everyone. I am having a problem when trying to makemigrations.
My code is:
start_date = models.DateTimeField(auto_now_add=True)
The error is:
You are trying to add a non-nullable field 'category' to item without a default; we can't do that (the database needs something to populate existing rows).
Please select a fix:
1) Provide a one-off default now (will be set on all existing rows with a null value for this column)
2) Quit, and let me add a default in models.py
Select an option: 1
Please enter the default value now, as valid Python
The datetime and django.utils.timezone modules are available, so you can do e.g. timezone.now
Type 'exit' to exit this prompt
Thank you for your help.
So I'm trying to add a SearchVectorField to a model in Django:
class JobPosting(models.Model):
...
...
search_vector = SearchVectorField()
I get that it should either be nullable or have a default value to be able to migrate so I deleted all entries in the table to prevent this problem.
However, I'm getting the following error when running makemigrations:
You are trying to add a non-`nullable` field 'search_vector' to jobposting without a default;
we can't do that (the database needs something to populate existing rows).
Please select a fix:
1) Provide a one-off default now
(will be set on all existing rows with a null value for this column)
2) Quit, and let me add a default in models.py
Select an option:
Why is it saying this if the table is empty? I don't want to make the column nullable, and I'd rather not have a default value if I can avoid it.
My question is, is there any way to force makemigrations and migrate as I don't understand the problem if the table is empty. I have other tables with data in them which I don't want to delete so can't delete all info in the database.
Alternatively, if option 1) is the solution, how would I format a default value for this type of field? I assume it's not a normal text field?
Thanks for any help.
I am not entirely sure why you do not want to have a default value, but I will assume this as given.
My question is, is there any way to force makemigrations and migrate
as I don't understand the problem if the table is empty.
Your current database table might be empty, but migrations are supposed to be repeatable on other database instances. Therefore Django cannot assume that the same holds on any other database.
A workaround might be to do define a migration that creates the field as nullable, indexes all entries and then updates it to be non-nullable.
# -*- coding: utf-8 -*-
from __future__ import unicode_literals
from django.contrib.postgres.search import SearchVector, SearchVectorField
from django.db import migrations
def index_entries(apps, schema_editor):
Entry = apps.get_model("mymodel", "Entry")
Entry.objects.update(search_vector=SearchVector('body_text'))
class Migration(migrations.Migration):
dependencies = [
('mymodel', '0001_initial'),
]
operations = [
migrations.AddField(
model_name='entry',
name='search_vector',
field=SearchVectorField(null=True),
),
migrations.RunPython(index_entries),
migrations.AlterField(
model_name='entry',
name='search_vector',
field=SearchVectorField(null=False),
),
]
I'd just make the field nullable (and probably not editable, since you're not going to change it in admin interface nor via forms):
class JobPosting(models.Model):
...
...
search_vector = SearchVectorField(null=True, editable=False)
And there will be no issues with migration.
Later you can make this field not nullable, but there is no real reason to do this because you will update it programmatically anyway.
As stated in https://docs.djangoproject.com/en/1.10/ref/models/fields/#django.db.models.Field.db_index, you can add indexes to your table using db_index=True. But how do you force hash vs btree indexes?
Things have changed a lot since the question was asked. It is now possible to define an index in the model layer through the metaclass of your model (at least since django 1.11):
https://docs.djangoproject.com/en/dev/ref/contrib/postgres/indexes/
For example:
from django.contrib.postgres.indexes import HashIndex
from django.db import models
class User(models.Model):
name = models.CharField(max_length=100)
class Meta:
indexes = (HashIndex(fields=('name',)),)
Django has no implemented particular index type selection through models.
Workaround would be to create empty migration and write SQL statement in your migration for consistency
https://docs.djangoproject.com/en/1.10/howto/writing-migrations/
manage.py makemigrations --empty app
Inside of migration in operations put following
migrations.RunSQL('Query to add index')
RunSQL docs
I am learning django by doing some tutorials and am currently on ownership in the effective-django tutorial. Unfortunately, the tutorials is written for an older version of django so some things are slightly different.
