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I was trying to replicate the answer found here with my own data, which happens to be a 3D numpy array of integers. I got close with the following code:
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
import matplotlib.pyplot as plt
data = np.random.randint(0,6,size=(49,512,512))
x = y = np.arange(0, 512, 1)
z = 20
i = data[z,:,:]
z1 = 21
i1 = data[z1,:,:]
z2 = 22
i2 = data[z2,:,:]
# here are the x,y and respective z values
X, Y = np.meshgrid(x, y)
Z = z*np.ones(X.shape)
Z1 = z1*np.ones(X.shape)
Z2 = z2*np.ones(X.shape)
# create the figure, add a 3d axis, set the viewing angle
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
ax.view_init(10,60)
# here we create the surface plot, but pass V through a colormap
# to create a different color for each patch
im = ax.plot_surface(X, Y, Z, facecolors=cm.viridis(i))
ax.plot_surface(X, Y, Z1, facecolors=cm.viridis(i1))
ax.plot_surface(X, Y, Z2, facecolors=cm.viridis(i2))
But this produces the plot below.
There are two things wrong with this plot: (1) the surfaces are a constant color and (2) the color bar doesn't seem to be referencing the data.
Following the advice here, I found that (1) can be solved by replacing data with a set of random numbers data = np.random.random(size=(49,512,512)), which produces the below image.
I think this suggests the integer data in the first image needs to be normalized before displaying properly, but, if it's possible, I would really like to make this plot without normalization; I want integer values to display like the second image. Also, I'm not sure why the color bar isn't connected to the color scale of the images themselves and could use advice on how to fix that. Ideally, the color bar to be connected to all three surfaces, not just the im surface.
Thanks in advance!
First, you have to normalize your data. Then, you pass the normalized data into the colormap to create the face colors:
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
import matplotlib.pyplot as plt
import matplotlib.colors as colors
data = np.random.randint(0,6,size=(49,512,512))
# create a Normalize object with the correct range
norm = colors.Normalize(vmin=data.min(), vmax=data.max())
# normalized_data contains values between 0 and 1
normalized_data = norm(data)
# extract the appropriate values
z = 20
z1 = 21
z2 = 22
i = normalized_data[z,:,:]
i1 = normalized_data[z1,:,:]
i2 = normalized_data[z2,:,:]
x = y = np.arange(0, 512, 1)
# here are the x,y and respective z values
X, Y = np.meshgrid(x, y)
Z = z*np.ones(X.shape)
Z1 = z1*np.ones(X.shape)
Z2 = z2*np.ones(X.shape)
# create the figure, add a 3d axis, set the viewing angle
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
ax.view_init(10,60)
# here we create the surface plot, but pass V through a colormap
# to create a different color for each patch
im = ax.plot_surface(X, Y, Z, facecolors=cm.viridis(i))
ax.plot_surface(X, Y, Z1, facecolors=cm.viridis(i1))
ax.plot_surface(X, Y, Z2, facecolors=cm.viridis(i2))
# create a scalar mappable to create an appropriate colorbar
sm = cm.ScalarMappable(cmap=cm.viridis, norm=norm)
fig.colorbar(sm)
I'm trying to make a 3D surface plot from a 2D array, using the values of my 2D array as the z value:
I want to do a surface plot like in the next pic:
This is my code
import numpy as npimport matplotlib.pyplot as pltimport math as mtfrom mpl_toolkits import mplot3d
ax = plt.axes(projection="3D")
z = [[248, 236,289,300,267,225,266,265,259,279,269,335],[246,253,241,232,276,213,198,201,222,229,193,237],[182,180,200,192,233,211,227,220,174,187,181,197],[124,102,137,130,144,168,149,164,168,156,90,156],[117,124,133,119,155,140,133,120,130,134,138,102],[155,140,137,125,146,102,129,114,119,113,132,122],[104,117,119,138,137,118,117,128,131,133,119,133],[136,115,108,105,133,104,121,135,136,127,135,112],[84,87,93,116,123,110,90,123,112,115,92,107],[118,94,100,83,132,90,111,91,98,116,100,95],[101,76,115,121,108,102,94,80,83,104,101,81],[86,86,109,105,95,75,18,87,92,99,101,128]]
y = np.arange(len(z))x = np.arange(len(z[0]))
(x ,y) = np.meshgrid(x,y)
ax.plot3D(x,y,z)plt.show()
This is what I tried but gives me an error.
