This is the content of my file:
david C001 C002 C004 C005 C006 C007
* C008 C009 C010 C011 C016 C017 C018
* C019 C020 C021 C022 C023 C024 C025
anna C500 C521 C523 C547 C555 C556
* C557 C559 C562 C563 C566 C567 C568
* C569 C571 C572 C573 C574 C575 C576
* C578
charlie C701 C702 C704 C706 C707 C708
* C709 C712 C715 C716 C717 C718
I want my output to be:
david=[C001,C002,C004,C005,C006,C007,C008,C009,C010,C011,C016,C017,C018,C019,C020,C021,C022,C023,C024,C025]
anna=[C500,C521,C523,C547,C555,C556,C557,C559,C562,C563,C566,C567,C568,C569,C571,C572,C573,C574,C575,C576,C578]
charlie=[C701,C702,C704,C706,C707,C708,C709,C712,C715,C716,C717,C718]
I am able to create:
david=[C001,C002,C004,C005,C006,C007]
anna=[C500,C521,C523,C547,C555,C556]
charlie=[C701,C702,C704,C706,C707,C708]
counting the number of words in a line and using line[0] as the array name and adding the remaining words to the array.
However, I don't know how to take the continuation of words in the next lines starting with "*" to the array.
Can anyone help?
NOTE: This solution relies on defaultdict being ordered, which is something that was introduced on Python 3.6
Somewhat naive approach:
from collections import defaultdict
# Create a dictionary of people
people = defaultdict(list)
# Open up your file in read-only mode
with open('your_file.txt', 'r') as f:
# Iterate over all lines, stripping them and splitting them into words
for line in filter(bool, map(str.split, map(str.strip, f))):
# Retrieve the name of the person
# either from the current line or use the name of the last person processed
name, words = list(people)[-1] if line[0] == '*' else line[0], line[1:]
# Add all remaining words to that person's record
people[name].extend(words)
print(people['anna'])
# ['C500', 'C521', 'C523', 'C547', 'C555', 'C556', 'C557', 'C559', 'C562', 'C563', 'C566', 'C567', 'C568', 'C569', 'C571', 'C572', 'C573', 'C574', 'C575', 'C576', 'C578']
It also has the additional benefit of returning an empty list for unknown names:
print(people['matt'])
# []
You could read the lists into a dictionary using regular expressions:
import re
with open('file_name') as file:
contents = file.read()
res_list = re.findall(r"[a-z]+\s+[^a-z]+",contents)
res_dict = {}
for p in res_list:
elt = p.split()
res_dict[elt[0]] = [e for e in elt[1:] if e != '*']
print(res_dict)
I figured out a way myself. Thanks to the ones who gave their own solution. It gave me new perspective.
Below is my code:
persons_library={}
persons=['david','anna','charlie']
for i,person in enumerate(persons,start=0):
persons_library[person]=[]
with open('data.txt','r') as f:
for line in f:
line=line.replace('*',"")
line=line.split()
for i,val in enumerate(line,start=0):
if val in persons_library:
key=val
else:
persons_library[key].append(val)
print(persons_library)
Related
I have a record as below:
29 16
A 1.2595034 0.82587254 0.7375044 1.1270138 -0.35065323 0.55985355
0.7200067 -0.889543 0.2300735 0.56767654 0.2789483 0.32296127 -0.6423197 0.26456305 -0.07363393 -1.0788593
B 1.2467299 0.78651106 0.4702038 1.204216 -0.5282698 0.13987103
0.5911153 -0.6729466 0.377103 0.34090135 0.3052503 0.028784657 -0.39129165 0.079238065 -0.29310825 -0.99383247
I want to split the data into key-value pairs neglecting the first top row i.e 29 16. It should be neglected.
The output should be something like this:
x = A , B
y = 1.2595034 0.82587254 0.7375044 1.1270138 -0.35065323 0.55985355 0.7200067 -0.889543 0.2300735 0.56767654 0.2789483 0.32296127 -0.6423197 0.26456305 -0.07363393 -1.0788593
1.2467299 0.78651106 0.4702038 1.204216 -0.5282698 0.13987103 0.5911153 -0.6729466 0.377103 0.34090135 0.3052503 0.028784657 -0.39129165 0.079238065 -0.29310825 -0.99383247
I am able to neglect the first line using the below code:
f = open(fileName, 'r')
lines = f.readlines()[1:]
Now how do I separate rest record in Python?
