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Sort list of strings numerically and filter duplicates?

Given a list of strings in the following format:
[
"464782,-100,4,3,1,100,0,0"
"465042,-166.666666666667,4,3,1,100,0,0",
"465825,-250.000000000001,4,3,1,100,0,0",
"466868,-166.666666666667,4,3,1,100,0,0",
"467390,-200.000000000001,4,3,1,100,0,0",
"469999,-100,4,3,1,100,0,0",
"470260,-166.666666666667,4,3,1,100,0,0",
"474173,-100,4,3,1,100,0,0",
"474434,-166.666666666667,4,3,1,100,0,0",
"481477,-100,4,3,1,100,0,1",
"531564,259.011439671919,4,3,1,60,1,0",
"24369,-333.333333333335,4,3,1,100,0,0",
"21082,410.958904109589,4,3,1,60,1,0",
"21082,-250,4,3,1,100,0,0",
"22725,-142.857142857143,4,3,1,100,0,0",
"23547,-166.666666666667,4,3,1,100,0,0",
"24369,-333.333333333335,4,3,1,100,0,0",
"27657,-200.000000000001,4,3,1,100,0,0",
"29301,-142.857142857143,4,3,1,100,0,0",
"30123,-166.666666666667,4,3,1,100,0,0",
"30945,-250,4,3,1,100,0,0",
"32588,-166.666666666667,4,3,1,100,0,0",
"34232,-250,4,3,1,100,0,0",
"35876,-142.857142857143,4,3,1,100,0,0",
"36698,-166.666666666667,4,3,1,100,0,0",
"37520,-250,4,3,1,100,0,0",
"42451,-142.857142857143,4,3,1,100,0,0",
"43273,-166.666666666667,4,3,1,100,0,0",
]
How can I sort the list based on the first number in each line with python?
And then, once sorted, remove all duplicates, if any are there?
The sorting criteria for the list is the number before the first comma in each line, which is always an integer.
I tried using list.sort() , however, this sorts the items in lexical order, not numerically.

You could use a dictionary for this. The key will be number before the first comma and the value the entire string. Duplicates will be eliminated, but only the last occurrence of a particular number's string is stored.
l = ['464782,-100,4,3,1,100,0,0',
'465042,-166.666666666667,4,3,1,100,0,0',
'465825,-250.000000000001,4,3,1,100,0,0',
'466868,-166.666666666667,4,3,1,100,0,0',
'467390,-200.000000000001,4,3,1,100,0,0',
...]
d = {int(s.split(',')[0]) : s for s in l}
result = [d[key] for key in sorted(d.keys())]

I would try one of these two methods:
def sort_list(lis):
nums = [int(num) if isdigit(num) else float(num) for num in lis]
nums = list(set(nums))
nums.sort()
return [str(i) for i in nums] # I assumed you wanted them to be strings.
The first will raise a TypeError if all items in lis are not ints, floats, or string representations of a number. The second method doesn't have that problem, but it's a bit wonkier.
def sort_list(lis):
ints = [int(num) for num in lis if num.isdigit()]
floats = [float(num) for num in lis if not num.isdigit()]
nums = ints.copy()
nums.extend(floats)
nums = list(set(nums))
nums.sort()
return [str(i) for i in nums] # I assumed you wanted them to be strings.
Hope this helps.

