How to click on the first google search result with python selenium? - python

I am trying to write program that will click on the first google search link that appears. My code is:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
import time
driver = webdriver.Firefox()
driver.get("https://www.google.com/")
search = driver.find_element_by_name("q")
search.clear()
search.send_keys("bee movie script")
search.send_keys(Keys.RETURN)
time.sleep(3)
assert "No results found." not in driver.page_source
result = driver.find_element_by_xpath('/html/body/div[6]/div[3]/div[8]/div[1]/div[2]/div/div[2]/div[2]/div/div/div[1]/div/div[1]/a/h3')
result.click()
I've tried a variation of things for result, but the automation is unable to find the element. I copied the xpath from inspect element, but I get an error that:
NoSuchElementException: Message: Unable to locate element: /html/body/div[6]/div[3]/div[8]/div[1]/div[2]/div/div[2]/div[2]/div/div/div[1]/div/div[1]/a/h3
Am I doing this html incorrectly and how can I fix it? Thank you.

I found a solution with:
results = driver.find_elements_by_xpath('//div[#class="r"]/a/h3') # finds webresults
results[0].click(). # clicks the first one

You can use the below xpath and css to select the nth link.
xpath:
Using the index
driver.find_element_by_xpath('(//div[#class="r"]/a)[1]').click()
If you want to access the first matching element you can simply use .find_element_xpath and script will pick the first element though there are multiple elements matching with the given locator strategy be it xpath, css or anything.
driver.find_element_by_css_selector("div.r a h3").click()

Related

How do I click on an item on my google search page with Selenium Python?

Good time of the day!
Faced with a seemingly simple problem,
But it’s been a while, and I’m asking for your help.
I work with Selenium on Python and I need to curse about
20 items on google search page by random request.
And I’ll give you an example of the elements below, and the bottom line is, once the elements are revealed,
Google generates new such elements
Problem:
Cannot click on the element. I will need to click on existing and then on new, generated elements in this block: click for open see blocks with element
Tried to click on xpath, having collected all the elements:
xpath = '//*[#id="qmCCY_adG4Sj3QP025p4__16"]/div/div/div[1]/div[4]'
all_elements = driver.find_element(By.XPATH, value=xpath)
for element in all_elements:
element.click()
sleep(2)
Important note!
id xpath has constantly changing and is generated by another on the google side
Tried to click on the class
class="r21Kzd"
Tried to click on the selector:
#qmCCY_adG4Sj3QP025p4__16 > div > div > div > div.wWOJcd > div.r21Kzd
Errors
This is when I try to click using xpath:
Message: no such element: Unable to locate element: {"method":"xpath","selector"://*[#id="vU-CY7u3C8PIrgTuuJH4CQ_9"]/div/div[1]/div[4]}
In other cases, the story is almost the same, the driver does not find the element and cannot click on it. Below I apply a scratch tag on which I need to click
screenshot tags on google search
Thanks for the help!
In case iDjcJe IX9Lgd wwB5gf are a fixed class name values of that element all you need is to use CSS_SELECTOR instead of CLASS_NAME with a correct syntax of CSS Selectors.
So, instead of driver.find_element(By.CLASS_NAME, "iDjcJe IX9Lgd wwB5gf") try using this:
driver.find_element(By.CSS_SELECTOR, ".iDjcJe.IX9Lgd.wwB5gf")
(dots before each class name, no spaces between them)

How to select a g-menu-item in selenium (Python)

I am trying to find news articles related to different web searches within a custom time frame. If someone knows a better way to do this than with selenium then please do tell. I tried to use API's but they are all expensive.
My Code:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Chrome(executable_path=r".\chromedriver.exe")
driver.get("https://www.google.com")
cookie_button = driver.find_element_by_id('L2AGLb')
cookie_button.click()
search_bar = driver.find_element_by_name("q")
search_bar.clear()
search_bar.send_keys("Taylor Swift")
search_bar.send_keys(Keys.RETURN)
news_button = driver.find_element_by_css_selector('[data-hveid="CAEQAw"]')
news_button.click()
tools_button = driver.find_element_by_id('hdtb-tls')
tools_button.click()
recent_button = driver.find_element_by_class_name('KTBKoe')
recent_button.click()
custom_range_button = dashboards_button = driver.find_elements_by_tag_name('g-menu-item')[6]
custom_range_button.click()
driver.close()
I am trying to click this button:
I have tried to select, the span, all parent divs and now the g-menu-item itself, in every case I have received the error:
selenium.common.exceptions.ElementNotInteractableException: Message: element not interactable
I understand this can happen when the element is not visible or can not be clicked but I also tried adding in sleep(2) between each operation, and I can see in the browser that selenium opens that it gets to the point in the image I have sent and then can't find the custom range button ??
In short:
Do you know how I can click this custom range button,
Or do you know how to scrape a lot of news articles from specific dates (without expensive API's)
Those g-menu are special type of tag,
you can locate them using :
//*[name()='g-menu-item']
this xpath will point to all the nodes.
further, I see that you are interested in 6th item.
(//*[name()='g-menu-item'])[6]
in code :
custom_range_button = driver.find_element_by_xpath("(//*[name()='g-menu-item'])[6]")
custom_range_button.click()

