SQL Query Syntax error in Pandas to_sql method in Python - python
I would like to parse periodical txt files into a database through SqlAlchemy and Pandas to_sql method. But i receive SqlAlchemy Error such as below, probably an SQL syntax error. Could you please tell me how can i edit the SQL query ?
import glob
import os
import pandas as pd
from sqlalchemy import create_engine
database_username = 'user'
database_password = 'usr321'
database_ip = '10.1.10.1'
database_name = 'mydb'
engine = sqlalchemy.create_engine('mysql+mysqlconnector://{0}:{1}#{2}/{3}'.format(database_username, database_password,database_ip, database_name))
list_of_files = glob.glob('/data01/*.txt')
for i in list_of_files:
data = pd.read_csv(i, header=None)
data.to_sql(name='table3', con=engine, if_exists = 'append', index=False)
THE ERROR :
sqlalchemy.exc.ProgrammingError: (mysql.connector.errors.ProgrammingError) 1054 (42S22): Unknown column '0' in 'field list'
[SQL: INSERT INTO table3(`0`, `1`, `2`, `3`, `4`, `5`, `6`) VALUES (%(0)s, %(1)s, %(2)s, %(3)s, %(4)s, %(5)s, %(6)s)]
[parameters: ({'0': '2020-04-29 08:40:00', '1': 'BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bskhdra1_lnk01', '2': 1, '3': 1753359343, '4': 1959.0, '5': 1753359344, '6': 1961.0}, {'0': '2020-04-29 08:40:00', '1': 'BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bskhdra1_lnk02', '2': 1, '3': 1753359343, '4': 1962.0, '5': 1753359344, '6': 1963.0}, {'0': '2020-04-29 08:40:00', '1': 'BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bskhdra1_lnk03', '2': 1, '3': 1753359343, '4': 1954.0, '5': 1753359344, '6': 1954.0}, {'0': '2020-04-29 08:40:00', '1': 'BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bvhdra01_lnk01', '2': 1, '3': 1753359343, '4': 1967.0, '5': 1753359344, '6': 1967.0}, {'0': '2020-04-29 08:40:00', '1': 'BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bvhdra01_lnk02', '2': 1, '3': 1753359343, '4': 1970.0, '5': 1753359344, '6': 1972.0}, {'0': '2020-04-29 08:40:00', '1': 'BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bvhdra01_lnk03', '2': 1, '3': 1753359343, '4': 1975.0, '5': 1753359344, '6': 1976.0}, {'0': '2020-04-29 08:40:00', '1': 'BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_mbhdra01_lnk01', '2': 1, '3': 1753359343, '4': 1438.0, '5': 1753359344, '6': 1435.0}, {'0': '2020-04-29 08:40:00', '1': 'BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_mbhdra01_lnk02', '2': 1, '3': 1753359343, '4': 1438.0, '5': 1753359344, '6': 1436.0} ... displaying 10 of 6578 total bound parameter sets ... {'0': '2020-04-29 08:40:00', '1': 'MBHDRA01_SPS/Diameter Link:Link name=mbhdra01_mbepgwv01_c3_lnk02', '2': 1, '3': 1753359343, '4': 1982.0, '5': 1753359344, '6': 1985.0}, {'0': '2020-04-29 08:40:00', '1': 'MBHDRA01_SPS/Diameter Link:Link name=mbhdra01_ANKSPTS03_lnk02', '2': 1, '3': 1753359343, '4': 0.0, '5': 1753359344, '6': 0.0})]
(Background on this error at: http://sqlalche.me/e/f405)
if it is needed content of each file like this ;
Content of each file like ;
[neg#nik:/data01]# head file_2020-04-29_13:55:00.txt
2020-04-29 13:55:00,BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bskhdra1_lnk01,True,1753359343,2374.0,1753359344,2375.0
2020-04-29 13:55:00,BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bskhdra1_lnk02,True,1753359343,2371.0,1753359344,2370.0
2020-04-29 13:55:00,BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bskhdra1_lnk03,True,1753359343,2374.0,1753359344,2376.0
2020-04-29 13:55:00,BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bvhdra01_lnk01,True,1753359343,2377.0,1753359344,2377.0
2020-04-29 13:55:00,BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bvhdra01_lnk02,True,1753359343,2369.0,1753359344,2364.0
2020-04-29 13:55:00,BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_bvhdra01_lnk03,True,1753359343,2362.0,1753359344,2361.0
2020-04-29 13:55:00,BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_mbhdra01_lnk01,True,1753359343,1629.0,1753359344,1631.0
2020-04-29 13:55:00,BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_mbhdra01_lnk02,True,1753359343,1634.0,1753359344,1632.0
2020-04-29 13:55:00,BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_mbhdra01_lnk03,True,1753359343,1633.0,1753359344,1632.0
2020-04-29 13:55:00,BSKHDEA1_SPS/Diameter Link:Link name=bskhdea1_ipx_ibasis1_asd_lnk02,True,1753359343,3871.0,1753359344,3869.0
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Deleting rows from a dataframe with nested for loops
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How to compare XLS file to json file?
