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Example:
Input : "Base derived derived You are great"
Output: "Base->derived:derived You are great"
Here, the first two spaces are replaced with -> and : respectively, the rest of the string remains the same.
Nothing fancy, but if it's a one-off application, this would do the trick, using the Python str.split() method to create a list, splitting the string into three chunks on the first two spaces, then create a new string with those three chunks separated by '->' and ':'.
your_string = "Base derived derived You are great"
split_string = your_string.split(maxsplit=2)
result = f"{split_string[0]}->{split_string[1]}:{split_string[2]}"
As suggested in comments by #yatu, this can be reduced to a single statement using the *-operator to unpack the list:
result = '{}->{}:{}'.format(*your_string.split(maxsplit=2))
result in both cases:
'Base->derived:derived You are great'
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I need help, in a long string, I want to know the the 2 characters after a number
example = "gz15gr123da1az4gr1sd23f168zgre4r6z"
if in example after 1 number == "gr":
so delete "gr"
If I understand your question correctly, what you need is regex:
import re
example = "gz15gr123da1az4gr1sd23f168zgre4r6z"
re.sub("(\d)gr", r"\1", example)
Output
gz15123da1az41sd23f168zgre4r6z
Explnatation
The re.sub function takes three arguments: the first argument is a patter, the second one the replacement, and the last of is the string itself. (\d)gr selects the parts that contain a number followed by gr, then replaces it with the number (\d) itself(removing the gr part).
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This is one of the string that I got:
str ='_Name_ created _coordinates_ so that _CITIZENS_ would learn _colonisation_.'
what I want:
['Name', 'coordinates','CITIZENS','colonisation']
I'm trying to get word in string such as Name, coordinate, citizens, colonisation with their original case.
I tried split method to remove underscores and make them individual word.
,but it did not work well.
How can I do this?
Yo can use a regular expression for that:
import re
text ='_Name_ created _coordinates_ so that _CITIZENS_ would learn _colonisation_.'
re.findall('_(\w*)_', text)
Note str is a built python function, don't use for variable names
A regex should do the trick:
import re
s = '_Name_ created _coordinates_ so that _CITIZENS_ would learn _colonisation_.'
result = re.findall('_(\w+)_', s)
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The string i needed to format is,
string = "How are you? abcdef"
I need to remove the "abcdef" from the string.
string = string.split(' ')[0]
Edit: Explanation. The line of code above will split the single string into a list of strings wherever there is a double space. It is important to note that whatever is split upon, will be removed. [0] then retrieves the first element in this newly formed list.
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My folder contains .jpg files in folder. I need to fetch only the characters from the file names.
I removed all the non alphabets but it resulted in a single string without spaces
Input: Boston_terrier_02303.jpg
Desired Output: Boston terrier
Assuming that you always have the same structure (n word fragments, 1 number, and the output), you can simply get your desired result by:
new_string = " ".join(string.split("_")[:-1])
To elaborate:
You start by splitting the strings at the underscores, and then selecting everything but the last. Then simply join the remaining strings with a space between them.
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I'm trying to figure out a function that does the opposite of strip for my Python class.
The exact question is:
What function can be used to surround a string with spaces in order to make it a certain length?
Thanks!
The "opposite" of strip is the center method:
>>> 'Hello, World!'.center(30)
' Hello, World! '
You can specify the fill character to use as second argument. The default is whitespace.
There are also ljust and rjust that will left-justify and right-justify the text up to a certain length, and as such could be considered "opposites" of lstrip and rstrip.
format strings
"%50s World"%("Hello")
"%-50s World"%("Hello")
"%^50s World"%("Hello")
or newfangled
"{0:50s} World".format("Hello")
"{0:>50s} World".format("Hello")
"{0:^50s} World".format("Hello")
these have nifty side effects
"%^*s World"%(50,"Hello")
Try s.center(N) where N is the line length you want, s - your string.
For example:
>>> "xx".center(10)
' xx '