I am trying to add a sys.exit to my code now, but I want it to display the print messages before quitting. Can I do this? Also, at the end of my code, I would like to give the user the option to quit or start again, but when they type quit after finishing the first game, it just uses quit as their name.
import random
import sys
def system_exit(exitCode):
sys.exit()
# uses randrange instead of randint for better results in Python 3.7
# randrange stops just before the upper range, use (1, 11) for 1-10
num = random.randrange(1, 11)
name = input("What is your name? Or if you would rather quit, type quit at
any time. " "\n")
i = name
while i != "quit":
print('Hello', name,'!')
while i.lower() == 'quit':
print ("Sorry, you did not select a number in the range or
selected to quit. Good bye.")
system_exit(4)
your_guess = input('Enter a number between 1 and 10.' '\n')
if (your_guess.lower() == "quit"):
print ("Sorry, you did not select a number in the range or
selected to quit. Good bye.") #this isn't showing up before closing
your_guess = int(your_guess)
# display the number guessed
print("Your number is", your_guess)
while num != your_guess:
if your_guess < num:
print("Your guess is too low.")
your_guess = int(input("Guess another number from
1 to 10: " '\n'))
elif your_guess > num:
print("Your guess is too high")
your_guess = int(input("Guess another number from
1 to 10: " '\n'))
else:
print ("Sorry, you did not select a number in the
range or selected to quit. Good bye.") #this isn't showing up before
closing
system_exit(4)
print("The correct number was", num)
print("***************************************************************")
name = input("What is your name? Or if you would rather quit, type
quit. ")
num = random.randrange(1, 11)
print("Thank you for playing!") #this isn't showing up before closing
system_exit(0)
Replace the following line of code:
your_guess = int(input('Enter a number between 1 and 10.'))
with the code below:
your_guess = input('Enter a number between 1 and 10.')
if (your_guess.lower() == 'quit'):
#print some break message
your_guess = int(your_guess)
Related
I want to use the try-except code block to notify the user not to insert float type values but integers. The code below doesn't throw an error but rather shuts down.
I guess they are logic errors on the try-except block.
userGuess = int(userGuess)
import random
MAX_GUESSES = 5 # max number of guesses allowed
MAX_RANGE = 20 # highest possible number
# show introductionpygame
print("welcome to my franchise guess number game")
print("guess any number between 1 and", MAX_RANGE)
print("you will have a range from", MAX_GUESSES, "guesses")
def playOneRound():
# choose random target
target = random.randrange(1, MAX_RANGE + 1)
# guess counter
guessCounter = 0
# loop fovever
while True:
userGuess = input("take a guess:")
#check for potential errors
try:
userGuess = int(userGuess)
except:
print("sorry, you are only allowed to enter integers thanks!")
# increment guess counter
guessCounter = guessCounter + 1
# if user's guess is correct, congratulate user, we're done
if userGuess == target:
print("you got it la")
print("it only took you", guessCounter, "guess(es)")
break
elif userGuess < target:
print("try again, your guess is too low.")
else:
print(" your guess was too high")
# if reached max guesses, tell answer correct answer, were done
if guessCounter == MAX_GUESSES:
print(" you didnt get it in ", MAX_GUESSES, "guesses")
print("the number was", target)
break
print("Thanks for playing ")
# main code
while True:
playOneRound() # call a function to play one round of the game
goAgain = input("play again?(press ENTER to continue, or q to quit ):")
if goAgain == "q":
break
The task can be split into two steps:
check that the input string can be converted into a number
check that this number is an integer
while True:
userGuess = input("take a guess: ")
try:
userGuess = float(userGuess) # stuff like "asdf", "33ff" will raise a ValueError
if userGuess.is_integer(): # this is False for 34.2
userGuess = int(userGuess)
break # an integer is found, leave the while loop
except ValueError:
pass # just try again
print("sorry, you are only allowed to enter integers thanks!")
i have to make this GUESS THE NUMBER Gamme from 1-100 that will restart if user wants to play again,
the user can try to find the number 10 times.
