Why would calling the super class `__getattribute__` cause an infinite recursion? - python

clearly the following will result in an infinite loop:
class Klaus:
def __getattribute__(self, key):
return getattr(type(self), key)
However, I don't see why calling the super class __getattribute__ would:
class Parent:
def __init__(self):
print("begin __init__")
self._x = 3
print("end __init__")
def __getattribute__(self, attr_name):
superk = super(type(self), self)
boohl = superk.__getattribute__ == self.__getattribute__
print("with age comes wisdom", boohl)
return superk.__getattribute__(attr_name)
class Child(Parent):
def __getattribute__(self, attr_name):
superk = super(type(self), self)
boohl = superk.__getattribute__ == self.__getattribute__
print("this booger is green!", boohl)
return super(type(self), self).__getattribute__(attr_name)
obj = Child()
print("lambda")
print(obj._x)
print("anonymous")

Because type(self) is always Child. Even though you're in a method of Parent, self is still an instance of Child.
This is why when you use the long form of super you must always explicitly use the current class, rather than this. Of course, in Python 3 you can use super() without any parameters anyway.

Related

Using #classmethod with #property [duplicate]

This question already has answers here:
Using property() on classmethods
(19 answers)
Closed 3 years ago.
In python I can add a method to a class with the #classmethod decorator. Is there a similar decorator to add a property to a class? I can better show what I'm talking about.
class Example(object):
the_I = 10
def __init__( self ):
self.an_i = 20
#property
def i( self ):
return self.an_i
def inc_i( self ):
self.an_i += 1
# is this even possible?
#classproperty
def I( cls ):
return cls.the_I
#classmethod
def inc_I( cls ):
cls.the_I += 1
e = Example()
assert e.i == 20
e.inc_i()
assert e.i == 21
assert Example.I == 10
Example.inc_I()
assert Example.I == 11
Is the syntax I've used above possible or would it require something more?
The reason I want class properties is so I can lazy load class attributes, which seems reasonable enough.
Here's how I would do this:
class ClassPropertyDescriptor(object):
def __init__(self, fget, fset=None):
self.fget = fget
self.fset = fset
def __get__(self, obj, klass=None):
if klass is None:
klass = type(obj)
return self.fget.__get__(obj, klass)()
def __set__(self, obj, value):
if not self.fset:
raise AttributeError("can't set attribute")
type_ = type(obj)
return self.fset.__get__(obj, type_)(value)
def setter(self, func):
if not isinstance(func, (classmethod, staticmethod)):
func = classmethod(func)
self.fset = func
return self
def classproperty(func):
if not isinstance(func, (classmethod, staticmethod)):
func = classmethod(func)
return ClassPropertyDescriptor(func)
class Bar(object):
_bar = 1
#classproperty
def bar(cls):
return cls._bar
#bar.setter
def bar(cls, value):
cls._bar = value
# test instance instantiation
foo = Bar()
assert foo.bar == 1
baz = Bar()
assert baz.bar == 1
# test static variable
baz.bar = 5
assert foo.bar == 5
# test setting variable on the class
Bar.bar = 50
assert baz.bar == 50
assert foo.bar == 50
The setter didn't work at the time we call Bar.bar, because we are calling
TypeOfBar.bar.__set__, which is not Bar.bar.__set__.
Adding a metaclass definition solves this:
class ClassPropertyMetaClass(type):
def __setattr__(self, key, value):
if key in self.__dict__:
obj = self.__dict__.get(key)
if obj and type(obj) is ClassPropertyDescriptor:
return obj.__set__(self, value)
return super(ClassPropertyMetaClass, self).__setattr__(key, value)
# and update class define:
# class Bar(object):
# __metaclass__ = ClassPropertyMetaClass
# _bar = 1
# and update ClassPropertyDescriptor.__set__
# def __set__(self, obj, value):
# if not self.fset:
# raise AttributeError("can't set attribute")
# if inspect.isclass(obj):
# type_ = obj
# obj = None
# else:
# type_ = type(obj)
# return self.fset.__get__(obj, type_)(value)
Now all will be fine.
If you define classproperty as follows, then your example works exactly as you requested.
class classproperty(object):
def __init__(self, f):
self.f = f
def __get__(self, obj, owner):
return self.f(owner)
The caveat is that you can't use this for writable properties. While e.I = 20 will raise an AttributeError, Example.I = 20 will overwrite the property object itself.
[answer written based on python 3.4; the metaclass syntax differs in 2 but I think the technique will still work]
You can do this with a metaclass...mostly. Dappawit's almost works, but I think it has a flaw:
class MetaFoo(type):
#property
def thingy(cls):
return cls._thingy
class Foo(object, metaclass=MetaFoo):
_thingy = 23
This gets you a classproperty on Foo, but there's a problem...
print("Foo.thingy is {}".format(Foo.thingy))
# Foo.thingy is 23
# Yay, the classmethod-property is working as intended!
foo = Foo()
if hasattr(foo, "thingy"):
print("Foo().thingy is {}".format(foo.thingy))
else:
print("Foo instance has no attribute 'thingy'")
# Foo instance has no attribute 'thingy'
# Wha....?
What the hell is going on here? Why can't I reach the class property from an instance?
I was beating my head on this for quite a while before finding what I believe is the answer. Python #properties are a subset of descriptors, and, from the descriptor documentation (emphasis mine):
The default behavior for attribute access is to get, set, or delete the
attribute from an object’s dictionary. For instance, a.x has a lookup chain
starting with a.__dict__['x'], then type(a).__dict__['x'], and continuing
through the base classes of type(a) excluding metaclasses.
So the method resolution order doesn't include our class properties (or anything else defined in the metaclass). It is possible to make a subclass of the built-in property decorator that behaves differently, but (citation needed) I've gotten the impression googling that the developers had a good reason (which I do not understand) for doing it that way.
