Output matplotlib plots from saving - python

I found a tutorial online for this matplotlib and numpy graph. The code runs smoothly, but there is no output. I have tried to save the graph as a file, but that does not seem to work.
import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits import mplot3d
fig = plt.figure()
ax = plt.axes(projection="3d")
zline = np.linspace(0, 15, 1000)
xline = np.sin(zline)
yline = np.cos(zline)
ax.plot3D(xline, yline, zline, "gray") # Data for three-dimensional scattered points
zdata = 15 * np.random.random(100)
xdata = np.sin(zdata) + 0.1 * np.random.randn(100)
ydata = np.cos(zdata) + 0.1 * np.random.randn(100)
ax.scatter3D(xdata, ydata, zdata, c=zdata, cmap="Greens");
def f(x, y):
return np.sin(np.sqrt(x ** 2 + y ** 2))
x = np.linspace(-6, 6, 30)
y = np.linspace(-6, 6, 30)
X, Y = np.meshgrid(x, y)
Z = f(X, Y)
fig = plt.figure()
ax = plt.axes(projection='3d')
ax.contour3D(X, Y, Z, 50, cmap='binary')
ax.set_xlabel('x')
ax.set_ylabel('y')
ax.set_zlabel('z');
theta = 2 * np.pi * np.random.random(1000)
r = 6 * np.random.random(1000)
x = np.ravel(r * np.sin(theta))
y = np.ravel(r * np.cos(theta))
z = f(x, y)
ax = plt.axes(projection="3d")
ax.plot_trisurf(x, y, z,cmap="viridis", edgecolor="none");
The link to the website is https://www.edureka.co/blog/python-projects/. Surely there is some way to access the graphical user interface to display the plots?

Adding plt.show() at the end will display both of the graphs.

Related

Clip a contourf() plot in 3D plot

I'm making multiple density plots in 3D with a circle shape, using contourf.
What I want to do is similar to a clip_path for a pcolormesh plot.
How can I clip the plot in 3D in particular for a contourf plot?
from mpl_toolkits.mplot3d import Axes3D
import numpy as np
import matplotlib.pyplot as plt
from matplotlib.path import Path
import matplotlib.patches as patches
fig = plt.figure()
ax = fig.gca(projection='3d')
x = np.linspace(0, 1, 100)
X, Y = np.meshgrid(x, x)
levels = np.linspace(-0.1, 0.4, 100) #(z_min,z_max,number of contour),
a=0
b=1
c=2
Z1 = a+.1*np.sin(2*X)*np.sin(4*Y)
Z2 = b+.1*np.sin(3*X)*np.sin(4*Y)
Z3 = c+.1*np.sin(4*X)*np.sin(5*Y)
plt.contourf(X, Y,Z1, levels=a+levels,cmap=plt.get_cmap('rainbow'))
plt.contourf(X, Y,Z2, levels=b+levels,cmap=plt.get_cmap('rainbow'))
plt.contourf(X, Y,Z3, levels=c+levels,cmap=plt.get_cmap('rainbow'))
ax.set_xlim3d(0, 1)
ax.set_ylim3d(0, 1)
ax.set_zlim3d(0, 2)
plt.show()
Are you sure your code generated that output image with the given parameters? I only got some blue squares. Tweaking a bit, it starts looking like yours.
To clip the contours, consider masking the Z arrays. As in:
from mpl_toolkits.mplot3d import Axes3D
import numpy as np
import matplotlib.pyplot as plt
import numpy.ma as ma
fig = plt.figure()
ax = fig.gca(projection='3d')
x = np.linspace(0, 1, 100)
X, Y = np.meshgrid(x, x)
levels = np.linspace(-0.1, 0.4, 100) #(z_min,z_max,number of contour),
a = 0
b = 1
c = 2
Z1 = a + .3 * np.sin(2 * X) * np.sin(4 * Y)
Z2 = b + .3 * np.sin(3 * X) * np.sin(4 * Y)
Z3 = c + .3 * np.sin(4 * X) * np.sin(5 * Y)
mask_cond = (X - .5) ** 2 + (Y - .5) ** 2 > .25
Z1 = ma.masked_where(mask_cond, Z1)
Z2 = ma.masked_where(mask_cond, Z2)
Z3 = ma.masked_where(mask_cond, Z3)
plt.contourf(X, Y, Z1, levels=a + levels, cmap='rainbow')
plt.contourf(X, Y, Z2, levels=b + levels, cmap='rainbow')
plt.contourf(X, Y, Z3, levels=c + levels, cmap='rainbow')
ax.set_xlim3d(0, 1)
ax.set_ylim3d(0, 1)
ax.set_zlim3d(0, 3)
plt.show()

How do I add cartesian axes to a polar plot in matplotlib?

