Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 2 years ago.
Improve this question
I decided to take on some programming projects and decided to follow this guide:
https://www.dreamincode.net/forums/topic/78802-martyr2s-mega-project-ideas-list/
I started with the first project, which is to reverse a string, pretty simple stuff as you can find out how to do that in the documentation. IE.
txt = "Hello World"[::-1]
print(txt)
dlroW olleH
s = "health" [::-1]
print(s)
htlaeh
And So on... There's two questions really. In this guide i'm not to sure if they just wanted you to reverse the string. It seems like they want Input? For the user to Enter the String.
In this case i thought it might be something like this:
string = Input("Enter a string")
print(s [::-1])
How ever this did not work, Not to sure how to implement this in Python 3.8.2. Could someone let me know and how they did it that would be great.
Thank you.
Your code has a space between s and the indices you want. You also have two variable names, s and string. Choose one. Finally, Input must be lowercase. Change it to this:
string = input("Enter a string")
print(string[::-1])
Your print statement needs some modifications.
Here it goes-
print(string[: :-1])
Related
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 5 years ago.
Improve this question
I'm continuing learning python and I want to use the value of a variable as a key in a dictionary, and the input of the user as the value of that key, but what I'm doing is doing the opposite.
def scan_option(option_type):
option_dict={}
elected_type = option_type + '_option'
option_dict.update(elected_type= raw_input("Enter the {} Option: ".format(option_type)))
return option_dict
print scan_option("Hardrive")
In case user answered 8:
The output is: {'elected_type': '8'}
and I want it to be: {'Hardrive_option': '8'}
What do I need to change in the code to do that?
update takes a dictionary as its argument. The stuff you fed it was a symbol and a string; it converts that to a dictionary and then does the update.
The syntax you need here is a simple dictionary assignment:
option_dict[elected_type] = raw_input(...)
You might try simpler commands when you first write your code. Once those work properly, then you can go for the one-line, compound commands.
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 6 years ago.
Improve this question
I have the following question:
considering the given list :
list = ['12','8','3']
why does print('8' in list) returns True
whereas
for i in range(5):
if '8' in list == True:
(code)
doesn't execute my code inside the if loop ?
Could someone explain me why, and how could I make this work ?
Maybe this question has already been asked but I don't see with which keywords I should search for it.
Thanks for the help :-)
You seem to have some logical errors in your code, so I'll try to outline what you should be doing.
You shouldn't name variables str or list or int because they might conflict with Python's built in keywords.
Your check did if '8' in list, but that will test if the string 8 is in the list, not the number. Drop the apostrophes.
You don't have to put if 8 in list in a loop, it'll do the looping and testing for you.
Solution
To check if a number is in a list, you can use python's built in in keyword, your write your own code to do the checking.
Remember not to use keywords like list, so I've changed the name to myList in these examples.
Using in
if 8 in myList: # Note that you don't have to say == True
print('8 is in the list!')
Or using for i in myList)
for i in myList:
if i == 8:
print('8 is in the list!')**
Or using for i in range(len(myList))
for i in range(len(myList)):
if myList[i] == 8:
print('8 is in the list!')
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 7 years ago.
Improve this question
I'm probably missing something very basic here, but here goes:
I'm using Python 2.7 and regex to identify digits within a string.
In the console, I type in:
>>> newstr = 'NukeNews/File_132.txt'
>>> int(re.findall(r'\d+',newstr)[0])
132
Which is what I expect.
However, in the script I'm running, I have the strings stored in a dictionary, linedict. I'm running this script:
news_id=[]
for line in line_vec:
print linedict[line]
newstr= linedict[line]
id_int = re.findall('r\d+',newstr)
print id_int
news_id.append(id_int)
It's a long list, but the output looks like:
NukeNews/File_132.txt
[]
So - the correct string is registered, but it's not matching on anything.
I was calling the first item in the list earlier (to match the console input of int(re.findall(r'\d+',newstr)[0]), but the script is telling me that the regex didn't find any instances of the digits in the string. I would expect this to return:
NukeNews/File_132.txt
['132']
Any idea why it's not working as expected? When I try running re.match(r'/d+',newstr) I also get an empty group (following the groups example on https://docs.python.org/2/library/re.html).
Edit: As pointed out, this is a case of not being careful with 'r' and r'*'. I'm just going to leave this up in case anyone else googling "why does my regex work in console but not in script" forgets to check this typo, like I did.
You've got your r inside the quotes so instead of getting a "raw string" you're getting a string with an 'r' in it ...
id_int = re.findall('r\d+',newstr)
# ^
# should be:
id_int = re.findall(r'\d+',newstr)
your "console" version also only takes the first of the found matches compared to your "script" version which appends the entire list.
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
Improve this question
Hello I've been trying to get this line of code working but it keeps going down to the else: statement.
Any ideas?
I cant understand what I'm doing wrong for it not to accept the if: condition.
print('What do you get when you cross a snowman with a vampire?')
answer1 = input()
if answer1.lower 'frostbite':
print ('Huh? how did you know that YOU SPY!')
else:
print('FROSBITE!')
It's hard to tell with the code fragment since it has a SyntaxError, but I'm guessing you have:
if answer1.lower == 'frostbite':
...
The problem here is that answer.lower is a bound method which is clearly not equal to any string. You need to call it to actually generate the lower case string:
if answer1.lower() == 'frostbite':
...
Someone told me the answer
Thanks friends
print('What do you get when you cross a snowman with a vampire?')
answer1 = input()
if answer1.lower() == 'frostbite':
print ('Huh? how did you know that YOU SPY!')
else:
print('FROSBITE!')
You have to compare the strings:
print('What do you get when you cross a snowman with a vampire?')
answer1 = input()
correct = 'frostbite'
if answer1.lower == correct :
print ('Huh? how did you know that YOU SPY!')
else:
print('FROSBITE!')
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 9 years ago.
Improve this question
For some reason this piece of script is returning the error: "TypeError: string indices must be integers"; and I cannot see what's wrong. Am I being stupid and overlooking an obvious mistake here? I can't see one for the life of me!
terms = {"ALU":"Arithmetic Logic Unit"}
term = input("Type in a term you wish to see: ")
if term in terms:
definition = term[terms]
sentence = term + " - " + definition
print(sentence)
else:
print("Term doesn't exist.")
I think you want it this way: definition = terms[term]
This line definition = term[terms] is trying to get a character out of the string term. You probably just typoed, and want
definition = terms[term]
^ here, reference the dict, not the string
You are indexing the string term instead of the dictionary terms. Try:
definition = terms[term]
You accidentally swapped the variables. Change this:
definition = term[terms]
To this:
definition = terms[term]