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Python - Download zip files with requests package but get unknown file format

I am using Python 3.8.12. I tried the following code to download files from URLs with the requests package, but got 'Unkown file format' message when opening the zip file. I tested on different zip URLs but the size of all zip files are 18KB and none of the files can be opened successfully.
import requests
file_url = 'https://www.censtatd.gov.
hk/en/EIndexbySubject.html?pcode=D5600091&scode=300&file=D5600091B2022MM11B.zip'
file_download = requests.get(file_url, allow_redirects=True, stream=True)
open(save_path+file_name, 'wb').write(file_download.content)
Zip file opening error message
Zip files size
However, once I updated the url as file_url = 'https://www.td.gov.hk/datagovhk_tis/mttd-csv/en/table41a_eng.csv' the code worked well and the csv file could be downloaded perfectly.
I try to use requests, urllib , wget and zipfile io packages, but none of them work.
The reason may be that the zip URL directs to both the zip file and a web page, while the csv URL directs to the csv file only.
I am really new to this field, could anyone help on it? Thanks a lot!

You might examine headers after sending HEAD request to get information regarding file, examining Content-Type allows you to reveal actual type of file
import requests
file_url = 'https://www.censtatd.gov.hk/en/EIndexbySubject.html?pcode=D5600091&scode=300&file=D5600091B2022MM11B.zip'
r = requests.head(file_url)
print(r.headers["Content-Type"])
gives output
text/html
So file you have URL to is actually HTML page.

import wget
url = 'https://www.censtatd.gov.hk/en/EIndexbySubject.html?
pcode=D5600091&scode=300&file=D5600091B2022MM11B.zip'
#url = 'https://golang.org/dl/go1.17.3.windows-amd64.zip'
wget.download(url)

Python script to download PDF not downloading the PDF?

I have a Python 3.10 script to download a PDF from a URL, I get no errors but when I run the code the PDF does not download. I've done a sanity check to ensure the PDF is actually on the URL (which it is)
I'm not sure if this maybe has something to do with HTTP/ HTTPS? This site does have an expired HTTPS certificate, but it is a government site and this is really for testing only so I am not worried about that and can ignore the error
from fileinput import filename
import os
import os.path
from datetime import datetime
import urllib.request
import requests
import urllib3
urllib3.disable_warnings()
resp = requests.get('http:// url domain .org', verify=False)
urllib.request.urlopen('http:// my url .pdf')
filename = datetime.now().strftime("%Y_%m_%d-%I_%M_%S_%p")
save_path = "C:/Users/bob/Desktop/folder"
Or maybe is the issue something to do with urllib3 ignoring the error and urllib downloading the file?
Redacted the specific URL here

The urllib.request.urlopen method doesn't save the remote URL to a file -- it returns a response object that can be treated as a file-like object. You could do something like:
response = urllib.request.urlopen('http:// my url .pdf')
with open('filename.pdf') as fd:
fd.write(response.read())
The urllib.request.urlretrieve method, on the other hand, will take care of writing the remote content to a local file. You would use it like this to write the PDF file to a local file named filename.pdf:
response = urllib.request.urlretrieve('http://my url .pdf',
filename='filename.pdf')
See the documentation for information about the return value from the urlretrieve method.

Download GitLab file with gitlab-python

I am trying to download a file or folder from my gitlab repository, but they only way I have seen to do it is using CURL and command line. Is there any way to download files from the repository with just the python-gitlab API? I have read through the API and have not found anything, but other posts said it was possible, just gave no solution.

You can do like this:
import requests
response = requests.get('https://<your_path>/file.txt')
data = response.text
and then save the contents (data) as file...
Otherwise use the API:
f = project.files.get(path='<folder>/file.txt',ref='<branch or commit>')
and then decode using:
import base64
content = base64.b64decode(f.content)
and then save content as file...

Taking list of mp4 URLs and downloading file python

How would I go about navigating to a URL that's stored in a list and downloading the file? I'd preferably like to be able to store the MP4 file as it's clip title. I've used requests to retrieve the urls.
Thanks
list_clips = ['https://clips.twitch.tv/SpeedySneakyHeronKappaClaus', 'https://clips.twitch.tv/SplendidGiantPuffinThunBeast', 'https://clips.twitch.tv/ArtsyAuspiciousHamburgerThisIsSparta', 'https://clips.twitch.tv/BoringNiceHerbsSaltBae']

You can use python's requests module to download the file. Please refer the code below
import requests, os
for clips in list_clips:
clip_title = os.path.basename(clips)
r = requests.get(clips)
with open(clip_title+'.mp4', 'wb') as f:
f.write(r.content)

Download excel file using python

I have a web link which downloads an excel file directly. It opens a page writing "your file is downloading" and starts downloading the file.
Is there any way i can automate it using requests module ?
I am able to do it with selenium but i want it to run in background so i was wondering if i can use request module.
I have used request.get but it simply gives the text i.e "your file is downloading" but somehow i am not able to get the file.

This Python3 code downloads any file from web to a memory:
import requests
from io import BytesIO
url = 'your.link/path'
def get_file_data(url):
response = requests.get(url)
f = BytesIO()
for chunk in response.iter_content(chunk_size=1024):
f.write(chunk)
f.seek(0)
return f
data = get_file_data(url)
You can use next code to read the Excel file:
import pandas as pd
xlsx = pd.read_excel(data, skiprows=0)
print(xlsx)

It sounds like you don't actually have a direct URL to the file, and instead need to engage with some javascript. Perhaps there is an underlying network call that you can find by inspecting the page traffic in your browser that shows a direct URL for downloading the file. With that you can actually just read the excel file URL directly with pandas:
import pandas as pd
url = "https://example.com/some_file.xlsx"
df = pd.read_excel(url)
print(df)
This is nice and tidy, but if you really want to use requests (or avoid pandas) you can download the raw file content as shown in this answer and then use the pyexcel_xlsx package's get_xlsx function to read it without any pandas involvement.