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Calculate summary statistic by category and filter - efficient code?

I have the two following dataframes.
df1:
code name region
0 AFG Afghanistan Middle East
1 NLD Netherlands Western Europe
2 AUT Austria Western Europe
3 IRQ Iraq Middle East
4 USA United States North America
5 CAD Canada North America
df2:
code year gdp per capita
0 AFG 2010 547.35
1 NLD 2010 44851.27
2 AUT 2010 3577.10
3 IRQ 2010 4052.06
4 USA 2010 52760.00
5 CAD 2010 41155.32
6 AFG 2015 578.47
7 NLD 2015 45175.23
8 AUT 2015 3952.80
9 IRQ 2015 4688.32
10 USA 2015 56863.37
11 CAD 2015 43635.10
I want to return the code, year, gdp per capita, and average (gdp per capita per region per year) for 2015 for countries with gdp above average for their region (should be NLD, IRQ, USA).
The result should look something like this:
code year gdp per capita average
3 NLD 2015 45175.23 24564.015
7 IRQ 2015 4688.32 2633.395
9 USA 2015 56863.37 50249.235
I wanted to try this in Python because I recently completed an introductory course to SQL and was amazed at the simplicity of the solution in SQL. While I managed to make it work in Python, it seems overly complicated to me. Is there any way to achieve the same result with less code or without the need for .groupby and helper columns? Please see my solution below.
data = pd.merge(df1, df2, how="inner", on="code")
grouper = data.groupby(["region", "year"])["gdp per capita"].mean().reset_index()
for i in range(len(data)):
average = (grouper.loc[(grouper["year"] == data.loc[i, "year"]) & (grouper["region"] == data.loc[i, "region"]), "gdp per capita"]).to_list()[0]
data.loc[i, "average"] = average
result = data.loc[(data["year"] == 2015) & (data["gdp per capita"] > data["average"]), ["code", "year", "gdp per capita", "average"]]
print(result)

Loops are basically never the right answer when it comes to pandas.
# This is your join and where clause.
df = df1.merge(df2, on='code')[lambda x: x.year.eq(2015)]
# This is your aggregate function.
df['average'] = df.groupby(['region'])['gdp per capita'].transform('mean')
# This is your select and having clause.
out = df[df['gdp per capita'].gt(df['average'])][['code', 'year', 'gdp per capita', 'average']]
print(out)
Output:
code year gdp per capita average
3 NLD 2015 45175.23 24564.015
7 IRQ 2015 4688.32 2633.395
9 USA 2015 56863.37 50249.235

Replace NA in DataFrame for multiple columns with mean per country

I want to replace NA values with the mean of other column with the same year.
Note: To replace NA values for Canada data, I want to use only the mean of Canada, not the mean from the whole dataset of course.
Here's a sample dataframe filled with random numbers. And some NA how i find them in my dataframe:
Country
Inhabitants
Year
Area
Cats
Dogs
Canada
38 000 000
2021
4
32
21
Canada
37 000 000
2020
4
NA
21
Canada
36 000 000
2019
3
32
21
Canada
NA
2018
2
32
21
Canada
34 000 000
2017
NA
32
21
Canada
35 000 000
2016
3
32
NA
Brazil
212 000 000
2021
5
32
21
Brazil
211 000 000
2020
4
NA
21
Brazil
210 000 000
2019
NA
32
21
Brazil
209 000 000
2018
4
32
21
Brazil
NA
2017
2
32
21
Brazil
207 000 000
2016
4
32
NA
What's the easiest way with pandas to replace those NA with the mean values of the other years? And is it possible to write a code for which it is possible to go through every NA and replace them (Inhabitants, Area, Cats, Dogs at once)?

Note Example is based on your additional data source from the comments
Replacing the NA-Values for multiple columns with mean() you can combine the following three methods:
fillna() (Iterating per column axis should be 0, which is default value of fillna())
groupby()
transform()
Create data frame from your example:
df = pd.read_excel('https://happiness-report.s3.amazonaws.com/2021/DataPanelWHR2021C2.xls')
Country name
year
Life Ladder
Log GDP per capita
Social support
Healthy life expectancy at birth
Freedom to make life choices
Generosity
Perceptions of corruption
Positive affect
Negative affect
Canada
2005
7.41805
10.6518
0.961552
71.3
0.957306
0.25623
0.502681
0.838544
0.233278
Canada
2007
7.48175
10.7392
nan
71.66
0.930341
0.249479
0.405608
0.871604
0.25681
Canada
2008
7.4856
10.7384
0.938707
71.84
0.926315
0.261585
0.369588
0.89022
0.202175
Canada
2009
7.48782
10.6972
0.942845
72.02
0.915058
0.246217
0.412622
0.867433
0.247633
Canada
2010
7.65035
10.7165
0.953765
72.2
0.933949
0.230451
0.41266
0.878868
0.233113
Call fillna() and iterate over all columns grouped by name of country:
df = df.fillna(df.groupby('Country name').transform('mean'))
Check your result for Canada:
df[df['Country name'] == 'Canada']
Country name
year
Life Ladder
Log GDP per capita
Social support
Healthy life expectancy at birth
Freedom to make life choices
Generosity
Perceptions of corruption
Positive affect
Negative affect
Canada
2005
7.41805
10.6518
0.961552
71.3
0.957306
0.25623
0.502681
0.838544
0.233278
Canada
2007
7.48175
10.7392
0.93547
71.66
0.930341
0.249479
0.405608
0.871604
0.25681
Canada
2008
7.4856
10.7384
0.938707
71.84
0.926315
0.261585
0.369588
0.89022
0.202175
Canada
2009
7.48782
10.6972
0.942845
72.02
0.915058
0.246217
0.412622
0.867433
0.247633
Canada
2010
7.65035
10.7165
0.953765
72.2
0.933949
0.230451
0.41266
0.878868
0.233113

