Develop Reference

Unable to click the Quality button

Any idea on how do I click the quality button as shown in the screenshot using selenium in python.
I am only able to open the settings menu, Not any further.
My main aim is to automatically change the video quality.
Thanks in advance!
list = driver.find_elements_by_name("ytp-settings-button")
list[0].click()

All the operation are dynamic in nature, the use of explicit wait is very important in this case. As per my observation , by using given below steps could help you
click on setting button
wait for object visible of "Quality"
Once found object, then click on it
wait for object visible of "480P" (i.e. required pixel)
once available, click on it.
To get xpath of quality and Pixel go to screenshot.
To stop the loading of element , check the parent tag in which the dynamic element appears and then right click on that tag and select "break on" then "subtree modification". This will stop the loading of website if any changes occur in that tag.

id of xpath is getting changed every time in selenium python 2.7 chrome

one more problem i hv,i asked similar question earlier and i tried that method but not able use that methon in this problem so pls help me. it's element
html code is - Filters 
So basically, question is that there is one button its kind of toggle button and i want click on that button to select device like Desktop, Tablet & Mobile all check boxes are already (default) selected now i have to uncheck or deselect device, to do this, first i have to click on that toggle button , when i click on toggle button its id (gwt-uid-598) 598 is getting changed every time or every refresh. Can you pls help me, what should or which method should i follow in this case.
i am using below python code.
Click on device Filters
elem = driver.find_element_by_xpath('//*[#id="gwt-uid-598"]/div/div/span')
elem.click()
Thanks in advance.

Good question.
Try to use another selector, for example: css class or use xpath method contains().
Example: //div[contains(text(), "checkbox")]
I can help you if you can provide source code of the page or needed element.

Unable to highlight text after selenium webdriver click()

I am using python code such as below to click an element within an iframe on an angularjs page.
browser = webdriver.Ie()
browser.switch_to.frame('name')
browser.find_element_by_id('value').click()
After using click() I am unable to manually highlight text that appears on the page. Why might this happen? How can I restore the ability to highlight text with the mouse?
I have tried switching back to default content, but this makes no difference. Any ideas?
Other strange effects after using click(): Links and buttons don't work while using the mouse manually unless double-clicked. These would normally require single click. It is as if there is an invisible overlay blocking text selection or clicking links. Radio buttons and menus still work.
Edit: The site uses silverlight and I am wondering if this is related to the problem that results from using click().

Mouse the focus to an object using selenium python

I am automating a website using selenium RC and python 2.7 on Ubuntu Linux. Here is what I need to do:
Go to the site http://borro.com.
Scroll down to the bottom of the page using key down native command
I need to hover the mouse on g +1
read the tool tip
click on the name that appears in the tool tip.
The problem I am having is -- I need the mouse to physically move there, wait for say 2 secs and then read the tool tip and click on the name
The mouse is not physically moving there and I think the focus is lost and it says element xpath not found.

We've solved a lot of our focus issues by sending a blank key to the element so it gets focused. In this case, you'd probably want to send blank key to the tooltip as soon as it appears. I'm familiar with webdriver but not RC, but RC should have something like send_key(element_xpath, " ") as well.
To get the tooltip's xpath, you can use firebug, and in the console, use something like
$x("//*[contains(text(), 'Publicly recommend this as')]")
to make sure this element is found and xpath is correct. I also recommend not using wildcard characters, so once you find the tooltip's xpath, try to replace the * by the actual element type.

Button Xpath and on hover on button xpath are given below
Actions builder = new Actions(driver);
WebElement tagElement = driver.findElement(By.id("button"));
builder.moveToElement(tagElement).build().perform();
/html/body/div/div/table/tbody/tr/td/div
Try:
selenium.mouseOver("mylocator");

Selenium: Testing pop-up windows

I have an issue when trying to test a web application with Selenium/Python. Basically I can't test elements of a pop-up window.
A scenario: I can test all elements for a page. But when I go to click on a button that opens up a small pop up box I can't test the elements on the popup. It's like the pop up isn't in focus or active.
I can test elements on the next page. For example click a button, brings me on to next page, and I can work with elements on the 'next' page. So it the problem seems to be popup specific.
I could post code but to be honest it might confuse at this stage. I may post code in a later post, thanks

There is a property called switch_to
Q: How do I handle pop up windows?
A: WebDriver offers the ability to cope with multiple windows. This is done by using the WebDriver.switch_to.window(knownName) method to switch to a window with a known name.
If the name is not known, you can use WebDriver.window_handles to obtain a list of known windows.
You may pass the handle to switch_to.window(handleName)
For example I used driverName.switchTo.window(driverName.getWindowHandle()) to get a hold of popups for which I didn't want to look for names.
Additional references:
http://code.google.com/p/selenium/wiki/FrequentlyAskedQuestions

For the Selenium RC API, you need to use the SelectWindow command to switch to the pop-up window. The window can be specified either by its name (as specified on the JavaScript window.open() function) or its title. To switch back to the main window, use SelectWindow(None).