So here's my take :D I expect you'd want to have the numbers parsed as well?
def generate_kv(fileName):
with open(fileName, 'r') as file:
# ignore first line
file.readline()
for line in file:
if '' == line.strip():
# empty line
continue
values = line.split(' ')
try:
yield values[0], [float(x) for x in values[1:]]
except ValueError:
print(f'one of the elements was not a float: {line}')
if __name__ == '__main__':
x = []
y = []
for key, value in generate_kv('sample.txt'):
x.append(key)
y.append(value)
print(x)
print(y)
assumes that the values in sample.txt look like this:
% cat sample.txt
29 16
A 1.2595034 0.82587254 0.7375044 1.1270138 -0.35065323 0.55985355 0.7200067 -0.889543 0.2300735 0.56767654 0.2789483 0.32296127 -0.6423197 0.26456305 -0.07363393 -1.0788593
B 1.2467299 0.78651106 0.4702038 1.204216 -0.5282698 0.13987103 0.5911153 -0.6729466 0.377103 0.34090135 0.3052503 0.028784657 -0.39129165 0.079238065 -0.29310825 -0.99383247
and the output:
% python sample.py
['A', 'B']
[[1.2595034, 0.82587254, 0.7375044, 1.1270138, -0.35065323, 0.55985355, 0.7200067, -0.889543, 0.2300735, 0.56767654, 0.2789483, 0.32296127, -0.6423197, 0.26456305, -0.07363393, -1.0788593], [1.2467299, 0.78651106, 0.4702038, 1.204216, -0.5282698, 0.13987103, 0.5911153, -0.6729466, 0.377103, 0.34090135, 0.3052503, 0.028784657, -0.39129165, 0.079238065, -0.29310825, -0.99383247]]
Alternatively, if you'd wanted to have a dictionary, do:
if __name__ == '__main__':
print(dict(generate_kv('sample.txt')))
That will convert the list into a dictionary and output:
{'A': [1.2595034, 0.82587254, 0.7375044, 1.1270138, -0.35065323, 0.55985355, 0.7200067, -0.889543, 0.2300735, 0.56767654, 0.2789483, 0.32296127, -0.6423197, 0.26456305, -0.07363393, -1.0788593], 'B': [1.2467299, 0.78651106, 0.4702038, 1.204216, -0.5282698, 0.13987103, 0.5911153, -0.6729466, 0.377103, 0.34090135, 0.3052503, 0.028784657, -0.39129165, 0.079238065, -0.29310825, -0.99383247]}
you can use this script if your file is a text
filename='file.text'
with open(filename) as f:
data = f.readlines()
x=[data[0][0],data[1][0]]
y=[data[0][1:],data[1][1:]]
If you're happy to store the data in a dictionary here is what you can do:
records = dict()
with open(filename, 'r') as f:
f.readline() # skip the first line
for line in file:
key, value = line.split(maxsplit=1)
records[key] = value.split()
The structure of records would be:
{
'A': ['1.2595034', '0.82587254', '0.7375044', ... ]
'B': ['1.2467299', '0.78651106', '0.4702038', ... ]
}
What's happening
with ... as f we're opening the file within a context manager (more info here). This allows us to automatically close the file when the block finishes.
Because the open file keeps track of where it is in the file we can use f.readline() to move the pointer down a line. (docs)
line.split() allows you to turn a string into a list of strings. With the maxsplits=1 arg it means that it will only split on the first space.
e.g. x, y = 'foo bar baz'.split(maxsplit=1), x = 'foo' and y = 'bar baz'
If I understood correctly, you want the numbers to be collected in a list. One way of doing this is:
import string
text = '''
29 16
A 1.2595034 0.82587254 0.7375044 1.1270138 -0.35065323 0.55985355 0.7200067 -0.889543 0.2300735 0.56767654 0.2789483 0.32296127 -0.6423197 0.26456305 -0.07363393 -1.0788593
B 1.2467299 0.78651106 0.4702038 1.204216 -0.5282698 0.13987103 0.5911153 -0.6729466 0.377103 0.34090135 0.3052503 0.028784657 -0.39129165 0.079238065 -0.29310825 -0.99383247
'''
lines = text.split('\n')
x = [
line[1:].strip().split()
for i, line in enumerate(lines)
if line and line[0].lower() in string.ascii_letters]
This will produce a list of lists when the outer list contains A, B, etc. and the inner lists contain the numbers associated to A, B, etc.
This code assumes that you are interested in lines starting with any single letter (case-insensitive).
For more elaborated conditions you may want to look into regular expressions.
