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I've coded a check for integers which returns a boolean value:
def NoZerosFives(n: str):
if '0' in n or '5' in n: #It checks if any of the digits is 0 or 5
return False
return True
which I then put in a script:
for n in range(10**20000, 10**100000000):
d = str(n)
if NoZerosFives(d):
pass
else:
print('Failed the check.')
n is obviously extremely large, and the else:print('Failed the check.') is here just to tell me if the script's going or not, but it's not printing anything.
My first thought is that the problem is not with Python but with my hardware (I have a pretty powerful laptop, but still a laptop). Is my computer not powerful enough? Should I have done something to my PC that I didn't do?
Or is the code not fit for the objective and I just need to do something different?
As #jordanm points out in a comment, NoZerosFives will not return True (which is the only way your code produces any output at all) for a very long time. Think about how long it's going to take, starting from 10**20000 (shown below), to reach a value with no zeros in it by just adding 1 at each step.
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Id codes at a company come in the form x-y-zzzzzz, where x is a digit and y is a letter and zzzzzz represents a string of 6 letters. Write a function which takes in a code as an input (e.g. 3-a-abaabb) and returns the zzzzzz part (e.g. abaabb).
I have no idea how to start and solve this question. any help would be much appreciated. My IDE is pycharm (solving python coding problems) I basically need to create a function which takes the code as an input and will return the last 6 letters
You can use str.spit('-') then search count in code with repeat is equal or not, like below:
def fnd_code(code):
repeat, char, search = code.split('-')
return search.count(char) == int(repeat)
print(fnd_code('3-a-abaabb'))
print(fnd_code('4-a-abaabb'))
Output:
True
False
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Kata description:
In this simple assignment you are given a number and have to make it negative. But maybe the number is already negative?
Example:
Kata.MakeNegative(1); // return -1
Kata.MakeNegative(-5); // return -5
Kata.MakeNegative(0); // return 0
Notes:
The number can be negative already, in which case no change is required.
Zero (0) is not checked for any specific sign. Negative zeros make no mathematical sense.
Ok so this kata asks me to make any number into a negative, I know I can do it with if, but I wanna see it work this way:
def make_negative( number ):
number = ((number)*(-1))
return number
When I test it works, but when I attempt it I get this: "9 should equal -9" even though it's a basic test case that I passed earlier (I also get the same error on the random test cases). Any ideas?
To make an always negative result I'g suggest the use of abs combied with the -1 multiplication
def make_negative(number):
return -1 * abs(number)
print(make_negative(10)) # -10
print(make_negative(-10)) # -10
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I'm currently scraping some tables on the internet where numbers are posted in varying numerical formats:
Animal - Left in Wild
Tigers - 18
Deer - 18m
Pigs - 180000
I've managed to strip the m away from the number, but I am wondering if/how I could use a if statement to allow some manipulation to ensure I document the number accurately:
if animal.strip("m") == animal.strip("m"):
left_in_wild = left_in_wild * 1000000
Obviously that code does not work, but it is a rough thought of how I'm thinking about getting around this. If anyone can has anything they think can be helpful let me know.
Thank you!
A simple IF statement could help with what you're looking for:
animal = "18m"
if 'm' in animal:
print animal.strip('m') + ",000,000"
if 'k' in animal:
print animal.strip('k') + ",000"
returns:
18,000,000
Something like:
import re
def get_number(s):
try:
i=int(re.match('(\d+)', s).group(1))
if "m" in s:
i*=1000000
return i
except:
print "No Number"
get_numbers("18m") returns 18000000
You could even expand it to have an elif "k" in s block if you had thousands or something.
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How can I write following while loop in python?
int v,t;
while (scanf("%d %d",&v,&t)==2)
{
//body
}
Python being a higher level language than C will normally use different patterns for this kind of situation. There is a deleted question that in fact had the exact same behavior than your C snippet - and thus would be "correct", but it became so ugly a piece of code in Python it was downvoted pretty fast.
So, first things first - it is 2015, and people can't simply look at a C's "scanf" on the prompt and divine they should type two white space separated integer numbers - you'd better give then a message. Anther big difference is that in Python variable assignments are considered statements, and can't be done inside an expression (the while expression in this case). So you have to have a while expression that is always true, and decide whether to break later.
Thus you can go with a pattern like this.
while True:
values = input("Type your values separated by space, any other thing to exit:").split()
try:
v = int(values[0])
t = int(values[1])
except IndexError, ValueError:
break
<body>
This replaces the behavior of your code:
import re
while True:
m = re.match("(\d) (\d)", input()):
if m is None: #The input did not match
break #replace it with an error message and continue to let the user try again
u, v = [int(e) for e in m.groups()]
pass #body
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numbers = []
palindromes = []
for i in range (100,999):
for j in range(100,999):
number = i * j
test = str(number)
if test == test[::-1]:
palindromes.append(number)
print(palindromes[-1])
This code gives back palindromes. However it gives back 580085, which is far from 906609 which is correct. Is there something in the code that makes it quit early?
Your list does contain all the palindromes in that range, but not necessarily in a sorted order; the biggest one is somewhere in the middle. Use max to retrieve it.
print(max(palindromes))