Call a stored method on a object [duplicate] - python

This question already has answers here:
How to access (get or set) object attribute given string corresponding to name of that attribute
(3 answers)
Closed 3 years ago.
I have a list of methods that i wish to apply on a list of objects. The objects contain info that will change the outcome of the methods. I will then store the objects that got an outcome that i want.
The code looks as the following: where chefs is the objects that should carry out an action on an ingredient.
I am getting this error AttributeError: 'Chef' object has no attribute 'possibleAction'
It seems like the compiler does not take the value from possibleAction (which i want) and instead just take the name of the variabel.
I am not sure if this is possible but i know that you can store function in variabels and then call them, so then this maybe works on methods too i thought. Anyway i am appriacting all the help i can get, cheers :)
possibleStates = []
for chef in state.getChefs():
for possibleAction in getAllPossibleActionForChef():
for ingredient in state.getKitchen().getIngredients():
newPossibleState = copy.copy(state)
if chef.possibleAction(ingredient): # Do doAction on state, if true save else trow away
possibleStates.append(newPossibleState)
return possibleStates

Use getattr to get the method you want using a string:
getattr(chef, possibleAction)(ingredient)

chef.possibleAction(ingredient):
This statement indicates that possibleAction() is an instance method belonging either to chef class or its parent class which can be called by chef object.
Ensure that chef class contains the possibleAction method declaration in it or in its parent class.

Related

How to dynamically return Object attributes in python, including attributes of objects that are attributes

I am trying to write a testing program for a python program that takes data, does calculations on it, then puts the output in a class instance object. This object contains several other objects, each with their own attributes. I'm trying to access all the attributes and sub-attributes dynamically with a one size fits all solution, corresponding to elements in a dictionary I wrote to cycle through and get all those attributes for printing onto a test output file.
Edit: this may not be clear from the above but I have a list of the attributes I want, so using something to actually get those attributes is not a problem, although I'm aware python has methods that accomplish this. What I need to do is to be able to get all of those attributes with the same function call, regardless of whether they are top level object attributes or attributes of object attributes.
Python is having some trouble with this - first I tried doing something like this:
for string in attr_dictionary:
...
outputFile.print(outputclass.string)
...
But Python did not like this, and returned an AttributeError
After checking SE, I learned that this is a supposed solution:
for string in attr_dictionary:
...
outputFile.print(getattr(outputclass, string))
...
The only problem is - I want to dynamically access the attributes of objects that are attributes of outputclass. So ideally it would be something like outputclass.objectAttribute.attribute, but this does not work in python. When I use getattr(outputclass, objectAttribute.string), python returns an AttributeError
Any good solution here?
One thing I have thought of trying is creating methods to return those sub-attributes, something like:
class outputObject:
...
def attributeIWant(self,...):
return self.subObject.attributeIWant
...
Even then, it seems like getattr() will return an error because attributeIWant() is supposed to be a function call, it's not actually an attribute. I'm not certain that this is even within the capabilities of Python to make this happen.
Thank you in advance for reading and/or responding, if anyone is familiar with a way to do this it would save me a bunch of refactoring or additional code.
edit: Additional Clarification
The class for example is outputData, and inside that class you could have and instance of the class furtherData, which has the attribute dataIWant:
class outputData:
example: furtherData
example = furtherData()
example.dataIWant = someData
...
with the python getattr I can't access both attributes directly in outputData and attributes of example unless I use separate calls, the attribute of example needs two calls to getattr.
Edit2: I have found a solution I think works for this, see below
I was able to figure this out - I just wrote a quick function that splits the attribute string (for example outputObj.subObj.propertyIWant) then proceeds down the resultant array, calling getattr on each subobject until it reaches the end of the array and returns the actual attribute.
Code:
def obtainAttribute(sample, attributeString: str):
baseObj = sample
attrArray = attributeString.split(".")
for string in attrArray:
if(attrArray.index(string) == (len(attrArray) - 1)):
return getattr(baseObj,string)
else:
baseObj = getattr(baseObj,string)
return "failed"
sample is the object and attributeString is, for example object.subObject.attributeYouWant

python see the full definition from the name of the function [duplicate]

