I'm trying to set up a database with a few specific fields (and I can't move away from the specification). One of the fields would be a column called metadata, but sqlalchemy prevents that:
sqlalchemy.exc.InvalidRequestError: Attribute name 'metadata' is reserved for the MetaData instance when using a declarative base class.
Is there a decent workaround for this? Do I need to monkeypatch the declarative_base function to rename the metadata attribute? I couldn't find an option to rename that attribute in the api docs.
Here's some example code that will fail with the above error:
#!/usr/bin/env python3.7
from sqlalchemy.ext.declarative import declarative_base, declared_attr
from sqlalchemy import Column, Integer
class CustomBase(object):
#declared_attr
def __tablename__(cls):
return cls.__name__.lower()
DBBase = declarative_base(cls=CustomBase)
class Data(DBBase):
id = Column(Integer, primary_key=True)
metadata = Column(Integer)
if __name__ == "__main__":
print(dir(Data()))
You can use like:
class Data(DBBase):
id = Column(Integer, primary_key=True)
# metadata = Column(Integer)
metadata_ = Column("metadata", Integer)
The constructor of Column class has a name parameter. You can find it from https://docs.sqlalchemy.org/en/13/core/metadata.html#sqlalchemy.schema.Column
The name field may be omitted at construction time and applied later
In other words, you could write a name as you want originally.
I Have a SQLalchemy class (flask-sqlalchemy) which inherits from another class and looks like this
class Cat(db.Model, Category):
__tablename__ = 'Cat'
id = db.Column(db.String(1000), primary_key=True, nullable=False)
parent_id = db.Column(db.String(1000), db.ForeignKey('SocArxivCategory.id'))
parent_category = db.relationship('Cat',
backref=db.backref('children',
order_by=Category.name,
lazy='selectin'),
remote_side='Cat.id')
and the parent class is
class Category():
__tablename__ = 'Category'
name = db.Column(db.String(2000), nullable=False)
You see that the Cat table builds a relationship using the Category.name attribute. But this seems to cause an error
....
File "/usr/local/lib/python2.7/site-packages/sqlalchemy/sql/compiler.py", line 692, in _fallback_column_name
raise exc.CompileError("Cannot compile Column object until "
CompileError: Cannot compile Column object until its 'name' is assigned.
so it seems to try to build the relationship before inheriting the name attribute? I am not sure whether this is an SQLalchemy issue or a Python issue? Any idea how to fix this?
Ok after a bit of searching and more consulting of the sqlalchemy docs I found a solution. Changing the definition of the relationship to
parent_category = db.relationship('Cat',
backref=db.backref('children',
order_by=lambda: Cat.name,
lazy='selectin'),
remote_side='Cat.id')
did the trick
I've got two models, Company and Employee, in a many-to-one relationship. They are defined in different Flask blueprints. I'm trying to add a cascade, which makes me need to define a relationship on Company (instead of just a relationship on Employee with backref set).
company_blueprint/models.py:
class Company(Base):
id = Column(Integer, primary_key=True)
employees = relationship("Employee", back_populates="company", cascade="all")
employee_blueprint/models.py:
from app.company_blueprint.models import Company
class Employee(Base):
name = Column(String)
company_id = Column(ForeignKey(Company.id))
company = relationship("company", back_populates="employees")
The problem is, when I try to delete a company in company_blueprint/views.py, the Employee model is not loaded. I get:
sqlalchemy.exc.InvalidRequestError: When initializing mapper Mapper|Company|company, expression 'Employee' failed to locate a name ("name 'Employee' is not defined"). If this is a class name, consider adding this relationship() to the <class 'app.company_model.models.Company'> class after both dependent classes have been defined.
I could try to import Employee in company_blueprint.models, but then I'm running into a circular import problem.
How do I fix this?
Edit: Thanks to Paradoxis, for now I've settled on the following:
Using strings to refer to foreign key columns, e.g. company_id = Column(ForeignKey("company.id"))
In my app.py, first import all models before anything else, i.e.
-
import flask
import app.employee_blueprint.models
import app.company_blueprint.models
# import other views, modules, etc.
This still feels a bit awkward.
