While parsing my request data from front-end and converting into JSON format using a serializer. I am getting some unexpected errors.
while request parsing pattern using serializers given as mentioned below, it shows me the following error:(I found the below error using: contact_serializer.errors)
{'address': {u'non_field_errors': [u'Invalid data. Expected a dictionary, but got str.']}}
I do not think it will work like this. You have to remember here is that if you input the values like this, it will ultimately be stored in DB, and it is hard coded values. Even if you insist to do it like this, then use a list of dictionary like this:
request.data['phone_number'] = [{'number': '9999999999'}]
request.data['cont_email'] = [{'email':'tim#gmail.com'}]
And update the serializer like this:
class CrmContactSerializer(serializers.ModelSerializer):
phone_number = PhoneNumberSerializer(source = 'contact_number', many=True)
cont_email = ContactEmailSerializer(source = 'contact_email', many=True)
class Meta:
model = RestaurantContactAssociation
fields = ('id','phone_number','cont_email','contact')
def create(self, validated_data):
phone_number = validated_data.pop('contact_number')
cont_email = validated_data.pop('contact_email')
restaurant = super(CrmContactSerializer, self).create(validated_data)
phone_instance = PhoneNumber(**phone_number)
phone_instance.restaurant = restaurant
phone_instance.save()
email_instance = ContactEmail(**phone_number)
email_instance.restaurant = restaurant
email_instance.save()
return restaurant
Reason for many=True is that one restaurant can have multiple numbers or emails(as it has one to many relationship with respective models).
Now, if you think of proper way of implementing, you can make phone_number and cont_email read only fields, so that it will be used when only reading, not writing:
class CrmContactSerializer(serializers.ModelSerializer):
phone_number = PhoneNumberSerializer(source = 'contact_number', read_only=True)
cont_email = ContactEmailSerializer(source = 'contact_email', read_only=True)
class Meta:
model = RestaurantContactAssociation
fields = ('id','phone_number','cont_email','contact')
In that way, validation error can be handled for phone number and cont email.
Related
I have model of category and need to serialize to give beautiful output.
My model
class Categorie(models.Model):
name = models.CharField(max_length=50)
My serializer
class CategorieSerializer(serializers.ModelSerializer):
class Meta:
model = Categorie
fields = ['name']
My code
class JokesCategories(APIView):
def get(self, request):
categories = Categorie.objects.all()
serializer = CategorieSerializer(categories, many=True)
output_data = {}
for num, dictionary in enumerate(serializer.data):
output_data[num] = dict(dictionary)['name']
return Response(output_data)
I have output
{
"0": "animal",
"1": "career"
}
But need
[
0: "animal",
1: "career"
]
Help for you advices.
You can't. A JSON object always has strings as keys, not integers. This is part of the JSON specifications [json.org]. You can for example use jsonlint to check if a certain text is valid JSON, and the latter is not.
Python's JSON encoder thus will fallback on converting the integers into strings to produce a valid JSON blob. Your dictionary indeed produced integers as keys, but the serializer thus converts it to strings.
Here it however might make more sense to use a list, and not an object, since the keys (indices) start at 0 and are incremental. Using a dictionary/JSON object thus does not make much sense:
class JokesCategories(APIView):
def get(self, request):
categories = Categorie.objects.all()
serializer = CategorieSerializer(categories, many=True)
output_data = [data['name'] for item in serializer.data]
return Response(output_data)
I have a visitorSaveSerializer which is responsible for validating the data to be saved:
class VisitorSaveSerializer(serializers.ModelSerializer):
class Meta:
model = Visitor
fields = ('gsm', 'email', 'firstname', 'lastname')
The problem is:
visitor_serializer = VisitorSaveSerializer(data={...related data here...})
if visitor_serializer.is_valid():
visitor_serializer.save()
visitor_id = visitor.serializer.data.get("id", 0) // Fails for sure.
OK, I know id is not among serializer fields, so last line fails.
How should I approach saving an object when I need to get last inserted id?
The serializer returns the instance saved, so you can obtain the primary key of that instance with:
visitor_serializer = VisitorSaveSerializer(data={…})
if visitor_serializer.is_valid():
visitor = visitor_serializer.save()
visitor_id = visitor.pk
I have a simple search in my Django project. I want to search through documents using their type and part of factory info in addition to search by name.
Here is my models.py:
class Docs(models.Model):
Date = models.DateField(default=date.today)
Name = models.CharField(max_length=50)
Type = models.ForeignKey(DocTypes)
Part = models.ForeignKey(Parts)
Link = models.FileField(upload_to='Docs/%Y/%m/%d')
class Parts(models.Model):
Name = models.CharField(max_length=50)
def __str__(self):
return str(self.Name)
class DocTypes(models.Model):
Type = models.CharField(max_length=50)
def __str__(self):
return str(self.Type)
My forms.py:
class DocsSearchForm(ModelForm):
class Meta:
model = Docs
fields = [ 'Name', 'Type', 'Part']
And this is part of my views.py, if no search was done then all documents are given
def showdocs(request):
if request.method == 'POST':
form = DocsSearchForm(request.POST)
documents = Docs.objects.filter(Name__contains=request.POST['Name']|
Type==request.POST['Type']|
Part==request.POST['Part'])
else:
form = DocsSearchForm()
documents = Docs.objects.all()
return render(
request,
'showdocs.html',
{'documents': documents, 'form':form}
So, the problem is the following: if I try to use a search then I have
NameError at /showdocs
name 'Type' is not defined.