But i have a problem..
every time the user says "yes" to play again,the program will not change the random number,i try to find some solution but i didnt
here is the code
import random
guesses = 0 # μετραει ποσες προσπαθειεςς εγιναν απο τον χρηστη
print("Hello,lets play a game...and try to find the number i have guess!!")
number = random.randint(1, 100)
**while guesses < 11:
print('Please Guess a number from (1-100):')
enter = input()
enter = int(enter)
guesses = guesses + 1
if enter < number:
print('This number you enter is lower,please try again')
if enter > number:
print('This number you enter is higher,please try again')
if enter == number:
score = 10 - guesses
score = str(score)
guesses = str(guesses)
print('Well Done, You found it! \nYor Score is' + score + '!')
print('DO you want to play again; yes/no:')
out = input()
if out == "no":
break
elif out == "yes":
guesses = 0
if guesses > 10:
number = str(number)
print("i'm sorry you lost, the number is " + number)
print("Have a great time")**
In addition to reset the guesses inside the elif out == "yes" block, reset also the number. Try:
elif out == "yes":
guesses = 0
number = random.randint(1, 100)
I'm doing an assignment for the computer to generate a random number and have the user input their guess. The problem is I'm supposed to give the user an option to input 'Exit' and it will break the While loop. What am I doing wrong? I'm running it and it says there's something wrong with the line guess = int(input("Guess a number from 1 to 9: "))
import random
num = random.randint(1,10)
tries = 1
guess = 0
guess = int(input("Guess a number from 1 to 9: "))
while guess != num:
if guess == num:
tries = tries + 1
break
elif guess == str('Exit'):
break
elif guess > num:
guess = int(input("Too high! Guess again: "))
tries = tries + 1
continue
else:
guess = int(input("Too low! Guess again: "))
tries = tries + 1
continue
print("Exactly right!")
print("You guessed " + str(tries) + " times.")
The easiest solution is probably to create a function that gets the displayed message as an input and returns the user input after testing that it fulfils your criteria:
def guess_input(input_message):
flag = False
#endless loop until we are satisfied with the input
while True:
#asking for user input
guess = input(input_message)
#testing, if input was x or exit no matter if upper or lower case
if guess.lower() == "x" or guess.lower() == "exit":
#return string "x" as a sign that the user wants to quit
return "x"
#try to convert the input into a number
try:
guess = int(guess)
#it was a number, but not between 1 and 9
if guess > 9 or guess < 1:
#flag showing an illegal input
flag = True
else:
#yes input as expected a number, break out of while loop
break
except:
#input is not an integer number
flag = True
#not the input, we would like to see
if flag:
#give feedback
print("Sorry, I didn't get that.")
#and change the message displayed during the input routine
input_message = "I can only accept numbers from 1 to 9 (or X for eXit): "
continue
#give back the guessed number
return guess
You can call this from within your main program like
#the first guess
guess = guess_input("Guess a number from 1 to 9: ")
or
#giving feedback from previous input and asking for the next guess
guess = guess_input("Too high! Guess again (or X to eXit): ")
You are trying the parse the string 'Exit' to an integer.
You can add a try/except around the casting line and handle invalid input.
import random
num = random.randint(1,9)
tries = 1
guess = 0
guess = input("Guess a number from 1 to 9: ")
try:
guess = int(guess) // try to cast the guess to a int
while guess != num:
if guess == num:
tries = tries + 1
break
elif guess > num:
guess = int(input("Too high! Guess again: "))
tries = tries + 1
continue
else:
guess = int(input("Too low! Guess again: "))
tries = tries + 1
continue
print("Exactly right!")
print("You guessed " + str(tries) + " times.")