That doesn't mean we're out of luck; we can access the properties on the class itself just fine...and we can get the class from type(self) within the instance, which we can use to make #property dispatchers:
class Foo(object, metaclass=MetaFoo):
_thingy = 23
#property
def thingy(self):
return type(self).thingy
Now Foo().thingy works as intended for both the class and the instances! It will also continue to do the right thing if a derived class replaces its underlying _thingy (which is the use case that got me on this hunt originally).
This isn't 100% satisfying to me -- having to do setup in both the metaclass and object class feels like it violates the DRY principle. But the latter is just a one-line dispatcher; I'm mostly okay with it existing, and you could probably compact it down to a lambda or something if you really wanted.
If you use Django, it has a built in #classproperty decorator.
from django.utils.decorators import classproperty
For Django 4, use:
from django.utils.functional import classproperty
I think you may be able to do this with the metaclass. Since the metaclass can be like a class for the class (if that makes sense). I know you can assign a __call__() method to the metaclass to override calling the class, MyClass(). I wonder if using the property decorator on the metaclass operates similarly.
Wow, it works:
class MetaClass(type):
def getfoo(self):
return self._foo
foo = property(getfoo)
#property
def bar(self):
return self._bar
class MyClass(object):
__metaclass__ = MetaClass
_foo = 'abc'
_bar = 'def'
print MyClass.foo
print MyClass.bar
Note: This is in Python 2.7. Python 3+ uses a different technique to declare a metaclass. Use: class MyClass(metaclass=MetaClass):, remove __metaclass__, and the rest is the same.
As far as I can tell, there is no way to write a setter for a class property without creating a new metaclass.
I have found that the following method works. Define a metaclass with all of the class properties and setters you want. IE, I wanted a class with a title property with a setter. Here's what I wrote:
class TitleMeta(type):
#property
def title(self):
return getattr(self, '_title', 'Default Title')
#title.setter
def title(self, title):
self._title = title
# Do whatever else you want when the title is set...
Now make the actual class you want as normal, except have it use the metaclass you created above.
# Python 2 style:
class ClassWithTitle(object):
__metaclass__ = TitleMeta
# The rest of your class definition...
# Python 3 style:
class ClassWithTitle(object, metaclass = TitleMeta):
# Your class definition...
It's a bit weird to define this metaclass as we did above if we'll only ever use it on the single class. In that case, if you're using the Python 2 style, you can actually define the metaclass inside the class body. That way it's not defined in the module scope.
def _create_type(meta, name, attrs):
type_name = f'{name}Type'
type_attrs = {}
for k, v in attrs.items():
if type(v) is _ClassPropertyDescriptor:
type_attrs[k] = v
return type(type_name, (meta,), type_attrs)
class ClassPropertyType(type):
def __new__(meta, name, bases, attrs):
Type = _create_type(meta, name, attrs)
cls = super().__new__(meta, name, bases, attrs)
cls.__class__ = Type
return cls
class _ClassPropertyDescriptor(object):
def __init__(self, fget, fset=None):
self.fget = fget
self.fset = fset
def __get__(self, obj, owner):
if self in obj.__dict__.values():
return self.fget(obj)
return self.fget(owner)
def __set__(self, obj, value):
if not self.fset:
raise AttributeError("can't set attribute")
return self.fset(obj, value)
def setter(self, func):
self.fset = func
return self
def classproperty(func):
return _ClassPropertyDescriptor(func)
class Bar(metaclass=ClassPropertyType):
__bar = 1
#classproperty
def bar(cls):
return cls.__bar
#bar.setter
def bar(cls, value):
cls.__bar = value
bar = Bar()
assert Bar.bar==1
Bar.bar=2
assert bar.bar==2
nbar = Bar()
assert nbar.bar==2
I happened to come up with a solution very similar to #Andrew, only DRY
class MetaFoo(type):
def __new__(mc1, name, bases, nmspc):
nmspc.update({'thingy': MetaFoo.thingy})
return super(MetaFoo, mc1).__new__(mc1, name, bases, nmspc)
#property
def thingy(cls):
if not inspect.isclass(cls):
cls = type(cls)
return cls._thingy
#thingy.setter
def thingy(cls, value):
if not inspect.isclass(cls):
cls = type(cls)
cls._thingy = value
class Foo(metaclass=MetaFoo):
_thingy = 23
class Bar(Foo)
_thingy = 12
This has the best of all answers:
The "metaproperty" is added to the class, so that it will still be a property of the instance
Don't need to redefine thingy in any of the classes
The property works as a "class property" in for both instance and class
You have the flexibility to customize how _thingy is inherited
In my case, I actually customized _thingy to be different for every child, without defining it in each class (and without a default value) by:
def __new__(mc1, name, bases, nmspc):
nmspc.update({'thingy': MetaFoo.services, '_thingy': None})
return super(MetaFoo, mc1).__new__(mc1, name, bases, nmspc)
If you only need lazy loading, then you could just have a class initialisation method.
EXAMPLE_SET = False
class Example(object):
#classmethod
def initclass(cls):
global EXAMPLE_SET
if EXAMPLE_SET: return
cls.the_I = 'ok'
EXAMPLE_SET = True
def __init__( self ):
Example.initclass()
self.an_i = 20
try:
print Example.the_I
except AttributeError:
print 'ok class not "loaded"'
foo = Example()
print foo.the_I
print Example.the_I
But the metaclass approach seems cleaner, and with more predictable behavior.
Perhaps what you're looking for is the Singleton design pattern. There's a nice SO QA about implementing shared state in Python.