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{"Name":{"0":"default_config","1":"default_config","2":"default_config","3":"default_config","4":"default_config","5":"gems1","6":"gems1","7":"gems1","8":"gems1","9":"gems1","10":"gems2","11":"gems2","12":"gems2","13":"gems2","14":"gems2","15":"gems3","16":"gems3","17":"gems3","18":"gems3","19":"gems3"},"Identifier":{"0":11294,"1":11294,"2":11294,"3":11294,"4":11294,"5":11295,"6":11295,"7":11295,"8":11295,"9":11295,"10":11296,"11":11296,"12":11296,"13":11296,"14":11296,"15":11297,"16":11297,"17":11297,"18":11297,"19":11297},"Segment Alias":{"0":"default","1":"default","2":"default","3":"default","4":"default","5":"rhinoQA_1","6":"rhinoQA_1","7":"rhinoQA_1","8":"rhinoQA_1","9":"rhinoQA_1","10":"rhinoQA_2","11":"rhinoQA_2","12":"rhinoQA_2","13":"rhinoQA_2","14":"rhinoQA_2","15":"rhinoQA_3","16":"rhinoQA_3","17":"rhinoQA_3","18":"rhinoQA_3","19":"rhinoQA_3"},"Segment 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cfa for test user and any non existing platform to get default B. request user 520000000101987 (has segment in hbi redis,but not in config), any platform","1":"default;A.request cfa for test user and any non existing platform to get default B. request user 520000000101987 (has segment in hbi redis,but not in config), any platform","2":"default;A.request cfa for test user and any non existing platform to get default B. request user 520000000101987 (has segment in hbi redis,but not in config), any platform","3":"default;A.request cfa for test user and any non existing platform to get default B. request user 520000000101987 (has segment in hbi redis,but not in config), any platform","4":"default;A.request cfa for test user and any non existing platform to get default B. request user 520000000101987 (has segment in hbi redis,but not in config), any platform","5":"*inserted_by_automated_test*","6":"*inserted_by_automated_test*","7":"*inserted_by_automated_test*","8":"*inserted_by_automated_test*","9":"*inserted_by_automated_test*","10":"x1","11":"x1","12":"x1","13":"x1","14":"x1","15":"x3","16":"x3","17":"x3","18":"x3","19":"x3"},"Pack Name":{"0":"test_bingo","1":"test_bingo","2":"test_bingo","3":"test_bingo","4":"test_bingo","5":"test_bingo","6":"test_bingo","7":"test_bingo","8":"test_bingo","9":"test_bingo","10":"test_bingo","11":"test_bingo","12":"test_bingo","13":"test_bingo","14":"test_bingo","15":"test_bingo","16":"test_bingo","17":"test_bingo","18":"test_bingo","19":"test_bingo"},"SKU":{"0":"gems_99","1":"gems_99","2":"gems_99","3":"gems_99","4":"gems_99","5":"gems_99","6":"gems_99","7":"gems_99","8":"gems_99","9":"gems_99","10":"gems_99","11":"gems_99","12":"gems_99","13":"gems_99","14":"gems_99","15":"gems_99","16":"gems_99","17":"gems_99","18":"gems_99","19":"gems_99"},"Sold 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B. request user 520000000101987 (has segment in hbi redis,but not in config), any platform', '2': 'default;A.request cfa for test user and any non existing platform to get default B. request user 520000000101987 (has segment in hbi redis,but not in config), any platform', '3': 'default;A.request cfa for test user and any non existing platform to get default B. request user 520000000101987 (has segment in hbi redis,but not in config), any platform', '4': 'default;A.request cfa for test user and any non existing platform to get default B. request user 520000000101987 (has segment in hbi redis,but not in config), any