Here is the code, it produces what I want but not in the way I want to output the result
import requests
from bs4 import BeautifulSoup
url = 'https://en.wikipedia.org/wiki/2020_coronavirus_pandemic_in_Florida'
fl = requests.get(url)
fl_soup = BeautifulSoup(fl.text, 'html.parser')
block = fl_soup.findAll('td', {'class': 'bb-04em'})
for name in fl_soup.findAll('td', {'class': 'bb-04em'}):
print(name.text)
output
2020-04-21
27,869(+3.0%)
867
I would like the output like this
2020-04-21 27,869(+3.0%) 867
Before accesing each <td>, try to get the data by each <tr>, you will get the information of each table row. Then you could search inside <td> or whatever you want.
The following should do what you want:
import requests
from bs4 import BeautifulSoup
url = 'https://en.wikipedia.org/wiki/2020_coronavirus_pandemic_in_Florida'
fl = requests.get(url)
fl_soup = BeautifulSoup(fl.text, 'html.parser')
div_with_table = fl_soup.find('div', {'class': 'barbox tright'})
table = div_with_table.find('table')
for row in table.findAll('tr'):
for cell in row.findAll('td', {'class': 'bb-04em'}):
print(cell.text, end=' ')
print() # new line for each row
For the last print statement include the end parameter. By default the print statement has end='\n'
print(name.text, end=' ')
This would give you the desired output.
Related
I am trying to extract each row individually to eventually create a dataframe to export them into a csv. I can't locate the individual parts of the html.
I can find and save the entire content (although I can only seem to save this on a loop so the pages appear hundreds of times), but I can't find any html parts nested beneath this. My code is as follows, trying to find the first row:
page = requests.get(url)
soup = BeautifulSoup(page.text, 'html.parser')
content = soup.find('div', {'class': 'view-content'})
for infos in content:
try:
data = infos.find('div', {'class': 'type type_18'}).text
except:
print("None found")
df = pd.DataFrame(data)
df.columns = df.columns.str.lower().str.replace(': ','')
df[['type','rrr']] = df['rrr'].str.split("|",expand=True)
df.to_csv (r'savehere.csv', index = False, header = True)
This code just prints "None found" because, I assume, it hasn't found anything else to print. I don't know if I am not finding the right html part or what.
Any help would be much appreciated.
What happens?
Main issue here is that content = soup.find('div', {'class': 'view-content'}) is no ResultSet and contains only a single element. Thats why your second loop only iterates once.
Also Caused by this behavior you will swap from beautifoulsoup method find() to python string method find() and these two are operating in a different way - Without try/except you will see the what is going on, it try to find a string:
for x in soup.find('div', {'class': 'view-content'}):
print(x.find('div'))
Output
...
-1
<div class="views-field views-field-title-1"> <span class="views-label views-label-title-1">RRR: </span> <span class="field-content"><div class="type type_18">Eleemosynary grant</div>2256</span> </div>
...
How to fix?
Select your elements more specific in this case the views-row:
sections = soup.find_all('div', {'class': 'views-row'})
While you iterate each section you could select expected value:
sections = soup.find_all('div', {'class': 'views-row'})
for section in sections:
print(section.select_one('div[class*="type_"]').text)
Example
Is scraping all the information and creates DataFrame
import requests
from bs4 import BeautifulSoup
import pandas as pd
data = []
website = #link here#
page = requests.get(url)
soup = BeautifulSoup(page.text, 'html.parser')
sections = soup.find_all('div', {'class': 'views-row'})
for section in sections:
d = {}
for row in section.select('div.views-field'):
d[row.span.text] = row.select_one('span:nth-of-type(2)').get_text('|',strip=True)
data.append(d)
df = pd.DataFrame(data)
### replacing : in header and set all to lower case
df.columns = df.columns.str.lower().str.replace(': ','')
...
