I want to create web server, and listen now.
Server must have different functions for each endpoint (and method).
I want to get (e.g. to variable) parameters (and data if POST)
Respond to get (and POST if its possible)
Respond in JSON
Someone can help me with this?
PS: I will be run it on Heroku, and send requests to it via Roblox's HttpService
Below see examples of each of your requirements using the Flask lightweight web framework.
After that is a link to a short description of how to deploy to Heroku.
# app.py
from flask import Flask
from flask import request, render_template
app = Flask(__name__)
#app.route('/test-get-request-parameters')
def test_get_request_parameters():
# 1. different function per endpoint
# 2. GET parameter to variable
# 3. respond to GET
var = request.args.get('some_request_variable')
return render_template('hello_world.html')
#app.route('/test-post-method',methods=['POST'])
def test_post_method():
# 2. receive POST data
# 3. respond to POST
print(request.get_json())
return 'hello, world!'
#app.route('/test-get-or-post', methods=['GET','POST'])
def test_get_or_post():
# 4. respond in JSON
if request.method == 'POST':
d = {'hello':'world'}
return d # this will be JSON response
return render_template('test.html')
To deploy to Heroku you need a Procfile with something like this in it:
web: gunicorn app:app
And you can follow these instructions: https://devcenter.heroku.com/articles/getting-started-with-python
Related
lets say I have this code
s =int(input("Input a number "))
x = s+5
print(x)
how do I run it on EC2 and then use flask to get the output using POST so I can use it on a front end ?
I want to make a webpage where a user can input s and then the backend which is an index.py file that communicates with AWS EC2 (using flask) to run the python code above and then return the value x to the front end
flask app sample code
#!/usr/bin/python
from flask import Flask, request, jsonify
from index import some_fun
app = Flask(_name_)
#app.route('/foo', methods=['POST'])
def foo():
data = request.form.to_dict()
function_response = some_fun(data['form_field'])
print(function_response)
return jsonify(data)
if __name__ == "__main__":
app.run()
You python script, index.py from where you want call some_function
def some_fun(x): return x + 5
here i have considered post request is of multipart/form-data.
if you are making post request with application/json
then
data = request.json
I'm trying to trigger a python module (market order for Oanda) using web hooks(from trading view).
Similar to this
1) https://www.youtube.com/watch?v=88kRDKvAWMY&feature=youtu.be
and this
2)https://github.com/Robswc/tradingview-webhooks-bot
But my broker is Oanda so I'm using python to place the trade. This link has more information.
https://github.com/hootnot/oanda-api-v20
The method is web hook->ngrok->python. When a web hook is sent, the ngrok (while script is also running) shows a 500 internal service error and that the server encountered an internal error and was unable to complete your request. Either the server is overloaded or there is an error in the application.
This is what my script says when its running (see picture);
First says some stuff related the market order then;
running script picture
One thing I noticed is that after Debug it doesn't say Running on... (so maybe my flask is not active?
Here is the python script;
from flask import Flask
import market_orders
# Create Flask object called app.
app = Flask(__name__)
# Create root to easily let us know its on/working.
#app.route('/')
def root():
return 'online'
#app.route('/webhook', methods=['POST'])
def webhook():
if request.method == 'POST':
# Parse the string data from tradingview into a python dict
print(market_orders.myfucn())
else:
print('do nothing')
if __name__ == '__main__':
app.run()
Let me know if there is any other information that would be helpful.
Thanks for your help.
I fixed it!!!! Google FTW
The first thing I learned was how to make my module a FLASK server. I followed these websites to figure this out;
This link helped me set up the flask file in a virtual environment. I also moved my Oanda modules to this new folder. And opened the ngrok app while in this folder via the command window. I also ran the module from within the command window using flask run.
https://topherpedersen.blog/2019/12/28/how-to-setup-a-new-flask-app-on-a-mac/
This link showed me how to set the FLASK_APP and the FLASK_ENV
Flask not displaying http address when I run it
Then I fixed the internal service error by adding return 'okay' after print(do nothing) in my script. This I learned from;
Flask Value error view function did not return a response
I have a python script app.py in my local server (path=Users/soubhik.b/Desktop) that generates a report and mails it to certain receivers. Instead of scheduling this script on my localhost, i want to create an API which can be accessed by the receivers such that they would get the mail if they hit the API with say a certain id.