POST values are:Part '1', Name 'Example', Type '1'.
If I delete
Type==request.POST['Type']|
Part==request.POST['Part']
then search by name works well. So I have a guess that problem is about searching by foreign key values, but have no ideas more. Will appreciate any help.
Try replacing the line with this
Docs.objects.filter(Name__contains=request.POST['Name'],
Type=request.POST['Type'],
Part=request.POST['Part']
)
It seems you have misunderstood the syntax. I don't know why you are trying to use | operator here.
That's not how Django filters work. You can't | them because they are not actually expressions, just keyword arguments. In this case, correct syntax would be:
Docs.objects.filter(
Name__contains=request.POST['Name'],
Type_Type=request.POST['Type'],
Part_Name=request.POST['Part'],
)`
I've got an API endpoint called TrackMinResource, which returns the minimal data for a music track, including the track's main artist returned as an ArtistMinResource. Here are the definitions for both:
class TrackMinResource(ModelResource):
artist = fields.ForeignKey(ArtistMinResource, 'artist', full=True)
class Meta:
queryset = Track.objects.all()
resource_name = 'track-min'
fields = ['id', 'artist', 'track_name', 'label', 'release_year', 'release_name']
include_resource_uri = False
cache = SimpleCache(public=True)
def dehydrate(self, bundle):
bundle.data['full_artist_name'] = bundle.obj.full_artist_name()
if bundle.obj.image_url != settings.NO_TRACK_IMAGE:
bundle.data['image_url'] = bundle.obj.image_url
class ArtistMinResource(ModelResource):
class Meta:
queryset = Artist.objects.all()
resource_name = 'artist-min'
fields = ['id', 'artist_name']
cache = SimpleCache(public=True)
def get_resource_uri(self, bundle_or_obj):
return '/api/v1/artist/' + str(bundle_or_obj.obj.id) + '/'
The problem is, the artist field on Track (previously a ForeignKey) is now a model method called main_artist (I've changed the structure of the database somewhat, but I'd like the API to return the same data as it did before). Because of this, I get this error:
{"error": "The model '<Track: TrackName>' has an empty attribute 'artist' and doesn't allow a null value."}
If I take out full=True from the 'artist' field of TrackMinResource and add null=True instead, I get null values for the artist field in the returned data. If I then assign the artist in dehydrate like this:
bundle.data['artist'] = bundle.obj.main_artist()
...I just get the artist name in the returned JSON, rather than a dict representing an ArtistMinResource (along with the associated resource_uris, which I need).
Any idea how to get these ArtistMinResources into my TrackMinResource? I can access an ArtistMinResource that comes out fine using the URL endpoint and asking for it by ID. Is there a function for getting that result from within the dehydrate function for TrackMinResource?
You can use your ArtistMinResource in TrackMinResource's dehydrate like this (assuming that main_artist() returns the object that your ArtistMinResource represents):
artist_resource = ArtistMinResource()
artist_bundle = artist_resource.build_bundle(obj=bundle.obj.main_artist(), request=request)
artist_bundle = artist_resource.full_dehydrate(artist_bundle)
artist_json = artist_resource.serialize(request=request, data=artist_bundle, format='application/json')
artist_json should now contain your full artist representation. Also, I'm pretty sure you don't have to pass the format if you pass the request and it has a content-type header populated.
What is wrong with my code?
class Group(ImageModel):
title = models.CharField(verbose_name = "Title", max_length=7)
photos = models.ManyToManyField('Photo', related_name='+',
verbose_name=_('Photo'),
null=True, blank=True)
.....
pid = Photo.objects.get(image = str_path)
gid= Group.objects.get(id = self.id)
self.save_photos(gid, pid)
....
def save_photos(self, gid, pid):
group_photo = GroupPhotos(groupupload=gid.id,
photo=pid.id
)
group_photo.save()
and my GroupPhotos models is:
class GroupPhotos(models.Model):
groupupload = models.ForeignKey('Group')
photo = models.ForeignKey('Photo')
class Meta:
db_table = u'group_photos'
when i want to save it from admin panel i am getting value error sth like this:
Cannot assign "38": "GroupPhotos.groupupload" must be a "Group" instance.
with group_photo = GroupPhotos(groupupload=gid, photo=pid) defination it is working but there is no any changes in GroupPhotos table(group_photos). printing this print pid.id,' >>> ',gid.id i am getting true relation...
UPDATE:
I have been working since morning, but no progress... i have also tried this but nothing changed:
pid = Photo.objects.get(image = str_path)
ger = Group.objects.get(id = self.id)
ger.title = self.title
ger.save()
ger.photos.add(pid)
The error is here:
group_photo = GroupPhotos(groupupload=gid.id, photo=pid.id)
The arguments to groupupload and photo should be instances of Group and Photo respectively. Try the following:
group_photo = GroupPhotos(groupupload=gid, photo=pid)
In other words, when creating an object you need to pass arguments of the expected type and not an integer (which may be the primary key key of the desired object but it also might not, which is why you need to pass an object of the correct type).
i have solved my problem with adding through option to my manytomanyfield:
photos = models.ManyToManyField('Photo', related_name='+',
verbose_name=_('Photo'),
null=True, blank=True, through=GroupPhotos)
some info about ManyToManyField.through here:
Django will automatically generate a table to manage many-to-many
relationships. However, if you want to manually specify the
intermediary table, you can use the through option to specify the
Django model that represents the intermediate table that you want to
use.
The most common use for this option is when you want to associate extra data with a many-to-many relationship.