you need to use plot_surface:
ax = plt.axes(projection="3d")
z = np.array([[248, 236,289,300,267,225,266,265,259,279,269,335],[246,253,241,232,276,213,198,201,222,229,193,237],[182,180,200,192,233,211,227,220,174,187,181,197],[124,102,137,130,144,168,149,164,168,156,90,156],[117,124,133,119,155,140,133,120,130,134,138,102],[155,140,137,125,146,102,129,114,119,113,132,122],[104,117,119,138,137,118,117,128,131,133,119,133],[136,115,108,105,133,104,121,135,136,127,135,112],[84,87,93,116,123,110,90,123,112,115,92,107],[118,94,100,83,132,90,111,91,98,116,100,95],[101,76,115,121,108,102,94,80,83,104,101,81],[86,86,109,105,95,75,18,87,92,99,101,128]])
y = np.arange(len(z))
x = np.arange(len(z[0]))
(x ,y) = np.meshgrid(x,y)
ax.plot_surface(x,y,z)
plt.show()
I have a spreadsheet file that I would like to input to create a 3D surface graph using Matplotlib in Python.
I used plot_trisurf and it worked, but I need the projections of the contour profiles onto the graph that I can get with the surface function, like this example.
I'm struggling to arrange my Z data in a 2D array that I can use to input in the plot_surface method. I tried a lot of things, but none seems to work.
Here it is what I have working, using plot_trisurf
import matplotlib
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
import numpy as np
import pandas as pd
df=pd.read_excel ("/Users/carolethais/Desktop/Dissertação Carol/Códigos/Resultados/res_02_0.5.xlsx")
fig = plt.figure()
ax = fig.gca(projection='3d')
# I got the graph using trisurf
graf=ax.plot_trisurf(df["Diametro"],df["Comprimento"], df["temp_out"], cmap=matplotlib.cm.coolwarm)
ax.set_xlim(0, 0.5)
ax.set_ylim(0, 100)
ax.set_zlim(25,40)
fig.colorbar(graf, shrink=0.5, aspect=15)
ax.set_xlabel('Diâmetro (m)')
ax.set_ylabel('Comprimento (m)')
ax.set_zlabel('Temperatura de Saída (ºC)')
plt.show()
This is a part of my df, dataframe:
Diametro Comprimento temp_out
0 0.334294 0.787092 34.801994
1 0.334294 8.187065 32.465551
2 0.334294 26.155976 29.206090
3 0.334294 43.648591 27.792126
4 0.334294 60.768219 27.163233
... ... ... ...
59995 0.437266 14.113660 31.947302
59996 0.437266 25.208851 30.317583
59997 0.437266 33.823035 29.405461
59998 0.437266 57.724209 27.891616
59999 0.437266 62.455890 27.709298
I tried this approach to use the imported data with plot_surface, but what I got was indeed a graph but it didn't work, here it's the way the graph looked with this approach:
Thank you so much
A different approach, based on re-gridding the data, that doesn't require that the original data is specified on a regular grid [deeply inspired by this example;-].
import matplotlib.pyplot as plt
import numpy as np
import matplotlib.tri as tri
from mpl_toolkits.mplot3d import Axes3D
np.random.seed(19880808)
# compute the sombrero over a cloud of random points
npts = 10000
x, y = np.random.uniform(-5, 5, npts), np.random.uniform(-5, 5, npts)
z = np.cos(1.5*np.sqrt(x*x + y*y))/(1+0.33*(x*x+y*y))
# prepare the interpolator
triang = tri.Triangulation(x, y)
interpolator = tri.LinearTriInterpolator(triang, z)
# do the interpolation
xi = yi = np.linspace(-5, 5, 101)
Xi, Yi = np.meshgrid(xi, yi)
Zi = interpolator(Xi, Yi)
# plotting
fig = plt.figure()
ax = fig.gca(projection='3d')
norm = plt.Normalize(-1,1)
ax.plot_surface(Xi, Yi, Zi,
cmap='inferno',
norm=plt.Normalize(-1,1))
plt.show()
plot_trisurf expects x, y, z as 1D arrays while plot_surface expects X, Y, Z as 2D arrays or as x, y, Z with x, y being 1D array and Z a 2D array.
Your data consists of 3 1D arrays, so plotting them with plot_trisurf is immediate but you need to use plot_surface to be able to project the isolines on the coordinate planes... You need to reshape your data.
It seems that you have 60000 data points, in the following I assume that you have a regular grid 300 points in the x direction and 200 points in y — but what is important is the idea of regular grid.