I have a polar contour plot, and I want to add cartesian axes to it. How can I do this? There seems to be no documentation for this.
import numpy as np
import matplotlib.pyplot as plt
def f(x, y):
return np.sin(x) ** 10 + np.cos(10 + y * x) * np.cos(x)
x = np.linspace(0, 8, 50)
y = np.linspace(0, 8, 40)
X, Y = np.meshgrid(x, y)
Z = f(X, Y)
fig, ax = plt.subplots(subplot_kw = dict(projection = 'polar'))
plt.axis('off')
ax.contourf(X, Y, Z)
To add cartesian axes to a polar plot, all you have to do is add a second pair of axes at the same position like so:
import numpy as np
import matplotlib.pyplot as plt
def f(x, y):
return np.sin(x) ** 10 + np.cos(10 + y * x) * np.cos(x)
x = np.linspace(0, 8, 50)
y = np.linspace(0, 8, 40)
X, Y = np.meshgrid(x, y)
Z = f(X, Y)
fig, ax = plt.subplots(subplot_kw = dict(projection = 'polar'))
plt.axis('off')
ax.contourf(X, Y, Z)
new_axis = fig.add_axes(ax.get_position(), frameon = False)
new_axis.plot()
plt.show()

How to plot a vector field using Numpy?

The idea is to plot the following vector field:
I have two main issue with it:
1) I do not know how to make sure that the arrows are not too long (I know I have to use length, but how?).
2) I am told to use Numpyto draw the vector field but again, how?
This is what I have tried:
# The components of the vector field
F_x = y*e**x
F_y = x**2 + e**x
F_z = z**2*e**z
# The grid
xf = np.linspace(-0.15, 2.25, 8)
yf = np.linspace(-0.15, 2.25, 8)
zf = np.linspace(-0.75, 2.50, 8)
X_grid, Y_grid, Z_grid = np.meshgrid(xf, yf, zf)
# The arrows; how to deal with them?
dx = 1
#dy = ...
#dz = ...
# Standardize the arrows; In this way all arrows have the same length.
length = np.sqrt(dx**2 + dy**2 + dz**2)
dx_N = dx/length
dy_N = dy/length
dz_N = dz/length
#how to involve numpy in the process??
# Drawing the figure
fig, ax = plt.subplots(1, 1)
ax.quiver(X_grid, Y_grid, Z_grid, dx_N, dy_N, dz_N, dy, dz, cmap=plt.get_cmap('gnuplot2'))
plt.show()
Thanks
EDIT
Based on the provided link I tried:
from sympy import *
x,y,z = sp.symbols('x y z', real = True)
import matplotlib.pyplot as plt
x, y, z = np.meshgrid(np.arange(0, 2 * np.pi, .2), np.arange(0, 2 * np.pi, .2), np.arange(0, 2 * np.pi, .2))
F_x = y * exp(x)
F_y = x**2 + exp(x)
F_z = z**2 * exp(z)
# Normalize the arrows:
F_x = F_x / np.sqrt(F_x**2 + F_y**2 + F_z**2)
F_y = F_y / np.sqrt(F_x**2 + F_y**2 + F_z**2)
F_z = F_z / np.sqrt(F_x**2 + F_y**2 + F_z**2)
plt.figure()
plt.title('Vector field')
Q = plt.quiver(x, y, z, F_x, F_y, F_z, units='width')
qk = plt.quiverkey(Q, 0.9, 0.9, 2, r'$2 \frac{m}{s}$', labelpos='E',
coordinates='figure')#I don't understand this line
The TypeError: Shape should contain integers only comes up.
The problem is that I don't understand this part of the code:
qk = plt.quiverkey(Q, 0.9, 0.9, 2, r'$2 \frac{m}{s}$', labelpos='E',
coordinates='figure')
I am still stuck on how to plot this vector field
Assume that you want a 3D quiver, you can check out the matplotlib tutorial on quiver3D. And to control the arrow size, check out the Axes3d.quiver library doc, especially the parameters.
A quick snippet:
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
x, y, z = np.meshgrid(np.arange(0, 2*np.pi, .5), np.arange(0, 2*np.pi, .5), np.arange(0, 2*np.pi, .5))
F_x = y * np.exp(x)
F_y = x**2 + np.exp(x)
F_z = z**2 * np.exp(z)
fig = plt.figure()
ax = fig.gca(projection='3d')
Q = ax.quiver(x, y, z, F_x, F_y, F_z, length=0.3, normalize=True)
But 3d quiver plot can be very crowded! : )
The quiver() method is a great tool to render vector fields. Since Matplotlib is a two-dimensional plotting library, we need to import the mplot3d toolkit to generate a three-dimensional plot.
Here's a good example:
Dependencies:
Axes3D for 3D rendering
Pyplot to get a MATLAB-like plotting framework
Numpy for numeric-array manipulation
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
x, y, z = np.meshgrid(np.arange(-0.8, 1, 0.25),
np.arange(-0.8, 1, 0.25),
np.arange(-0.8, 1, 0.8))
u = np.sin(np.pi * x) * np.cos(np.pi * y) * np.cos(np.pi * z)
v = -np.cos(np.pi * x) * np.sin(np.pi * y) * np.cos(np.pi * z)
w = (np.sqrt(2.0 / 3.0) * np.cos(np.pi * x) * np.cos(np.pi * y) * np.sin(np.pi * z))
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.quiver(x, y, z, u, v, w,
length=0.15,
color='Purple'
)
ax.view_init(elev=10, azim=30)
ax.dist=8
plt.show()

