The raw ECG that I have is in csv format. I need to convert it into .txt file which will have only the ECG data. I need a python code for the same. Can I get some help on this.
csv_file = 'ECG_data_125Hz_Simulator_Patch_Normal_Sinus.csv'
txt_file = 'ECG_data_125Hz_Simulator_Patch_Normal_Sinus.txt'
import csv
with open(txt_file, "w") as my_output_file:
with open(csv_file, "r") as my_input_file:
//need to write data to the output file
my_output_file.close()
The input ECG data looks like this:
Raw_ECG_data
What worked for me
import csv
csv_file = 'FL_insurance_sample.csv'
txt_file = 'ECG_data_125Hz_Simulator_Patch_Normal_Sinus.txt'
with open(txt_file, "w") as my_output_file:
with open(csv_file, "r") as my_input_file:
[ my_output_file.write(" ".join(row)+'\n') for row in csv.reader(my_input_file)]
my_output_file.close()
A few things:
You can open multiple files with the same context manager (with statement):
with open(csv_file, 'r') as input_file, open(txt_file, 'w') as output_file:
...
When using a context manager to handle files, there's no need to close the file, that's what the with statement is doing; it's saying "with the file open, do the following". So once the block is ended, the file is closed.
You could do something like:
with open(csv_file, 'r') as input_file, open(txt_file, 'w') as output_file:
for line in input_file:
output_file.write(line)
... But as #MEdwin says a csv can just be renamed and the commas will no longer act as separators; it will just become a normal .txt file. You can rename a file in python using os.rename():
import os
os.rename('file,txt', 'file.csv')
Finally, if you want to remove certain columns from the csv when writing to the txt file, you can use .split(). This allows you use an identifier such as a comma, and separate the line according this identifier into a list of strings. For example:
"Hello, this is a test".split(',')
>>> ["Hello", "this is a test"]
You can then just write certain indices from the list to the new file.
For more info on deleting columns en masse, see this post
Related
I am currently reading the csv file in "rb" mode and uploading the file to an s3 bucket.
with open(csv_file, 'rb') as DATA:
s3_put_response = requests.put(s3_presigned_url,data=DATA,headers=headers)
All of this is working fine but now I have to validate the headers in the csv file before making the put call.
When I try to run below, I get an error.
with open(csv_file, 'rb') as DATA:
csvreader = csv.reader(file)
columns = next(csvreader)
# run-some-validations
s3_put_response = requests.put(s3_presigned_url,data=DATA,headers=headers)
This throws
_csv.Error: iterator should return strings, not bytes (did you open the file in text mode?)
As a workaround, I have created a new function which opens the file in "r" mode and does validation on the csv headers and this works ok.
def check_csv_headers():
with open(csv_file, 'r') as file:
csvreader = csv.reader(file)
columns = next(csvreader)
I do not want to read the same file twice. Once for header validation and once for uploading to s3. The upload part also doesn't work if I do it in "r" mode.
Is there a way I can achieve this while reading the file only once in "rb" mode ? I have to make this work using the csv module and not the pandas library.
Doing what you want is possible but not very efficient. Simply opening a file isn't that expensive. The CSV reader only reads only line at a time, not the entire file.
To do what you want you have to :
Read the first line as bytes
Decode it into a string (using the correct encoding)
Convert it to a list of strings
Parse it with csv.reader and finally
Seek to the start of the stream.
Otherwise you'll end up uploading only the data without the headers :
with open(csv_file, 'rb') as DATA:
header=file.readline()
lines=[header.decode()]
csvreader = csv.reader(lines)
columns = next(csvreader)
// run-some-validations
DATA.seek(0)
s3_put_response = requests.put(s3_presigned_url,data=DATA,headers=headers)
Opening the file as text is not only simpler, it allows you to separate the validation logic from the upload code.
