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I am trying to create a multi-layered perceptron for the purpose of classifying a dataset of hand drawn digits obtained from the MNIST database. It implements 2 hidden layers that have a sigmoid activation function while the output layer utilizes SoftMax. However, for whatever reason I am not able to get it to work. I have attached the training loop from my code below, this I am confident is where the problems stems from. Can anyone identify possible issues with my implementation of the perceptron?
def train(self, inputs, targets, eta, niterations):
"""
inputs is a numpy array of shape (num_train, D) containing the training images
consisting of num_train samples each of dimension D.
targets is a numpy array of shape (num_train, D) containing the training labels
consisting of num_train samples each of dimension D.
eta is the learning rate for optimization
niterations is the number of iterations for updating the weights
"""
ndata = np.shape(inputs)[0] # number of data samples
# adding the bias
inputs = np.concatenate((inputs, -np.ones((ndata, 1))), axis=1)
# numpy array to store the update weights
updatew1 = np.zeros((np.shape(self.weights1)))
updatew2 = np.zeros((np.shape(self.weights2)))
updatew3 = np.zeros((np.shape(self.weights3)))
for n in range(niterations):
# forward phase
self.outputs = self.forwardPass(inputs)
# Error using the sum-of-squares error function
error = 0.5*np.sum((self.outputs-targets)**2)
if (np.mod(n, 100) == 0):
print("Iteration: ", n, " Error: ", error)
# backward phase
deltao = self.outputs - targets
placeholder = np.zeros(np.shape(self.outputs))
for j in range(np.shape(self.outputs)[1]):
y = self.outputs[:, j]
placeholder[:, j] = y * (1 - y)
for y in range(np.shape(self.outputs)[1]):
if not y == j:
placeholder[:, j] += -y * self.outputs[:, y]
deltao *= placeholder
# compute the derivative of the second hidden layer
deltah2 = np.dot(deltao, np.transpose(self.weights3))
deltah2 = self.hidden2*self.beta*(1.0-self.hidden2)*deltah2
# compute the derivative of the first hidden layer
deltah1 = np.dot(deltah2[:, :-1], np.transpose(self.weights2))
deltah1 = self.hidden1*self.beta*(1.0-self.hidden1)*deltah1
# update the weights of the three layers: self.weights1, self.weights2 and self.weights3
updatew1 = eta*(np.dot(np.transpose(inputs),deltah1[:, :-1])) + (self.momentum * updatew1)
updatew2 = eta*(np.dot(np.transpose(self.hidden1),deltah2[:, :-1])) + (self.momentum * updatew2)
updatew3 = eta*(np.dot(np.transpose(self.hidden2),deltao)) + (self.momentum * updatew3)
self.weights1 -= updatew1
self.weights2 -= updatew2
self.weights3 -= updatew3
def forwardPass(self, inputs):
"""
inputs is a numpy array of shape (num_train, D) containing the training images
consisting of num_train samples each of dimension D.
"""
# layer 1
# the forward pass on the first hidden layer with the sigmoid function
self.hidden1 = np.dot(inputs, self.weights1)
self.hidden1 = 1.0/(1.0+np.exp(-self.beta*self.hidden1))
self.hidden1 = np.concatenate((self.hidden1, -np.ones((np.shape(self.hidden1)[0], 1))), axis=1)
# layer 2
# the forward pass on the second hidden layer with the sigmoid function
self.hidden2 = np.dot(self.hidden1, self.weights2)
self.hidden2 = 1.0/(1.0+np.exp(-self.beta*self.hidden2))
self.hidden2 = np.concatenate((self.hidden2, -np.ones((np.shape(self.hidden2)[0], 1))), axis=1)
# output layer
# the forward pass on the output layer with softmax function
outputs = np.dot(self.hidden2, self.weights3)
outputs = np.exp(outputs)
outputs /= np.repeat(np.sum(outputs, axis=1),outputs.shape[1], axis=0).reshape(outputs.shape)
return outputs
Update: I have since figured something out that I messed up during the backpropagation of the SoftMax algorithm. The actual deltao should be:
deltao = self.outputs - targets
placeholder = np.zeros(np.shape(self.outputs))
for j in range(np.shape(self.outputs)[1]):
y = self.outputs[:, j]
placeholder[:, j] = y * (1 - y)
# the counter for the for loop below used to also be named y causing confusion
for i in range(np.shape(self.outputs)[1]):
if not i == j:
placeholder[:, j] += -y * self.outputs[:, i]
deltao *= placeholder
After this correction the overflow errors have seemed to have sorted themselves however, there is now a new problem, no matter my efforts the accuracy of the perceptron does not exceed 15% no matter what variables I change
Second Update: After a long time I have finally found a way to get my code to work. I had to change the backpropogation of SoftMax (in code this is called deltao) to the following:
deltao = np.exp(self.outputs)
deltao/=np.repeat(np.sum(deltao,axis=1),deltao.shape[1]).reshape(deltao.shape)
deltao = deltao * (1 - deltao)
deltao *= (self.outputs - targets)/np.shape(inputs)[0]
Only problem is I have no idea why this works as a derivative of SoftMax could anyone explain this?