I am running into problems when adding an 'owner' field to my model Contact in models.py:
from django.db import models
from django.core.urlresolvers import reverse
from django.contrib.auth.models import User
class Contact(models.Model):
"""
Interface for contact class
"""
first_name = models.CharField(max_length=255)
last_name = models.CharField(max_length=255)
email = models.EmailField()
owner = models.ForeignKey(User)
def __str__(self):
return ' '.join([self.first_name, self.last_name])
def get_absolute_url(self):
return reverse('contacts-view', kwargs={'pk': self.id})
When trying to run 'makemigrations', i get warnings:
You are trying to add a non-nullable field 'owner' to contact without a default: can't do that
This makes sense for an existing database, so i tried flushing the database. However, the problem remains. What should be the default value for the field owner? I also tried making the field nullable but that gives me the error that field owner cannot be null.
I usually set to 1. In this case already existed records will be assigned to the first user.
If you want you can later reassign these records in the next data migration.
Well, it does not matter if the database is empty or not. It matters that you probably have already at least one migration that first creates the model, and then you try to run makemigrations that adds the field.
If these migrations are not too important for you (which I recon they are not since this is a tutorial), just delete all previous migrations and run makemigrations fresh.
Alternatively, you would have to manually change migrations, possibly provide a default value etc.
No idea why this error is popping up. Here are the models I created -
from django.db import models
from django.contrib.auth.models import User
class Shows(models.Model):
showid= models.CharField(max_length=10, unique=True, db_index=True)
name = models.CharField(max_length=256, db_index=True)
aka = models.CharField(max_length=256, db_index=True)
score = models.FloatField()
class UserShow(models.Model):
user = models.ForeignKey(User)
show = models.ForeignKey(Shows)
Here is the view from which I access these models -
from django.http import HttpResponse
from django.template import Context
from django.template.loader import get_template
from django.http import HttpResponse, Http404
from django.contrib.auth.models import User
def user_page(request, username):
try:
user = User.objects.get(username=username)
except:
raise Http404('Requested user not found.')
shows = user.usershow_set.all()
template = get_template('user_page.html')
variables = Context({
'username': username,
'shows' : shows})
output = template.render(variables)
return HttpResponse(output)
At this point I get an error -
OperationalError: (1054, "Unknown column 'appname_usershow.show_id' in 'field list'")
As you see this column is not even present in my models? Why this error?
maybe your tables schema has been changed? Also, running syncdb does not update already created tables.
You might need to drop all the tables & then run syncdb again. Also remember to take backup of your data!!
As #inception said my tables schema had changed & running syncdb did not update already created tables.
Apparently any changes to the models when updated through syncdb does not change (as in update/modify) the actual tables. So I dropped the relevant DB & ran syncdb on empty DB. Now it works fine. :)
For others, SOUTH data migration tool for Django seems to be favorite option. It seems to provide options which django models & syncdb falls short on. Must check out...
Update 29th Sept 2019: From Django 1.7 upwards, migrations are built into the core of Django. If you are running a previous lower version of Django, you can find the repository on BitBucket.
Normally I get this when when I'm trying to access field which doesn't exist in Database.
Check if the field exist in the database. If you change model and perform syncdb it won't update the database, I'm not sure if that's the case.
On other note Django offers shortcut to replace try/except block in your code using get_object_or_404. (available in django.shortcuts )
try:
user = User.objects.get(username=username)
except:
raise Http404('Requested user not found.')
can be changed to:
user = get_object_or_404(User, username=username)
I have met the same problems:
First, run
manage.py sqlall [appname]
and you can find:
`id` integer AUTO_INCREMENT NOT NULL PRIMARY KEY,
and I add the column manual:
ALTER TABLE tb_realtime_data ADD id integer AUTO_INCREMENT NOT NULL PRIMARY KEY FIRST;
and then it worked.
I think django will add the column called id itself.