How to use __setattr__ correctly, avoiding infinite recursion

I want to define a class containing read and write methods, which can be called as follows:
instance.read
instance.write
instance.device.read
instance.device.write
To not use interlaced classes, my idea was to overwrite the __getattr__ and __setattr__ methods and to check, if the given name is device to redirect the return to self. But I encountered a problem giving infinite recursions. The example code is as follows:
class MyTest(object):
def __init__(self, x):
self.x = x
def __setattr__(self, name, value):
if name=="device":
print "device test"
else:
setattr(self, name, value)
test = MyTest(1)
As in __init__ the code tried to create a new attribute x, it calls __setattr__, which again calls __setattr__ and so on. How do I need to change this code, that, in this case, a new attribute x of self is created, holding the value 1?
Or is there any better way to handle calls like instance.device.read to be 'mapped' to instance.read?
As there are always questions about the why: I need to create abstractions of xmlrpc calls, for which very easy methods like myxmlrpc.instance,device.read and similar can be created. I need to 'mock' this up to mimic such multi-dot-method calls.
You must call the parent class __setattr__ method:
class MyTest(object):
def __init__(self, x):
self.x = x
def __setattr__(self, name, value):
if name=="device":
print "device test"
else:
super(MyTest, self).__setattr__(name, value)
# in python3+ you can omit the arguments to super:
#super().__setattr__(name, value)
Regarding the best-practice, since you plan to use this via xml-rpc I think this is probably better done inside the _dispatch method.
A quick and dirty way is to simply do:
class My(object):
def __init__(self):
self.device = self
Or you can modify self.__dict__ from inside __setattr__():
class SomeClass(object):
def __setattr__(self, name, value):
print(name, value)
self.__dict__[name] = value
def __init__(self, attr1, attr2):
self.attr1 = attr1
self.attr2 = attr2
sc = SomeClass(attr1=1, attr2=2)
sc.attr1 = 3
You can also use object.
class TestClass:
def __init__(self):
self.data = 'data'
def __setattr__(self, name, value):
print("Attempt to edit the attribute %s" %(name))
object.__setattr__(self, name, value)
or you can just use #property:
class MyTest(object):
def __init__(self, x):
self.x = x
#property
def device(self):
return self
If you don't want to specify which attributes can or cannot be set, you can split the class to delay the get/set hooks until after initialization:
class MyTest(object):
def __init__(self, x):
self.x = x
self.__class__ = _MyTestWithHooks
class _MyTestWithHooks(MyTest):
def __setattr__(self, name, value):
...
def __getattr__(self, name):
...
if __name__ == '__main__':
a = MyTest(12)
...
As noted in the code you'll want to instantiate MyTest, since instantiating _MyTestWithHooks will result in the same infinite recursion problem as before.