This code is built up as follows: My robot takes a picture, some tf computer vision model calculates where in the picture the target object starts. This information (x1 and x2 coordinate) is passed to a pytorch model. It should learn to predict the correct motor activations, in order to get closer to the target. After the movement is executed, the robot takes a picture again and the tf cv model should calculate whether the motor activation brought the robot closer to the desired state (x1 at 10, x2 coordinate at at31)
However every time i run the code pytorch is not able to calculate the gradients.
I'm wondering if this is some data-type problem or if it is a more general one: Is it impossible to calculate the gradients if the loss is not calculated directly from the pytorch network's output?
Any help and suggestions will be greatly appreciated.
#define policy model (model to learn a policy for my robot)
import torch
import torch.nn as nn
import torch.nn.functional as F
class policy_gradient_model(nn.Module):
def __init__(self):
super(policy_gradient_model, self).__init__()
self.fc0 = nn.Linear(2, 2)
self.fc1 = nn.Linear(2, 32)
self.fc2 = nn.Linear(32, 64)
self.fc3 = nn.Linear(64,32)
self.fc4 = nn.Linear(32,32)
self.fc5 = nn.Linear(32, 2)
def forward(self,x):
x = self.fc0(x)
x = F.relu(self.fc1(x))
x = F.relu(self.fc2(x))
x = F.relu(self.fc3(x))
x = F.relu(self.fc4(x))
x = F.relu(self.fc5(x))
return x
policy_model = policy_gradient_model().double()
print(policy_model)
optimizer = torch.optim.AdamW(policy_model.parameters(), lr=0.005, betas=(0.9,0.999), eps=1e-08, weight_decay=0.01, amsgrad=False)
#make robot move as predicted by pytorch network (not all code included)
def move(motor_controls):
#define curvature
# motor_controls[0] = sigmoid(motor_controls[0])
activation_left = 1+(motor_controls[0])*99
activation_right = 1+(1- motor_controls[0])*99
print("activation left:", activation_left, ". activation right:",activation_right, ". time:", motor_controls[1]*100)
#start movement
#main
import cv2
import numpy as np
import time
from torch.autograd import Variable
print("start training")
losses=[]
losses_end_of_epoch=[]
number_of_steps_each_epoch=[]
loss_function = nn.MSELoss(reduction='mean')
#each epoch
for epoch in range(2):
count=0
target_reached=False
while target_reached==False:
print("epoch: ", epoch, ". step:", count)
###process and take picture
indices = process_picture()
###binary_network(sliced)=indices as input for policy model
optimizer.zero_grad()
###output: 1 for curvature, 1 for duration of movement
motor_controls = policy_model(Variable(torch.from_numpy(indices))).detach().numpy()
print("NO TANH output for motor: 1)activation left, 2)time ", motor_controls)
motor_controls[0] = np.tanh(motor_controls[0])
motor_controls[1] = np.tanh(motor_controls[1])
print("TANH output for motor: 1)activation left, 2)time ", motor_controls)
###execute suggested action
move(motor_controls)
###take and process picture2 (after movement)
indices = (process_picture())
###loss=(binary_network(picture2) - desired
print("calculate loss")
print("idx", indices, type(torch.tensor(indices)))
# loss = 0
# loss = (indices[0]-10)**2+(indices[1]-31)**2
# loss = loss/2
print("shape of indices", indices.shape)
array=np.zeros((1,2))
array[0]=indices
print(array.shape, type(array))
array2 = torch.ones([1,2])
loss = loss_function(torch.tensor(array).double(), torch.tensor([[10.0,31.0]]).double()).float()
print("loss: ", loss, type(loss), loss.shape)
# array2[0] = loss_function(torch.tensor(array).double(),
torch.tensor([[10.0,31.0]]).double()).float()
losses.append(loss)
#start line causing the error-message (still part of main)
###calculate gradients
loss.backward()
#end line causing the error-message (still part of main)
###apply gradients
optimizer.step()
#Output (so far as intented) (not all included)
#calculate loss
idx [14. 15.] <class 'torch.Tensor'>
shape of indices (2,)
(1, 2) <class 'numpy.ndarray'>
loss: tensor(136.) <class 'torch.Tensor'> torch.Size([])
#Error Message:
Traceback (most recent call last):
File "/home/pi/Desktop/GradientPolicyLearning/PolicyModel.py", line 259, in <module>
array2.backward()
File "/home/pi/.local/lib/python3.7/site-packages/torch/tensor.py", line 134, in backward
torch.autograd.backward(self, gradient, retain_graph, create_graph)
File "/home/pi/.local/lib/python3.7/site-packages/torch/autograd/__init__.py", line 99, in
backward
allow_unreachable=True) # allow_unreachable flag
RuntimeError: element 0 of tensors does not require grad and does not have a grad_fn
If you call .detach() on the prediction, that will delete the gradients. Since you are first getting indices from the model and then trying to backprop the error, I would suggest
prediction = policy_model(torch.from_numpy(indices))
motor_controls = prediction.clone().detach().numpy()
This would keep the predictions as it is with the calculated gradients that can be backproped.
