Reading several datasets - python

I need to read 8 datasets:
df01, df02, df03, df04, df05, df06, df07, df08
This is my current approach:
#Set up file paths
filepath_2_df01= "folderX/df01.csv"
filepath_2_df02= "folderX//df02.csv"
filepath_2_df03= "folderX//df03.csv"
filepath_2_df04= "folderX//df04.csv"
filepath_2_df05= "folderY/df05.csv"
filepath_2_df06= "folderY/df06.csv"
filepath_2_df07= "folderY/df07.csv"
filepath_2_df08= "folderY/df08.csv"
#Read files
df01= pd.read_csv(filepath_2_df01)
df02= pd.read_csv(filepath_2_df02)
df03= pd.read_csv(filepath_2_df03)
df04= pd.read_csv(filepath_2_df04)
df05= pd.read_csv(filepath_2_df05)
df06= pd.read_csv(filepath_2_df06)
df07= pd.read_csv(filepath_2_df07)
df08= pd.read_csv(filepath_2_df08)
Is there a more concise way of doing that?

You can use glob for this:
import glob
dfs = []
for file in glob.glob('folderX/*.csv'):
dfs.append(pd.read_csv(file))
for df in dfs:
print(df)

use glob
from glob import glob
filenames = glob('/**/df*.csv') #get list of filenames, starting with df, in a specific folder. ** will search for subfolders as well(folderX and folderY, in your case)
dataframes = [pd.read_csv(f) for f in filenames] # using list comprehension, get a list of dataframes.
master_df = pd.concat(dataframes) #Concatenate list of dataframes to get a master dataframe

Related

how to use pandas to read some Excel file at a time? [duplicate]