This question already has answers here:
How can I get the source code of a Python function?
(13 answers)
Closed 4 years ago.
I recently asked a question with title "python find the type of a function" and got very helpful answers. Here is a related question.
Suppose I import *.py files written by me, and these imports result in f being one of the functions defined by me. Now I write to my python interpreter x = f. Later, I want to see the full definition of f, preferably with comments still in place, knowing only x. Is this possible? Does python remember which file the definition was imported from, which is, of course, not enough to give the full definition of f, unless one can find the actual relevant definition?
The built in help(object) will give you the correct documentation if you alias k to some function you commented - same for inspect.getsource(k) - they know which function is ment by your variable name alias k at this time.
See:
the help() built in
inspect.getsource(k)
(taken from here)
Example:
# reusing this code - created it for some other question today
class well_documented_example_class(object):
"""Totally well documented class"""
def parse(self, message):
"""This method does coool things with your 'message'
'message' : a string with text in it to be parsed"""
self.data = [x.strip() for x in message.split(' ')]
return self.data
# alias for `parse()`:
k = well_documented_example_class.parse
help(k)
Prints:
Help on function parse in module __main__:
parse(self, message)
This method does coool things with your 'message'
'message' : a string with text in it to be parsed
Same goes for inspect.getsource(k):
# from https://stackoverflow.com/a/52333691/7505395
import inspect
print(inspect.getsource(k))
prints:
def parse(self, message):
"""This method does coool things with your 'message'
'message' : a string with text in it to be parsed"""
self.data = [x.strip() for x in message.split(' ')]
return self.data
You should think of the way Python uses variables. You have objects (can be classes, functions, lists, scalars or whatelse) and variables that only hold references to those objects.
That explains why when multiple variables point to the same mutable object, if you change it through one of those variables, the change in visible in all other ones.
This is the same thing here. The function object manages all its attributes: its docstring, its code, and its source (if it has: C function show no source). Assigning the function to a new variable does not hide the object behind anything: you still access the original object.
Things would go differently with decorators, because the decorator creates a new object, and the original object is only available to the decorated one.

Python: change class instance name - create class instance through function [duplicate]

This question already has answers here:
How can you dynamically create variables? [duplicate]
(8 answers)
Closed 4 years ago.
I have a class for which I want to create instances through a function, but I also want to be able to name the instances with the value of a Tkinter.Entry widget.
The simplified version of that I am trying to achieve is the following:
class vtdiagram():
IO=0.0
IC=0.0
EO=0.0
EC=0.0
IGA=0.0
def printvtvalues(self):
print self.IO
print self.IC
print self.EO
print self.EC
print self.IGA
def createvtinstance():
global Nametemp
Nametemp=vtdiagram()
If I run this code, then I can call Nametemp.printvtvalues() and get all values printed, so it works fine.
I am now trying to change the name of the instance Nametemp to the string that is on the Tkinter entry widget. Basically, if engine1 is written on the entry box when I createvtinstance(), I would like to then call the instance by:
engine1.printvtvalues()
and get the values.
I imagine the function should look something like this:
def createvtinstance():
global Nametemp
Nametemp=vtdiagram()
Nametemp._command_to_change_the_name_=stringinentrybox.get()
Do you guys have know of a command that can do such a thing?
Or is there a way that I could achieve the same effect, maybe using a dictionary?
***edit: The reason I need to name the variables is for the following (in plain English): I am creating an 'engine simulator'.
The idea is that the user will enter engine parameters -plus its name- in a GUI and this is the vtdiagram class.
The reason for using a class is that I have the characteristics of 'engine1, engine2...' saved as an instance of the class but I also need to have functions attached to it. This is because I want to generate graphs and diagrams of saved engines but only when called. So I can compare engine1 and engine2, but then get 'forget' engine2 from the GUI to compare 1 and 3.
Please keep in mind I am quite new to python :) ***
Many thanks!
Juan
I wouldn't recommend changing the name of a variable based on user input.
You could "achieve the same effect" like this:
Objects=[]
Names=[]
def createvtinstance(Object=4,Name="engine1"):
global Nametemp
global Objects
global Names
Nametemp=Object # I'll just use an int to demonstrate.
Objects+=[Nametemp]
Names+=[Name]
def Use(Name="engine1"):print(Objects[Names.index(Name)]) # Or: Objects[Names.index(Name)].SomeFunction()
If you REALLY want to alter the name of a variable based on user input, then you could do it like this:
def createvtinstance(Name="engine1"):
if (not Name[0]in"qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM") or False in(i in"1234567890qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM"for i in Name) or Name in("tkinter","createvtinstance","Name","vtdiagram",):return "Invalid name." # This should make the code more "robust".
try:exec("global "+Name+"\n"+Name+"=vtdiagram()")
except SyntaxError:return "Invalid name."
Or this:
def createvtinstance(Name="engine1"):
if (not Name[0]in"qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM") or False in(i in"1234567890qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM"for i in Name) or Name in("tkinter","createvtinstance","Name","vtdiagram",):raise NameError("The name "+Name+" does not comply to validation rules.") # This should make the code more "robust".
try:exec("global "+Name+"\n"+Name+"=vtdiagram()")
except SyntaxError:raise NameError(Name+" is a reserved keyword.")
The top example shows how you would use a list to find an object in another list; using a string. This is what I'd probably do in this situation, however a dictionary could be better.
The bottom examples show how you would actually name a variable based on user input. This is NOT RECOMMENDED. Everyone seems to agree that using exec is counterproductive, and should be avoided. Python can't compile code in exec statements until execution, and won't be able to colour code your code.
People have been suggesting the use of python dictionaries, so I decided to research them. Dictionaries (dict) seem to be a data type similar to lists, except they can be indexed using strings (or other "immutable" data types). Here is a version of my first example that uses a dictionary instead of lists:
Objects={}
def createvtinstance(Object=4,Name="engine1"):
global Objects
Objects[Name]=Object
def Use(Name="engine1"):print(Objects[Name]) # Or: Objects[Name].SomeFunction()
Python seems to have a built in dictionary called globals, which stores all your variables, so you could probably do:
def createvtinstance(Object=4,Name="engine1"):
globals()[Name]=Object # Or globals()[Name]=vtdiagram()
However, this will allow the user to break your program, if they use a name like createvtinstance or tkinter.