The code below shows
the use of plot_trisurf (with a coarser mesh), similar to your code;
the correct use of reshaping and its application in plot_surface;
note that the number of rows in reshaping corresponds to the number
of points in y and the number of columns to the number of points in x;
and 4. incorrect use of reshaping, the resulting subplots are somehow
similar to the plot you showed, maybe you just need to fix the number
of row and columns.
import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
x, y = np.arange(30)/3.-5, np.arange(20)/2.-5
x, y = (arr.flatten() for arr in np.meshgrid(x, y))
z = np.cos(1.5*np.sqrt(x*x + y*y))/(1+0.1*(x*x+y*y))
fig, axes = plt.subplots(2, 2, subplot_kw={"projection" : "3d"})
axes = iter(axes.flatten())
ax = next(axes)
ax.plot_trisurf(x,y,z, cmap='Reds')
ax.set_title('Trisurf')
X, Y, Z = (arr.reshape(20,30) for arr in (x,y,z))
ax = next(axes)
ax.plot_surface(X,Y,Z, cmap='Reds')
ax.set_title('Surface 20×30')
X, Y, Z = (arr.reshape(30,20) for arr in (x,y,z))
ax = next(axes)
ax.plot_surface(X,Y,Z, cmap='Reds')
ax.set_title('Surface 30×20')
X, Y, Z = (arr.reshape(40,15) for arr in (x,y,z))
ax = next(axes)
ax.plot_surface(X,Y,Z, cmap='Reds')
ax.set_title('Surface 40×15')
plt.tight_layout()
plt.show()
I have a data file in NumPy array, I would like to view the 3D-image. I am sharing an example, where I can view 2D image of size (100, 100), this is a slice in xy-plane at z = 0.
import numpy as np
from matplotlib import pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
X, Y, Z = np.mgrid[-10:10:100j, -10:10:100j, -10:10:100j]
T = np.sin(X*Y*Z)/(X*Y*Z)
T=T[:,:,0]
im = plt.imshow(T, cmap='hot')
plt.colorbar(im, orientation='vertical')
plt.show()
How can I view a 3D image of the data T of shape (100, 100, 100)?
I think the main problem is, that you do have 4 informations for each point, so you are actually interessted in a 4-dimensional object. Plotting this is always difficult (maybe even impossible). I suggest one of the following solutions:
You change the question to: I'm not interessted in all combinations of x,y,z, but only the ones, where z = f(x,y)
You change the accuracy of you plot a bit, saying that you don't need 100 levels of z, but only maybe 5, then you simply make 5 of the plots you already have.
In case you want to use the first method, then there are several submethods:
A. Plot the 2-dim surface f(x,y)=z and color it with T
B. Use any technic that is used to plot complex functions, for more info see here.
The plot given by method 1.A (which I think is the best solution) with z=x^2+y^2 yields:
I used this programm:
import numpy as np
from matplotlib import pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
import matplotlib as mpl
X, Y = np.mgrid[-10:10:100j, -10:10:100j]
Z = (X**2+Y**2)/10 #definition of f
T = np.sin(X*Y*Z)
norm = mpl.colors.Normalize(vmin=np.amin(T), vmax=np.amax(T))
T = mpl.cm.hot(T) #change T to colors
fig = plt.figure()
ax = fig.gca(projection='3d')
surf = ax.plot_surface(X, Y, Z, facecolors=T, linewidth=0,
cstride = 1, rstride = 1)
plt.show()
The second method gives something like:
With the code:
norm = mpl.colors.Normalize(vmin=-1, vmax=1)
X, Y= np.mgrid[-10:10:101j, -10:10:101j]
fig = plt.figure()
ax = fig.gca(projection='3d')
for i in np.linspace(-1,1,5):
Z = np.zeros(X.shape)+i
T = np.sin(X*Y*Z)
T = mpl.cm.hot(T)
ax.plot_surface(X, Y, Z, facecolors=T, linewidth=0, alpha = 0.5, cstride
= 10, rstride = 10)
plt.show()
Note: I changed the function to T = sin(X*Y*Z) because dividing by X*Y*Zmakes the functions behavior bad, as you divide two number very close to 0.
I have got a solution to my question. If we have the NumPy data, then we can convert them into TVTK ImageData and then visualization is possible with the help of mlab form Mayavi. The code and its 3D visualization are the following
from tvtk.api import tvtk
import numpy as np
from mayavi import mlab
X, Y, Z = np.mgrid[-10:10:100j, -10:10:100j, -10:10:100j]
data = np.sin(X*Y*Z)/(X*Y*Z)
i = tvtk.ImageData(spacing=(1, 1, 1), origin=(0, 0, 0))
i.point_data.scalars = data.ravel()
i.point_data.scalars.name = 'scalars'
i.dimensions = data.shape
mlab.pipeline.surface(i)
mlab.colorbar(orientation='vertical')
mlab.show()
For another randomly generated data
from numpy import random
data = random.random((20, 20, 20))
The visualization will be
Using Matplotlib, I want to plot a 2D heat map. My data is an n-by-n Numpy array, each with a value between 0 and 1. So for the (i, j) element of this array, I want to plot a square at the (i, j) coordinate in my heat map, whose color is proportional to the element's value in the array.
