I was practicing using the pygame package in python by making a graphics oriented game and in my game, I want to switch between multiple backgrounds as the user progresses through it. For the example I am posting, the first background will be a black screen with 5 statements on it and my second background will be a room. However, I am unable to figure this out because whenever I try to run the code, the game window doesn't show anything. I can post my code for the while loop below for further clarification.
while running:
screen.fill((0, 0, 0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
first_line()
second_line()
third_line_1()
third_line_2()
fourth_line()
fifth_line()
sleep(10)
screen.blit(background_room, (0, 0))
pygame.display.update()
The way I would probably do it is something like
import pygame
from pygame.locals import *
class Backround:
FIVE_STATEMENTS = 0
ROOM = 1
viewport_size = (800, 600)
def main():
pygame.init()
screen = pygame.display.set_mode(viewport_size)
backround_room = pygame.Surface(viewport_size)
# load the image...
backround_statements = pygame.Surface(viewport_size)
backround_statements.fill((0, 0, 0))
# blit the five statements onto here
backround_to_render = Backround.FIVE_STATEMENTS
running = True
while running:
for event in pygame.event.get():
if event.type == QUIT:
running = False
if backround_to_render == Backround.FIVE_STATEMENTS:
# if the statements ever change, probably want to fill() and re-blit them on
screen.blit(backround_statements, (0,0))
elif backround_to_render == Backround.ROOM:
screen.blit(backround_room, (0,0))
else:
print("Oh no!!!!!!!")
pygame.display.flip()
if __name__ == "__main__":
main()
Related
I tried to use python to display image:
import pygame
win = pygame.display.set_mode((500, 500))
DisplayImage("Prologue.jpg", win)
And when it runs, nothing happened. It also happened for
DisplayImage("Streets.jpg", win)
However, when I tried the exact same thing later on in the code, it ran perfectly.
I checked, the picture was in the same folder as the .py file, and I didn't type the name wrong.
The function is:
def DisplayImage(imageName, screen):
screen.fill((0, 0, 0))
Image = pygame.image.load(imageName).convert()
screen_rect = screen.get_rect()
Image_rect = Image.get_rect().fit(screen_rect)
Image = pygame.transform.scale(Image, Image_rect.size)
screen.blit(Image, [0, 0])
pygame.display.update()
Update:
I commented out all of the lines and copy and pasted that line out so it's the only line that runs. It runs perfectly.
Update 2:
Found the issue. The reason it doesn't work was that the pygame window was "not responding". I don't know what caused it to not respond, but in one of the test runs I didn't make it show "not responding", and the images were loaded fine. The "not responding" always shows up when I type in my player name, and the function looks like this:
def createName():
playerName = input("Enter the player name\n")
desiredName = input("Is "+playerName+" the desired name?[1]Yes/[2]No\n")
if desiredName == "1":
return playerName
elif desiredName == "2":
playerName = createName()
Sometimes when I type the player name nothing happens, and the letters only show up after a while. If this happens, the pygame window is bound to not respond.
You cannot use input in the application loop. input waits for an input. While the system is waiting for input, the application loop will halt and the game will not respond.
Use the KEYDOWN event instead of input:
run = True
while run:
event_list = pygame.event.get()
for event in event_list:
if event.type == pygame.QUIT:
run = False
if event.type == pygame.KEYDOWN:
if pygame.key == pygame.K_1:
# [...]
if pygame.key == pygame.K_2:
# [...]
Another option is to get the input in a separate thread.
Minimal example:
import pygame
import threading
pygame.init()
window = pygame.display.set_mode((400, 400))
clock = pygame.time.Clock()
color = "red"
def get_input():
global color
color = input('enter color (e.g. blue): ')
input_thread = threading.Thread(target=get_input)
input_thread.start()
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
window_center = window.get_rect().center
window.fill(0)
pygame.draw.circle(window, color, window_center, 100)
pygame.display.flip()
pygame.quit()
exit()
I tried to use python to display image:
import pygame
win = pygame.display.set_mode((500, 500))
DisplayImage("Prologue.jpg", win)
And when it runs, nothing happened. It also happened for
DisplayImage("Streets.jpg", win)
However, when I tried the exact same thing later on in the code, it ran perfectly.
I checked, the picture was in the same folder as the .py file, and I didn't type the name wrong.
The function is:
def DisplayImage(imageName, screen):
screen.fill((0, 0, 0))
Image = pygame.image.load(imageName).convert()
screen_rect = screen.get_rect()
Image_rect = Image.get_rect().fit(screen_rect)
Image = pygame.transform.scale(Image, Image_rect.size)
screen.blit(Image, [0, 0])
pygame.display.update()
Update:
I commented out all of the lines and copy and pasted that line out so it's the only line that runs. It runs perfectly.
Update 2:
Found the issue. The reason it doesn't work was that the pygame window was "not responding". I don't know what caused it to not respond, but in one of the test runs I didn't make it show "not responding", and the images were loaded fine. The "not responding" always shows up when I type in my player name, and the function looks like this:
def createName():
playerName = input("Enter the player name\n")
desiredName = input("Is "+playerName+" the desired name?[1]Yes/[2]No\n")
if desiredName == "1":
return playerName
elif desiredName == "2":
playerName = createName()
Sometimes when I type the player name nothing happens, and the letters only show up after a while. If this happens, the pygame window is bound to not respond.