Python - Calling a class as a parameter [duplicate]

This question already has answers here:
How to access (get or set) object attribute given string corresponding to name of that attribute
(3 answers)
Closed 5 years ago.
I'm quite new in Python, but googling around did not match any answer for it .
I created a module, containing 10 GUI buttons classes. To use a button I write in code ButtonLib.TypeA(**kwargs), ButtonLib.TypeB(**kwargs) and so on.
kwargs is same for all buttons.
Buttons ( amount and type ) are selected by user (stored in button_type_vector) and not known in advance.
I wish to know if there is a way writing code more efficiently rather than:
for x in button_type_vector:
if x == 'TypeA':
ButtonLib.TypeA(**kwargs)
elif x== 'TypeB' :
ButtonLib.TypeB(**kwargs)
and so on.
by efficiently I mean something like:
for x in button_type_vector:
ButtonLib.x(**kwargs)
thnks
You can use the getattr built-in function to access attributes of an object using strings:
Return the value of the named attribute of object. name must be a string. If the string is the name of one of the object’s attributes, the result is the value of that attribute. For example, getattr(x, 'foobar') is equivalent to x.foobar. If the named attribute does not exist, default is returned if provided, otherwise AttributeError is raised.
for x in button_type_vector:
getattr(ButtonLib, x)(**kwargs)
As mentioned by #MadPyhisist, modules are not some kind of magical object, and thus can be used with like any normal object could be getattr.
You could define a dictionary (preferably inside your module):
buttons = {
"TypeA": TypeA,
"TypeB": TypeB,
…
}
and then call the entry:
ButtonLib.buttons[x](**kwargs)
If your button classes have a function returning their name, you could also define the dictionary like this:
buttons = {
button_type.name: button_type
for button_type in [TypeA, TypeB, …]
}
More advanced: Python stores the name of a class in .__name__.
Even more advanced: You could get the elements of the module with getattr(ButtonLib, name). But this might impair readability.

Python Class shows name not defined [duplicate]

This question already has answers here:
Python - Why is this class variable not defined in the method?
(3 answers)
Why is instance variable not getting recognized
(2 answers)
Closed 6 years ago.
I am writing a piece of code for a homework class, which should allow me to calculate various distance statistics about two lists. However, when I assign the lists to the class, and try to print the result of one of the functions, I get the error,
NameError: name 'ratings1' is not defined
Leading me to believe that I did something incorrectly either in my __init__ function or the referencing in the functions. Can you help clarify what I'm doing wrong?
class similarity:
def __init__(self, ratingX, ratingY):
self.ratings1=ratingX
self.ratings2=ratingY
def minkowski(self,r):
self.r=r
mink=0
length=len(ratings1)
for i in range(0,length):
mink=mink+(abs(ratings1[i]-ratings2[i]))**r
mink=mink**(1/r)
result='Given r=%d, Minkowski distance=%f'%(r,mink)
return result
def pearson(self):
Xavg=average(ratings1)
Yavg=average(ratings2)
n=len(ratings1)
diffX=[]
diffY=[]
for i in range(0,n):
diffX.append(ratings1[i]-Xavg)
diffY.append(ratings2[i]-Yavg)
return diffX
diffXY=[]
for i in range(0,n):
diffXY.append(diffX[i]*diffY[i])
example2=similarity([1,3,5,5,6],[4,6,10,12,13])
print(example2.pearson())
Note: this error persists if I change the references to "ratings1/2" to "ratingsX/Y" in the functions.
You need to use self before every reference to instance variable, ie self.ratings1, and your indentation is wrong as well.
ratings are associated with class. Use self.ratings1 and so on..
I just figured out my mistake. For each function I failed to use the self. phrase before the ratings name. To amend this, I added
ratings1=self.
ratings2=self.ratings2
To the beginning of each function. Problem solved.

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