I would like to read several CSV files from a directory into pandas and concatenate them into one big DataFrame. I have not been able to figure it out though. Here is what I have so far:
import glob
import pandas as pd
# Get data file names
path = r'C:\DRO\DCL_rawdata_files'
filenames = glob.glob(path + "/*.csv")
dfs = []
for filename in filenames:
dfs.append(pd.read_csv(filename))
# Concatenate all data into one DataFrame
big_frame = pd.concat(dfs, ignore_index=True)
I guess I need some help within the for loop?
See pandas: IO tools for all of the available .read_ methods.
Try the following code if all of the CSV files have the same columns.
I have added header=0, so that after reading the CSV file's first row, it can be assigned as the column names.
import pandas as pd
import glob
import os
path = r'C:\DRO\DCL_rawdata_files' # use your path
all_files = glob.glob(os.path.join(path , "/*.csv"))
li = []
for filename in all_files:
df = pd.read_csv(filename, index_col=None, header=0)
li.append(df)
frame = pd.concat(li, axis=0, ignore_index=True)
Or, with attribution to a comment from Sid.
all_files = glob.glob(os.path.join(path, "*.csv"))
df = pd.concat((pd.read_csv(f) for f in all_files), ignore_index=True)
It's often necessary to identify each sample of data, which can be accomplished by adding a new column to the dataframe.
pathlib from the standard library will be used for this example. It treats paths as objects with methods, instead of strings to be sliced.
Imports and Setup
from pathlib import Path
import pandas as pd
import numpy as np
path = r'C:\DRO\DCL_rawdata_files' # or unix / linux / mac path
# Get the files from the path provided in the OP
files = Path(path).glob('*.csv') # .rglob to get subdirectories
Option 1:
Add a new column with the file name
dfs = list()
for f in files:
data = pd.read_csv(f)
# .stem is method for pathlib objects to get the filename w/o the extension
data['file'] = f.stem
dfs.append(data)
df = pd.concat(dfs, ignore_index=True)
Option 2:
Add a new column with a generic name using enumerate
dfs = list()
for i, f in enumerate(files):
data = pd.read_csv(f)
data['file'] = f'File {i}'
dfs.append(data)
df = pd.concat(dfs, ignore_index=True)
Option 3:
Create the dataframes with a list comprehension, and then use np.repeat to add a new column.
[f'S{i}' for i in range(len(dfs))] creates a list of strings to name each dataframe.
[len(df) for df in dfs] creates a list of lengths
Attribution for this option goes to this plotting answer.
# Read the files into dataframes
dfs = [pd.read_csv(f) for f in files]
# Combine the list of dataframes
df = pd.concat(dfs, ignore_index=True)
# Add a new column
df['Source'] = np.repeat([f'S{i}' for i in range(len(dfs))], [len(df) for df in dfs])
Option 4:
One liners using .assign to create the new column, with attribution to a comment from C8H10N4O2
df = pd.concat((pd.read_csv(f).assign(filename=f.stem) for f in files), ignore_index=True)
or
df = pd.concat((pd.read_csv(f).assign(Source=f'S{i}') for i, f in enumerate(files)), ignore_index=True)
An alternative to darindaCoder's answer:
path = r'C:\DRO\DCL_rawdata_files' # use your path
all_files = glob.glob(os.path.join(path, "*.csv")) # advisable to use os.path.join as this makes concatenation OS independent
df_from_each_file = (pd.read_csv(f) for f in all_files)
concatenated_df = pd.concat(df_from_each_file, ignore_index=True)
# doesn't create a list, nor does it append to one
import glob
import os
import pandas as pd
df = pd.concat(map(pd.read_csv, glob.glob(os.path.join('', "my_files*.csv"))))
Almost all of the answers here are either unnecessarily complex (glob pattern matching) or rely on additional third-party libraries. You can do this in two lines using everything Pandas and Python (all versions) already have built in.
For a few files - one-liner
df = pd.concat(map(pd.read_csv, ['d1.csv', 'd2.csv','d3.csv']))
For many files
import os
filepaths = [f for f in os.listdir(".") if f.endswith('.csv')]
df = pd.concat(map(pd.read_csv, filepaths))
For No Headers
If you have specific things you want to change with pd.read_csv (i.e., no headers) you can make a separate function and call that with your map:
def f(i):
return pd.read_csv(i, header=None)
df = pd.concat(map(f, filepaths))
This pandas line, which sets the df, utilizes three things:
Python's map (function, iterable) sends to the function (the
pd.read_csv()) the iterable (our list) which is every CSV element
in filepaths).
Panda's read_csv() function reads in each CSV file as normal.
Panda's concat() brings all these under one df variable.
Easy and Fast
Import two or more CSV files without having to make a list of names.
import glob
import pandas as pd
df = pd.concat(map(pd.read_csv, glob.glob('data/*.csv')))
The Dask library can read a dataframe from multiple files:
>>> import dask.dataframe as dd
>>> df = dd.read_csv('data*.csv')
(Source: https://examples.dask.org/dataframes/01-data-access.html#Read-CSV-files)
