I am trying to parse some HTML but the section that I want simply does not show up in the soup. Both the prior section and the posterior section are there, but not the one I want. Am I doing something wrong?
URL: https://coronavirus-portugal-esriportugal.hub.arcgis.com/
My code (with the URL):
from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup
url = 'https://coronavirus-portugal-esriportugal.hub.arcgis.com/'
uClient = uReq(url)
page_html = uClient.read()
uClient.close()
soup = soup(page_html, 'html.parser')
body = soup.body
print(body.prettify())
I am looking for the first four numbers (those corresponding to "Casos Confirmados", "Casos Suspeitos", "Recuperados", "Óbitos")
The data is retrieved dynamically from a backend SQL database. If you inspect the network traffic updating the page (and know a little SQL) you can work out how to write a query to send yourself to retrieve the portugal specific data. Here, 215 corresponds with Portugal.
import requests
r = requests.get('https://services1.arcgis.com/0MSEUqKaxRlEPj5g/arcgis/rest/services/ncov_cases/FeatureServer/1/query?f=json&where=OBJECTID=215&outFields=*')
print(r.json())
All data (use a different query):
https://services1.arcgis.com/0MSEUqKaxRlEPj5g/arcgis/rest/services/ncov_cases/FeatureServer/1/query?f=json&where=1=1&outFields=*
You can also dynamically pick up the other identifier used in the query string
import requests, re
country_id = 215
with requests.Session() as s:
r = s.get('https://coronavirus-portugal-esriportugal.hub.arcgis.com/')
p = re.compile(r'https://services1.arcgis.com/(.*?)/arcgis')
code = p.findall(r.text)[0]
r = s.get(f'https://services1.arcgis.com/{code}/arcgis/rest/services/ncov_cases/FeatureServer/1/query?f=json&where=OBJECTID={country_id}&outFields=*')
print(r.json())
Related
I am trying to webscrape a government site that uses frameset.
Here is the URL - https://lakecounty.in.gov/departments/voters/election-results-c/2022GeneralElectionResults/index.htm
I've tried using splinter/selenium
url = "https://lakecounty.in.gov/departments/voters/election-results-c/2022GeneralElectionResults/index.htm"
browser.visit(url)
time.sleep(10)
full_xpath_frame = '/html/frameset/frameset/frame[2]'
tree = browser.find_by_xpath(full_xpath_frame)
for i in tree:
print(i.text)
It just returns an empty string.
I've tried using the requests library.
import requests
from lxml import HTML
url = "https://lakecounty.in.gov/departments/voters/election-results-c/2022GeneralElectionResults/index.htm"
# get response object
response = requests.get(url)
# get byte string
data = response.content
print(data)
And it returns this
b"<html>\r\n<head>\r\n<meta http-equiv='Content-Type'\r\ncontent='text/html; charset=iso-
8859-1'>\r\n<title>Lake_ County Election Results</title>\r\n</head>\r\n<FRAMESET rows='20%,
*'>\r\n<FRAME src='titlebar.htm' scrolling='no'>\r\n<FRAMESET cols='20%, *'>\r\n<FRAME
src='menu.htm'>\r\n<FRAME src='Lake_ElecSumm_all.htm' name='reports'>\r\n</FRAMESET>
\r\n</FRAMESET>\r\n<body>\r\n</body>\r\n</html>\r\n"
I've also tried using beautiful soup and it gave me the same thing. Is there another python library I can use in order to get the data that's inside the second table?
Thank you for any feedback.
As mentioned you could go for the frames and its src:
BeautifulSoup(r.text).select('frame')[1].get('src')
or directly to the menu.htm:
import requests
from bs4 import BeautifulSoup
r = requests.get('https://lakecounty.in.gov/departments/voters/election-results-c/2022GeneralElectionResults/menu.htm')
link_list = ['https://lakecounty.in.gov/departments/voters/election-results-c/2022GeneralElectionResults'+a.get('href') for a in BeautifulSoup(r.text).select('a')]
for link in link_list[:1]:
r = requests.get(link)
soup = BeautifulSoup(r.text)
###...scrape what is needed
I am trying to build a scraper to get some abstracts of academic papers and their corresponding titles on this page.
The problem is that my for link in bsObj.findAll('a',{'class':'search-track'}) does not return the links I need to further build my scraper. In my code, the check is like this:
for link in bsObj.findAll('a',{'class':'search-track'}):
print(link)
The for loop above does print out anything, however, the href links should be inside the <a class="search-track" ...</a>.
I have referred to this post, but changing the Beautifulsoup parser is not solving the problem of my code. I am using "html.parser" in my Beautifulsoup constructor: bsObj = bs(html.content, features="html.parser").