Unable to find element by any means

I'm kinda of a newbie in Selenium, started learning it for my job some time ago. Right now I'm working with a code that will open the browser, enter the specified website, put the products ID in the search box, search, and them open it. Once it opens the product, it needs to extract its name and price and write it in a CSV file. I'm kinda struggling with it a bit.
The main problem right now is that Selenium is unable to open the product after searching it. I've tried by ID, name and class and it still didn't work.
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
import csv
driver = webdriver.Firefox()
driver.get("https://www.madeiramadeira.com.br/")
assert "Madeira" in driver.title
elem = driver.find_element_by_id("input-autocomplete")
elem.clear()
elem.send_keys("525119")
elem.send_keys(Keys.RETURN)
product_link = driver.find_element_by_id('variant-url').click()
The error I get is usually this:
NoSuchElementException: Message: Unable to locate element: [id="variant-url"]
There are multiple elements with the id="variant-url", So you could use the index to click on the desired element, Also you need to handle I think the cookie pop-Up. Check the below code, hope it will help
#Disable the notifications window which is displayed on the page
option = Options()
option.add_argument("--disable-notifications")
driver = webdriver.Chrome(r"Driver_Path",chrome_options=option)
driver.get("https://www.madeiramadeira.com.br/")
assert "Madeira" in driver.title
elem = driver.find_element_by_id("input-autocomplete")
elem.clear()
elem.send_keys("525119")
elem.send_keys(Keys.RETURN)
#Clicked on the cookie popup button
accept= driver.find_element_by_xpath("//button[#id='lgpd-button-agree']")
accept.click()
OR with explicitWait
accept=WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"//button[#id='lgpd-button-agree']")))
accept.click()
#Here uses the XPath with the index like [1][2] to click on the specific element
product_link = driver.find_element_by_xpath("((//a[#id='variant-url'])[1])")
product_link.click()
OR with explicitWait
product_link=WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"((//a[#id='variant-url'])[1])")))
product_link.click()
I used to get this error all the time when starting. The problem is that there are probably multiple elements with the same ID "variant-url". There are two ways you can fix this
By using "driver.find_elementS_by_id"
product_links = driver.find_elements_by_id('variant-url')
product_links[2].click()
This will create an index off all the elements with id 'variant-url' then click the index of 2. This works but it is annoying to find the correct index of the button you want to click and also takes a long time if there are many elements with the same ID.
By using Xpaths or CSS selectors
This way is a lot easier as each element has a specific Xpath of Selector. It will look like this.
product_link = driver.get_element_by_xpath("XPATH GOES HERE").click()
To get an Xpath or selector 1. go into developer mode on your browser by inspecting the element 2. right click the element in the F12 menu 3. hover over copy 4. move to copy Xpath and click on it.
Hope this helps you :D

Unable to locate element XPath (Selenium)

I am trying to use this XPath in Selenium with Python but it's generating an error: 'Message: no such element: Unable to locate element':
driver.find_element(By.XPATH, '//div[contains (#class, "files-list-grid-view")]/div[1][contains (#class, "folder")]').click()
This code works in Dev Tools with $x().
I need a marked element.
If the dataref node value is unique and it is not changing dynamically then you can use the below xpath :
element = driver.find_element_by_xpath("//div[#dataref='folder-0']")
If you are still getting an error then try to give some delay before locating it like below :
from time import sleep
sleep(3)
element = driver.find_element_by_xpath("//div[#dataref='folder-0']")
# And perform some action here
Still it doesn't work then check for frame or iframe using //iframe or //frame locators and if there are any matches and the locator that you are trying to locate is in some frame then switch to it using the below line and try to run your code again :
from time import sleep
# Switch to corresponding frame
driver.switch_to_frame("frame locator")
# Wait for sometime
sleep(3)
# Try to find an element
element = driver.find_element_by_xpath("//div[#dataref='folder-0']")
# And perform some action here
I hope it works...

Unable to click invisible select python

I am trying to retrieve all possible lists from this website
Model will only open when year is selected. Similarly Make will only open when Model is selected. I want to store all combination of Year, Model and Make for learning purpose.
However I am not able to click year field only. It seems it is hidden and without this I can't go ahead with rest of code.
from selenium import webdriver
import time
from selenium.webdriver.support.ui import Select
from bs4 import BeautifulSoup
driver = webdriver.Chrome()
driver.get("https://www.osram-americas.com/en-us/applications/automotive-lighting-systems/Pages/lrgmain.aspx")
# Switch to new window opened
driver.switch_to.window(driver.window_handles[-1])
# Close the new window
driver.close()
# Switch back to original browser (first window)
driver.switch_to.window(driver.window_handles[0])
el = driver.find_element_by_id('sbToggle_27562807')
el.click()
It gives error :-
Message: no such element: Unable to locate element: {"method":"id","selector":"sbToggle_27562807"}
Message: no such element: Unable to locate element: {"method":"id","selector":"sbToggle_27562807"}
year element is not hidden, actually your locator to locate element using find_element_by_id('sbToggle_27562807') is not correct. In this element id attribute value is dynamically changing that's why you're unable to locate this element.
Instead of id locator you should try using some different locator. I would suggest, for better way try using find_element_by_css_selector() as below :-
el = driver.find_element_by_css_selector("div#fldYear a.sbToggle")
el.click()
Use this CSS selector to get to the arrow pointing downwards on the select year dropdown
"div[id='fldYear'] > div[class='sbHolder'] > a[class='sbToggle']"
or this xpath
"//div[#id='fldYear']/div[#class='sbHolder']/a[#class='sbToggle']"
Click on this to webelement to get the options
The element IDs change on each reload of the page, you'll have to find a different way to find the dropdown.
You can always find the <a> link with the "-- Select Year --" text, for example.

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