With the below code i can create an API to display a certain text. But, what do i modify to run the script through this?
Also if i want to place the script in a server instead of localhost, how do i configure the same?
from flask import Flask
app = Flask(__name__)
#app.route("/")
def hello():
return ("hello world")
if __name__ == '__main__':
app.run(debug=True)
Python Version is 2.7
A good way to do this would be to put the script into a function, then import that function in your Flask API file and run it using that. For hosting on a web server you can use Python Anywhere if you are a beginner else heroku is also a good option.
If you are tying to achieve something using Python-Flask API than you can have a close look at this documentations and proceed further https://www.flaskapi.org/, http://flask.pocoo.org/docs/1.0/api/
Apart from these here are few basic examples and references you can refer for a quickstart :
1-https://programminghistorian.org/en/lessons/creating-apis-with-python-and-flask
2- https://flask-restful.readthedocs.io/en/latest/
3- https://realpython.com/flask-connexion-rest-api/
You could do something like this
from flask import Flask
from flask_restful import Resource, Api
app = Flask(__name__)
api = Api(app)
class ExecuteScript:
def printScript:
return "Hello World"
api.add_resource(ExecuteScript, '/printScript')
if __name__ == '__main__':
app.run(debug=True)
I am new to API, and get a tasks of creating POST API. I have created a code somehow.
I want to add data to the hello.txt through post API, So how will I do it?
Here is my code:
import flask
from flask import request, jsonify
app = flask.Flask(__name__)
app.config["DEBUG"] = True
#app.route('/api/v1/resources/messages', methods = ['POST'])
def api_message():
if request.headers['Content-Type'] == 'text/plain':
return "Text Message: " + request.data
elif request.headers['Content-Type'] == 'application/octet-stream':
return "Binary message written!"
elif request.headers['Content-Type'] == 'application/json':
f = open('F:\Asif_Ahmed\Projects\api\hello.txt',"w")
f.write(request.data)
f.close()
return "JSON Message: " + json.dumps(request.json)
else:
return "415 Unsupported Media Type ;)"
app.run()
from flask import Flask, jsonify, render_template, request #import flask library
from flask_basicauth import BasicAuth # import flask library for create basic authentication if needed
from flask_cors import CORS # import flask library Cross-Origin Resource Sharing that is a mechanism that uses additional HTTP headers to tell a browser to let a web application running at one origin (domain) have permission to access selected resources from a server at a different origin
app = Flask(__name__)
CORS(app) #set-up cors for my app
#if you want use basic authentication you need set-up username and password
app.config['BASIC_AUTH_USERNAME'] = 'admin'
app.config['BASIC_AUTH_PASSWORD'] = 'password'
basic_auth = BasicAuth(app)#set-up username and password for my app but in this case I'm not specifying yet in which API use them
#app.route('/api/v1/resources/add_messages', methods=['POST'])#create my POST api
#basic_auth.required# set-up basic authentication for this API, comment out if not needed
def update_credential ():
json_credential=request.get_json()#get the JSON sent via API
print (json_credential["message"])#get the node "message" of my JSON
###########
#code to write in your file, you need write the json_credential["message"]
###########
return ("ok")
if __name__ == '__main__':
app.run(host='0.0.0.0', port=1024, threaded=True)#start my flask app with local_host IP and specific port, if you don't specify the port it will run in the default port
In this case the JSON Input should be:
{"message":"your text"}
Please let me know if something is not clear, I even try this code on my local and the JSON is passed without problems.....
So you need run your python script and see that the API is running, if you had no JSON to send and was just a simple API that give back information you should have used even Chrome but in this case that you need send some JSON data I would advice you to use Postman.
See screenshot example:
Github offers to send Post-receive hooks to an URL of your choice when there's activity on your repo.
I want to write a small Python command-line/background (i.e. no GUI or webapp) application running on my computer (later on a NAS), which continually listens for those incoming POST requests, and once a POST is received from Github, it processes the JSON information contained within. Processing the json as soon as I have it is no problem.
The POST can come from a small number of IPs given by github; I plan/hope to specify a port on my computer where it should get sent.
