I'm trying to export a CSV to an Azure Data Lake Storage but when the file system/container does not exist the code breaks. I have also read through the documentation but I cannot seem to find anything helpful for this situation.
How do I go about creating a container in Azure Data Lake Storage if the container specified by the user does not exist?
Current Code:
try:
file_system_client = service_client.get_file_system_client(file_system="testfilesystem")
except Exception:
file_system_client = service_client.create_file_system(file_system="testfilesystem")
Traceback:
(FilesystemNotFound) The specified filesystem does not exist.
RequestId:XXXX
Time:2021-03-31T13:39:21.8860233Z
The try catch pattern should be not used here since the Azure Data lake gen2 library has the built in exists() method for file_system_client.
First, make sure you've installed the latest version library: azure-storage-file-datalake 12.3.0. If you're not sure which version you're using, please use pip show azure-storage-file-datalake command to check the current version.
Then you can use the code below:
from azure.storage.filedatalake import DataLakeServiceClient
service_client = DataLakeServiceClient(account_url="{}://{}.dfs.core.windows.net".format(
"https", "xxx"), credential="xxx")
#the get_file_system_client method will not throw error if the file system does not exist, if you're using the latest library 12.3.0
file_system_client = service_client.get_file_system_client("filesystem333")
print("the file system exists: " + str(file_system_client.exists()))
#create the file system if it does not exist
if not file_system_client.exists():
file_system_client.create_file_system()
print("the file system is created.")
#other code
I've tested it locally, it can work successfully:
I have been searching since a couple of days for a solution without success.
We have a windows service build to copy some files from one location to another one.
So I build the code shown below with Python 3.7.
The full coding can be found on Github.
When I run the service using python all is working fine, I can install the service and also start the service.
This using commands:
Install the service:
python jis53_backup.py install
Run the service:
python jis53_backup.py start
When I now compile this code using pyinstaller with command:
pyinstaller -F --hidden-import=win32timezone jis53_backup.py
After the exe is created, I can install the service but when trying to start the service I get the error:
Error starting service: The service did not respond to the start or
control request in a timely fashion
I have gone through multiple posts on Stackoverflow and on Google related to this error however, without success. I don't have the option to install the python 3.7 programs on the PC's that would need to run this service. That's why we are trying to get a .exe build.
I have made sure to have the path updated according to the information that I found in the different questions.
Image of path definitions:
I also copied the pywintypes37.dll file.
From -> Python37\Lib\site-packages\pywin32_system32
To -> Python37\Lib\site-packages\win32
Does anyone have any other suggestions on how to get this working?
'''
Windows service to copy a file from one location to another
at a certain interval.
'''
import sys
import time
from distutils.dir_util import copy_tree
import servicemanager
import win32serviceutil
import win32service
from HelperModules.CheckFileExistance import check_folder_exists, create_folder
from HelperModules.ReadConfig import (check_config_file_exists,
create_config_file, read_config_file)
from ServiceBaseClass.SMWinService import SMWinservice
sys.path += ['filecopy_service/ServiceBaseClass',
'filecopy_service/HelperModules']
class Jis53Backup(SMWinservice):
_svc_name_ = "Jis53Backup"
_svc_display_name_ = "JIS53 backup copy"
_svc_description_ = "Service to copy files from server to local drive"
def start(self):
self.conf = read_config_file()
if not check_folder_exists(self.conf['dest']):
create_folder(self.conf['dest'])
self.isrunning = True
def stop(self):
self.isrunning = False
def main(self):
self.ReportServiceStatus(win32service.SERVICE_RUNNING)
while self.isrunning:
# Copy the files from the server to a local folder
# TODO: build function to trigger only when a file is changed.
copy_tree(self.conf['origin'], self.conf['dest'], update=1)
time.sleep(30)
if __name__ == '__main__':
if sys.argv[1] == 'install':
if not check_config_file_exists():
create_config_file()
if len(sys.argv) == 1:
servicemanager.Initialize()
servicemanager.PrepareToHostSingle(Jis53Backup)
servicemanager.StartServiceCtrlDispatcher()
else:
win32serviceutil.HandleCommandLine(Jis53Backup)
I was also facing this issue after compiling using pyinstaller. For me, the issue was that I was using the paths to configs and logs file in dynamic way, for ex:
curr_path = os.path.dirname(os.path.abspath(__file__))
configs_path = os.path.join(curr_path, 'configs', 'app_config.json')
opc_configs_path = os.path.join(curr_path, 'configs', 'opc.json')
log_file_path = os.path.join(curr_path, 'logs', 'application.log')
This was working fine when I was starting the service using python service.py install/start. But after compiling it using pyinstaller, it always gave me error of not starting in timely fashion.