You cannot use input in the application loop. input waits for an input. While the system is waiting for input, the application loop will halt and the game will not respond.
Use the KEYDOWN event instead of input:
run = True
while run:
event_list = pygame.event.get()
for event in event_list:
if event.type == pygame.QUIT:
run = False
if event.type == pygame.KEYDOWN:
if pygame.key == pygame.K_1:
# [...]
if pygame.key == pygame.K_2:
# [...]
Another option is to get the input in a separate thread.
Minimal example:
import pygame
import threading
pygame.init()
window = pygame.display.set_mode((400, 400))
clock = pygame.time.Clock()
color = "red"
def get_input():
global color
color = input('enter color (e.g. blue): ')
input_thread = threading.Thread(target=get_input)
input_thread.start()
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
window_center = window.get_rect().center
window.fill(0)
pygame.draw.circle(window, color, window_center, 100)
pygame.display.flip()
pygame.quit()
exit()
I wanted to do something after a period of time. On stack overflow I found a question that helps solve that, (Link) but when I run the program the code works, however it goes away after a millisecond. Whereas I want it to stay there after the amount of time I want it to wait. In this case for a test run I am blitting some text onto the screen. Here is the code:
import pygame
# Importing the modules module.
pygame.init()
# Initializes Pygame
SCREEN_WIDTH = 800
SCREEN_HEIGHT = 600
screen = pygame.display.set_mode((800, 600))
# Sets the screen to pygame looks and not normal python looks.
pygame.display.set_caption("Test Run")
# Changes the title
# Heading
headingfont = pygame.font.Font('Bouncy-PERSONAL_USE_ONLY.otf', 45)
headingX = 230
headingY = 10
class Other():
def show_heading():
Heading = headingfont.render("Health Run!", True, (255, 255, 255))
screen.blit(Heading, (headingX, headingY))
pygame.time.set_timer(pygame.USEREVENT, 100)
running = True
while running:
screen.fill((0,0,0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.USEREVENT:
Other.show_heading()
#Update Display
pygame.display.update()
If you want to draw the text permanently, you need to draw it in the application loop. Set a Boolean variable "draw_text" when the timer event occurs. Draw the text depending on draw_text in the application loop:
draw_text = False
running = True
while running:
screen.fill((0,0,0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.USEREVENT:
draw_text = True
if draw_text:
Other.show_heading()
#Update Display
pygame.display.update()
For more information about timers and timer events, see Spawning multiple instances of the same object concurrently in python, How can I show explosion image when collision happens? or Adding a particle effect to my clicker game and many more.
I'm completely new to Python and I just started learning Pygame. I'm trying to work with drawing shapes right now, but I can't get the window to open. Idk what the problem is, here's my code:
`#import libraries
import pygame
import math
#init pygame
pygame.init()
#clock
clock = pygame.time.Clock()
#window screen
screen_height_x = 500
screen_height_y = 400
screen = pygame.display.set_mode((screen_height_x, screen_height_y))
#RGBA colors
Black = (0, 0, 0)
White = (255, 255, 255)
Blue = (0, 0, 255)
Red = (255, 0, 0)
Green = (0, 255, 0)
#program
running = True
while running:
for event in pygame.event.get():
running = False
screen.fill(Black)
pygame.display.update()
clock.tick(30)
#Quit
pygame.quit()
quit()`
You're immediately quitting the main loop and you also aren't drawing anything. Try this instead:
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
screen.fill(Black)
pygame.display.update()
clock.tick(30)
#Quit
pygame.quit()
quit()
Disclaimer: I cannot try this out at the moment but it should get you started in the right direction.
Is this a class part of the projet or the main class ? If it is the main class, you it should contain a main function.
If this is the main function, you should declare it by adding def main(): before the pygame.init()
And add the module to exectute this as the main script under Quit
if __name__ == "__main__":
main()
Sorry, im french my english is not the best aha !
I am in a beginner python class and we are working on our final projects. For my game however I wanted to be able to restart the game within itself. I did this by using imports to launch a new script to then re-run my game. However whenever I try to do it more than once my window breaks, or the code does not import the next file. My game is kinda long so I've created a very short program to give an example of my issue.
(This being the file yin.py)
import pygame
BLACK = (0, 0, 0)
pygame.init()
SIZE = [300, 300]
screen = pygame.display.set_mode(SIZE)
clock = pygame.time.Clock()
done = False
while not done:
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
if event.type == pygame.MOUSEBUTTONDOWN:
import yang
done = True
screen.fill(BLACK)
pygame.display.flip()
clock.tick(30)
pygame.quit()
(and this file yang.py)
import pygame
WHITE = (255, 255, 255)
pygame.init()
SIZE = [300, 300]
screen = pygame.display.set_mode(SIZE)
clock = pygame.time.Clock()
done = False
while not done:
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
if event.type == pygame.MOUSEBUTTONDOWN:
import yin
done = True
screen.fill(WHITE)
pygame.display.flip()
clock.tick(30)
pygame.quit()
I've tried doing multiple things but so far I have gotten nowhere, it still is giving me display not initialized even though I have 'pygame.init()'. My teacher isn't responding to my emails and I have an encroaching deadline. Any help will be appreciated. :p
The "import" statement only imports once. If the name already exists, it doesn't import again. You should put your code into a function. Then, you can call the function as many times as you want.