Obviously, if your text is in a file, you could substitute lines = ... with:
with open(filepath, 'r') as lines:
x = ...
Also, if the items in x should not be separated, but rather in a string, you may want to change line[1:].strip().split() with line[1:].strip().
Instead, if you want the numbers as float and not string, you should replace line[1:].strip().split() with [float(value) for value in line[1:].strip().split()].
EDIT:
Alternatively to line[1:].strip().split() you may want to do:
line.split(maxsplit=1)[1].split()
as suggested in some other answer. This would generalize better if the first token is not a single character.
I need to extract the name of the constants and their corresponding values from a .txt file into a dictionary. Where key = NameOfConstants and Value=float.
The start of the file looks like this:
speed of light 299792458.0 m/s
gravitational constant 6.67259e-11 m**3/kg/s**2
Planck constant 6.6260755e-34 J*s
elementary charge 1.60217733e-19 C
How do I get the name of the constants easy?
This is my attempt:
with open('constants.txt', 'r') as infile:
file1 = infile.readlines()
constants = {i.split()[0]: i.split()[1] for i in file1[2:]}
I'm not getting it right with the split(), and I need a little correction!
{' '.join(line.split()[:-2]):' '.join(line.split()[-2:]) for line in lines}
From your text file I'm unable to get the correct value of no of spaces to split. So below code is designed to help you. Please have a look, it worked for you above stated file.
import string
valid_char = string.ascii_letters + ' '
valid_numbers = string.digits + '.'
constants = {}
with open('constants.txt') as file1:
for line in file1.readlines():
key = ''
for index, char in enumerate(line):
if char in valid_char:
key += char
else:
key = key.strip()
break
value = ''
for char in line[index:]:
if char in valid_numbers:
value += char
else:
break
constants[key] = float(value)
print constants
Have You tried using regular expressions?
for example
([a-z]|\s)*
matches the first part of a line until the digits of the constants begin.
Python provides a very good tutorial on regular expressions (regex)
https://docs.python.org/2/howto/regex.html
You can try out your regex online as well
https://regex101.com/
with open('constants.txt', 'r') as infile:
lines = infile.readlines()
constants = {' '.join(line.split()[:-2]):float(' '.join(line.split()[-2:-1])) for line in lines[2:]}
Since there were two lines above not needed.
This would best be solved using a regexp.
Focussing on your question (how to get the names) and your desires (have something shorter):
import re
# Regular expression fetches all characters
# until the first occurence of a number
REGEXP = re.compile('^([a-zA-Z\s]+)\d.*$')
with open('tst.txt', 'r') as f:
for line in f:
match = REGEXP.match(line)
if match:
# On a match the part between parentheses
# are copied to the first group
name = match.group(1).strip()
else:
# Raise something, or change regexp :)
pass
What about re.split-
import re
lines = open(r"C:\txt.txt",'r').readlines()
for line in lines:
data = re.split(r'\s{3,}',line)
print "{0} : {1}".format(data[0],''.join(data[1:]))
Or use oneliner to make dictionary-
{k:v.strip() for k,v in [(re.split(r'\s{3,}',line)[0],''.join(re.split(r'\s{3,}',line)[1:])) for line in open(r"C:\txt.txt",'r').readlines() ]}
Output-
gravitational constant : 6.67259e-11m**3/kg/s**2
Planck constant : 6.6260755e-34J*s
elementary charge : 1.60217733e-19C
Dictionary-
{'Planck constant': '6.6260755e-34J*s', 'elementary charge': '1.60217733e-19C', 'speed of light': '299792458.0m/s', 'gravitational constant': '6.67259e-11m**3/kg/s**2'}
i've searched pretty hard and cant find a question that exactly pertains to what i want to..
I have a file called "words" that has about 1000 lines of random A-Z sorted words...
10th
1st
2nd
3rd
4th
5th
6th
7th
8th
9th
a
AAA
AAAS
Aarhus
Aaron
AAU
ABA
Ababa
aback
abacus
abalone
abandon
abase
abash
abate
abater
abbas
abbe
abbey
abbot
Abbott
abbreviate
abc
abdicate
abdomen
abdominal
abduct
Abe
abed
Abel
Abelian
I am trying to load this file into a dictionary, where using the word are the key values and the keys are actually auto-gen/auto-incremented for each word
e.g {0:10th, 1:1st, 2:2nd} ...etc..etc...
below is the code i've hobbled together so far, it seems to sort of works but its only showing me the last entry in the file as the only dict pair element
f3data = open('words')
mydict = {}
for line in f3data:
print line.strip()
cmyline = line.split()
key = +1
mydict [key] = cmyline
print mydict
key = +1
+1 is the same thing as 1. I assume you meant key += 1. I also can't see a reason why you'd split each line when there's only one item per line.