And the print(len(bsObj)) prints out "3" while it prints out "2" for both "lxml" and "html5lib".
Also, I started off using urllib.request.urlopen to get the page and then tried requests.get() instead. Unfortunately the two approaches give me the same bsObj.
Here is the code I've written:
#from urllib.request import urlopen
import requests
from bs4 import BeautifulSoup as bs
import ssl
'''
The elsevier search is kind of a tree structure:
"keyword --> a list of journals (a journal contain many articles) --> lists of articles
'''
address = input("Please type in your keyword: ") #My keyword is catalyst for water splitting
#https://www.elsevier.com/en-xs/search-results?
#query=catalyst%20for%20water%20splitting&labels=journals&page=1
address = address.replace(" ", "%20")
address = "https://www.elsevier.com/en-xs/search-results?query=" + address + "&labels=journals&page=1"
journals = []
articles = []
def getJournals(url):
global journals
#html = urlopen(url)
html = requests.get(url)
bsObj = bs(html.content, features="html.parser")
#print(len(bsObj))
#testFile = open('testFile.txt', 'wb')
#testFile.write(bsObj.text.encode(encoding='utf-8', errors='strict') +'\n'.encode(encoding='utf-8', errors='strict'))
#testFile.close()
for link in bsObj.findAll('a',{'class':'search-track'}):
print(link)
########does not print anything########
'''
if 'href' in link.attrs and link.attrs['href'] not in journals:
newJournal = link.attrs['href']
journals.append(newJournal)
'''
return None
# Ignore SSL certificate errors
ctx = ssl.create_default_context()
ctx.check_hostname = False
ctx.verify_mode = ssl.CERT_NONE
getJournals(address)
print(journals)
Can anyone tell me what the problem is in my code that the for loop does not print out any links? I need to store the links of journals in a list and then visit each link to scrape the abstracts of papers. By right the abstracts part of a paper is free and the website shouldn't have blocked my ID because of it.
This page is dynamically loaded with jscript, so Beautifulsoup can't handle it directly. You may be able to do it using Selenium, but in this case you can do it by tracking the api calls made by the page (for more see, as one of many examples, here.
In your particular case it can be done this way:
from bs4 import BeautifulSoup as bs
import requests
import json
#this is where the data is hiding:
url = "https://site-search-api.prod.ecommerce.elsevier.com/search?query=catalyst%20for%20water%20splitting&labels=journals&start=0&limit=10&lang=en-xs"
html = requests.get(url)
soup = bs(html.content, features="html.parser")
data = json.loads(str(soup))#response is in json format so we load it into a dictionary
Note: in this case, it's also possible to dispense with Beautifulsoup altogether and load the response directly, as in data = json.loads(html.content). From this point:
hits = data['hits']['hits']#target urls are hidden deep inside nested dictionaries and lists
for hit in hits:
print(hit['_source']['url'])
Ouput:
https://www.journals.elsevier.com/water-research
https://www.journals.elsevier.com/water-research-x
etc.
I am trying to practice web-scraping from a e-commerce webpage. I have identified the class name of the container (cell which contains each product) to be 'c3e8SH'. I then used the following code to scrape for all containers in that webpage. After which, I used len(containers) to check the number of containers in the webpage.
However, it returned a 0. Can someone point out what I am doing incorrectly? Thank you very much!
import bs4
from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup
my_url = 'https://www.lazada.sg/catalog/?spm=a2o42.home.search.1.488d46b5mJGzEu&q=switch%20games&_keyori=ss&from=search_history&sugg=switch%20games_0_1'
# opening up connection, grabbing the page
uClient = uReq(my_url)
page_html = uClient.read()
uClient.close()
#html parsing
page_soup = soup(page_html, 'html.parser')
#grabs each product
containers = page_soup.find_all('div', class_='c3e8SH')
len(containers)
(1) Firstly, param cookies is needed.