To ensure only one line is read at a time you can use buffering=1
def check_csv_headers():
with open(csv_file, 'r', buffering=1) as file:
csvreader = csv.reader(file)
columns = next(csvreader)
// run-some-validations
with open(csv_data, 'rb') as DATA:
s3_put_response = requests.put(s3_presigned_url,data=DATA,headers=headers)
Or
def check_csv_headers():
with open(csv_file, 'r', buffering=1) as file:
csvreader = csv.reader(file)
columns = next(csvreader)
// run-some-validations
//If successful
return True
def upload_csv(filePath):
if check_csv_headers(filePath) :
with open(csv_data, 'rb') as DATA:
s3_put_response = requests.put(s3_presigned_url,data=DATA,headers=headers)
I want to output csv file with python. I have gone through below code and it is working well with .txt file but I am unable to print csv through it.
import os
import tempfile
filename = tempfile.mktemp(".txt")
open (filename , "w").write ("Printing file")
os.startfile(filename, "print")
Actually I want to print a csv file that had been already created, there will be no need to write and create new file then print it out.
Edit: From print I meant hardcopy print through printer
If you want to print the content of a csv you can try this:
import csv
file_path = 'a.csv'
with open(file_path) as file:
content = csv.reader(file)
for row in content:
print(row)
I was talking about printing csv file as hardcopy with python code.
def printing():
#reading from csv writing in txt
with open("CSV_files//newfile.txt", "w") as my_output_file:
cs = pd.read_csv("CSV_files\\attendance.csv",header=None,index_col=None)
with open("CSV_files//attendance.csv", "r") as my_input_file:
[ my_output_file.write(" | ".join(row)+'\n') for row in csv.reader(my_input_file)]
my_output_file.close()
#reading from file and storing into reader and converting into string as .write() takes string
strnew = ""
with open('CSV_files//newfile.txt',"r") as f:
reader = f.read()
strnew = reader
#for checking
with open('CSV_files//print.txt',"w") as f:
f.write(strnew)
#printing
filename = tempfile.mktemp("attendance.txt")#creating a temp file
open (filename , "w").write(strnew)
os.startfile(filename, "print")
messagebox.showinfo("Print","Printing Request sent successfully!")
For more info:
github project link
I must be missing something very simple here, but I've been hitting my head against the wall for a while and don't understand where the error is. I am trying to open a csv file and read the data. I am detecting the delimiter, then reading in the data with this code:
with open(filepath, 'r') as csvfile:
dialect = csv.Sniffer().sniff(csvfile.read())
delimiter = repr(dialect.delimiter)[1:-1]
csvdata = [line.split(delimiter) for line in csvfile.readlines()]
However, my csvfile is being read as having no length. If I run:
print(sum(1 for line in csvfile))
The result is zero. If I run:
print(sum(1 for line in open(filepath, 'r')))
Then I get five lines, as expected. I've checked for name clashes by changing csvfile to other random names, but this does not change the result. Am I missing a step somewhere?
You need to move the file pointer back to the start of the file after sniffing it. You don't need to read the whole file in to do that, just enough to include a few rows:
import csv
with open(filepath, 'r') as f_input:
dialect = csv.Sniffer().sniff(f_input.read(2048))
f_input.seek(0)
csv_input = csv.reader(f_input, dialect)
csv_data = list(csv_input)
Also, the csv.reader() will do the splitting for you.
I am trying to add extra columns in a csv file after processing an input csv file. But, I am getting extra new line added after each line in the output.
What's missing or wrong in my below code -
import csv
with open('test.csv', 'r') as infile:
with open('test_out.csv', 'w') as outfile:
reader = csv.reader(infile, delimiter=',')
writer = csv.writer(outfile, delimiter=',')
for row in reader:
colad = row[5].rstrip('0123456789./ ')
if colad == row[5]:
col2ad = row[11]
else:
col2ad = row[5].split(' ')[-1]
writer.writerow([row[0],colad,col2ad] +row[1:])
I am processing huge a csv file so would like to get rid of those extra lines.
