Develop Reference

Conditional - Try something for x seconds [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 1 year ago.
Improve this question
This is my first question, as I have started to code recently.
here it goes...
I dont know how to do it, so I haven't coded it yet.
The idea is to have a Conditional to try doing something for x seconds, and if nothing happens on this x seconds, then do something to try it again.
Like this..
Try for 5 seconds to:
click on element to download something # <- this I know how to do
if nothing happens: # <- no error, just not executed the line above
refresh the page
try again:
finally:
You have your file
sorry for my English, as it is not my primary language and I am also learning it...

what web scraping tool you are using? selenium ? I can only give you my
logic if you do not post your code.
import datetime
def page_refresh():
print('refresh page')
driver.refresh()
def check_and_wait():
status_ready = False
while (not status_ready):
start_time = datetime.now()
while(not status_ready and datetime.now()-start_time<5): # loop 5 seconds
if(condtion == True): # if something happen
status_ready = True
return
page_refresh() # nothing happen , loop again

Executing for loop with if loop inside until it's complete [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 years ago.
Improve this question
I want to accomplish the following thing in my python program:
for l in list(p):
if condition1:
S1
s2
s3
if condition2:
return something
What I want to do here that, is it possible to execute the for loop until it's finished and then execute the 2nd if loop only once. The thing is that the 2nd if loop has to be inside for loop and it should execute only once.
Please let me know if that's possible and how can I do it??

You may want to move that code block to the else block of the for loop which executes immediately after the for loop is exhausted. The second if will be executed only once:
for l in p:
if condition1:
...
else:
if condition2:
return something
The else block of the for will be executed provided there were no exceptions, break or return statements in the body of the for loop.
On a side note, if p is iterable, you don't need to call list on it before using it in your for

Try using a for loop with an increment counter i and index to reference the list elements. Then you can add a condition to condition2 that prevents it from evaluating unless i == len(list(p)).

How can i improve this code to run faster? [closed]

Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 7 years ago.
Improve this question
I'm making The Powder Toy in Python, and I encountered some problems. Firstly the code runs VERY slowly. I know the problem is in my main file: http://pastebin.com/bbQ4H4Xu. The other files are just detecting input / creating the 2d array, so the problem isn't there.
Within my main file, the problem seems to be in the method updatescreen(). How can I increase the performance of this function?
import pygame
#inputkey.py
from pygame.locals import *
def input_key():
global inputt
inputt = ""
key = pygame.key.get_pressed()
if key[K_q]:
return 'q'
elif key[K_w]:
return 'w'
elif key[K_e]:
return 'e'
elif key[K_r]:
return 'r'
#Createblocks.py
blocks = []
for i in range(400):
blocks.append([])
for j in range(400):
blocks[i].append(0)

Your Main.py file has a print statement in the loop:
def updatescreen():
#The problem is here, it slows down the code.
for i in range(windh):
for x in range(windw):
print x, i # <== Here
if not blocks[i][x] == 0:
if blocks[i][x] == "Stone":
screen.blit(elementStone, (x,i))
presumably for debug? That's performing windw * windh = 2,500 print operations, which will slow the code down for sure. Try removing that and see how it improves.

How Can I Print Running Text? For Example to Print "Stack" Python Will Print S then t then a then c and then k? [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
I am using notepad++ for writing codes and then seeing output using Windows Power Shell. Now lets say I want to print this...
"Stack Overflow"
But not all at once. First of all it will print S then t then a then c then k then a space and then O ...... ?
So is there any function/method to post the text as we type in old PCs?
If the question is not complete let me know what more information I can provide you.
Update
#uʍop ǝpısdn Yes, you understood my requirement. And many thanks for the answer. :)
Well I didn't know that it calls Emulating text. :)

Here you go:
import time, sys
for letter in "Stack Overflow":
sys.stdout.write(letter)
sys.stdout.flush()
time.sleep(1) # that's in seconds, adjust at will
sys.stdout.write('\n')
Why stdout.flush?
Output from a running program is usually buffered (i.e. held waiting) until certain conditions are met. The call to sleep() will not fulfill these conditions, and the text will not appear. By calling flush() after each letter, you force it out.

from __future__ import print_function # only needed for Python 2.x
import random
from time import sleep
def delay_print(s, min_delay=0.1, max_delay=0.8):
for ch in s:
delay = min_delay + random.random() * (max_delay - min_delay)
sleep(delay)
print(ch, end="")
print('')
delay_print("StackOverflow")

Assign all the computer's power to Python [closed]

Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 9 years ago.
Improve this question
I'm running a python program that finds all the prime numbers. Is it possible to allocate all the computer's power to this single task. By using all the 4 cores that my processor have?
Thanks!
p.s. I'm using Linux of course!
The code I'm using is:
nextCheck = time.time() + 60
primesFound = 0
while 1:
if isPrime(toTest):
open("primeList.txt", "a").write(str(toTest)+"\n")
primesFound += 1
toTest += 2
if (toTest+1) % 1000 == 0:
if time.time() >= nextCheck:
print "Average speed: " + str(float(primesFound)/((time.time()-nextCheck)+60)) + "/s"
primesFound = 0
nextCheck = time.time() + 60

Use multiprocessing. If you are using CPython, only one thread at a time can execute Python bytecode so using threads isn't that much help.
If you can e.g. write a simple function to test a number, you can use a multiprocessing.Pool object's map() method to apply that function to a list of numbers.

You can also assign a higher priority to your Python process using nice:
nice -n -20 python app.py
... that will help, but will not guarantee that you are squeezing out all the power from your computer.
For that code, the best you can try is:
do not write numbers directly to an output file and save them in a memory structure,
program an event for not checking all the time about whether you need to print the speed statistics or not,
try to split out in several concurrent tasks the operations performed within function "isPrime" for executing them as separte tasks.
... however, I do not know whether this application worths this effort.