Now you can do
loss = loss_function(prediction, torch.tensor([[10.0,31.0]]).double()).float()
Note, you might wanna call double of the prediction if it throws an error.
It is indeed impossible to calculate the gradients if the loss is not calculated directly from the PyTorch network's output because then you would not be able to apply the chain rule which is used to optimise the gradients.
simple solution, turn on the Context Manager that sets gradient calculation to ON, if it is off
torch.set_grad_enabled(True) # Context-manager
Make sure that all your inputs into the NN, the output of NN and ground truth/target values are all of type torch.tensor and not list, numpy.array or any other iterable.
Also, make sure that they are not converted to list or numpy.array at any point either.
In my case, I got this error because I performed list comprehension on the tensor containing predicted values from NN. I did this to get the max value in each row. Then, converted the list back to a torch.tensor. before calculating the loss.
This back and forth conversion disables the gradient calculations
In my case, I got past this error by specifying requires_grad=True when defining my input tensors
import numpy as np
import matplotlib.pyplot as plt
plt.style.use('dark_background')
# define rosenbrock function and gradient
a = 1
b = 5
def f(x):
return (a - x[0]) ** 2 + b * (x[1] - x[0] ** 2) ** 2
def jac(x):
dx1 = -2 * a + 4 * b * x[0] ** 3 - 4 * b * x[0] * x[1] + 2 * x[0]
dx2 = 2 * b * (x[1] - x[0] ** 2)
return np.array([dx1, dx2])
# create stochastic rosenbrock function and gradient
def f_rand(x):
return f(x) * np.random.uniform(0.5, 1.5)
def jac_rand(x): return jac(x) * np.random.uniform(0.5, 1.5)
# use hand coded adam
x = np.array([0.1, 0.1])
x0 = x.copy()
j = jac_rand(x)
beta1=0.9
beta2=0.999
eps=1e-8
m = x * 0
v = x * 0
learning_rate = .1
for ii in range(200):
m = (1 - beta1) * j + beta1 * m # first moment estimate.
v = (1 - beta2) * (j ** 2) + beta2 * v # second moment estimate.
mhat = m / (1 - beta1 ** (ii + 1)) # bias correction.
vhat = v / (1 - beta2 ** (ii + 1))
x = x - learning_rate * mhat / (np.sqrt(vhat) + eps)
x -= learning_rate * v
j = jac_rand(x)
print('hand code finds optimal to be ', x, f(x))
# attempt to use pytorch
import torch
x_tensor = torch.tensor(x0, requires_grad=True)
optimizer = torch.optim.Adam([x_tensor], lr=learning_rate)
def closure():
optimizer.zero_grad()
loss = f_rand(x_tensor)
loss.backward()
return loss
for ii in range(200):
optimizer.step(closure)
print('My PyTorch attempt found ', x_tensor, f(x_tensor))
Following worked for me:
loss.requires_grad = True
loss.backward()
I have a following loop where I am calculating softmax transform for batches of different sizes as below
import numpy as np
def softmax(Z,arr):
"""
:param Z: numpy array of any shape (output from hidden layer)
:param arr: numpy array of any shape (start, end)
:return A: output of multinum_logit(Z,arr), same shape as Z
:return cache: returns Z as well, useful during back propagation
"""
A = np.zeros(Z.shape)
for i in prange(len(arr)):
shiftx = Z[:,arr[i,1]:arr[i,2]+1] - np.max(Z[:,int(arr[i,1]):int(arr[i,2])+1])
A[:,arr[i,1]:arr[i,2]+1] = np.exp(shiftx)/np.exp(shiftx).sum()
cache = Z
return A,cache
Since this for loop is not vectorized it is the bottleneck in my code. What is a possible solution to make it faster. I have tried using #jit of numba which makes it little faster but not enough. I was wondering if there is another way to make it faster or vectorize/parallelize it.
Sample input data for the function
Z = np.random.random([1,10000])
arr = np.zeros([100,3])
arr[:,0] = 1
temp = int(Z.shape[1]/arr.shape[0])
for i in range(arr.shape[0]):
arr[i,1] = i*temp
arr[i,2] = (i+1)*temp-1
arr = arr.astype(int)
EDIT:
I forgot to stress here that my number of class is varying. For example batch 1 has say 10 classes, batch 2 may have 15 classes. Therefore I am passing an array arr which keeps track of the which rows belong to batch1 and so on. These batches are different than the batches in traditional neural network framework
In the above example arr keeps track of starting index and end index of rows. So the denominator in the softmax function will be sum of only those observations whose index lie between the starting and ending index.