To resolve this, I made all the dynamic paths to static, for ex:
configs_path = 'C:\\Program Files (x86)\\ScantechOPC\\configs\\app_config.json'
opc_configs_path = 'C:\\Program Files (x86)\\ScantechOPC\\configs\\opc.json'
debug_file = 'C:\\Program Files (x86)\\ScantechOPC\\logs\\application.log'
After compiling via pyinstaller, it is now working fine without any error. Looks like when we do dynamic path, it doesn't get the actual path to files and thus it gives error.
Hope this solves your problem too. Thanks
I am working on a script to transfer some files to a Cisco IOS device using netmiko FileTransfer. Below is the code that I found to accomplish this. However I cant seem to find where the source_file should be or how to specify where on the host that files lives. How do I specify where to copy that file from?
dest_file_system = 'disk0:/'
source_file = 'test1.txt' # where should this file be live?
dest_file = 'test1.txt'
with FileTransfer(ssh_conn, source_file=source_file, dest_file=dest_file,
file_system=dest_file_system) as scp_transfer:
if not scp_transfer.check_file_exists():
if not scp_transfer.verify_space_available():
raise ValueError("Insufficient space available on remote device")
print("\nTransferring file\n")
scp_transfer.transfer_file()
The source file from the scripts perspective if you simple want to call it by name should be in the same directory as the script itself. If you want to move the file to a new directory the search path in the script is relative to the directory the script is run from. Example 1 - The file_name.txt is in the same directory as your script In your script simply call the file source = "file_name.txt". Example 2 create test_folder in current directory that holds your script and call it test_folder move the file_name.txt into test_folder. In your script your source variable would no need to look like this source = "test_folder/file_name.txt"
Hopefully, till now you found the solution already. If not then You can try the netmiko file transfer feature also. That will be a more secure and efficient way to do it.
try below sample script.
from getpass import getpass
from netmiko import ConnectHandler, file_transfer
password = getpass()
cisco = {
"device_type": "cisco_ios",
"host": "cisco1.twb-tech.com",
"username": "pyclass",
"password": password,
}
source_file = "test1.txt"
dest_file = "test1.txt"
direction = "put"
file_system = "flash:"
ssh_conn = ConnectHandler(**cisco)
transfer_dict = file_transfer(
ssh_conn,
source_file=source_file,
dest_file=dest_file,
file_system=file_system,
direction=direction,
overwrite_file=True,
)
print(transfer_dict)
I need to add the win_unicode_console module to my usercustomize.py file, as described by the documentation.
I've discovered my user site packages directory with:
>>> import site
>>> site.getusersitepackages()
'C:\\Users\\my name\\AppData\\Roaming\\Python\\Python35\\site-packages'
I haven't been able to get to this directory using any method. I've tried using pushd instead of cd to emulate a network drive, and I've also tried getting there using run. No matter what I do in python, or in cmd terminal. I get the response The network path was not found.
Here is an example of one I've tried in cmd:
C:\>pushd \\Users\\my name\\AppData\\Roaming\\Python\\Python35\\site-packages
The network path was not found.
What am I doing wrong, or what could be wrong with the path?
DOS style backslashes don't need to be escaped within the Windows console (else they may have used forward slashes way back when!).
Follow these steps to manually create usercustomize.py:
Start->Run:cmd
Make sure you're on the C: drive
c:
Create the directory. mkdir creates the missing parents. Obviously, change "my name" as appropriate.
mkdir C:\Users\my name\AppData\Roaming\Python\Python35\site-packages
Create usercustomize.py:
notepad C:\Users\my name\AppData\Roaming\Python\Python35\site-packages\usercustomize.py
Click "yes" to create your file.