I had the same problem on Windows (your OS as well, I presume?). CSV and Windows as combination make a \r\r\n at the end of each line (so: double newline).
You need to open the output file in binary mode:
with open('test_out.csv', 'wb') as outfile:
For other answers:
Python's CSV writer produces wrong line terminator
CSV in Python adding an extra carriage return
I have the following code:
import re
#open the xml file for reading:
file = open('path/test.xml','r+')
#convert to string:
data = file.read()
file.write(re.sub(r"<string>ABC</string>(\s+)<string>(.*)</string>",r"<xyz>ABC</xyz>\1<xyz>\2</xyz>",data))
file.close()
where I'd like to replace the old content that's in the file with the new content. However, when I execute my code, the file "test.xml" is appended, i.e. I have the old content follwed by the new "replaced" content. What can I do in order to delete the old stuff and only keep the new?
You need seek to the beginning of the file before writing and then use file.truncate() if you want to do inplace replace:
import re
myfile = "path/test.xml"
with open(myfile, "r+") as f:
data = f.read()
f.seek(0)
f.write(re.sub(r"<string>ABC</string>(\s+)<string>(.*)</string>", r"<xyz>ABC</xyz>\1<xyz>\2</xyz>", data))
f.truncate()
The other way is to read the file then open it again with open(myfile, 'w'):
with open(myfile, "r") as f:
data = f.read()
with open(myfile, "w") as f:
f.write(re.sub(r"<string>ABC</string>(\s+)<string>(.*)</string>", r"<xyz>ABC</xyz>\1<xyz>\2</xyz>", data))
Neither truncate nor open(..., 'w') will change the inode number of the file (I tested twice, once with Ubuntu 12.04 NFS and once with ext4).
By the way, this is not really related to Python. The interpreter calls the corresponding low level API. The method truncate() works the same in the C programming language: See http://man7.org/linux/man-pages/man2/truncate.2.html
file='path/test.xml'
with open(file, 'w') as filetowrite:
filetowrite.write('new content')
Open the file in 'w' mode, you will be able to replace its current text save the file with new contents.
Using truncate(), the solution could be
import re
#open the xml file for reading:
with open('path/test.xml','r+') as f:
#convert to string:
data = f.read()
f.seek(0)
f.write(re.sub(r"<string>ABC</string>(\s+)<string>(.*)</string>",r"<xyz>ABC</xyz>\1<xyz>\2</xyz>",data))
f.truncate()
import os#must import this library
if os.path.exists('TwitterDB.csv'):
os.remove('TwitterDB.csv') #this deletes the file
else:
print("The file does not exist")#add this to prevent errors
I had a similar problem, and instead of overwriting my existing file using the different 'modes', I just deleted the file before using it again, so that it would be as if I was appending to a new file on each run of my code.
See from How to Replace String in File works in a simple way and is an answer that works with replace
fin = open("data.txt", "rt")
fout = open("out.txt", "wt")
for line in fin:
fout.write(line.replace('pyton', 'python'))
fin.close()
fout.close()
in my case the following code did the trick
with open("output.json", "w+") as outfile: #using w+ mode to create file if it not exists. and overwrite the existing content
json.dump(result_plot, outfile)
Using python3 pathlib library:
import re
from pathlib import Path
import shutil
shutil.copy2("/tmp/test.xml", "/tmp/test.xml.bak") # create backup
filepath = Path("/tmp/test.xml")
content = filepath.read_text()
filepath.write_text(re.sub(r"<string>ABC</string>(\s+)<string>(.*)</string>",r"<xyz>ABC</xyz>\1<xyz>\2</xyz>", content))
Similar method using different approach to backups:
from pathlib import Path
filepath = Path("/tmp/test.xml")
filepath.rename(filepath.with_suffix('.bak')) # different approach to backups
content = filepath.read_text()
filepath.write_text(re.sub(r"<string>ABC</string>(\s+)<string>(.*)</string>",r"<xyz>ABC</xyz>\1<xyz>\2</xyz>", content))