I think that You wanted to make pagination using for loop and range method and to grab RRR value.I've done the next pages meaning pagination in long url.
from bs4 import BeautifulSoup
import requests
import pandas as pd
url = #insert url#
data=[]
for page in range(1,7):
req=requests.get(url.format(page=page))
soup = BeautifulSoup(req.content,'lxml')
for r in soup.select('[class="views-field views-field-title-1"] span:nth-child(2)'):
rr=list(r.stripped_strings)[-1]
#print(rr)
data.append(rr)
df = pd.DataFrame(data,columns=['RRR'])
print(df)
#df.to_csv('data.csv',index=False)
Output:
List
I am trying to scrape the prices from a website and it's working but... I can't write the result to a text.file.
this is my python code.
import requests
from bs4 import BeautifulSoup as bs
url = "https://www.futbin.com/stc/cheapest"
r = requests.get(url)
soup = bs(r.content, "html.parser")
price = soup.find("div", {"class":"d-flex row col-md-9 px-0"})
name =("example")
f =open(name + '.txt', "a")
f.write(price.text)
This is not working but if I print it instead of try to write it to a textfile it's working. I have searched for a long time but don't understand it. I think it must be a string to write to a text file but don't know how to change the ouput to a string.
You're getting error due to unicode character.
Try to add encoding='utf-8' property while opening a file.
Also your code gives a bit messy output. Try this instead:
import requests
from bs4 import BeautifulSoup as bs
url = "https://www.futbin.com/stc/cheapest"
r = requests.get(url)
soup = bs(r.content, "html.parser")
rows = soup.find("div", {"class":"d-flex row col-md-9 px-0"})
prices = rows.findAll("span",{"class":"price-holder-row"})
names = rows.findAll("div",{"class":"name-holder"})
price_list = []
name_list = []
for price in prices:
price_list.append(price.text.strip("\n "))
for name in names:
name_list.append(name.text.split()[0])
name =("example")
with open(f"{name}.txt",mode='w', encoding='utf-8') as f:
for name, price in zip(name_list,price_list):
f.write(f"{name}:{price}\n")
Okay, so I need to scrape the following webpage: https://www.programmableweb.com/category/all/apis?deadpool=1
It's a list of APIs. There are approx 22,000 APIs to scrape.
I need to:
1) Get the URL of each API in the table (pages 1-889), and also to scrape the following info:
API name
Description
Category
Submitted
2) I then need to scrape a bunch of information from each URL.
3) Export the data to a CSV
The thing is, I’m a bit lost of how to think about this project. From what I can see, there are no AJAX calls been made to populate the table, which means I’m going to have to parse the HTML directly (right?)
In my head, the logic would be something like this:
Use the requests & BS4 libraries to scrape the table
Then, somehow grab the HREF from every row
Access that HREF, scrape the data, move onto the next one
Rinse and repeat for all table rows.
Am I on the right track, is this possible with requests & BS4?
Here's are some screenshots of what I've been trying to explain.
Thank you SOO much for any help. This is hurting my head haha
Here we go using requests, BeautifulSoup and pandas:
import requests
from bs4 import BeautifulSoup
import pandas as pd
url = 'https://www.programmableweb.com/category/all/apis?deadpool=1&page='
num = int(input('How Many Page to Parse?> '))
print('please wait....')
name = []
desc = []
cat = []
sub = []
for i in range(0, num):
r = requests.get(f"{url}{i}")
soup = BeautifulSoup(r.text, 'html.parser')
for item1 in soup.findAll('td', attrs={'class': 'views-field views-field-title col-md-3'}):
name.append(item1.text)
for item2 in soup.findAll('td', attrs={'class': 'views-field views-field-search-api-excerpt views-field-field-api-description hidden-xs visible-md visible-sm col-md-8'}):
desc.append(item2.text)
for item3 in soup.findAll('td', attrs={'class': 'views-field views-field-field-article-primary-category'}):
cat.append(item3.text)
for item4 in soup.findAll('td', attrs={'class': 'views-field views-field-created'}):
sub.append(item4.text)
result = []
for item in zip(name, desc, cat, sub):
result.append(item)
df = pd.DataFrame(
result, columns=['API Name', 'Description', 'Category', 'Submitted'])
df.to_csv('output.csv')
print('Task Completed, Result saved to output.csv file.')