How can I add a delay to every method in a Python sub-class when I don't want to replicate every method in the parent class

My apologies if this question has already been answered somewhere, but if it has I have not been able to locate the answer.
I would like to create a sub-class of a parent class in such a way that there will be a delay (e.g. time.sleep()) before each call to the corresponding parent class method. I would like to do this in such a way that I do not need to replicate each parent class method in the child class. In fact, I would like to have a generic method that would work with virtually any parent class -- so that I do not even need to know all the parent class methods.
The delay would be specified when instantiating the sub-class.
For example:
class Parent():
....
def method1(self):
....
def method2(self):
....
class Child(Parent):
def __init__(self, delay)
self.delay = delay
....
child = Child(1)
A call to child.method1() would result in a 1 second delay before Parent.method1() is called.
I think the previously given answers have not really addressed your specific need to delay ALL methods from the parent class, and not necessarily have to go and decorate them. You said you do NOT want to have to replicate the parent class method in the child class just so that you can delay them. This answer uses the same delay wrapper from S.Lott, but also uses a metaclass (http://www.voidspace.org.uk/python/articles/metaclasses.shtml)
#!/usr/bin/env python
from types import FunctionType
import time
def MetaClassFactory(function):
class MetaClass(type):
def __new__(meta, classname, bases, classDict):
newClassDict = {}
for attributeName, attribute in classDict.items():
if type(attribute) == FunctionType:
attribute = function(attribute)
newClassDict[attributeName] = attribute
return type.__new__(meta, classname, bases, newClassDict)
return MetaClass
def delayed(func):
def wrapped(*args, **kwargs):
time.sleep(2)
func(*args, **kwargs)
return wrapped
Delayed = MetaClassFactory(delayed)
class MyClass(object):
__metaclass__ = Delayed
def a(self):
print 'foo'
def b(self):
print 'bar'
The MetaClassFactory wraps every function in the delayed decorator. If you wanted to make sure certain built-ins like the init function were not delayed, you could just check for that name in the MetaClassFactory and ignore it.
Really, what you have here is a design that involves a Strategy object.
Your best approach is to fix the parent class to include a call to a "delay object". A default delay object does nothing.
This violates the "so that I do not even need to know all the parent class methods" hoped-for feature set.
Method lookup doesn't have a handy __getmethod__ that corresponds to __getattribute__; this gap makes it difficult to tap into Python's internals for method invocation.
class Parent( object ):
delay= ZeroDelay()
def method1(self):
self.delay()
....
def method2(self):
self.delay()
...
class ZeroDelay( object ):
def __call__( self ):
pass
class ShortDelay( ZeroDelay ):
def __init__( self, duration=1.0 )
self.duration= duration
def __call__( self ):
time.sleep( self.duration )
class Child( Parent ):
delay= ShortDelay( 1 )
EDIT: Of course, you can decorate each method, also.
def delayed( delayer ):
def wrap( a_method ):
def do_delay( *args, **kw ):
delayer()
return a_method( *args, **kw )
return do_delay
return wrap
class Parent( object ):
delay= ZeroDelay()
#delayed( self.delay )
def method1(self):
self.delay()
....
#delayed( self.delay )
def method2(self):
self.delay()
...
S.Lott solution is a good one. If you need more granularity (i.e. to delay only certain methods, not all of them), you could go with a decorator:
from time import sleep
def delayed(func):
'''This is the decorator'''
def wrapped(*args, **kwargs):
sleep(2)
func(*args, **kwargs)
return wrapped
class Example(object):
#delayed
def method(self, str):
print str
e = Example()
print "Brace! I'm delaying!"
e.method("I'm done!")
The idea is that you add #delayed in before the definition of those methods you want to delete.
EDIT: Even more granularity: setting an arbitrary delay:
from time import sleep
def set_delay(seconds):
def delayed(func):
'''This is the decorator'''
def wrapped(*args, **kwargs):
sleep(seconds)
func(*args, **kwargs)
return wrapped
return delayed
class Example(object):
#set_delay(1)
def method(self, str):
print str
#set_delay(2)
def method_2(self, str):
print str
e = Example()
print "Brace! I'm delaying!"
e.method("I'm done!")
e.method_2("I'm also done!")
You can achieve what you want by using the method __getattribute__
class Child(Parent):
def __init__(self, delay):
self.delay = delay
def __getattribute__(self, name):
attr = object.__getattribute__(self, name)
if hasattr(attr, '__call__'):
def proxFct(*args, **kwargs):
time.sleep(object.__getattribute__(self, "delay"))
return attr(*args, **kwargs)
return proxFct
else:
return attr
Update: Updated according delnan's comment
Update 2: Updated according delnan's second comment