You will get the validation page as below if you only request the link without cookies
https://www.lazada.sg/catalog/?spm=a2o42.home.search.1.488d46b5mJGzEu&q=switch%20games&_keyori=ss&from=search_history&sugg=switch%20games_0_1
(2) secondly, The page you want to scrape is dynamicly loaded
That's why what you see through web browser is different from what you get by codes
for convenience , i'd prefer to use requests module.
import requests
my_url = 'https://www.lazada.sg/catalog/?spm=a2o42.home.search.1.488d46b5mJGzEu&q=switch%20games&_keyori=ss&from=search_history&sugg=switch%20games_0_1'
cookies = {
"Hm_lvt_7cd4710f721b473263eed1f0840391b4":"1548133175,1548135160,1548135844",
"Hm_lpvt_7cd4710f721b473263eed1f0840391b4":"1548135844",
"x5sec":"7b22617365727665722d6c617a6164613b32223a223862623264333633343063393330376262313364633537653564393939303732434c50706d754946454e2b4b356f7231764b4c643841453d227d",
}
ret = requests.get(my_url, cookies=cookies)
print("New Super Mario Bros" in ret.text) # True
# then you can get a json-style shop-items in ret.text
shop-items like as:
item_json =
{
"#context":"https://schema.org",
"#type":"ItemList",
"itemListElement":[
{
"offers":{
"priceCurrency":"SGD",
"#type":"Offer",
"price":"72.90",
"availability":"https://schema.org/InStock"
},
"image":"https://sg-test-11.slatic.net/p/ae0494e8a5eb7412830ac9822984f67a.jpg",
"#type":"Product",
"name":"Nintendo Switch New Super Mario Bros U Deluxe", # item name
"url":"https://www.lazada.sg/products/nintendo-switch-new-super-mario-bros-u-deluxe-i292338164-s484601143.html?search=1"
},
...
]
}
as json data showed, you can get any item's name, url-link, price, and so on.
Try using a different parser.
I recommend lxml.
So your line where you create the page_soup would be:
page_soup = soup(page_html, 'lxml')
I tried to find c3e8SH in your suggested document with regex, but I coudn't find such class name. Please, check your document again.
I am trying to scrape data from the following url: https://www.pro-football-reference.com/boxscores/201809060phi.htm
Specifically, I want info from the "Passing, Rushing, & Receiving" table. I have the following code:
from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup
# assigning url
my_url = 'https://www.pro-football-reference.com/boxscores/201809060phi.htm'
# opening up connection, grabbing the page
raw_page = uReq(my_url)
page_html = raw_page.read()
raw_page.close()
# html parsing
page_soup = soup(page_html,"html.parser")
# assign variable to stat table
stat_table = page_soup.find ("div",{"id":"all_player_offense"})
inner_table = stat_table.findAll("tr")
print(len(inner_table)
It should be printing the number of player rows in that table. The output I get from this is 0 instead of what I expected, 17.
You're getting the parent div to the table instead of the table itself. Double check the HTML markup of the page and you'll find the id of the table.
Also note that the table uses a tbody instead of immediately listing the rows, so you'll have to account for that as well.
I'm using beautiful soup for the first time and the text from the span class is not being extracted. I'm not familiarized with HTML so I'm unsure as to why this happens, so it'd be great to understand.
I've used the code below:
from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup
my_url = 'https://www.anz.com.au/personal/home-loans/your-loan/interest-rates/#varhome'
uClient = uReq(my_url)
page_html = uClient.read()
uClient.Close()
page_soup = soup(page_html, "html.parser")
content = page_soup.findAll("span",attrs={"data-item":"rate"})
With this code for index 0 it returns the following:
<span class="productdata" data-baserate-code="VRI" data-cc="AU" data-
item="rate" data-section="PHL" data-subsection="VR"></span>
However I'd expect something like this when I inspect via Chrome, which has the text such as the interest rate:
<span class="productdata" data-cc="AU" data-section="PHL" data-
subsection="VR" data-baserate-code="VRI" data-item="rate">5.20% p.a.</span>
Data you are trying to extract does not exists. It is loaded using JS after the page is loaded. Website uses a JSON api to load information on the page. So Beautiful soup can not find the data. Data can be viewed at following link that hits JSON API on the site and provides JSON data.
https://www.anz.com/productdata/productdata.asp?output=json&country=AU§ion=PHL
You can parse the json and get the data. Also for HTTP requests I would recommend requests package.
As others said, the content is JavaScript generated, you can use selenium together ChromeDriver to find the data you want with something like:
from selenium import webdriver
driver = webdriver.Chrome()
driver.get("https://www.anz.com.au/personal/home-loans/your-loan/interest-rates/#varhome")
items = driver.find_elements_by_css_selector("span[data-item='rate']")
itemsText = [item.get_attribute("textContent") for item in items]
>>> itemsText
['5.20% p.a.', '5.30% p.a.', '5.75% p.a.', '5.52% p.a.', ....]
As seen above, BeautifulSoup wasn't necessary at all, but you can use it instead to parse the page source and get the same results:
from bs4 import BeautifulSoup
soup = BeautifulSoup(driver.page_source, 'html.parser')
items = soup.findAll("span",{"data-item":"rate"})
itemsText = [item.text for items in items]