Result can be viewed online: Check Here
Output Simple:
Now For href parsing:
import requests
from bs4 import BeautifulSoup
import pandas as pd
url = 'https://www.programmableweb.com/category/all/apis?deadpool=0&page='
num = int(input('How Many Page to Parse?> '))
print('please wait....')
links = []
for i in range(0, num):
r = requests.get(f"{url}{i}")
soup = BeautifulSoup(r.text, 'html.parser')
for link in soup.findAll('td', attrs={'class': 'views-field views-field-title col-md-3'}):
for href in link.findAll('a'):
result = 'https://www.programmableweb.com'+href.get('href')
links.append(result)
spans = []
for link in links:
r = requests.get(link)
soup = soup = BeautifulSoup(r.text, 'html.parser')
span = [span.text for span in soup.select('div.field span')]
spans.append(span)
data = []
for item in spans:
data.append(item)
df = pd.DataFrame(data)
df.to_csv('data.csv')
print('Task Completed, Result saved to data.csv file.')
Check Result Online: Here
Sample View is Below:
In Case if you want those 2 csv files together so here's the code:
import pandas as pd
a = pd.read_csv("output.csv")
b = pd.read_csv("data.csv")
merged = a.merge(b)
merged.to_csv("final.csv", index=False)
Online Result: Here
You should read more about scraping if you are going to pursue it .
from bs4 import BeautifulSoup
import csv , os , requests
from urllib import parse
def SaveAsCsv(list_of_rows):
try:
with open('data.csv', mode='a', newline='', encoding='utf-8') as outfile:
csv.writer(outfile).writerow(list_of_rows)
except PermissionError:
print("Please make sure data.csv is closed\n")
if os.path.isfile('data.csv') and os.access('data.csv', os.R_OK):
print("File data.csv Already exists \n")
else:
SaveAsCsv([ 'api_name','api_link','api_desc','api_cat'])
BaseUrl = 'https://www.programmableweb.com/category/all/apis?deadpool=1&page={}'
for i in range(1, 890):
print('## Getting Page {} out of 889'.format(i))
url = BaseUrl.format(i)
res = requests.get(url)
soup = BeautifulSoup(res.text,'html.parser')
table_rows = soup.select('div.view-content > table[class="views-table cols-4 table"] > tbody tr')
for row in table_rows:
tds = row.select('td')
api_name = tds[0].text.strip()
api_link = parse.urljoin(url, tds[0].find('a').get('href'))
api_desc = tds[1].text.strip()
api_cat = tds[2].text.strip() if len(tds) >= 3 else ''
SaveAsCsv([api_name,api_link,api_desc,api_cat])
I developed this simple web scraping program to scrape newegg.com. I made a for loop to print out the name of the product, price, and shipping cost.
However, when I run the for loop it doesn't print out anything and does not give me any error. Before I write the for loop (commented items) I have ran those lines (commented items) and it prints the details only for one of the products.
from bs4 import BeautifulSoup
import requests
import csv
source = requests.get('https://www.newegg.com/PS4-Systems/SubCategory/ID-3102').text
soup = BeautifulSoup(source, 'lxml')
#prod = soup.find('a', class_='item-title').text
#price = soup.find('li', class_='price-current').text.strip()
#ship = soup.find('li', class_='price-ship').text.strip()
#print(prod.strip())
#print(price.strip())
#print(ship)
for info in soup.find_all('div', class_='item-container '):
prod = soup.find('a', class_='item-title').text
price = soup.find('li', class_='price-current').text.strip()
ship = soup.find('li', class_='price-ship').text.strip()
print(prod.strip())
#price.splitlines()[3].replace('\xa0', '')
print(price.strip())
print(ship)
Write less code:
from bs4 import BeautifulSoup
import requests
source = requests.get('https://www.newegg.com/PS4-Systems/SubCategory/ID-3102').text
soup = BeautifulSoup(source, 'lxml')
for info in soup.find_all('div', class_='item-container '):
print(info.find('a', class_='item-title').text)
print(info.find('li', class_='price-current').text.strip())
print(info.find('li', class_='price-ship').text.strip())
Besides the 'space' typo and the indentation, you didn't actually use info in your for loop. This will just keep printing the first item. Use info in your for loop where you had soup.