I am using such relationships in most of the model classes. According to my understanding, you don't need any special thing or relationship in both classes. Simply add a relationship in parent model class and add a backref, it will work.
class Company(Base):
id = Column(Integer, primary_key=True)
employees = relationship("Employee", backref="company", cascade="all, delete-orphan")
I'm using flask-sqlalchemy.
I currently declare my models using:
class MyModel(db.Model):
__tablename__ = 'my_table'
id = db.Column(db.Integer, primary_key=True)
...
I want to create a base model class so I will be able to declare my models like this:
class MyBase(db.Model):
pass
class MyModel(MyBase):
__tablename__ = 'my_table'
id = db.Column(db.Integer, primary_key=True)
...
Is it possible?
I'm getting the following error:
InvalidRequestError: Class <class 'api.models.base.base_model.BaseModel'> does not have a __table__ or __tablename__ specified and does not inherit from an existing table-mapped class.
I would want to be able to put the tablename and all the column attributes inside my model and not inside my base class.
Since your custom base model is not a real model, you need to tell SQLAlchemy that it is abstract by setting __abstract__ = True on the class.
class MyBase(db.Model):
__abstract__ = True
Unless you are adding common functionality to this custom base, there's no point in doing this. The empty custom base is basically equivalent to just inheriting from db.Model directly.
Simplified, I have the following class structure (in a single file):
Base = declarative_base()
class Item(Base):
__tablename__ = 'item'
id = Column(BigInteger, primary_key=True)
# ... skip other attrs ...
class Auction(Base):
__tablename__ = 'auction'
id = Column(BigInteger, primary_key=True)
# ... skipped ...
item_id = Column('item', BigInteger, ForeignKey('item.id'))
item = relationship('Item', backref='auctions')
I get the following error from this:
sqlalchemy.exc.InvalidRequestError
InvalidRequestError: When initializing mapper Mapper|Auction|auction, expression
'Item' failed to locate a name ("name 'Item' is not defined"). If this is a
class name, consider adding this relationship() to the Auction class after
both dependent classes have been defined.
I'm not sure how Python cannot find the Item class, as even when passing the class, rather than the name as a string, I get the same error. I've been struggling to find examples of how to do simple relationships with SQLAlchemy so if there's something fairly obvious wrong here I apologise.
This all turned out to be because of the way I've set SQLAlchemy up in Pyramid. Essentially you need to follow this section to the letter and make sure you use the same declarative_base instance as the base class for each model.
I was also not binding a database engine to my DBSession which doesn't bother you until you try to access table metadata, which happens when you use relationships.
if it's a subpackage class, add Item and Auction class to __init__.py in the subpackage.
The SQLAlchemy documentation on Importing all SQLAlchemy Models states in part:
However, due to the behavior of SQLAlchemy's "declarative" configuration mode, all modules which hold active SQLAlchemy models need to be imported before those models can successfully be used. So, if you use model classes with a declarative base, you need to figure out a way to get all your model modules imported to be able to use them in your application.
Once I imported all of the models (and relationships), the error about not finding the class name was resolved.
Note: My application does not use Pyramid, but the same principles apply.
Case with me
Two models defined in separate files, one is Parent and the other is Child, related with a Foreign Key. When trying to use Child object in celery, it gave
sqlalchemy.exc.InvalidRequestError: When initializing mapper Mapper|Child|child, expression 'Parent' failed to locate a name ("name 'Parent' is not defined"). If this is a class name, consider adding this relationship() to the <class 'app.models.child'>
parent.py
from app.models import *
class Parent(Base):
__tablename__ = 'parent'
id = Column(BigInteger, primary_key=True, autoincrement=True)
name = Column(String(60), nullable=False, unique=True)
number = Column(String(45), nullable=False)
child.py
from app.models import *
class Child(Base):
__tablename__ = 'child'
id = Column(BigInteger, primary_key=True, autoincrement=True)
parent_id = Column(ForeignKey('parent.id'), nullable=False)
name = Column(String(60), nullable=False)
parent = relationship('Parent')
Solution
Add an import statement for Parent in beginning of child.py
child.py (modified)
from app.models import *
from app.models.parent import Parent # import Parent in child.py 👈👈
class Child(Base):
__tablename__ = 'child'
id = Column(BigInteger, primary_key=True, autoincrement=True)
parent_id = Column(ForeignKey('parent.id'), nullable=False)
name = Column(String(60), nullable=False)
parent = relationship('Parent')
Why this worked
The order in which models get loaded is not fixed in SQLAlchemy.