platform', '5': '*inserted_by_automated_test*', '6': '*inserted_by_automated_test*', '7': '*inserted_by_automated_test*', '8': '*inserted_by_automated_test*', '9': '*inserted_by_automated_test*', '10': 'x1', '11': 'x1', '12': 'x1', '13': 'x1', '14': 'x1', '15': 'x3', '16': 'x3', '17': 'x3', '18': 'x3', '19': 'x3'}, 'Pack Name': {'0': 'test_bingo', '1': 'test_bingo', '2': 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'14': 'N', '15': 'N', '16': 'N', '17': 'N', '18': 'N', '19': 'N'}, 'Footer Type': {'0': 1, '1': 1, '2': 1, '3': 1, '4': 1, '5': 1, '6': 1, '7': 1, '8': 1, '9': 1, '10': 1, '11': 1, '12': 1, '13': 1, '14': 1, '15': 1, '16': 1, '17': 1, '18': 1, '19': 1}, 'Footer Text': {'0': 'test_text', '1': 'test_text', '2': 'test_text', '3': 'test_text', '4': 'test_text', '5': 'test_text', '6': 'test_text', '7': 'test_text', '8': 'test_text', '9': 'test_text', '10': 'test_text', '11': 'test_text', '12': 'test_text', '13': 'test_text', '14': 'test_text', '15': 'test_text', '16': 'test_text', '17': 'test_text', '18': 'test_text', '19': 'test_text'}, 'Pack Image': {'0': 'gems_1.png', '1': 'gems_2.png', '2': 'gems_3.png', '3': 'gems_4.png', '4': 'gems_5.png', '5': 'gems_1.png', '6': 'gems_2.png', '7': 'gems_3.png', '8': 'gems_4.png', '9': 'gems_5.png', '10': 'gems_1.png', '11': 'gems_2.png', '12': 'gems_3.png', '13': 'gems_4.png', '14': 'gems_5.png', '15': 'gems_1.png', '16': 'gems_2.png', '17': 'gems_3.png', '18': 'gems_4.png', '19': 'gems_5.png'}} {'id': 0, 'segmentAlias': 'default', 'userIds': [-1], 'platforms': ['gp'], 'content': {'items': [{'name': 'default_config', 'identifier': 0, 'itemsOrder': 1, 'dollarValue': 1.99, 'remarks': 'default!', 'itemsQuantity': 5, 'is_best': 'Y', 'is_popular': 'N', 'packName': 'test_bingo', 'footerType': 1, 'footerText': 'test_text', 'soldItem': 'Gems', 'packImage': 'gems_1.png', 'SKU': 'gems_99'}, {'name': 'default_config', 'identifier': 1, 'itemsOrder': 2, 'dollarValue': 2.99, 'remarks': 'default!', 'itemsQuantity': 15, 'is_best': 'Y', 'is_popular': 'N', 'packName': 'test_bingo', 'footerType': 1, 'footerText': 'test_text', 'soldItem': 'Gems', 'packImage': 'gems_2.png', 'SKU': 'gems_99'}, {'name': 'default_config', 'identifier': 2, 'itemsOrder': 3, 'dollarValue': 3.99, 'remarks': 'default!', 'itemsQuantity': 25, 'is_best': 'Y', 'is_popular': 'N', 'packName': 'test_bingo', 'footerType': 1, 'footerText': 'test_text', 'soldItem': 'Gems', 'packImage': 'gems_3.png', 'SKU': 'gems_99'}, {'name': 'default_config', 'identifier': 3, 'itemsOrder': 4, 'dollarValue': 4.99, 'remarks': 'default!', 'itemsQuantity': 35, 'is_best': 'Y', 'is_popular': 'N', 'packName': 'test_bingo', 'footerType': 1, 'footerText': 'test_text', 'soldItem': 'Gems', 'packImage': 'gems_4.png', 'SKU': 'gems_99'}, {'name': 'default_config', 'identifier': 4, 'itemsOrder': 5, 'dollarValue': 5.99, 'remarks': 'default!', 'itemsQuantity': 45, 'is_best': 'Y', 'is_popular': 'N', 'packName': 'test_bingo', 'footerType': 1, 'footerText': 'test_text', 'soldItem': 'Gems', 'packImage': 'gems_5.png', 'SKU': 'gems_99'}]}} <class 'dict'> {'id': 1, 'segmentAlias': 's1', 'userIds': [-1], 'platforms': ['ios'], 'content': {'items': [{'name': 'gems1', 'identifier': 0, 'itemsOrder': 1, 'dollarValue': 1.99, 'remarks': 'x', 'itemsQuantity': 5, I cannot compare those dicts
You will need to read the excel file and convert it to json with pandas. Also check in which format is your json file when converting from pandas. Maybe you need to change the orientation. df = pd.read_excel(xlsx, sheet_name=sheet) json_from_excel = df.to_json(orient='records') Next you will need to order your json data here is an example function. def ordered(obj): if isinstance(obj, dict): return sorted((k, ordered(v)) for k, v in obj.items()) if isinstance(obj, list): return sorted(ordered(x) for x in obj) else: return obj And finally you can make the compare. if ordered(json_from_excel) == ordered(json_data): #do something
