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Python - update records with for loop

firstly apologies for the basic question, just starting off with Python.
I have the following code:
import sqlite3
conn = sqlite3.connect("test.sqb")
cursor = conn.cursor()
sql = "SELECT * FROM report WHERE type LIKE 'C%'"
cursor.execute(sql)
data = cursor.fetchall()
for row in data:
print (row[0])
cursor.execute("UPDATE report SET route='ABCDE'")
conn.commit()
conn.close()
Why is it updating all records and not just the filtered records from sql query, even though the print (row[0]) just shows the filtered records.
Many thanks.

What's actually happening is you are running this query for each record returned from the SELECT query.
UPDATE report SET route='ABCDE'
If you only want to update route where type starts with C add the criteria to the UPDATE query and execute it once.
import sqlite3
conn = sqlite3.connect("test.sqb")
cursor = conn.cursor()
sql = "SELECT * FROM report WHERE type LIKE 'C%'"
cursor.execute(sql)
data = cursor.fetchall()
cursor.execute("UPDATE report SET route='ABCDE' WHERE type LIKE 'C%'")
conn.commit()
conn.close()

Saving result of a Query in a variable

import pymysql
connection = pymysql.connect(host='......', user='....', password='.....', database='......')
cursor=connection.cursor()
q1="select count(*) from lk_employee_data where date(entry_time)=('2020-11-18')"
cursor.execute(q1)
q1 query is giving result 1.While if i run same query in Database result is 190.So what I want to know why it is not working correctly.And I also want to save result of q1 query in a variabe.

cursor.execute() will return the number of affected rows by the query executed. To retrieve data you have to access to cursor results directly as below:
cursor = connection.cursor()
q1="select count(*) from lk_employee_data where date(entry_time)=('2020-11-18')"
cursor.execute(q1)
results = cursor.fetchall()

Print a value in Python from oracle database

I have an issue when displaying a value in python retrieved from oracle table into CLOB field:
Oracle query:
SELECT EXTRACTVALUE(xmltype(t.xml), '/DCResponse/ResponseInfo/ApplicationId')
FROM table t
WHERE id = 2
Value displayed in Oracle Client
5701200
Python code
import cx_Oracle
conn = cx_Oracle.Connection("user/pwd#localhost:1521/orcl")
cursor = conn.cursor()
cursor.execute("""SELECT EXTRACTVALUE(xmltype(t.xml),'/DCResponse/ResponseInfo/ApplicationId') FROM table t where id = 2""")
for row in cursor:
print(row)
Python Console: Nothing is displayed!!! I want to show:5701200
Please Help.
Best Regards
Giancarlo

There are only a few issues with your code :
Replace cx_Oracle.Connection with cx_Oracle.connect
Be careful about the indentation related to the print(row)
Triple double-quotes, within the SELECT statement, are redundant,
replace them with Single double-quotes
Prefer Using print(row[0]) in order to return the desired number rather than
a tuple printed.
import cx_Oracle
conn = cx_Oracle.connect('user/pwd#localhost:1521/orcl')
cursor = conn.cursor()
query = "SELECT EXTRACTVALUE(xmltype(t.xml),'/DCResponse/ResponseInfo/ApplicationId')"
query += " FROM tab t "
query += " WHERE t.ID = 2 "
cursor.execute( query )
for row in cursor:
print(row[0])
Assigning a query to a variable not required, as stated in my case, but preferable to use in order to display the long SELECT statement decently.

If you want to iterate over result, use this one:
for row in cursor.execute("sql_query")
print(row)
or you can fetch each row like this:
cursor = conn.cursor()
cursor.execute("sql_query")
while True:
row = cursor.fetchone()
print(row)

Replace L, in SQL results in python

I'm running pyodbc connected to my db and when i run a simply query I get a load of results back such as
(7L, )(12L,) etc.
How do I replace the the 'L, ' with '' so I can pass the ids into another query
Thanks
Here's my code
import pyodbc
cnxn = pyodbc.connect('DSN=...;UID=...;PWD=...', ansi=True)
cursor = cnxn.cursor()
rows = cursor.execute("select id from orders")
for row in rows:
test = cursor.execute("select name from customer where order_id = %(id)s" %{'id':row})
print test

Use parameters:
...
test = cursor.execute("select name from customer where order_id = ?", row.id)
...
The L after the number indicates that the value is a long type.

Insert data into MySQL table from Python script

I have a MySQL Table named TBLTEST with two columns ID and qSQL. Each qSQL has SQL queries in it.
I have another table FACTRESTTBL.
There are 10 rows in the table TBLTEST.
For example, On TBLTEST lets take id =4 and qSQL ="select id, city, state from ABC".
How can I insert into the FACTRESTTBL from TBLTEST using python, may be using dictionary?
Thx!

You can use MySQLdb for Python.
Sample code (you'll need to debug it as I have no way of running it here):
#!/usr/bin/python
import MySQLdb
# Open database connection
db = MySQLdb.connect("localhost","testuser","test123","TESTDB" )
# prepare a cursor object using cursor() method
cursor = db.cursor()
# Select qSQL with id=4.
cursor.execute("SELECT qSQL FROM TBLTEST WHERE id = 4")
# Fetch a single row using fetchone() method.
results = cursor.fetchone()
qSQL = results[0]
cursor.execute(qSQL)
# Fetch all the rows in a list of lists.
qSQLresults = cursor.fetchall()
for row in qSQLresults:
id = row[0]
city = row[1]
#SQL query to INSERT a record into the table FACTRESTTBL.
cursor.execute('''INSERT into FACTRESTTBL (id, city)
values (%s, %s)''',
(id, city))
# Commit your changes in the database
db.commit()
# disconnect from server
db.close()