For convenience, each model is given an autoincrementing primary key field named id unless you explicitly specify primary_key=True on a field (see the section titled “AutoField” in Appendix A).
you can click here for details.
Good luck.
I faced the same error like you posted above with MySQL database back-end, after long time of resolving this error, I ended up with below solution.
Manually added column to database through workbench with name exactly the same as it is shown in your error message.
After that run below command
python manage.py makemigrations
Now migrations will be successfully created
After that run below command
python manage.py migrate --fake
Now every thing works fine without any data lose issue
In the appropriate field explicitly set
primary_key = True
This is quite an old question but you might find the below useful anyway:
Check the database, you're most likely missing the show_id in the appname_usershow table.
This could occur when you change or add a field but you forget running migration.
OR
When you're accessing a non managed table and you're trying to add a ForeignKey to your model.
Following the example above:
class UserShow(models.Model):
# some attributes ...
show = models.ForeignKey(Show, models.DO_NOTHING)
class Meta:
managed = False
db_table = 'appname_departments'
This is a late response but hopefully someone will find this useful.
I was working on Django REST APIs using DB models. When I added a new column to my existing model(said column already existed in the db table from the start), I received the error shown below:
"Unknown column ',column name>' in 'field list'"executed".
What I missed was migrating the model over to the database.
So I executed the following commands from python terminal:
py -3 manage.py makemigrations ---> It will not allow NULL values for the new column added to the model, even though the column is present in the database from the start. So you need to add a default value, mine was an Integerfield, so I updated my column definition in the model as IntegerField(default=0).
From here onwards it should be straightforward, if there are no other errors.
py -3 manage.py migrate
py -3 manage.py runserver
After executing these steps when I called my REST APIs they were working properly.
I created a model file for my app and then did several sqlall as I refined my tables. One of the changes I made was I set primary_key=True to one of my fields. At the end called for syncdb. Added a dummy value and and tried to access it with User.objects.all(), User being my model class. Although this worked fine, this error came up while printing the list returned by the all() call. It read DatabaseError: (1054, "Unknown column 'polls_user.id' in 'field list'")
Surprisingly, I tried and could get it resolved with another call to syncdb. I remember not having seen the id column in the table at any time throughout the exercise when I checked it through the mysql command line client.
I received this error while trying to use Django Rest Framework serializers. Make sure if you have a serializer that subclasses ModelSerializer, that you migrate any changes to the Models before writing your serializer classes (or just comment anything related to the serializer, migrate, then uncomment).
PS F:\WebApp> python manage.py makemigrations
You are trying to add a non-nullable field 'price' to destination without a default; we can't do that (the database needs something to populate existing rows).
Please select a fix:
1) Provide a one-off default now (will be set on all existing rows with a null value for this column)
2) Quit, and let me add a default in models.py
Select an option: 2
PS F:\WebApp> python manage.py sqlmigrate travello 0001
BEGIN;
-- Create model Destination
CREATE TABLE travello_destination (id integer AUTO_INCREMENT NOT NULL PRIMARY KEY, name varchar(100) NOT NULL, img varchar(100) NOT NULL, desc longtext NOT NULL, offer bool NOT NULL);
COMMIT;
PS F:\WebApp> python manage.py makemigrations
Migrations for 'travello':
travello\migrations\0002_destination_price.py
- Add field price to destination
PS F:\WebApp> python manage.py migrate
Operations to perform:
Apply all migrations: admin, auth, contenttypes, sessions, travello
Running migrations:
Applying travello.0002_destination_price... OK
I had this issue when using a composite Primary Key of several VarChar fields and trying to call a table_set.all() queryset.
Django wanted a table_name_id PK column for this queryset, there wasn't one so it threw out this error.
I fixed it by manually creating the table_name_id and setting it to an auto-incremented, integer PK column instead of the composite PK.
I then specified those VarChar composite columns as unique_together in the Model's meta section so they act like a PK.
The direct solution is delete files under folder ../Project/App/migrations, and the method to avoid this problem is create new databaes table column instead of chagne the existing one.