You can try this.
First we need to remove the duplicates inside the list using set()
removed_duplicates_list = list(set(listr))
Then we convert the list of strings in to a list of tuples
list_of_tuples = [tuple(i.split(",")) for i in removed_duplicates_list]
Then we sort it using the sort()
list_of_tuples.sort()
The complete code sample below:
listr = [
"464782,-100,4,3,1,100,0,0"
"465042,-166.666666666667,4,3,1,100,0,0",
"465825,-250.000000000001,4,3,1,100,0,0",
"466868,-166.666666666667,4,3,1,100,0,0",
"467390,-200.000000000001,4,3,1,100,0,0",
"469999,-100,4,3,1,100,0,0",
"470260,-166.666666666667,4,3,1,100,0,0",
"474173,-100,4,3,1,100,0,0",
"474434,-166.666666666667,4,3,1,100,0,0",
"481477,-100,4,3,1,100,0,1",
"531564,259.011439671919,4,3,1,60,1,0",
"24369,-333.333333333335,4,3,1,100,0,0",
"21082,410.958904109589,4,3,1,60,1,0",
"21082,-250,4,3,1,100,0,0",
"22725,-142.857142857143,4,3,1,100,0,0",
"23547,-166.666666666667,4,3,1,100,0,0",
"24369,-333.333333333335,4,3,1,100,0,0",
"27657,-200.000000000001,4,3,1,100,0,0",
"29301,-142.857142857143,4,3,1,100,0,0",
"30123,-166.666666666667,4,3,1,100,0,0",
"30945,-250,4,3,1,100,0,0",
"32588,-166.666666666667,4,3,1,100,0,0",
"34232,-250,4,3,1,100,0,0",
"35876,-142.857142857143,4,3,1,100,0,0",
"36698,-166.666666666667,4,3,1,100,0,0",
"37520,-250,4,3,1,100,0,0",
"42451,-142.857142857143,4,3,1,100,0,0",
"43273,-166.666666666667,4,3,1,100,0,0",
]
removed_duplicates_list = list(set(listr))
list_of_tuples = [tuple(i.split(",")) for i in removed_duplicates_list]
list_of_tuples.sort()
print(list_of_tuples) # the output is a list of tuples
OUTPUT:
[('21082', '-250', '4', '3', '1', '100', '0', '0'),
('21082', '410.958904109589', '4', '3', '1', '60', '1', '0'),
('22725', '-142.857142857143', '4', '3', '1', '100', '0', '0'),
('23547', '-166.666666666667', '4', '3', '1', '100', '0', '0'),
('24369', '-333.333333333335', '4', '3', '1', '100', '0', '0'),
('27657', '-200.000000000001', '4', '3', '1', '100', '0', '0'),
('29301', '-142.857142857143', '4', '3', '1', '100', '0', '0'),
('30123', '-166.666666666667', '4', '3', '1', '100', '0', '0'),
('30945', '-250', '4', '3', '1', '100', '0', '0'),
('32588', '-166.666666666667', '4', '3', '1', '100', '0', '0'),
('34232', '-250', '4', '3', '1', '100', '0', '0'),
('35876', '-142.857142857143', '4', '3', '1', '100', '0', '0'),
('36698', '-166.666666666667', '4', '3', '1', '100', '0', '0'),
('37520', '-250', '4', '3', '1', '100', '0', '0'),
('42451', '-142.857142857143', '4', '3', '1', '100', '0', '0'),
('43273', '-166.666666666667', '4', '3', '1', '100', '0', '0'),
('464782','-100','4','3','1','100','0'),
('465042','-166.666666666667','4','3','1','100','0','0'),
('465825', '-250.000000000001', '4', '3', '1', '100', '0', '0'),
('466868', '-166.666666666667', '4', '3', '1', '100', '0', '0'),
('467390', '-200.000000000001', '4', '3', '1', '100', '0', '0'),
('469999', '-100', '4', '3', '1', '100', '0', '0'),
('470260', '-166.666666666667', '4', '3', '1', '100', '0', '0'),
('474173', '-100', '4', '3', '1', '100', '0', '0'),
('474434', '-166.666666666667', '4', '3', '1', '100', '0', '0'),
('481477', '-100', '4', '3', '1', '100', '0', '1'),
('531564', '259.011439671919', '4', '3', '1', '60', '1', '0')]