However, there's really no reason to do the looping yourself.
with open('words') as f3data:
mydict = dict(enumerate(line.strip() for line in f3data))
dict(enumerate(x.rstrip() for x in f3data))
But your error is key += 1.
f3data = open('words')
print f3data.readlines()
The use of zero-based numeric keys in a dict is very suspicious. Consider whether a simple list would suffice.
Here is an example using a list comprehension:
>>> mylist = [word.strip() for word in open('/usr/share/dict/words')]
>>> mylist[1]
'A'
>>> mylist[10]
"Aaron's"
>>> mylist[100]
"Addie's"
>>> mylist[1000]
"Armand's"
>>> mylist[10000]
"Loyd's"
I use str.strip() to remove whitespace and newlines, which are present in /usr/share/dict/words. This may not be necessary with your data.
However, if you really need a dictionary, Python's enumerate() built-in function is your friend here, and you can pass the output directly into the dict() function to create it:
>>> mydict = dict(enumerate(word.strip() for word in open('/usr/share/dict/words')))
>>> mydict[1]
'A'
>>> mydict[10]
"Aaron's"
>>> mydict[100]
"Addie's"
>>> mydict[1000]
"Armand's"
>>> mydict[10000]
"Loyd's"
With keys that dense, you don't want a dict, you want a list.
with open('words') as fp:
data = map(str.strip, fp.readlines())
But if you really can't live without a dict:
with open('words') as fp:
data = dict(enumerate(X.strip() for X in fp))
{index: x.strip() for index, x in enumerate(open('filename.txt'))}
This code uses a dictionary comprehension and the enumerate built-in, which takes an input sequence (in this case, the file object, which yields each line when iterated through) and returns an index along with the item. Then, a dictionary is built up with the index and text.
One question: why not just use a list if all of your keys are integers?
Finally, your original code should be
f3data = open('words')
mydict = {}
for index, line in enumerate(f3data):
cmyline = line.strip()
mydict[index] = cmyline
print mydict
Putting the words in a dict makes no sense. If you're using numbers as keys you should be using a list.
from __future__ import with_statement
with open('words.txt', 'r') as f:
lines = f.readlines()
words = {}
for n, line in enumerate(lines):
words[n] = line.strip()
print words
Really been struggling with this one for some time now, i have many text files with a specific format from which i need to extract all the data and file into different fields of a database. The struggle is tweaking the parameters for parsing, ensuring i get all the info correctly.
the format is shown below:
WHITESPACE HERE of unknown length.
K PA DETAILS
2 4565434 i need this sentace as one DB record
2 4456788 and this one
5 4879870 as well as this one, content will vary!
X Max - there sometimes is a line beginning with 'Max' here which i don't need
There is a Line here that i do not need!
WHITESPACE HERE of unknown length.
The tough parts were 1) Getting rid of whitespace, and 2)defining the fields from each other, see my best attempt, below:
dict = {}
XX = (open("XX.txt", "r")).readlines()
for line in XX:
if line.isspace():
pass
elif line.startswith('There is'):
pass
elif line.startswith('Max', 2):
pass
elif line.startswith('K'):
pass
else:
for word in line.split():
if word.startswith('4'):
tmp_PA = word
elif word == "1" or word == "2" or word == "3" or word == "4" or word == "5":
tmp_K = word
else:
tmp_DETAILS = word
cu.execute('''INSERT INTO bugInfo2 (pa, k, details) VALUES(?,?,?)''',(tmp_PA,tmp_K,tmp_DETAILS))
At the minute, i can pull the K & PA fields no problem using this, however my DETAILS is only pulling one word, i need the entire sentance, or at least 25 chars of it.
Thanks very much for reading and I hope you can help! :)
K
You are splitting the whole line into words. You need to split into first word, second word and the rest. Like line.split(None, 2).
It would probably use regular expressions. And use the oposite logic, that is if it starts with number 1 through 5, use it, otherwise pass. Like:
pattern = re.compile(r'([12345])\s+\(d+)\s+\(.*\S)')
f = open('XX.txt', 'r') # No calling readlines; lazy iteration is better
for line in f:
m = pattern.match(line)
if m:
cu.execute('''INSERT INTO bugInfo2 (pa, k, details) VALUES(?,?,?)''',
(m.group(2), m.group(1), m.group(3)))
Oh, and of course, you should be using prepared statement. Parsing SQL is orders of magnitude slower than executing it.
