not supported and will be removed
This error happens when openpyxl cannot understand/read an extension (source). Here is the list of built-in extensions openpyxl currently knows that is doesn't support:
Conditional Formatting
Data Validation
Sparkline Group
Slicer List
Protected Range
Ignored Error
Web Extension
Slicer List
Timeline Ref
Also see the Worksheet extension list specification.
Try to add single quotes to your data_only parameter like this:
wb = load_workbook('NFL.xlsx', data_only = **'True'**)
This works for me.
Using python 3.5 under Anaconda3, Excel 2016, Windows10 -- I had the same problem initially with an xlsx file. Tried to make it into a csv and did not work. What worked was: select the entire spreadsheet, copy on a Notepad, select the notepad text, paste in a new spreadsheet, save as xslx. It looks like any extra formatting would result in a warning.
It is already listed in the first answer what is wrong with it If you only want to get rid of the error that is given in red for some reason. You can go to the file location of the error and # the line where is says warn(msg) this will stop the error being displayed the code still works fine in my experience.I am not sure if this will work after compiled but this should work in the same machine.
PS:I had the same error and this is what I did because I though it could be confusing for the end user
PS:You can use a try and except error catcher too but this is quicker.
I am practicing with openpyxl and I'm working on an Excel file called 'test.xlsx'. The file only has 3 columns and 7 rows. The .xlsx file was created with LibreOffice.
When I run...
>>> #! python3
>>> import openpyxl
>>> wb = openpyxl.load_workbook('test.xlsx')
>>> sheet = wb.get_sheet_by_name('Sheet1')
>>> sheet.get_highest_column()
1025
The returned value should be 3.
A quick Google search suggested I run:
>>> sheet.calculate_dimension()
and got the return value:
'A1:AMK7'
This should only be 'A1:C7'.
I remember reading that LibreOffice could be part of the problem to this.
However, I can't switch to MSOffice, and I hate OpenOffice.
Is there suggestion on how I could fix this, or work around it?
Thanks!
It sounds like you're using older versions of LibreOffice and openpyxl. LibreOffice did used to set a default value of "A1:AMK7" for the dimensions but it version 5 doesn't seem to be doing that any more. openpyxl used to rely on the dimensions tag when reading files but hasn't done this for a while. Please try using openpyxl 2.3-b2