Overriding inherited properties’ getters and setters in Python

I’m currently using the #property decorator to achieve “getters and setters” in a couple of my classes. I wish to be able to inherit these #property methods in a child class.
I have some Python code (specifically, I’m working in py3k) which looks vaguely like so:
class A:
#property
def attr(self):
try:
return self._attr
except AttributeError:
return ''
class B(A):
#property
def attr(self):
return A.attr # The bit that doesn't work.
#attr.setter
def attr(self, value):
self._attr = value
if __name__ == '__main__':
b = B()
print('Before set:', repr(b.attr))
b.attr = 'abc'
print(' After set:', repr(b.attr))
I have marked the part that doesn’t work with a comment. I want the base class’ attr getter to be returned. A.attr returns a property object (which is probably very close to what I need!).
Edit:
After receiving the answer below from Ned I thought up what I think is a more elegant solution to this problem.
class A:
#property
def attr(self):
try:
return self._attr
except AttributeError:
return ''
class B(A):
#A.attr.setter
def attr(self, value):
self._attr = value
if __name__ == '__main__':
b = B()
print('Before set:', repr(b.attr))
b.attr = 'abc'
print(' After set:', repr(b.attr))
The .setter decorator expects a property object which we can get using #A.attr. This means we do not have to declare the property again in the child class.
(This is the difference between working on a problem at the end of the day vs working on it at the beginning of the day!)
To override a setter in python 2 I did this:
class A(object):
def __init__(self):
self._attr = None
#property
def attr(self):
return self._attr
#attr.setter
def attr(self, value):
self._attr = value
class B(A):
#A.attr.setter
def attr(self, value):
# Do some crazy stuff with `value`
value = value[0:3]
A.attr.fset(self, value)
To understand where A.attr.fset came from see the documentation on the property class:
https://docs.python.org/2/library/functions.html#property
I think you want:
class B(A):
#property
def attr(self):
return super(B, self).attr
You mention wanting to return the parent class's getter, but you need to invoke the getter, not return it.

How to call a property of the base class if this property is being overwritten in the derived class?