Edit as appropriate
Or use the following script to have Python do it for you:
import site
import os
import os.path
import io
user_site_dir = site.getusersitepackages()
user_customize_filename = os.path.join(user_site_dir, 'usercustomize.py')
win_unicode_console_text = u"""
# win_unicode_console
import win_unicode_console
win_unicode_console.enable()
"""
if os.path.exists(user_site_dir):
print("User site dir already exists")
else:
print("Creating site dir")
os.makedirs(user_site_dir)
if not os.path.exists(user_customize_filename):
print("Creating {filename}".format(filename=user_customize_filename))
file_mode = 'w+t'
else:
print("{filename} already exists".format(filename=user_customize_filename))
file_mode = 'r+t'
with io.open(user_customize_filename, file_mode) as user_customize_file:
existing_text = user_customize_file.read()
if not win_unicode_console_text in existing_text:
# file pointer should already be at the end of the file after read()
user_customize_file.write(win_unicode_console_text)
print("win_unicode_console added to {filename}".format(filename=user_customize_filename))
else:
print("win_unicode_console already enabled")
I am trying to obtain the current NoteBook name when running the IPython notebook. I know I can see it at the top of the notebook. What I am after something like
currentNotebook = IPython.foo.bar.notebookname()
I need to get the name in a variable.
adding to previous answers,
to get the notebook name run the following in a cell:
%%javascript
IPython.notebook.kernel.execute('nb_name = "' + IPython.notebook.notebook_name + '"')
this gets you the file name in nb_name
then to get the full path you may use the following in a separate cell:
import os
nb_full_path = os.path.join(os.getcwd(), nb_name)
I have the following which works with IPython 2.0. I observed that the name of the notebook is stored as the value of the attribute 'data-notebook-name' in the <body> tag of the page. Thus the idea is first to ask Javascript to retrieve the attribute --javascripts can be invoked from a codecell thanks to the %%javascript magic. Then it is possible to access to the Javascript variable through a call to the Python Kernel, with a command which sets a Python variable. Since this last variable is known from the kernel, it can be accessed in other cells as well.
%%javascript
var kernel = IPython.notebook.kernel;
var body = document.body,
attribs = body.attributes;
var command = "theNotebook = " + "'"+attribs['data-notebook-name'].value+"'";
kernel.execute(command);
From a Python code cell
print(theNotebook)
Out[ ]: HowToGetTheNameOfTheNoteBook.ipynb
A defect in this solution is that when one changes the title (name) of a notebook, then this name seems to not be updated immediately (there is probably some kind of cache) and it is necessary to reload the notebook to get access to the new name.
[Edit] On reflection, a more efficient solution is to look for the input field for notebook's name instead of the <body> tag. Looking into the source, it appears that this field has id "notebook_name". It is then possible to catch this value by a document.getElementById() and then follow the same approach as above. The code becomes, still using the javascript magic
%%javascript
var kernel = IPython.notebook.kernel;
var thename = window.document.getElementById("notebook_name").innerHTML;
var command = "theNotebook = " + "'"+thename+"'";
kernel.execute(command);
Then, from a ipython cell,
In [11]: print(theNotebook)
Out [11]: HowToGetTheNameOfTheNoteBookSolBis
Contrary to the first solution, modifications of notebook's name are updated immediately and there is no need to refresh the notebook.
As already mentioned you probably aren't really supposed to be able to do this, but I did find a way. It's a flaming hack though so don't rely on this at all:
import json
import os
import urllib2
import IPython
from IPython.lib import kernel
connection_file_path = kernel.get_connection_file()
connection_file = os.path.basename(connection_file_path)
kernel_id = connection_file.split('-', 1)[1].split('.')[0]
# Updated answer with semi-solutions for both IPython 2.x and IPython < 2.x
if IPython.version_info[0] < 2:
## Not sure if it's even possible to get the port for the
## notebook app; so just using the default...
notebooks = json.load(urllib2.urlopen('http://127.0.0.1:8888/notebooks'))
for nb in notebooks:
if nb['kernel_id'] == kernel_id:
print nb['name']
break
else:
sessions = json.load(urllib2.urlopen('http://127.0.0.1:8888/api/sessions'))
for sess in sessions:
if sess['kernel']['id'] == kernel_id:
print sess['notebook']['name']
break
I updated my answer to include a solution that "works" in IPython 2.0 at least with a simple test. It probably isn't guaranteed to give the correct answer if there are multiple notebooks connected to the same kernel, etc.
It seems I cannot comment, so I have to post this as an answer.
The accepted solution by #iguananaut and the update by #mbdevpl appear not to be working with recent versions of the Notebook.