How can I do this?
The imshow() function with parameters interpolation='nearest' and cmap='hot' should do what you want.
Please review the interpolation parameter details, and see Interpolations for imshow and Image antialiasing.
import matplotlib.pyplot as plt
import numpy as np
a = np.random.random((16, 16))
plt.imshow(a, cmap='hot', interpolation='nearest')
plt.show()
Seaborn is a high-level API for matplotlib, which takes care of a lot of the manual work.
seaborn.heatmap automatically plots a gradient at the side of the chart etc.
import numpy as np
import seaborn as sns
import matplotlib.pylab as plt
uniform_data = np.random.rand(10, 12)
ax = sns.heatmap(uniform_data, linewidth=0.5)
plt.show()
You can even plot upper / lower left / right triangles of square matrices. For example, a correlation matrix, which is square and is symmetric, so plotting all values would be redundant.
corr = np.corrcoef(np.random.randn(10, 200))
mask = np.zeros_like(corr)
mask[np.triu_indices_from(mask)] = True
with sns.axes_style("white"):
ax = sns.heatmap(corr, mask=mask, vmax=.3, square=True, cmap="YlGnBu")
plt.show()
I would use matplotlib's pcolor/pcolormesh function since it allows nonuniform spacing of the data.
Example taken from matplotlib:
import matplotlib.pyplot as plt
import numpy as np
# generate 2 2d grids for the x & y bounds
y, x = np.meshgrid(np.linspace(-3, 3, 100), np.linspace(-3, 3, 100))
z = (1 - x / 2. + x ** 5 + y ** 3) * np.exp(-x ** 2 - y ** 2)
# x and y are bounds, so z should be the value *inside* those bounds.
# Therefore, remove the last value from the z array.
z = z[:-1, :-1]
z_min, z_max = -np.abs(z).max(), np.abs(z).max()
fig, ax = plt.subplots()
c = ax.pcolormesh(x, y, z, cmap='RdBu', vmin=z_min, vmax=z_max)
ax.set_title('pcolormesh')
# set the limits of the plot to the limits of the data
ax.axis([x.min(), x.max(), y.min(), y.max()])
fig.colorbar(c, ax=ax)
plt.show()
For a 2d numpy array, simply use imshow() may help you:
import matplotlib.pyplot as plt
import numpy as np
def heatmap2d(arr: np.ndarray):
plt.imshow(arr, cmap='viridis')
plt.colorbar()
plt.show()
test_array = np.arange(100 * 100).reshape(100, 100)
heatmap2d(test_array)
This code produces a continuous heatmap.
You can choose another built-in colormap from here.
Here's how to do it from a csv:
import numpy as np
import matplotlib.pyplot as plt
from scipy.interpolate import griddata
# Load data from CSV
dat = np.genfromtxt('dat.xyz', delimiter=' ',skip_header=0)
X_dat = dat[:,0]
Y_dat = dat[:,1]
Z_dat = dat[:,2]
# Convert from pandas dataframes to numpy arrays
X, Y, Z, = np.array([]), np.array([]), np.array([])
for i in range(len(X_dat)):
X = np.append(X, X_dat[i])
Y = np.append(Y, Y_dat[i])
Z = np.append(Z, Z_dat[i])
# create x-y points to be used in heatmap
xi = np.linspace(X.min(), X.max(), 1000)
yi = np.linspace(Y.min(), Y.max(), 1000)
# Interpolate for plotting
zi = griddata((X, Y), Z, (xi[None,:], yi[:,None]), method='cubic')
# I control the range of my colorbar by removing data
# outside of my range of interest
zmin = 3
zmax = 12
zi[(zi<zmin) | (zi>zmax)] = None
# Create the contour plot
CS = plt.contourf(xi, yi, zi, 15, cmap=plt.cm.rainbow,
vmax=zmax, vmin=zmin)
plt.colorbar()
plt.show()
where dat.xyz is in the form
x1 y1 z1
x2 y2 z2
...
Use matshow() which is a wrapper around imshow to set useful defaults for displaying a matrix.
a = np.diag(range(15))
plt.matshow(a)
https://matplotlib.org/stable/api/_as_gen/matplotlib.axes.Axes.matshow.html
This is just a convenience function wrapping imshow to set useful defaults for displaying a matrix. In particular:
Set origin='upper'.
Set interpolation='nearest'.
Set aspect='equal'.
Ticks are placed to the left and above.
Ticks are formatted to show integer indices.
Here is a new python package to plot complex heatmaps with different kinds of row/columns annotations in Python: https://github.com/DingWB/PyComplexHeatmap