Here's a vectorized softmax function. It's the implementation of an assignment from Stanford's cs231n course on conv nets.
The function takes in optimizable parameters, input data, targets, and a regularizer. (You can ignore the regularizer as that references another class exclusive to some cs231n assignments).
It returns a loss and gradients of the parameters.
def softmax_loss_vectorized(W, X, y, reg):
"""
Softmax loss function, vectorized version.
Inputs and outputs are the same as softmax_loss_naive.
"""
# Initialize the loss and gradient to zero.
loss = 0.0
dW = np.zeros_like(W)
num_train = X.shape[0]
scores = X.dot(W)
shift_scores = scores - np.amax(scores,axis=1).reshape(-1,1)
softmax = np.exp(shift_scores)/np.sum(np.exp(shift_scores), axis=1).reshape(-1,1)
loss = -np.sum(np.log(softmax[range(num_train), list(y)]))
loss /= num_train
loss += 0.5* reg * np.sum(W * W)
dSoftmax = softmax.copy()
dSoftmax[range(num_train), list(y)] += -1
dW = (X.T).dot(dSoftmax)
dW = dW/num_train + reg * W
return loss, dW
For comparison's sake, here is a naive (non-vectorized) implementation of the same method.
def softmax_loss_naive(W, X, y, reg):
"""
Softmax loss function, naive implementation (with loops)
Inputs have dimension D, there are C classes, and we operate on minibatches
of N examples.
Inputs:
- W: A numpy array of shape (D, C) containing weights.
- X: A numpy array of shape (N, D) containing a minibatch of data.
- y: A numpy array of shape (N,) containing training labels; y[i] = c means
that X[i] has label c, where 0 <= c < C.
- reg: (float) regularization strength
Returns a tuple of:
- loss as single float
- gradient with respect to weights W; an array of same shape as W
"""
loss = 0.0
dW = np.zeros_like(W)
num_train = X.shape[0]
num_classes = W.shape[1]
for i in xrange(num_train):
scores = X[i].dot(W)
shift_scores = scores - max(scores)
loss_i = -shift_scores[y[i]] + np.log(sum(np.exp(shift_scores)))
loss += loss_i
for j in xrange(num_classes):
softmax = np.exp(shift_scores[j])/sum(np.exp(shift_scores))
if j==y[i]:
dW[:,j] += (-1 + softmax) * X[i]
else:
dW[:,j] += softmax *X[i]
loss /= num_train
loss += 0.5 * reg * np.sum(W * W)
dW /= num_train + reg * W
return loss, dW
Source
I've created a neural network to estimate the sin(x) function for an input x. The network has 21 output neurons (representing numbers -1.0, -0.9, ..., 0.9, 1.0) with numpy that does not learn, as I think I implemented the neuron architecture incorrectly when I defined the feedforward mechanism.
When I execute the code, the amount of test data it estimates correctly sits around 48/1000. This happens to be the average data point count per category if you split 1000 test data points between 21 categories. Looking at the network output, you can see that the network seems to just start picking a single output value for every input. For example, it may pick -0.5 as the estimate for y regardless of the x you give it. Where did I go wrong here? This is my first network. Thank you!
import random
import numpy as np
import math
class Network(object):
def __init__(self,inputLayerSize,hiddenLayerSize,outputLayerSize):
#Create weight vector arrays to represent each layer size and initialize indices randomly on a Gaussian distribution.
self.layer1 = np.random.randn(hiddenLayerSize,inputLayerSize)
self.layer1_activations = np.zeros((hiddenLayerSize, 1))
self.layer2 = np.random.randn(outputLayerSize,hiddenLayerSize)
self.layer2_activations = np.zeros((outputLayerSize, 1))
self.outputLayerSize = outputLayerSize
self.inputLayerSize = inputLayerSize
self.hiddenLayerSize = hiddenLayerSize
# print(self.layer1)
# print()
# print(self.layer2)
# self.weights = [np.random.randn(y,x)
# for x, y in zip(sizes[:-1], sizes[1:])]
def feedforward(self, network_input):
#Propogate forward through network as if doing this by hand.
#first layer's output activations:
for neuron in range(self.hiddenLayerSize):
self.layer1_activations[neuron] = 1/(1+np.exp(network_input * self.layer1[neuron]))
#second layer's output activations use layer1's activations as input:
for neuron in range(self.outputLayerSize):
for weight in range(self.hiddenLayerSize):
self.layer2_activations[neuron] += self.layer1_activations[weight]*self.layer2[neuron][weight]
self.layer2_activations[neuron] = 1/(1+np.exp(self.layer2_activations[neuron]))
#convert layer 2 activation numbers to a single output. The neuron (weight vector) with highest activation will be output.