Changing the orientation of pyplot graph's x values
I have the following data: stage_summary = {'Day1': {'1': 100.0, '2': 0.0, '3': 0.0, '4': 0.0, '5': 0.0, '6': 0.0, '7': 0.0, '8': 0.0}, 'Day2': {'1': 100.0, '2': 0.0, '3': 0.0, '4': 0.0, '5': 0.0, '6': 0.0, '7': 0.0, '8': 0.0}, 'Day3': {'1': 89.8, '2': 10.2, '3': 0.0, '4': 0.0, '5': 0.0, '6': 0.0, '7': 0.0, '8': 0.0}, 'Day4': {'1': 58.6, '2': 41.4, '3': 0.0, '4': 0.0, '5': 0.0, '6': 0.0, '7': 0.0, '8': 0.0}, 'Day5': {'1': 52.71, '2': 47.06, '3': 0.0, '4': 0.0, '5': 0.0, '6': 0.23, '7': 0.0, '8': 0.0}, 'Day6': {'1': 47.89, '2': 50.65, '3': 0.0, '4': 0.0, '5': 0.0, '6': 1.46, '7': 0.0, '8': 0.0}, 'Day7': {'1': 49.72, '2': 46.95, '3': 0.0, '4': 0.0, '5': 0.0, '6': 3.33, '7': 0.0, '8': 0.0}, 'Day8': {'1': 52.59, '2': 39.35, '3': 0.0, '4': 0.0, '5': 0.0, '6': 8.05, '7': 0.0, '8': 0.01}, 'Day9': {'1': 55.45, '2': 30.73, '3': 0.0, '4': 0.0, '5': 0.0, '6': 13.74, '7': 0.0, '8': 0.08}} date_list = ['2019-05-28', '2019-05-29', '2019-05-30', '2019-05-31', '2019-06-03', '2019-06-04', '2019-06-05', '2019-06-06', '2019-06-07'] And I plot the data in this way, as a line graph: for each_state in list(range(1,9)): tmp = [] for each_day in stage_summary: tmp.append(stage_summary[each_day][str(each_state)]) plt.plot(date_list, tmp, label=str('State ' + str(each_state))) plt.ylabel('Probability') plt.xlabel('Days') plt.legend(loc='best') which results in the following graph, However, as you can see, the x labels are dates, which are long strings. And therefore, it has to be rotated and be presented vertically to make it readable. But I am not sure how I can change the orientation of x values in a plotly graph. How can I do so?
You are using matplotlib and not plotly, right? If yes, try: for each_state in list(range(1,9)): tmp = [] for each_day in stage_summary: tmp.append(stage_summary[each_day][str(each_state)]) plt.plot(date_list, tmp, label=str('State ' + str(each_state))) plt.ylabel('Probability') plt.xlabel('Days') plt.xticks(rotation=45) plt.legend(loc='best')
Set plotly.graph_objs.Layout.xaxis.tickangle = 90. Detail: https://plot.ly/python/axes/#set-and-style-axes-title-labels-and-ticks
How to return key for column with smallest values
I have this dictionary: d= {'1': { '2': 1, '3': 0, '4': 0, '5': 1, '6': 29 } ,'2': {'1': 13, '3': 1, '4': 0, '5': 21, '6': 0 } ,'3': {'1': 0, '2': 0, '4': 1, '5': 0, '6': 1 } ,'4': {'1': 1, '2': 17, '3': 1, '5': 2, '6': 0 } ,'5': {'1': 39, '2': 1, '3': 0, '4': 0, '6': 14 } ,'6': {'1': 0, '2': 0, '3': 43, '4': 1, '5': 0 } } I want to write a function that returns the column where all the values are <2 (less than 2). So far i have turned the dictionary into a list, and then tried a lot of things that didn't work... I know that the answer is column number 4. This was my latest attemp: def findFirstRead(overlaps): e= [[d[str(i)].get(str(j), '-') for j in range(1, 7)] for i in range(1, 7)] nested_list = e for i in map(itemgetter(x),nested_list): if i<2: return x+1 else: continue ...and it was very wrong
The following set and list comprehension lists columns where the column has a max value of 2: columns = {c for r, row in d.iteritems() for c in row} [c for c in columns if max(v.get(c, -1) for v in d.itervalues()) < 2] This returns ['4'].