I fixed it as shown below. I checked it on Python v3.6.1 + Notebook v5.0.0 and on Python v3.6.5 and Notebook v5.5.0.
import jupyterlab
if jupyterlab.__version__.split(".")[0] == "3":
from jupyter_server import serverapp as app
key_srv_directory = 'root_dir'
else :
from notebook import notebookapp as app
key_srv_directory = 'notebook_dir'
import urllib
import json
import os
import ipykernel
def notebook_path(key_srv_directory, ):
"""Returns the absolute path of the Notebook or None if it cannot be determined
NOTE: works only when the security is token-based or there is also no password
"""
connection_file = os.path.basename(ipykernel.get_connection_file())
kernel_id = connection_file.split('-', 1)[1].split('.')[0]
for srv in app.list_running_servers():
try:
if srv['token']=='' and not srv['password']: # No token and no password, ahem...
req = urllib.request.urlopen(srv['url']+'api/sessions')
else:
req = urllib.request.urlopen(srv['url']+'api/sessions?token='+srv['token'])
sessions = json.load(req)
for sess in sessions:
if sess['kernel']['id'] == kernel_id:
return os.path.join(srv[key_srv_directory],sess['notebook']['path'])
except:
pass # There may be stale entries in the runtime directory
return None
As stated in the docstring, this works only when either there is no authentication or the authentication is token-based.
Note that, as also reported by others, the Javascript-based method does not seem to work when executing a "Run all cells" (but works when executing cells "manually"), which was a deal-breaker for me.
The ipyparams package can do this pretty easily.
import ipyparams
currentNotebook = ipyparams.notebook_name
On Jupyter 3.0 the following works. Here I'm showing the entire path on the Jupyter server, not just the notebook name:
To store the NOTEBOOK_FULL_PATH on the current notebook front end:
%%javascript
var nb = IPython.notebook;
var kernel = IPython.notebook.kernel;
var command = "NOTEBOOK_FULL_PATH = '" + nb.base_url + nb.notebook_path + "'";
kernel.execute(command);
To then display it:
print("NOTEBOOK_FULL_PATH:\n", NOTEBOOK_FULL_PATH)
Running the first Javascript cell produces no output.
Running the second Python cell produces something like:
NOTEBOOK_FULL_PATH:
/user/zeph/GetNotebookName.ipynb
Yet another hacky solution since my notebook server can change. Basically you print a random string, save it and then search for a file containing that string in the working directory. The while is needed because save_checkpoint is asynchronous.
from time import sleep
from IPython.display import display, Javascript
import subprocess
import os
import uuid
def get_notebook_path_and_save():
magic = str(uuid.uuid1()).replace('-', '')
print(magic)
# saves it (ctrl+S)
display(Javascript('IPython.notebook.save_checkpoint();'))
nb_name = None
while nb_name is None:
try:
sleep(0.1)
nb_name = subprocess.check_output(f'grep -l {magic} *.ipynb', shell=True).decode().strip()
except:
pass
return os.path.join(os.getcwd(), nb_name)
There is no real way yet to do this in Jupyterlab. But there is an official way that's now under active discussion/development as of August 2021:
https://github.com/jupyter/jupyter_client/pull/656
In the meantime, hitting the api/sessions REST endpoint of jupyter_server seems like the best bet. Here's a cleaned-up version of that approach:
from jupyter_server import serverapp
from jupyter_server.utils import url_path_join
from pathlib import Path
import re
import requests
kernelIdRegex = re.compile(r"(?<=kernel-)[\w\d\-]+(?=\.json)")
def getNotebookPath():
kernelId = kernelIdRegex.search(get_ipython().config["IPKernelApp"]["connection_file"])[0]
for jupServ in serverapp.list_running_servers():
for session in requests.get(url_path_join(jupServ["url"], "api/sessions"), params={"token": jupServ["token"]}).json():
if kernelId == session["kernel"]["id"]:
return Path(jupServ["root_dir"]) / session["notebook"]['path']
Tested working with
python==3.9
jupyter_server==1.8.0
jupyterlab==4.0.0a7
Modifying #jfb method, gives the function below which worked fine on ipykernel-5.3.4.
def getNotebookName():
display(Javascript('IPython.notebook.kernel.execute("NotebookName = " + "\'"+window.document.getElementById("notebook_name").innerHTML+"\'");'))
try:
_ = type(NotebookName)
return NotebookName
except:
return None
Note that the display javascript will take some time to reach the browser, and it will take some time to execute the JS and get back to the kernel. I know it may sound stupid, but it's better to run the function in two cells, like this:
nb_name = getNotebookName()
and in the following cell:
for i in range(10):
nb_name = getNotebookName()
if nb_name is not None:
break
However, if you don't need to define a function, the wise method is to run display(Javascript(..)) in one cell, and check the notebook name in another cell. In this way, the browser has enough time to execute the code and return the notebook name.