from bs4 import BeautifulSoup
import requests
import csv
source = requests.get('https://www.newegg.com/PS4-Systems/SubCategory/ID-3102').text
soup = BeautifulSoup(source, 'lxml')
for info in soup.find_all('div', class_='item-container'):
prod = info.find('a', class_='item-title').text.strip()
price = info.find('li', class_='price-current').text.strip().splitlines()[1].replace(u'\xa0', '')
if u'$' not in price:
price = info.find('li', class_='price-current').text.strip().splitlines()[0].replace(u'\xa0', '')
ship = info.find('li', class_='price-ship').text.strip()
print(prod)
print(price)
print(ship)
Because your code is not using info in the code below for info in soup.....: but soup.find(..), it will just keep looking for the first occurrence of e.g. soup.find('a', class_='item-title'). If you use info.find(....) it will use the next <div> element every loop of the for-loop.
Edit:
I also found that the price is not always the second item when you use .splitlines(), sometimes it's the first. I therefor added a check to see if the item contained the '$' sign. If not, it used the first list item.
#Rick you mistakenly added extra space in for info in soup.find_all('div', class_='item-container '): this line after attribute value
check below code it will work as you expected
from bs4 import BeautifulSoup
import requests
import csv
source = requests.get('https://www.newegg.com/PS4-Systems/SubCategory/ID-3102').text
soup = BeautifulSoup(source, 'lxml')
for info in soup.find_all('div', class_='item-container '):
prod = soup.find('a', class_='item-title').text
price = soup.find('li', class_='price-current').text.strip()
ship = soup.find('li', class_='price-ship').text.strip()
print(prod.strip())
print(price.strip())
print(ship)
hope this solve your problem...
I have a list of divs, and I'm trying to get certain info in each of them. The div classes are the same so I'm not sure how I would go about this.
I have tried for loops but have been getting various errors
Code to get list of divs:
import requests
from bs4 import BeautifulSoup
import re
url = 'https://sneakernews.com/release-dates/'
response = requests.get(url)
data = response.text
soup = BeautifulSoup(data, "lxml")
soup1 = soup.find("div", {'class': 'popular-releases-block'})
soup1 = str(soup1.find("div", {'class': 'row'}))
soup1 = soup1.split('</div>')
print(soup1)
Code I want to loop for each item in the soup1 list:
linkinfo = soup1.find('a')['href']
date = str(soup1.find('span'))
name = soup1.find('a')
non_decimal = re.compile(r'[^\d.]+')
date = non_decimal.sub('', date)
name = str(name)
name = re.sub('</a>', '', name)
link, name = name.split('>')
link = re.sub('<a href="', '', link)
link = re.sub('"', '', link)
name = name.split(' ')
name = str(name[-1])
date = str(date)
link = str(link)
print(link)
print(name)
print(date)
Based on the URL you posted above, I imagine you are interested in something like this:
import requests
from bs4 import BeautifulSoup
url = requests.get('https://sneakernews.com/release-dates/').text
soup = BeautifulSoup(url, 'html.parser')
tags = soup.find_all('div', {'class': 'col lg-2 sm-3 popular-releases-box'})
for tag in tags:
link = tag.find('a').get('href')
print(link)
print(tag.text)
#Anything else you want to do
If you are using the BeautifulSoup library, then you do not need regex to try to parse through HTML tags. Instead, use the handy methods that accompany BeautifulSoup. If you would like to apply a regex to the text output from the tags you locate via BeautifulSoup to accomplish a more specific task, then that would be reasonable.
My understanding is that you want to loop your code for each item within a list.
An example of this:
my_list = ["John", "Fred", "Tom"]
for name in my_list:
print(name)
This will loop for each name that is in my_list and print out each item (reffered to here as name in the list). You could do something similar with your code:
for item in soup1:
# perform some action