So, in my case, Child was being loaded before Parent. Hence, SQLAlchemy can't find what is Parent. So, we just imported Parent before Child gets loaded.
Namaste 🙏
I've solved the same error by inheriting a 'db.Model' instead of 'Base'... but I'm doing the flask
Eg:
from flask_sqlalchemy import SQLAlchemy
db = SQLAlchemy()
class someClass(db.Model):
someRelation = db.relationship("otherClass")
Also, even though this doesn't apply to the OP, for anyone landing here having gotten the same error, check to make sure that none of your table names have dashes in them.
For example, a table named "movie-genres" which is then used as a secondary in a SQLAlchemy relationship will generate the same error "name 'movie' is not defined", because it will only read as far as the dash. Switching to underscores (instead of dashes) solves the problem.
My Solution
One models file, or even further, if you need.
models.py
from sqlalchemy import Boolean, BigInteger, Column, DateTime, Float, ForeignKey, BigInteger, Integer, String
from sqlalchemy.orm import relationship
from sqlalchemy.ext.declarative import declarative_base
Base = declarative_base()
from .parent import Parent
from .child import Child
parent.py
from sqlalchemy import Boolean, BigInteger, Column, DateTime, Float, ForeignKey, BigInteger, Integer, String
from sqlalchemy.orm import relationship
from sqlalchemy.ext.declarative import declarative_base
#Base = declarative_base()
class Parent(Base):
__tablename__ = 'parent'
id = Column(BigInteger, primary_key=True, autoincrement=True)
name = Column(String(60), nullable=False, unique=True)
number = Column(String(45), nullable=False)
child.py
from sqlalchemy import Boolean, BigInteger, Column, DateTime, Float, ForeignKey, BigInteger, Integer, String
from sqlalchemy.orm import relationship
from sqlalchemy.ext.declarative import declarative_base
Base = declarative_base()
class Child(Base):
__tablename__ = 'child'
id = Column(BigInteger, primary_key=True, autoincrement=True)
parent_id = Column(ForeignKey('parent.id'), nullable=False)
name = Column(String(60), nullable=False)
parent = relationship('Parent')
Why this worked
Same Deepam answer, but with just one models.py file to import another models
I had a different error, but the answers in here helped me fix it.
The error I received:
sqlalchemy.exc.InvalidRequestError: When initializing mapper mapped class Parent->parents, expression 'Child' failed to locate a name ('Child'). If this is a class name, consider adding this relationship() to the <class 'parent.Parent'> class after both dependent classes have been defined.
My set-up is similar toDeepam's answer.
Briefly what I do different:
I have multiple separate .py files for each db.Model.
I use a construct/fill database .py file that pre-fills db.Model objects in either Multi-threading or single threading way
What caused the error:
Only in multi-threaded set up the error occured
This construct/fill .py script did import Parent, but not Child.
What fixed it:
Adding an import to Child fixed it.
I had yet another solution, but this helped clue me in. I was trying to implement versioning, from https://docs.sqlalchemy.org/en/14/orm/examples.html#versioning-objects using the "history_mapper" class.
I got this same error. All I had to do to fix it was change the order in which my models were imported.
Use back_populates for relationship mapping in both models.
Also keep in mind to import both the models in the models/__init__.py
Base = declarative_base()
class Item(Base):
__tablename__ = 'item'
id = Column(BigInteger, primary_key=True)
# ... skip other attrs ...
auctions = relationship('Auction', back_populates='item')
class Auction(Base):
__tablename__ = 'auction'
id = Column(BigInteger, primary_key=True)
# ... skipped ...
item_id = Column('item', BigInteger, ForeignKey('item.id'))
item = relationship('Item', back_populates='auctions')