If I understand correctly your file format, you can try this script
filename = 'bug.txt'
f = file(filename,'r')
foundHeaders = False
records = []
for rawline in f:
line = rawline.strip()
if not foundHeaders:
tokens = line.split()
if tokens == ['K','PA','DETAILS']:
foundHeaders = True
continue
else:
tokens = line.split(None,2)
if len(tokens) != 3:
break
try:
K = int(tokens[0])
PA = int(tokens[1])
except ValueError:
break
records.append((K,PA,tokens[2]))
f.close()
for r in records:
print r # replace this by your DB insertion code
This will start reading the records when it encounters the header line, and stop as soon as the format of the line is no longer (K,PA,description).
Hope this helps.
Here is my attempt using re
import re
stuff = open("source", "r").readlines()
whitey = re.compile(r"^[\s]+$")
header = re.compile(r"K PA DETAILS")
juicy_info = re.compile(r"^(?P<first>[\d])\s(?P<second>[\d]+)\s(?P<third>.+)$")
for line in stuff:
if whitey.match(line):
pass
elif header.match(line):
pass
elif juicy_info.match(line):
result = juicy_info.search(line)
print result.group('third')
print result.group('second')
print result.group('first')
Using re I can pull the data out and manipulate it on a whim. If you only need the juicy info lines, you can actually take out all the other checks, making this a REALLY concise script.
import re
stuff = open("source", "r").readlines()
#create a regular expression using subpatterns.
#'first, 'second' and 'third' are our own tags ,
# we could call them Adam, Betty, etc.
juicy_info = re.compile(r"^(?P<first>[\d])\s(?P<second>[\d]+)\s(?P<third>.+)$")
for line in stuff:
result = juicy_info.search(line)
if result:#do stuff with data here just use the tag we declared earlier.
print result.group('third')
print result.group('second')
print result.group('first')
import re
reg = re.compile('K[ \t]+PA[ \t]+DETAILS[ \t]*\r?\n'\
+ 3*'([1-5])[ \t]+(\d+)[ \t]*([^\r\n]+?)[ \t]*\r?\n')
with open('XX.txt') as f:
mat = reg.search(f.read())
for tripl in ((2,1,3),(5,4,6),(8,7,9)):
cu.execute('''INSERT INTO bugInfo2 (pa, k, details) VALUES(?,?,?)''',
mat.group(*tripl)
I prefer to use [ \t] instead of \s because \s matches the following characters:
blank , '\f', '\n', '\r', '\t', '\v'
and I don't see any reason to use a symbol representing more that what is to be matched, with risks to match erratic newlines at places where they shouldn't be
Edit
It may be sufficient to do:
import re
reg = re.compile(r'^([1-5])[ \t]+(\d+)[ \t]*([^\r\n]+?)[ \t]*$',re.MULTILINE)
with open('XX.txt') as f:
for mat in reg.finditer(f.read()):
cu.execute('''INSERT INTO bugInfo2 (pa, k, details) VALUES(?,?,?)''',
mat.group(2,1,3)
The text file contains two columns- index number(5 spaces) and characters(30 spaces).
It is arranged in lexicographic order. I want to perform binary search to search for the keyword.
Here's an interesting way to do it with Python's built-in bisect module.
import bisect
import os
class Query(object):
def __init__(self, query, index=5):
self.query = query
self.index = index
def __lt__(self, comparable):
return self.query < comparable[self.index:]
class FileSearcher(object):
def __init__(self, file_pointer, record_size=35):
self.file_pointer = file_pointer
self.file_pointer.seek(0, os.SEEK_END)
self.record_size = record_size + len(os.linesep)
self.num_bytes = self.file_pointer.tell()
self.file_size = (self.num_bytes // self.record_size)
def __len__(self):
return self.file_size
def __getitem__(self, item):
self.file_pointer.seek(item * self.record_size)
return self.file_pointer.read(self.record_size)
if __name__ == '__main__':
with open('data.dat') as file_to_search:
query = raw_input('Query: ')
wrapped_query = Query(query)
searchable_file = FileSearcher(file_to_search)
print "Located # line: ", bisect.bisect(searchable_file, wrapped_query)
Do you need do do a binary search? If not, try converting your flatfile into a cdb (constant database). This will give you very speedy hash lookups to find the index for a given word:
import cdb
# convert the corpus file to a constant database one time
db = cdb.cdbmake('corpus.db', 'corpus.db_temp')
for line in open('largecorpus.txt', 'r'):
index, word = line.split()
db.add(word, index)
db.finish()
In a separate script, run queries against it:
import cdb
db = cdb.init('corpus.db')
db.get('chaos')
12345
If you need to find a single keyword in a file:
line_with_keyword = next((line for line in open('file') if keyword in line),None)
if line_with_keyword is not None:
print line_with_keyword # found
To find multiple keywords you could use set() as #kriegar suggested:
def extract_keyword(line):
return line[5:35] # assuming keyword starts on 6 position and has length 30
with open('file') as f:
keywords = set(extract_keyword(line) for line in f) # O(n) creation
if keyword in keywords: # O(1) search
print(keyword)
You could use dict() above instead of set() to preserve index information.