outputs = [x / 10 for x in range(-int((self.outputLayerSize/2)), int((self.outputLayerSize/2))+1, 1)] #range(-10, 11, 1)
return(outputs[np.argmax(self.layer2_activations)])
def train(self, training_pairs, epochs, minibatchsize, learn_rate):
#apply gradient descent
test_data = build_sinx_data(1000)
for epoch in range(epochs):
random.shuffle(training_pairs)
minibatches = [training_pairs[k:k + minibatchsize] for k in range(0, len(training_pairs), minibatchsize)]
for minibatch in minibatches:
loss = 0 #calculate loss for each minibatch
#Begin training
for x, y in minibatch:
network_output = self.feedforward(x)
loss += (network_output - y) ** 2
#adjust weights by abs(loss)*sigmoid(network_output)*(1-sigmoid(network_output)*learn_rate
loss /= (2*len(minibatch))
adjustWeights = loss*(1/(1+np.exp(-network_output)))*(1-(1/(1+np.exp(-network_output))))*learn_rate
self.layer1 += adjustWeights
#print(adjustWeights)
self.layer2 += adjustWeights
#when line 63 placed here, results did not improve during minibatch.
print("Epoch {0}: {1}/{2} correct".format(epoch, self.evaluate(test_data), len(test_data)))
print("Training Complete")
def evaluate(self, test_data):
"""
Returns number of test inputs which network evaluates correctly.
The ouput assumed to be neuron in output layer with highest activation
:param test_data: test data set identical in form to train data set.
:return: integer sum
"""
correct = 0
for x, y in test_data:
output = self.feedforward(x)
if output == y:
correct+=1
return(correct)
def build_sinx_data(data_points):
"""
Creates a list of tuples (x value, expected y value) for Sin(x) function.
:param data_points: number of desired data points
:return: list of tuples (x value, expected y value
"""
x_vals = []
y_vals = []
for i in range(data_points):
#parameter of randint signifies range of x values to be used*10
x_vals.append(random.randint(-2000,2000)/10)
y_vals.append(round(math.sin(x_vals[i]),1))
return (list(zip(x_vals,y_vals)))
# training_pairs, epochs, minibatchsize, learn_rate
sinx_test = Network(1,21,21)
print(sinx_test.feedforward(10))
sinx_test.train(build_sinx_data(600),20,10,2)
print(sinx_test.feedforward(10))
I didn't examine thoroughly all of your code, but some issues are clearly visible:
* operator doesn't perform matrix multiplication in numpy, you have to use numpy.dot. This affects, for instance, these lines: network_input * self.layer1[neuron], self.layer1_activations[weight]*self.layer2[neuron][weight], etc.
Seems like you are solving your problem via classification (selecting 1 out of 21 classes), but using L2 loss. This is somewhat mixed up. You have two options: either stick to classification and use a cross entropy loss function, or perform regression (i.e. predict the numeric value) with L2 loss.
You should definitely extract sigmoid function to avoid writing the same expression all over again:
def sigmoid(z):
return 1 / (1 + np.exp(-z))
def sigmoid_derivative(x):
return sigmoid(x) * (1 - sigmoid(x))
You perform the same update of self.layer1 and self.layer2, which clearly wrong. Take some time analyzing how exactly backpropagation works.
I edited how my loss function was integrated into my function and also correctly implemented gradient descent. I also removed the use of mini-batches and simplified what my network was trying to do. I now have a network which attempts to classify something as even or odd.
Some extremely helpful guides I used to fix things up:
Chapter 1 and 2 of Neural Networks and Deep Learning, by Michael Nielsen, available for free at http://neuralnetworksanddeeplearning.com/chap1.html . This book gives thorough explanations for how Neural Nets work, including breakdowns of the math behind their execution.
Backpropagation from the Beginning, by Erik Hallström, linked by Maxim. https://medium.com/#erikhallstrm/backpropagation-from-the-beginning-77356edf427d
. Not as thorough as the above guide, but I kept both open concurrently, as this guide is more to the point about what is important and how to apply the mathematical formulas that are thoroughly explained in Nielsen's book.
How to build a simple neural network in 9 lines of Python code https://medium.com/technology-invention-and-more/how-to-build-a-simple-neural-network-in-9-lines-of-python-code-cc8f23647ca1
. A useful and fast introduction to some neural networking basics.
Here is my (now functioning) code:
import random
import numpy as np
import scipy
import math
class Network(object):
def __init__(self,inputLayerSize,hiddenLayerSize,outputLayerSize):
#Layers represented both by their weights array and activation and inputsums vectors.