I'm changing some classes of mine from an extensive use of getters and setters to a more pythonic use of properties.
But now I'm stuck because some of my previous getters or setters would call the corresponding method of the base class, and then perform something else. But how can this be accomplished with properties? How to call the property getter or setter in the parent class?
Of course just calling the attribute itself gives infinite recursion.
class Foo(object):
#property
def bar(self):
return 5
#bar.setter
def bar(self, a):
print a
class FooBar(Foo):
#property
def bar(self):
# return the same value
# as in the base class
return self.bar # --> recursion!
#bar.setter
def bar(self, c):
# perform the same action
# as in the base class
self.bar = c # --> recursion!
# then do something else
print 'something else'
fb = FooBar()
fb.bar = 7
You might think you could call the base class function which is called by property:
class FooBar(Foo):
#property
def bar(self):
# return the same value
# as in the base class
return Foo.bar(self)
Though this is the most obvious thing to try I think - it does not work because bar is a property, not a callable.
But a property is just an object, with a getter method to find the corresponding attribute:
class FooBar(Foo):
#property
def bar(self):
# return the same value
# as in the base class
return Foo.bar.fget(self)
super() should do the trick:
return super().bar
In Python 2.x you need to use the more verbose syntax:
return super(FooBar, self).bar
There is an alternative using super that does not require to explicitly reference the base class name.
Base class A:
class A(object):
def __init__(self):
self._prop = None
#property
def prop(self):
return self._prop
#prop.setter
def prop(self, value):
self._prop = value
class B(A):
# we want to extend prop here
pass
In B, accessing the property getter of the parent class A:
As others have already answered, it's:
super(B, self).prop
Or in Python 3:
super().prop
This returns the value returned by the getter of the property, not the getter itself but it's sufficient to extend the getter.
In B, accessing the property setter of the parent class A:
The best recommendation I've seen so far is the following:
A.prop.fset(self, value)
I believe this one is better:
super(B, self.__class__).prop.fset(self, value)
In this example both options are equivalent but using super has the advantage of being independent from the base classes of B. If B were to inherit from a C class also extending the property, you would not have to update B's code.
Full code of B extending A's property:
class B(A):
#property
def prop(self):
value = super(B, self).prop
# do something with / modify value here
return value
#prop.setter
def prop(self, value):
# do something with / modify value here
super(B, self.__class__).prop.fset(self, value)
One caveat:
Unless your property doesn't have a setter, you have to define both the setter and the getter in B even if you only change the behaviour of one of them.
try
#property
def bar:
return super(FooBar, self).bar
Although I'm not sure if python supports calling the base class property. A property is actually a callable object which is set up with the function specified and then replaces that name in the class. This could easily mean that there is no super function available.
You could always switch your syntax to use the property() function though:
class Foo(object):
def _getbar(self):
return 5
def _setbar(self, a):
print a
bar = property(_getbar, _setbar)
class FooBar(Foo):
def _getbar(self):
# return the same value
# as in the base class
return super(FooBar, self)._getbar()
def bar(self, c):
super(FooBar, self)._setbar(c)
print "Something else"
bar = property(_getbar, _setbar)
fb = FooBar()
fb.bar = 7
Some small improvements to Maxime's answer:
Using __class__ to avoid writing B. Note that self.__class__ is the runtime type of self, but __class__ without self is the name of the enclosing class definition. super() is a shorthand for super(__class__, self).
Using __set__ instead of fset. The latter is specific to propertys, but the former applies to all property-like objects (descriptors).
class B(A):
#property
def prop(self):
value = super().prop
# do something with / modify value here
return value
#prop.setter
def prop(self, value):
# do something with / modify value here
super(__class__, self.__class__).prop.__set__(self, value)
You can use the following template:
class Parent():
def __init__(self, value):
self.__prop1 = value
#getter
#property
def prop1(self):
return self.__prop1
#setter
#prop1.setter
def prop1(self, value):
self.__prop1 = value
#deleter
#prop1.deleter
def prop1(self):
del self.__prop1
class Child(Parent):
#getter
#property
def prop1(self):
return super(Child, Child).prop1.__get__(self)
#setter
#prop1.setter
def prop1(self, value):
super(Child, Child).prop1.__set__(self, value)
#deleter
#prop1.deleter
def prop1(self):
super(Child, Child).prop1.__delete__(self)
Note! All of the property methods must be redefined together. If do not want to redefine all methods, use the following template instead:
class Parent():
def __init__(self, value):
self.__prop1 = value
#getter
#property
def prop1(self):
return self.__prop1
#setter
#prop1.setter
def prop1(self, value):
self.__prop1 = value
#deleter
#prop1.deleter
def prop1(self):
del self.__prop1
class Child(Parent):
#getter
#Parent.prop1.getter
def prop1(self):
return super(Child, Child).prop1.__get__(self)
#setter
#Parent.prop1.setter
def prop1(self, value):
super(Child, Child).prop1.__set__(self, value)
#deleter
#Parent.prop1.deleter
def prop1(self):
super(Child, Child).prop1.__delete__(self)
class Base(object):
def method(self):
print "Base method was called"
class Derived(Base):
def method(self):
super(Derived,self).method()
print "Derived method was called"
d = Derived()
d.method()
(that is unless I am missing something from your explanation)

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