I hope this will help to.
I place all your list elements in a separate file named lista.txt
In this example I will get your list from file... I like to be more organizated and to have separate files you can do in on python as well, but the idea is you need to get all elements from list one by one (while function or for function) and to add them to a temporary list by checking if the new items already exist, if is exist pass and then you can sample use .sort() because will do the trick and with numbers.
# Global variables
file = "lista.txt"
tempList = []
# Logic get items from file
def GetListFromFile(fileName):
# Local variables
showDoneMsg = True
# Try to run this code
try:
# Open file and try to read it
with open(fileName, mode="r") as f:
# Define line
line = f.readline()
# For every line in file
while line:
# Get out all end white space (\n, \r)
item = line.rstrip()
# Check if this item is not allready in the list
if item not in tempList:
# Append item to a temporar list
tempList.append(item)
# Show me if a itmes allready exist
else:
print("Dublicate >>", item)
# Go to new line
line = f.readline()
# This is optional because is callet automatical
# but I like to be shore
f.close()
# Execptions
except FileNotFoundError:
print("ERROR >> File do not exist!")
showDoneMsg = False
# Sort the list
tempList.sort()
# Show me when is done if file exist
if showDoneMsg == True:
print("\n>>> DONE <<<\n")
# Logic show list items
def ShowListItems(thisList):
if len(thisList) == 0:
print("Temporary list is empty...")
else:
print("This is new items list:")
for i in thisList:
print(i)
# Execute function
GetListFromFile(file)
# Testing if items was sorted
ShowListItems(tempList)
Out put:
========================= RESTART: D:\Python\StackOverflow\help.py =========================
Dublicate >> 43273,-166.666666666667,4,3,1,100,0,0
>>> DONE <<<
21082,-250,4,3,1,100,0,0
21082,410.958904109589,4,3,1,60,1,0
22725,-142.857142857143,4,3,1,100,0,0
...
474434,-166.666666666667,4,3,1,100,0,0
481477,-100,4,3,1,100,0,1
531564,259.011439671919,4,3,1,60,1,0
>>>

Is there a way to generate a list string within Python, without any other 3rd party packages?

this code generates a list of integers
dir_list = list(range(11))
dir_list
numpy could transfer each element to string type
import numpy as np
dir_list = np.array(dir_list, dtype=np.str)
dir_list
array(['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '10'],
dtype='<U2')
is there a way to finish the job within Python, without any other 3rd party packages?

You can simply map each integer to string using inbuilt map function and map returns iterator so you can convert it into list.
list(map(str, range(11))) should do.
output:
['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '10']

Of course, this way you can iterate over each element of range object and convert to str and store as list:
dir_list = [str(i) for i in range(11)]
>>> dir_list
['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '10']

How to reverse multiple lists?

scores=open('scores.csv','r')
for score in scores.readlines():
score = score.strip()
rev=[]
for s in reversed(score[0:]):
rev.append(s)
print(rev)
This is my code, what I am going to do is the print reversed list from scores.csv
If I print scores at the beginning, the result is:
['0.74,0.63,0.58,0.89\n', '0.91,0.89,0.78,0.99\n', '0.43,0.35,0.34,0.45\n', '0.56,0.61,0.66,0.58\n', '0.50,0.49,0.76,0.72\n', '0.88,0.75,0.61,0.78\n']
It looks normal, and if I print score after I remove all \n in the list, the result is:
0.74,0.63,0.58,0.89
0.91,0.89,0.78,0.99
0.43,0.35,0.34,0.45
0.56,0.61,0.66,0.58
0.50,0.49,0.76,0.72
0.88,0.75,0.61,0.78
it still looks ok, but if I print at the end of the code, it shows:
['9', '8', '.', '0', ',', '8', '5', '.', '0', ',', '3', '6', '.', '0', ',', '4', '7', '.', '0']
['9', '9', '.', '0', ',', '8', '7', '.', '0', ',', '9', '8', '.', '0', ',', '1', '9', '.', '0']
['5', '4', '.', '0', ',', '4', '3', '.', '0', ',', '5', '3', '.', '0', ',', '3', '4', '.', '0']
['8', '5', '.', '0', ',', '6', '6', '.', '0', ',', '1', '6', '.', '0', ',', '6', '5', '.', '0']
['2', '7', '.', '0', ',', '6', '7', '.', '0', ',', '9', '4', '.', '0', ',', '0', '5', '.', '0']
['8', '7', '.', '0', ',', '1', '6', '.', '0', ',', '5', '7', '.', '0', ',', '8', '8', '.', '0']
looks like python converts my result from decimal to integer, but when I am trying to use float(s) to convert it back, it gives me an error. I would like to know what's wrong with my code?