self.layer1 = np.random.randn(hiddenLayerSize,inputLayerSize)
self.layer2 = np.random.randn(outputLayerSize,hiddenLayerSize)
self.layer1_activations = np.zeros((hiddenLayerSize, 1))
self.layer2_activations = np.zeros((outputLayerSize, 1))
self.layer1_inputsums = np.zeros((hiddenLayerSize, 1))
self.layer2_inputsums = np.zeros((outputLayerSize, 1))
self.layer1_errorsignals = np.zeros((hiddenLayerSize, 1))
self.layer2_errorsignals = np.zeros((outputLayerSize, 1))
self.layer1_deltaw = np.zeros((hiddenLayerSize, inputLayerSize))
self.layer2_deltaw = np.zeros((outputLayerSize, hiddenLayerSize))
self.outputLayerSize = outputLayerSize
self.inputLayerSize = inputLayerSize
self.hiddenLayerSize = hiddenLayerSize
print()
print(self.layer1)
print()
print(self.layer2)
print()
# self.weights = [np.random.randn(y,x)
# for x, y in zip(sizes[:-1], sizes[1:])]
def feedforward(self, network_input):
#Calculate inputsum and and activations for each neuron in the first layer
for neuron in range(self.hiddenLayerSize):
self.layer1_inputsums[neuron] = network_input * self.layer1[neuron]
self.layer1_activations[neuron] = self.sigmoid(self.layer1_inputsums[neuron])
# Calculate inputsum and and activations for each neuron in the second layer. Notice that each neuron in the second layer represented by
# weights vector, consisting of all weights leading out of the kth neuron in (l-1) layer to the jth neuron in layer l.
self.layer2_inputsums = np.zeros((self.outputLayerSize, 1))
for neuron in range(self.outputLayerSize):
for weight in range(self.hiddenLayerSize):
self.layer2_inputsums[neuron] += self.layer1_activations[weight]*self.layer2[neuron][weight]
self.layer2_activations[neuron] = self.sigmoid(self.layer2_inputsums[neuron])
return self.layer2_activations
def interpreted_output(self, network_input):
#convert layer 2 activation numbers to a single output. The neuron (weight vector) with highest activation will be output.
self.feedforward(network_input)
outputs = [x / 10 for x in range(-int((self.outputLayerSize/2)), int((self.outputLayerSize/2))+1, 1)] #range(-10, 11, 1)
return(outputs[np.argmax(self.layer2_activations)])
# def build_expected_output(self, training_data):
# #Views expected output number y for each x to generate an expected output vector from the network
# index=0
# for pair in training_data:
# expected_output_vector = np.zeros((self.outputLayerSize,1))
# x = training_data[0]
# y = training_data[1]
# for i in range(-int((self.outputLayerSize / 2)), int((self.outputLayerSize / 2)) + 1, 1):
# if y == i / 10:
# expected_output_vector[i] = 1
# #expect the target category to be a 1.
# break
# training_data[index][1] = expected_output_vector
# index+=1
# return training_data
def train(self, training_data, learn_rate):
self.backpropagate(training_data, learn_rate)
def backpropagate(self, train_data, learn_rate):
#Perform for each x,y pair.
for datapair in range(len(train_data)):
x = train_data[datapair][0]
y = train_data[datapair][1]
self.feedforward(x)
# print("l2a " + str(self.layer2_activations))
# print("l1a " + str(self.layer1_activations))
# print("l2 " + str(self.layer2))
# print("l1 " + str(self.layer1))
for neuron in range(self.outputLayerSize):
#Calculate first error equation for error signals of output layer neurons
self.layer2_errorsignals[neuron] = (self.layer2_activations[neuron] - y[neuron]) * self.sigmoid_prime(self.layer2_inputsums[neuron])
#Use recursive formula to calculate error signals of hidden layer neurons
self.layer1_errorsignals = np.multiply(np.array(np.matrix(self.layer2.T) * np.matrix(self.layer2_errorsignals)) , self.sigmoid_prime(self.layer1_inputsums))
#print(self.layer1_errorsignals)
# for neuron in range(self.hiddenLayerSize):
# #Use recursive formula to calculate error signals of hidden layer neurons
# self.layer1_errorsignals[neuron] = np.multiply(self.layer2[neuron].T,self.layer2_errorsignals[neuron]) * self.sigmoid_prime(self.layer1_inputsums[neuron])
#Partial derivative of C with respect to weight for connection from kth neuron in (l-1)th layer to jth neuron in lth layer is
#(jth error signal in lth layer) * (kth activation in (l-1)th layer.)
#Update all weights for network at each iteration of a training pair.
#Update weights in second layer
for neuron in range(self.outputLayerSize):
for weight in range(self.hiddenLayerSize):
self.layer2_deltaw[neuron][weight] = self.layer2_errorsignals[neuron]*self.layer1_activations[weight]*(-learn_rate)
self.layer2 += self.layer2_deltaw
#Update weights in first layer
for neuron in range(self.hiddenLayerSize):
self.layer1_deltaw[neuron] = self.layer1_errorsignals[neuron]*(x)*(-learn_rate)
self.layer1 += self.layer1_deltaw
#Comment/Uncomment to enable error evaluation.
