I have an Mlflow project that raises an exception. I execute that function using mlflow.run, but I get mlflow.exceptions.ExecutionException("Run (ID '<run_id>') failed").
Is there any way I could get the exception that is being raised where I am executing mlflow.run?
Or is it possible to send an mlflow.exceptions.ExecutionException with custom message set from within the project?
Unfortunately not at the moment. mlflow run starts a new process and there is no protocol for exception passing right now. In general the other project does not even have to be in the same language.
One workaround I can think of is to pass the exception via mlflow by setting run tag. E.g.:
try:
...
except Exception as ex:
mlflow.set_tag("exception", str(ex))
Related
I'm using a Python script to get Stock price from an API,
Everythinks works great but sometimes I receive html errors instead of prices,
These errors prevent the script from continuing and the terminal stopped working,
how do I test the response from the API before passing the information to the next script?
I don't want the terminal to stop when it receives server errors.
Only one line to get price :
get_price = api_client.quote('TWTR')
The question, "How do I test the response from the API before passing the information" is well suited for a try/except block. For example the following will attempt to call quote() and if an exception is raised it will print a message to the console:
try:
get_price = api_client.quote('TWTR')
except <Exception Type Goes Here>:
# handle the exception case.
print('Getting quote did not work as expected')
The example is useful for illustrating the point but you should improve the exception handling. I recommend you take a look at resources to help you understand how to appropriately handle exceptions in your code. A few that I have found useful would be:
The Python Docs: Learn what an exception is and how they can be used
Python Exception Handling: A blog post that details how to combine some of the concepts in the Python documentation practically.
I'm developing some REST api for a webservice.
Starting from some days I've experienced a big problem that is blocking me.
When the code has an exception (during developing) the django server respond only after 5/8 or 10 minutes... with the error that occurs.
To understand what is happening I've started the server in debug using pycharm.... and then clicking on pause during the big waiting.. the code is looping here into python2.7/SocketServer.py
def _eintr_retry(func, *args):
"""restart a system call interrupted by EINTR"""
while True:
try:
return func(*args)
except (OSError, select.error) as e:
if e.args[0] != errno.EINTR:
raise
print(foo)
What can I do? I'm pretty desperate!
Sometimes that happens in Django debug mode because Django generates a nice page with traceback and a list of all local variables for every stack frame.
When Django models has an inefficient __str__ (__unicode__ since you're using Python 2) method, this can result in Django loading many thousands of objects from the database to display traceback.
In my experience this is the only reason for a very long pauses on exception in Django. Try running with DEBUG = False or check what exactly model has inefficient __str__ method that hits database.
I am trying to implement a job which reads from Azure Queue and writes into db. occasionally some errors are raised from the Azure server such as timeout, server busy etc. How to handle such errors in the code, I tried ti run the code in a try catch loop but, I am not able to identify Azure errors?
I triedn to import WindowsAzureError from azure , but it doesn't work (no such module to import)?
Which is a good way to handle errors in this case?
If you're using 0.30+ all errors that occur after the request to the service has been will extend from AzureException. AzureException can be found in the azure.common package which Azure storage takes a dependency on. Errors which are thrown if invalid args are passed to a method (ex None for the queue name) might not extend from this and will be standard Python exception like ValueError.
Thanks #Terran,
exception azure.common.AzureConflictHttpError(message, status_code)
Bases: azure.common.AzureHttpError
exception azure.common.AzureException
Bases: exceptions.Exception
exception azure.common.AzureHttpError(message, status_code)
Bases: azure.common.AzureException
exception azure.common.AzureMissingResourceHttpError(message, status_code)
Bases: azure.common.AzureHttpError
This helped me.. http://azure-sdk-for-python.readthedocs.org/en/latest/ref/azure.common.html
I debug django application and want to suspend code execution at the point where exception occurs with cursor pointing to problematic place in code. Pretty HTML display by django would be helpful either but not mandatory. My IDE is PyCharm.
If I set pycharm to suspend on termination of exception, then I never catch it, because django handles the exception with HTML debug info and exceptions never terminate. Setting DEBUG_PROPAGATE_EXCEPTIONS = True inside settings.py causes HTML debug info to disappear but the execution does not terminate either.
If I set pycharm to suspend on raise of exception, then I have to pass all existing exceptions inside py internals such as copy.py, decimal.py, gettext.py, etc, which is inconvenient (there are so many of them that I could never reach exceptions caused by my code).
If I set "temporary" setup to suspend on raise of exception which occurs after given breakpoint (which I place at the last line of settings.py) then django server does not start.
Thanks in advance for your help.
This should happen automatically in PyCharm. What you need to do is set no breakpoints, but run as debug (click on the green bug icon). When the exception occurs, execution should automatically halt.
i'm using Python with MySQL and Django. I keep seeing this error and I can't figure out where the exception is being thrown:
Exception _mysql_exceptions.ProgrammingError: (2014, "Commands out of sync; you can't run this command now") in <bound method Cursor.__del__ of <MySQLdb.cursors.Cursor object at 0x20108150>> ignored
I have many "try" and "exception" blocks in my code--if the exception occurred within one of those, then I would see my own debugging messages. The above Exception is obviously being caught somewhere since my program does not abort when the Exception is thrown.
I'm very puzzled, can someone help me out?
I had exactly that error (using MySQLdb and Django) and discovered that the reason it was "ignored" was that it occurred in a __del__ method. Exceptions in __del__ are categorically ignored:
object.__del__ datamodel
There doesn't seem to be any way to catch it from further up the stack (at least according to this thread), but you can edit MySQLdb/cursors.py or monkey-patch to get your own __del__ in there that catches the exception and drops you into a pdb prompt or logs a full traceback.
This is a Python Error.
See: http://eric.lubow.org/2009/python/pythons-mysqldb-2014-error-commands-out-of-sync/
It looks like there is a problem with your MySQLdb Query.
I believe this error can occur if you are using the same connection/cursor from multiple threads.
However, I dont think the creators of Django has made such a mistake, but if you are doing something by yourself it can easily happen.
After printing out a bunch of stuff and debugging, I figured out the problem I think. One of the libraries that I used didn't close the connection or the cursor. But this problem only shows up if I iterate through a large amount of data. The problem is also very intermittent and I still don't know who's throwing the "command out of sync" exception. But now that we closed both the connection and cursor, I don't see the errors anymore.
The exceptions in object destructors (__del__) are ignored, which this message indicates. If you execute some MySQL command without fetching results from the cursor (e.g. 'create procedure' or 'insert') then the exception is unnoticed until the cursor is destroyed.
If you want to raise and catch an exception, call explicitly cursor.close() somewhere before going out of the scope.