Here's how you could do a binary search on a text file:
import bisect
lines = open('file').readlines() # O(n) list creation
keywords = map(extract_keyword, lines)
i = bisect.bisect_left(keywords, keyword) # O(log(n)) search
if keyword == keywords[i]:
print(lines[i]) # found
There is no advantage compared to the set() variant.
Note: all variants except the first one load the whole file in memory. FileSearcher() suggested by #Mahmoud Abdelkader don't require to load the whole file in memory.
I wrote a simple Python 3.6+ package that can do this. (See its github page for more information!)
Installation: pip install binary_file_search
Example file:
1,one
2,two_a
2,two_b
3,three
Usage:
from binary_file_search.BinaryFileSearch import BinaryFileSearch
with BinaryFileSearch('example.file', sep=',', string_mode=False) as bfs:
# assert bfs.is_file_sorted() # test if the file is sorted.
print(bfs.search(2))
Result: [[2, 'two_a'], [2, 'two_b']]
It is quite possible, with a slight loss of efficiency to perform a binary search on a sorted text file with records of unknown length, by repeatedly bisecting the range, and reading forward past the line terminator. Here's what I do to look for look thru a csv file with 2 header lines for a numeric in the first field. Give it an open file, and the first field to look for. It should be fairly easy to modify this for your problem. A match on the very first line at offset zero will fail, so this may need to be special-cased. In my circumstance, the first 2 lines are headers, and are skipped.
Please excuse my lack of polished python below. I use this function, and a similar one, to perform GeoCity Lite latitude and longitude calculations directly from the CSV files distributed by Maxmind.
Hope this helps
========================================
# See if the input loc is in file
def look1(f,loc):
# Compute filesize of open file sent to us
hi = os.fstat(f.fileno()).st_size
lo=0
lookfor=int(loc)
# print "looking for: ",lookfor
while hi-lo > 1:
# Find midpoint and seek to it
loc = int((hi+lo)/2)
# print " hi = ",hi," lo = ",lo
# print "seek to: ",loc
f.seek(loc)
# Skip to beginning of line
while f.read(1) != '\n':
pass
# Now skip past lines that are headers
while 1:
# read line
line = f.readline()
# print "read_line: ", line
# Crude csv parsing, remove quotes, and split on ,
row=line.replace('"',"")
row=row.split(',')
# Make sure 1st fields is numeric
if row[0].isdigit():
break
s=int(row[0])
if lookfor < s:
# Split into lower half
hi=loc
continue
if lookfor > s:
# Split into higher half
lo=loc
continue
return row # Found
# If not found
return False
Consider using a set instead of a binary search for finding a keyword in your file.
Set:
O(n) to create, O(1) to find, O(1) to insert/delete
If your input file is separated by a space then:
f = open('file')
keywords = set( (line.strip().split(" ")[1] for line in f.readlines()) )
f.close()
my_word in keywords
<returns True or False>
Dictionary:
f = open('file')
keywords = dict( [ (pair[1],pair[0]) for pair in [line.strip().split(" ") for line in f.readlines()] ] )
f.close()
keywords[my_word]
<returns index of my_word>
Binary Search is:
O(n log n) create, O(log n) lookup
edit: for your case of 5 characters and 30 characters you can just use string slicing
f = open('file')
keywords = set( (line[5:-1] for line in f.readlines()) )
f.close()
myword_ in keywords
or
f = open('file')
keywords = dict( [(line[5:-1],line[:5]) for line in f.readlines()] )
f.close()
keywords[my_word]