This also works:
In [2]:
df = pd.read_excel('DataPanelWHR2021C2.xls')
In [3]:
# Check for number of null values in df
df.isnull().sum()
Out [3]:
Country name 0
year 0
Life Ladder 0
Log GDP per capita 36
Social support 13
Healthy life expectancy at birth 55
Freedom to make life choices 32
Generosity 89
Perceptions of corruption 110
Positive affect 22
Negative affect 16
dtype: int64
SOLUTION
In [4]:
# Adds mean of column to any NULL values
df.fillna(df.mean(), inplace=True)
In [5]:
# 2nd check for number of null values
df.isnull().sum()
Out [5]: No more NULL values
Country name 0
year 0
Life Ladder 0
Log GDP per capita 0
Social support 0
Healthy life expectancy at birth 0
Freedom to make life choices 0
Generosity 0
Perceptions of corruption 0
Positive affect 0
Negative affect 0
dtype: int64

Adding a subindex to merged dataframes

I have 3 dataframes each with the same columns (years) and same indexes (countries).
Now I want to merge these 3 dataframes. But since all have the same columns it is appending those.
So 'd like to keep the country index and add a subindex for each dataframe because all represent different numbers for each year.
#dataframe 1
#CO2:
2005 2010 2015 2020
country
Afghanistan 169405 210161 259855 319447
Albania 762 940 1154 1408
Algeria 158336 215865 294768 400126
#dataframe 2
#Arrivals + Departures:
2005 2010 2015 2020
country
Afghanistan 977896 1326120 1794547 2414943
Albania 103132 154219 224308 319440
Algeria 3775374 5307448 7389427 10159656
#data frame 3
#Travel distance in km:
2005 2010 2015 2020
country
Afghanistan 9330447004 12529259781 16776152792 22337458954
Albania 63159063 82810491 107799357 139543748
Algeria 12254674181 17776784271 25782632480 37150057977
The result should be something like:
2005 2010 2015 2020
country
Afghanistan co2 169405 210161 259855 319447
flights 977896 1326120 1794547 2414943
traveldistance 9330447004 12529259781 16776152792 22337458954
Albania ....
How can I do this?
NOTE: The years are an input so these are not fixed. They could just be 2005,2010 for example.
Thanks in advance.

I have tried to solve the problem using concat and groupby using your dataset hope it helps
First concat the 3 dfs
l=[df,df2,df3]
f=pd.concat(l,keys= ['CO2','Flights','traveldistance'],axis=0,).reset_index().rename(columns={'level_0':'Category'})
the use groupby to get the values
result_df=f.groupby(['country', 'Category'])[f.columns[2:]].first()
Hope it helps and solve your problem
Output looks like this

How to output the top 5 of a specific column along with associated columns using python?

I've tried to use df2.nlargest(5, ['1960'] this gives me:
Country Name Country Code ... 2017 2018
0 IDA & IBRD total IBT ... 6335039629.0000 6412522234.0000
1 Low & middle income LMY ... 6306560891.0000 6383958209.0000
2 Middle income MIC ... 5619111361.0000 5678540888.0000
3 IBRD only IBD ... 4731120193.0000 4772284113.0000
6 Upper middle income UMC ... 2637690770.0000 2655635719.0000
This is somewhat right, but it's outputting all the columns. I just want it to include the column name "Country Name" and "1960" only, but sort by the column "1960."
So the output should look like this...
Country Name 1960
China 5000000000
India 499999999
USA 300000
France 100000
Germany 90000

Pandas group by but keep another column

Say that I have a dataframe that looks something like this
date location year
0 1908-09-17 Fort Myer, Virginia 1908
1 1909-09-07 Juvisy-sur-Orge, France 1909
2 1912-07-12 Atlantic City, New Jersey 1912
3 1913-08-06 Victoria, British Columbia, Canada 1912
I want to use pandas groupby function to create an output that shows the total number of incidents by year but also keep the location column that will display one of the locations that year. Any which one works. So it would look something like this:
total location
year
1908 1 Fort Myer, Virginia
1909 1 Juvisy-sur-Orge, France
1912 2 Atlantic City, New Jersey
Can this be done without doing funky joining? The furthest I can get is using the normal groupby
df = df.groupby(['year']).count()
But that only gives me something like this
location
year
1908 1 1
1909 1 1
1912 2 2
How can I display one of the locations in this dataframe?

You can use groupby.agg and use 'first' to extract the first location in each group:
res = df.groupby('year')['location'].agg(['first', 'count'])
print(res)
# first count
# year
# 1908 Fort Myer, Virginia 1
# 1909 Juvisy-sur-Orge, France 1
# 1912 Atlantic City, New Jersey 2