Matplotlib animation save does not create animation for surface plots

I am trying to use matplotlib.animation to animate the time evolution of a surface. A working example is found on this stackexchange question/answer. Using plt.show() I can see the animation fine. The problem is when I try to save it. When saving as either a gif or mp4 I get only one from of the animation. I do not get this problem if I am doing 1d animations, for example using plt.plot(). Below is what I am trying:
from mpl_toolkits.mplot3d import axes3d
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.animation as animation
from matplotlib import cm
def generate(X, Y, phi):
R = 1 - np.sqrt(X**2 + Y**2)
return np.cos(2 * np.pi * X + phi) * R
fig = plt.figure()
ax = axes3d.Axes3D(fig)
xs = np.linspace(-1, 1, 50)
ys = np.linspace(-1, 1, 50)
X, Y = np.meshgrid(xs, ys)
Z = generate(X, Y, 0.0)
wframe = ax.plot_surface(X, Y, Z, rstride=2, cstride=2, cmap=cm.coolwarm )
ax.set_zlim(-1,1)
def update(i, ax, fig):
ax.cla()
phi = i * 360 / 2 / np.pi / 100
Z = generate(X, Y, phi)
wframe = ax.plot_surface( X, Y, Z, rstride=2,
cstride=2, cmap=cm.coolwarm )
ax.set_zlim(-1,1)
return wframe,
ani = animation.FuncAnimation( fig, update, frames=10,
fargs=(ax, fig), interval=100 )
ani.save('plottest3d2.mp4', fps=30)
ani.save('plottest3d3.gif', fps=30, writer='imagemagick')
plt.show()
Any help explaining the discrepancy between showing the plot and saving would be great.

Beginner-Make a frame based video in python from figures

I plot figures in a for loop which is a loop for my time, basically at each time step I plot a surf out of my data as below:
for time_step in range(0,nt):
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
x = np.arange(xmin, xmax+dx, dx)
z = np.arange(zmin, zmax+dz, dz)
X, Z = np.meshgrid(x, z)
ax.plot_surface(X, Z, w1[time_step])
plt.show()
Suppose that w1[time_step] changes in the loop and is sth different at each time step, all other assumptions you can have. I plot but don't know only how to make them into a video.
I have done it matlab, but I want to do sth similar in Python
Matplotlib as some animation features you might want to use. Check the following recipe (that I collected from here):
from mpl_toolkits.mplot3d import axes3d
import matplotlib.pyplot as plt
import numpy as np
import time
def generate(X, Y, phi):
R = 1 - np.sqrt(X**2 + Y**2)
return np.cos(2 * np.pi * X + phi) * R
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
xs = np.linspace(-1, 1, 50)
ys = np.linspace(-1, 1, 50)
X, Y = np.meshgrid(xs, ys)
Z = generate(X, Y, 0.0)
wframe = None
tstart = time.time()
for phi in np.linspace(0, 360 / 2 / np.pi, 100):
oldcol = wframe
Z = generate(X, Y, phi)
wframe = ax.plot_wireframe(X, Y, Z, rstride=2, cstride=2)
# Remove old line collection before drawing
if oldcol is not None:
ax.collections.remove(oldcol)
plt.pause(.001)
print('FPS: %f' % (100 / (time.time() - tstart)))
Just replace the wireframe plot for whatever you want (and also use your data obviously) and you should have what you are looking for.

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