In your approach, score is a string, so it's doing exactly what you tell it to: reverse the entire line character by character. You can do two things:
Use the csv module to read your CSV file (recommended), to get a list of float values, then reverse that.
Split your line on commas, then reverse that list, and finally stitch it back together. An easy way to reverse a list in Python is mylist[::-1].
For number 2, it would be something like:
score = score.strip()
temp = score.split(',')
temp_reversed = temp[::-1]
score_reversed = ','.join(temp_reversed)

always use csv module to read csv files. This module parses the data, splits according to commas, etc...
Your attempt is just reversing the line char by char. I'd rewrite it completely using csv module, which yields the tokens already split by comma (default):
import csv
with open('scores.csv','r') as scores:
cr = csv.reader(scores)
rev = []
for row in cr:
rev.append(list(reversed(row))
that doesn't convert data to float, that said, I'd replace the loop by a comprehension + float conversion
rev = [[float(x) for x in reversed(row)] for row in cr]

Python Findall not finding anything

I am learning about Regex and am stuck with this code:
import re
resume = '''
(738) 383-5729
(373) 577-0492
(403) 443-2759
(375) 880-8576
(641) 576-2342
(951) 268-8744
'''
phoneRegex = re.compile(r'\d')
mo = phoneRegex.findall(resume)
print(mo.group())
When I try with search instead of findall, it works. But it can't find any match with findall.
What am I doing wrong?

findall() returns a simple list of strings matching the pattern.
It has no group() method, just omit that:
>>> print(mo)
['7', '3', '8', '3', '8', '3', '5', '7', '2', '9', '3', '7', '3', '5', '7',
'7', '0', '4', '9', '2', '4', '0', '3', '4', '4', '3', '2', '7', '5', '9',
'3', '7', '5', '8', '8', '0', '8', '5', '7', '6', '6', '4', '1', '5', '7',
'6', '2', '3', '4', '2', '9', '5', '1', '2', '6', '8', '8', '7', '4', '4']

It seems that you're trying to match phone numbers in resume, for that you can use:
resume = '''
(738) 383-5729
(373) 577-0492
(403) 443-2759
(375) 880-8576
(641) 576-2342
(951) 268-8744
'''
mo = re.findall(r'\(\d{3}\) \d{3}-\d{4}', resume)
for x in mo:
print(x)
Output:
(738) 383-5729
(373) 577-0492
(403) 443-2759
(375) 880-8576
(641) 576-2342
(951) 268-8744
Python Demo
Regex Demo & Explanation

Since (it looks like) you're just out for the numbers, you could do something like
>>> [''.join(c for c in l if c in '0123456789') for l in resume.strip().splitlines()]
['7383835729', '3735770492', '4034432759', '3758808576', '6415762342', '9512688744']
That might save you some trouble from internationally formed numbers (such as +46-(0)7-08/123 456 and the like).

Re.findall() module is used when you want to iterate over the lines by line, it will return a list of all the matches not group.
So in your case it returns as list
print(mo[0])

Python 3: how to create list out of float numbers?

Anyone knows how can I solve this issue?
I have the following code.
result=[]
for i in range(len(response_i['objcontent'][0]['rowvalues'])):
lat = response_i['objcontent'][0]['rowvalues'][i][0]
print(lat)
for i in lat:
result.append(i)
print (result)
Following is the output of print(lat):
92.213725
191.586143
228.981615
240.353291
and following is the output of print(result):
['9', '2', '.', '2', '1', '3', '7', '2', '5', '1', '9', '1', '.', '5', '8',
'6', '1', '4', '3', '2', '2', '8', '.', '9', '8', '1', '6', '1', '5', '2',
'4', '0', '.', '3', '5', '3', '2', '9', '1']
I expected to get the output in following format:
[92.213725, 191.586143, 228.981615, 240.353291]
Anyone knows how to fix this issue?
Thanks

So, your error is that instead of simply adding your latitute to the list, you are iterating over each character of the latitude, as a string, and adding that character to a list.
result=[]
for value in response_i['objcontent'][0]['rowvalues']:
lat = value[0]
print(lat)
result.append(float(lat))
print (result)
Besides that, using range(len(...))) is the way things have to be done in almost all modern languages, because they either don't implement a "for ...each" or do it in an incomplete or faulty way.
In Python, since the beginning it is a given that whenever one wants a for iteration he wants to get the items of a sequence, not its indices (for posterior retrieval of the indices). Some auxiliar built-ins come in to play to ensure you just interate the sequence: zip to mix one or more sequences, and enumerate to yield the indices as well if you need them.