Making a dictionary of overlaps from a dictionary
This problem is teasing me: I have 6 different sequences that each overlap, they are name 1-6. I have made a function that represents the sequences in a dictionary, and a function that gives me the part of the sequences that overlap. Now i should use those 2 functions to construct a dictionary that take the number of overlapping positions in both the right-to-left order and in the left-to-right oder. The dictionary I have made look like: {'1': 'GGCTCCCCACGGGGTACCCATAACTTGACAGTAGATCTCGTCCAGACCCCTAGC', '2': 'CTTTACCCGGAAGAGCGGGACGCTGCCCTGCGCGATTCCAGGCTCCCCACGGG', '3': 'GTCTTCAGTAGAAAATTGTTTTTTTCTTCCAAGAGGTCGGAGTCGTGAACACATCAGT', '4': 'TGCGAGGGAAGTGAAGTATTTGACCCTTTACCCGGAAGAGCG', '5': 'CGATTCCAGGCTCCCCACGGGGTACCCATAACTTGACAGTAGATCTC', '6': 'TGACAGTAGATCTCGTCCAGACCCCTAGCTGGTACGTCTTCAGTAGAAAATTGTTTTTTTCTTCCAAGAGGTCGGAGT'} I should end up with a result like: {'1': {'3': 0, '2': 1, '5': 1, '4': 0, '6': 29}, '3': {'1': 0, '2': 0, '5': 0, '4': 1, '6': 1}, '2': {'1': 13, '3': 1, '5': 21, '4': 0, '6': 0}, '5': {'1': 39, '3': 0, '2': 1, '4': 0, '6': 14}, '4': {'1': 1, '3': 1, '2': 17, '5': 2, '6': 0}, '6': {'1': 0, '3': 43, '2': 0, '5': 0, '4': 1}} I seems impossible. I guess it's not, so if somebody could (not do it) but push me in the right direction, it would be great.
This is a bit of a complicated one-liner, but it should work. Using find_overlaps() as the function that finds overlaps and seq_dict as the original dictionary of sequences: overlaps = {seq:{other_seq:find_overlaps(seq_dict[seq],seq_dict[other_seq]) for other_seq in seq_dict if other_seq != seq} for seq in seq_dict} Here it is with a bit nicer spacing: overlaps = \ {seq: {other_seq: find_overlaps(seq_dict[seq],seq_dict[other_seq]) for other_seq in seq_dict if other_seq != seq} for seq in seq_dict}
The clean way: dna = { '1': 'GGCTCCCCACGGGGTACCCATAACTTGACAGTAGATCTCGTCCAGACCCCTAGC', '2': 'CTTTACCCGGAAGAGCGGGACGCTGCCCTGCGCGATTCCAGGCTCCCCACGGG', '3': 'GTCTTCAGTAGAAAATTGTTTTTTTCTTCCAAGAGGTCGGAGTCGTGAACACATCAGT', '4': 'TGCGAGGGAAGTGAAGTATTTGACCCTTTACCCGGAAGAGCG', '5': 'CGATTCCAGGCTCCCCACGGGGTACCCATAACTTGACAGTAGATCTC', '6': 'TGACAGTAGATCTCGTCCAGACCCCTAGCTGGTACGTCTTCAGTAGAAAATTG' \ 'TTTTTTTCTTCCAAGAGGTCGGAGT' } def overlap(a, b): l = min(len(a), len(b)) while True: if a[-l:] == b[:l] or l == 0: return l l -= 1 def all_overlaps(d): result = {} for k1, v1 in d.items(): overlaps = {} for k2, v2 in d.items(): if k1 == k2: continue overlaps[k2] = overlap(v1, v2) result[k1] = overlaps return result print all_overlaps(dna) (By the way, you could've provided overlap yourself in the question to make it easier for everyone to answer.)