#print("Epoch {0}: Error: {1}".format(datapair, self.evaluate(test_data)))
# print("l2a " + str(self.layer2_activations))
# print("l1a " + str(self.layer1_activations))
# print("l1 " + str(self.layer1))
# print("l2 " + str(self.layer2))
def evaluate(self, test_data):
error = 0
for x, y in test_data:
#x is integer, y is single element np.array
output = self.feedforward(x)
error += y - output
return error
#eval function for sin(x)
# def evaluate(self, test_data):
# """
# Returns number of test inputs which network evaluates correctly.
# The ouput assumed to be neuron in output layer with highest activation
# :param test_data: test data set identical in form to train data set.
# :return: integer sum
# """
# correct = 0
# for x, y in test_data:
# outputs = [x / 10 for x in range(-int((self.outputLayerSize / 2)), int((self.outputLayerSize / 2)) + 1,
# 1)] # range(-10, 11, 1)
# newy = outputs[np.argmax(y)]
# output = self.interpreted_output(x)
# #print("output: " + str(output))
# if output == newy:
# correct+=1
# return(correct)
def sigmoid(self, z):
return 1 / (1 + np.exp(-z))
def sigmoid_prime(self, z):
return (1 - self.sigmoid(z)) * self.sigmoid(z)
def build_simple_data(data_points):
x_vals = []
y_vals = []
for each in range(data_points):
x = random.randint(-3,3)
expected_output_vector = np.zeros((1, 1))
if x > 0:
expected_output_vector[[0]] = 1
else:
expected_output_vector[[0]] = 0
x_vals.append(x)
y_vals.append(expected_output_vector)
print(list(zip(x_vals,y_vals)))
print()
return (list(zip(x_vals,y_vals)))
simpleNet = Network(1, 3, 1)
# print("Pretest")
# print(simpleNet.feedforward(-3))
# print(simpleNet.feedforward(10))
# init_weights_l1 = simpleNet.layer1
# init_weights_l2 = simpleNet.layer2
# simpleNet.train(build_simple_data(10000),.1)
# #sometimes Error converges to 0, sometimes error converges to 10.
# print("Initial Weights:")
# print(init_weights_l1)
# print(init_weights_l2)
# print("Final Weights")
# print(simpleNet.layer1)
# print(simpleNet.layer2)
# print("Post-test")
# print(simpleNet.feedforward(-3))
# print(simpleNet.feedforward(10))
def test_network(iterations,net,training_points):
"""
Casually evaluates pre and post test
:param iterations: number of trials to be run
:param net: name of network to evaluate.
;param training_points: size of training data to be used
:return: four 1x1 arrays.
"""
pretest_negative = 0
pretest_positive = 0
posttest_negative = 0
posttest_positive = 0
for each in range(iterations):
pretest_negative += net.feedforward(-10)
pretest_positive += net.feedforward(10)
net.train(build_simple_data(training_points),.1)
for each in range(iterations):
posttest_negative += net.feedforward(-10)
posttest_positive += net.feedforward(10)
return(pretest_negative/iterations, pretest_positive/iterations, posttest_negative/iterations, posttest_positive/iterations)
print(test_network(10000, simpleNet, 10000))
While much differs between this code and the code posted in the OP, there is a particular difference that is interesting. In the original feedforward method notice
#second layer's output activations use layer1's activations as input:
for neuron in range(self.outputLayerSize):
for weight in range(self.hiddenLayerSize):
self.layer2_activations[neuron] += self.layer1_activations[weight]*self.layer2[neuron][weight]
self.layer2_activations[neuron] = 1/(1+np.exp(self.layer2_activations[neuron]))
The line
self.layer2_activations[neuron] += self.layer1_activations[weight]*self.layer2[neuron][weight]
Resembles
self.layer2_inputsums[neuron] += self.layer1_activations[weight]*self.layer2[neuron][weight]
In the updated code. This line performs the dot product between each weight vector and each input vector (the activations from layer 1) to arrive at the input_sum for a neuron, commonly referred to as z (think sigmoid(z)). In my network, the derivative of the sigmoid function, sigmoid_prime, is used to calculate the gradient of the cost function with respect to all the weights. By multiplying sigmoid_prime(z) * network error between actual and expected output. If z is very big (and positive), the neuron will have an activation value very close to 1. That means that the network is confident that that neuron should be activating. The same is true if z is very negative. The network, then, doesn't want to radically adjust weights that it is happy with, so the scale of the change in each weight for a neuron is given by the gradient of sigmoid(z), sigmoid_prime(z). Very large z means very small gradient and very small change applied to weights (the gradient of sigmoid is maximized at z = 0, when the network is unconfident about how a neuron should be categorized and when the activation for that neuron is 0.5).
Since I was continually adding on to each neuron's input_sum (z) and never resetting the value for new inputs of dot(weights, activations), the value for z kept growing, continually slowing the rate of change for the weights until weight modification grew to a standstill. I added the following line to cope with this:
self.layer2_inputsums = np.zeros((self.outputLayerSize, 1))
The new posted network can be copy and pasted into an editor and executed so long as you have the numpy module installed. The final line of output to print will be a list of 4 arrays representing final network output. The first two are the pretest values for a negative and positive input, respectively. These should be random. The second two are post-test values to determine how well the network classifies as positive and negative number. A number near 0 denotes negative, near 1 denotes positive.