The problem is, I don't know enough about web technologies to deal with the vast number of options you find when searching.. do I use Django, Requests, sockets,Flask, microframeworks...? I don't know what most of the terms involved mean, and most sound like they offer too much/are too big to solve my problem - I'm simply overwhelmed and don't know where to start.
Most tutorials about POST/GET I could find seem to be concerned with either sending or directly requesting data from a website, but not with continually listening for it.
I feel the problem is not really a difficult one, and will boil down to a couple of lines, once I know where to go/how to do it. Can anybody offer pointers/tutorials/examples/sample code?
First thing is, web is request-response based. So something will request your link, and you will respond accordingly. Your server application will be continuously listening on a port; that you don't have to worry about.
Here is the similar version in Flask (my micro framework of choice):
from flask import Flask, request
import json
app = Flask(__name__)
#app.route('/',methods=['POST'])
def foo():
data = json.loads(request.data)
print "New commit by: {}".format(data['commits'][0]['author']['name'])
return "OK"
if __name__ == '__main__':
app.run()
Here is a sample run, using the example from github:
Running the server (the above code is saved in sample.py):
burhan#lenux:~$ python sample.py
* Running on http://127.0.0.1:5000/
Here is a request to the server, basically what github will do:
burhan#lenux:~$ http POST http://127.0.0.1:5000 < sample.json
HTTP/1.0 200 OK
Content-Length: 2
Content-Type: text/html; charset=utf-8
Date: Sun, 27 Jan 2013 19:07:56 GMT
Server: Werkzeug/0.8.3 Python/2.7.3
OK # <-- this is the response the client gets
Here is the output at the server:
New commit by: Chris Wanstrath
127.0.0.1 - - [27/Jan/2013 22:07:56] "POST / HTTP/1.1" 200 -
Here's a basic web.py example for receiving data via POST and doing something with it (in this case, just printing it to stdout):
import web
urls = ('/.*', 'hooks')
app = web.application(urls, globals())
class hooks:
def POST(self):
data = web.data()
print
print 'DATA RECEIVED:'
print data
print
return 'OK'
if __name__ == '__main__':
app.run()
I POSTed some data to it using hurl.it (after forwarding 8080 on my router), and saw the following output:
$ python hooks.py
http://0.0.0.0:8080/
DATA RECEIVED:
test=thisisatest&test2=25
50.19.170.198:33407 - - [27/Jan/2013 10:18:37] "HTTP/1.1 POST /hooks" - 200 OK
You should be able to swap out the print statements for your JSON processing.
To specify the port number, call the script with an extra argument:
$ python hooks.py 1234
I would use:
https://github.com/carlos-jenkins/python-github-webhooks
You can configure a web server to use it, or if you just need a process running there without a web server you can launch the integrated server:
python webhooks.py
This will allow you to do everything you said you need. It, nevertheless, requires a bit of setup in your repository and in your hooks.
Late to the party and shameless autopromotion, sorry.
If you are using Flask, here's a very minimal code to listen for webhooks:
from flask import Flask, request, Response
app = Flask(__name__)
#app.route('/webhook', methods=['POST'])
def respond():
print(request.json) # Handle webhook request here
return Response(status=200)
And the same example using Django:
from django.http import HttpResponse
from django.views.decorators.http import require_POST
#require_POST
def example(request):
print(request.json) # Handle webhook request here
return HttpResponse('Hello, world. This is the webhook response.')
If you need more information, here's a great tutorial on how to listen for webhooks with Python.
If you're looking to watch for changes in any repo...
1. If you own the repo that you want to watch
In your repo page, Go to settings
click webhooks, new webhook (top right)
give it your ip/endpoint and setup everything to your liking
use any server to get notified
2. Not your Repo
take the url you want i.e https://github.com/fire17/gd-xo/
add /commits/master.atom to the end such as:
https://github.com/fire17/gd-xo/commits/master.atom
Use any library you want to get that page's content, like:
filter out the keys you want, for example the element
response = requests.get("https://github.com/fire17/gd-xo/commits/master.atom").text
response.split("<updated>")[1].split("</updated>")[0]
'2021-08-06T19:01:53Z'
make a loop that checks this every so often and if this string has changed, then you can initiate a clone/pull request or do whatever you like