If you don't mind to use a library, the most robust way is:
import ipynbname
nb_name = ipynbname.name()
If you are using Visual Studio Code:
import IPython ; IPython.extract_module_locals()[1]['__vsc_ipynb_file__']
Assuming you have the Jupyter Notebook server's host, port, and authentication token, this should work for you. It's based off of this answer.
import os
import json
import posixpath
import subprocess
import urllib.request
import psutil
def get_notebook_path(host, port, token):
process_id = os.getpid();
notebooks = get_running_notebooks(host, port, token)
for notebook in notebooks:
if process_id in notebook['process_ids']:
return notebook['path']
def get_running_notebooks(host, port, token):
sessions_url = posixpath.join('http://%s:%d' % (host, port), 'api', 'sessions')
sessions_url += f'?token={token}'
response = urllib.request.urlopen(sessions_url).read()
res = json.loads(response)
notebooks = [{'kernel_id': notebook['kernel']['id'],
'path': notebook['notebook']['path'],
'process_ids': get_process_ids(notebook['kernel']['id'])} for notebook in res]
return notebooks
def get_process_ids(name):
child = subprocess.Popen(['pgrep', '-f', name], stdout=subprocess.PIPE, shell=False)
response = child.communicate()[0]
return [int(pid) for pid in response.split()]
Example usage:
get_notebook_path('127.0.0.1', 17004, '344eb91bee5742a8501cc8ee84043d0af07d42e7135bed90')
To realize why you can't get notebook name using these JS-based solutions, run this code and notice the delay it takes for the message box to appear after python has finished execution of the cell / entire notebook:
%%javascript
function sayHello() {
alert('Hello world!');
}
setTimeout(sayHello, 1000);
More info
Javascript calls are async and hence not guaranteed to complete before python starts running another cell containing the code expecting this notebook name variable to be already created... resulting in NameError when trying to access non-existing variables that should contain notebook name.
I suspect some upvotes on this page became locked before voters could discover that all %%javascript-based solutions ultimately don't work... when the producer and consumer notebook cells are executed together (or in a quick succession).
All Json based solutions fail if we execute more than one cell at a time
because the result will not be ready until after the end of the execution
(its not a matter of using sleep or waiting any time, check it yourself but remember to restart kernel and run all every test)
Based on previous solutions, this avoids using the %% magic in case you need to put it in the middle of some other code:
from IPython.display import display, Javascript
# can have comments here :)
js_cmd = 'IPython.notebook.kernel.execute(\'nb_name = "\' + IPython.notebook.notebook_name + \'"\')'
display(Javascript(js_cmd))
For python 3, the following based on the answer by #Iguananaut and updated for latest python and possibly multiple servers will work:
import os
import json
try:
from urllib2 import urlopen
except:
from urllib.request import urlopen
import ipykernel
connection_file_path = ipykernel.get_connection_file()
connection_file = os.path.basename(connection_file_path)
kernel_id = connection_file.split('-', 1)[1].split('.')[0]
running_servers = !jupyter notebook list
running_servers = [s.split('::')[0].strip() for s in running_servers[1:]]
nb_name = '???'
for serv in running_servers:
uri_parts = serv.split('?')
uri_parts[0] += 'api/sessions'
sessions = json.load(urlopen('?'.join(uri_parts)))
for sess in sessions:
if sess['kernel']['id'] == kernel_id:
nb_name = os.path.basename(sess['notebook']['path'])
break
if nb_name != '???':
break
print (f'[{nb_name}]')
just use ipynbname , which is practical
import ipynbname
nb_fname = ipynbname.name()
nb_path = ipynbname.path()
print(f"{nb_fname=}")
print(f"{nb_path=}")
I found this in https://stackoverflow.com/a/65907473/15497427