I have implemented and trained a neural network with Theano of k binary inputs (0,1), one hidden layer and one unit in the output layer. Once it has been trained I want to obtain inputs that maximizes the output (e.g. x which makes unit of output layer closest to 1). So far I haven't found an implementation of it, so I am trying the following approach:
Train network => obtain trained weights (theta1, theta2)
Define the neural network function with x as input and trained theta1, theta2 as fixed parameters. That is: f(x) = sigmoid( theta1*(sigmoid (theta2*x ))). This function takes x and with given trained weights (theta1, theta2) gives output between 0 and 1.
Apply gradient descent w.r.t. x on the neural network function f(x) and obtain x that maximizes f(x) with theta1 and theta2 given.
For these I have implemented the following code with a toy example (k = 2). Based on the tutorial on http://outlace.com/Beginner-Tutorial-Theano/ but changed vector y, so that there is only one combination of inputs that gives f(x) ~ 1 which is x = [0, 1].
Edit1: As suggested optimizer was set to None and bias unit was fixed to 1.
Step 1: Train neural network. This runs well and with out error.
import os
os.environ["THEANO_FLAGS"] = "optimizer=None"
import theano
import theano.tensor as T
import theano.tensor.nnet as nnet
import numpy as np
x = T.dvector()
y = T.dscalar()
def layer(x, w):
b = np.array([1], dtype=theano.config.floatX)
new_x = T.concatenate([x, b])
m = T.dot(w.T, new_x) #theta1: 3x3 * x: 3x1 = 3x1 ;;; theta2: 1x4 * 4x1
h = nnet.sigmoid(m)
return h
def grad_desc(cost, theta):
alpha = 0.1 #learning rate
return theta - (alpha * T.grad(cost, wrt=theta))
in_units = 2
hid_units = 3
out_units = 1
theta1 = theano.shared(np.array(np.random.rand(in_units + 1, hid_units), dtype=theano.config.floatX)) # randomly initialize
theta2 = theano.shared(np.array(np.random.rand(hid_units + 1, out_units), dtype=theano.config.floatX))
hid1 = layer(x, theta1) #hidden layer
out1 = T.sum(layer(hid1, theta2)) #output layer
fc = (out1 - y)**2 #cost expression
cost = theano.function(inputs=[x, y], outputs=fc, updates=[
(theta1, grad_desc(fc, theta1)),
(theta2, grad_desc(fc, theta2))])
run_forward = theano.function(inputs=[x], outputs=out1)
inputs = np.array([[0,1],[1,0],[1,1],[0,0]]).reshape(4,2) #training data X
exp_y = np.array([1, 0, 0, 0]) #training data Y
cur_cost = 0
for i in range(5000):
for k in range(len(inputs)):
cur_cost = cost(inputs[k], exp_y[k]) #call our Theano-compiled cost function, it will auto update weights
print(run_forward([0,1]))
Output of run forward for [0,1] is: 0.968905860574.
We can also get values of weights with theta1.get_value() and theta2.get_value()
Step 2: Define neural network function f(x). Trained weights (theta1, theta2) are constant parameters of this function.
Things get a little trickier here because of the bias unit, which is part of he vector of inputs x. To do this I concatenate b and x. But the code now runs well.
b = np.array([[1]], dtype=theano.config.floatX)
#b_sh = theano.shared(np.array([[1]], dtype=theano.config.floatX))
rand_init = np.random.rand(in_units, 1)
rand_init[0] = 1
x_sh = theano.shared(np.array(rand_init, dtype=theano.config.floatX))
th1 = T.dmatrix()
th2 = T.dmatrix()
nn_hid = T.nnet.sigmoid( T.dot(th1, T.concatenate([x_sh, b])) )
nn_predict = T.sum( T.nnet.sigmoid( T.dot(th2, T.concatenate([nn_hid, b]))))
Step 3:
Problem is now in gradient descent as is not limited to values between 0 and 1.
fc2 = (nn_predict - 1)**2
cost3 = theano.function(inputs=[th1, th2], outputs=fc2, updates=[
(x_sh, grad_desc(fc2, x_sh))])
run_forward = theano.function(inputs=[th1, th2], outputs=nn_predict)
cur_cost = 0
for i in range(10000):
cur_cost = cost3(theta1.get_value().T, theta2.get_value().T) #call our Theano-compiled cost function, it will auto update weights
if i % 500 == 0: #only print the cost every 500 epochs/iterations (to save space)
print('Cost: %s' % (cur_cost,))
print x_sh.get_value()
The last iteration prints:
Cost: 0.000220317356533
[[-0.11492753]
[ 1.99729555]]
Furthermore input 1 keeps becoming more negative and input 2 increases, while the optimal solution is [0, 1]. How can this be fixed?
You are adding b=[1] via broadcasting rules as opposed to concatenating it. Also, once you concatenate it, your x_sh has one dimension to many which is why the error occurs at nn_predict and not nn_hid