except ValueError:
if guess == str('Exit'):
print("Good bye")
else:
print("Invalid input")
import random
def start():
print "\t\t***-- Please enter Y for Yes and N for No --***"
answer = raw_input("\t\t Would you like to play a Guessing Game?: ")
if answer == "Y"
or answer == "y":
game()
elif answer == "N"
or answer == "n":
end()
def end():
print("\t\t\t **Goodbye** ")
raw_input("\t\t\t**Press ENTER to Exit**")
def game():
print "\t\t\t Welcome to Williams Guessing Game"
user_name = raw_input("\n\t\t Please enter your name: ")
print "\n", user_name, "I am thinking of a number between 1 and 20"
print "You have 5 attempts at getting it right"
attempt = 0
number = random.randint(1, 20)
while attempt < 5:
guess = input("\t\nPlease enter a number: ")
attempt = attempt + 1
answer = attempt
if guess < number:
print "\nSorry", user_name, "your guess was too low"
print "You have ", 5 - attempt, " attempts left\n"
elif guess > number:
print "\nSorry ", user_name, " your guess was too high"
print "You have ", 5 - attempt, " attempts left\n"
elif guess == number:
print "\n\t\t Yay, you selected my lucky number. Congratulations"
print "\t\t\tYou guessed it in", attempt, "number of attempts!\n"
answer = raw_input("\n\t\t\t\tTry again? Y/N?: ")
if answer == "Y"
or answer == "y":
game()
elif answer == "N"
or answer == "n":
end()
start()
If you want the computer to guess your number, you could use a function like this:
import random
my_number = int(raw_input("Please enter a number between 1 and 20: "))
guesses = []
def make_guess():
guess = random.randint(1, 20)
while guess in guesses:
guess = random.randint(1, 20)
guesses.append(guess)
return guess
while True:
guess = make_guess()
print(guess)
if guess == my_number:
print("The computer wins!")
break
else:
print(guesses)
It's just a quick-and-dirty example, but I hope it gives you the idea. This way, the computer gets unlimited guesses, but you could easily change the while loop to limit its number of guesses.
Your program chooses the number to be guessed by selecting an integer at random in the range 1 to 1000 (inclusive). If the player's guess is incorrect, your program should loop until the player finally gets the number right. Your program should keep telling the player Too high or Too low to help the player “zero in” on the correct answer. After a game ends, the program should prompt the user to enter "y" to play again or "n" to exit the game.
My problem is how do you generate a new random integer each time they want to play again?
Here's my code.
import random
randomNumber = random.randrange(1, 1000)
def main():
print ""
number = input("I have a number between 1 and 1000. Can you guess my number? Please type your first guess: ")
guess(number)
def guess(number1):
correct = False
while not correct:
if number1 > randomNumber:
print "Too high. Try again."
print ""
elif number1 < randomNumber:
print "Too low. Try again."
print ""
elif number1 == randomNumber:
break
number1 = input ("What number do you guess? ")
if number1 == randomNumber:
playAagain = raw_input ("Excellent! You guessed the number! Would you like to play again (y or n)? ")
if playAagain == "y":
main()
main()
Take this line:
randomNumber = random.randrange(1, 1000)
and place it inside guess:
import random
def main():
print ""
number = input("I have a number between 1 and 1000. Can you guess my number? Please type your first guess: ")
guess(number)
def guess(number1):
#########################################
randomNumber = random.randrange(1, 1000)
#########################################
correct = False
while not correct:
if number1 > randomNumber:
print "Too high. Try again."
print ""
elif number1 < randomNumber:
print "Too low. Try again."
print ""
elif number1 == randomNumber:
break
number1 = input ("What number do you guess? ")
if number1 == randomNumber:
playAagain = raw_input ("Excellent! You guessed the number! Would you like to play again (y or n)? ")
if playAagain == "y":
main()
main()
Now, a new random integer will be created each time the function is called.
Put a loop in main() and initialize randomNumber at the beginning of the loop.
please try this remove four spaces starting from random to starting of while loop
import random
print " welcome to game of guessing "
print "you have 6 attempts"
num1 = random.randint(1,100)
print num1 # this is your computer generated number ( skip while running :only for test purpose)
num2 = num1+random.randint(1,15)
print " hint: number is close to " + str(num2)
count=1
while count<=6:
print " enter the number you think"
inputnum=raw_input()
if inputnum==str(num1):
print "congrats you guess the correct number"
break
elif inputnum<str(num1):
print " number is lower than correct one "
count=count+1
elif inputnum>str(num1):
print "number is greater than correct one"
count=count+1
else:
break
You just have to define your main() function like this.
def main():
global randomNumber
print ""
randomNumber = random.randrange(1, 1000)
number = input("I have a number between 1 and 1000. Can you guess my number? Please type your first guess: ")
guess(number)
And everything will be perfect. Hope this helps.