The Dask dataframes implement a subset of the Pandas dataframe API. If all the data fits into memory, you can call df.compute() to convert the dataframe into a Pandas dataframe.
I googled my way into Gaurav Singh's answer.
However, as of late, I am finding it faster to do any manipulation using NumPy and then assigning it once to a dataframe rather than manipulating the dataframe itself on an iterative basis and it seems to work in this solution too.
I do sincerely want anyone hitting this page to consider this approach, but I don't want to attach this huge piece of code as a comment and making it less readable.
You can leverage NumPy to really speed up the dataframe concatenation.
import os
import glob
import pandas as pd
import numpy as np
path = "my_dir_full_path"
allFiles = glob.glob(os.path.join(path,"*.csv"))
np_array_list = []
for file_ in allFiles:
df = pd.read_csv(file_,index_col=None, header=0)
np_array_list.append(df.as_matrix())
comb_np_array = np.vstack(np_array_list)
big_frame = pd.DataFrame(comb_np_array)
big_frame.columns = ["col1", "col2"....]
Timing statistics:
total files :192
avg lines per file :8492
--approach 1 without NumPy -- 8.248656988143921 seconds ---
total records old :1630571
--approach 2 with NumPy -- 2.289292573928833 seconds ---
A one-liner using map, but if you'd like to specify additional arguments, you could do:
import pandas as pd
import glob
import functools
df = pd.concat(map(functools.partial(pd.read_csv, sep='|', compression=None),
glob.glob("data/*.csv")))
Note: map by itself does not let you supply additional arguments.
If you want to search recursively (Python 3.5 or above), you can do the following:
from glob import iglob
import pandas as pd
path = r'C:\user\your\path\**\*.csv'
all_rec = iglob(path, recursive=True)
dataframes = (pd.read_csv(f) for f in all_rec)
big_dataframe = pd.concat(dataframes, ignore_index=True)
Note that the three last lines can be expressed in one single line:
df = pd.concat((pd.read_csv(f) for f in iglob(path, recursive=True)), ignore_index=True)
You can find the documentation of ** here. Also, I used iglobinstead of glob, as it returns an iterator instead of a list.
EDIT: Multiplatform recursive function:
You can wrap the above into a multiplatform function (Linux, Windows, Mac), so you can do:
df = read_df_rec('C:\user\your\path', *.csv)
Here is the function:
from glob import iglob
from os.path import join
import pandas as pd
def read_df_rec(path, fn_regex=r'*.csv'):
return pd.concat((pd.read_csv(f) for f in iglob(
join(path, '**', fn_regex), recursive=True)), ignore_index=True)
Inspired from MrFun's answer:
import glob
import pandas as pd
list_of_csv_files = glob.glob(directory_path + '/*.csv')
list_of_csv_files.sort()
df = pd.concat(map(pd.read_csv, list_of_csv_files), ignore_index=True)
Notes:
By default, the list of files generated through glob.glob is not sorted. On the other hand, in many scenarios, it's required to be sorted e.g. one may want to analyze number of sensor-frame-drops v/s timestamp.
In pd.concat command, if ignore_index=True is not specified then it reserves the original indices from each dataframes (i.e. each individual CSV file in the list) and the main dataframe looks like
timestamp id valid_frame
0
1
2
.
.
.
0
1
2
.
.
.
With ignore_index=True, it looks like:
timestamp id valid_frame
0
1
2
.
.
.
108
109
.
.
.
IMO, this is helpful when one may want to manually create a histogram of number of frame drops v/s one minutes (or any other duration) bins and want to base the calculation on very first timestamp e.g.
begin_timestamp = df['timestamp'][0]
Without, ignore_index=True, df['timestamp'][0] generates the series containing very first timestamp from all the individual dataframes, it does not give just a value.
Another one-liner with list comprehension which allows to use arguments with read_csv.
df = pd.concat([pd.read_csv(f'dir/{f}') for f in os.listdir('dir') if f.endswith('.csv')])
Alternative using the pathlib library (often preferred over os.path).
This method avoids iterative use of pandas concat()/apped().
From the pandas documentation:
It is worth noting that concat() (and therefore append()) makes a full copy of the data, and that constantly reusing this function can create a significant performance hit. If you need to use the operation over several datasets, use a list comprehension.
import pandas as pd
from pathlib import Path
dir = Path("../relevant_directory")
df = (pd.read_csv(f) for f in dir.glob("*.csv"))
df = pd.concat(df)
If multiple CSV files are zipped, you may use zipfile to read all and concatenate as below:
import zipfile
import pandas as pd
ziptrain = zipfile.ZipFile('yourpath/yourfile.zip')
train = []
train = [ pd.read_csv(ziptrain.open(f)) for f in ziptrain.namelist() ]
df = pd.concat(train)
Based on Sid's good answer.
To identify issues of missing or unaligned columns
Before concatenating, you can load CSV files into an intermediate dictionary which gives access to each data set based on the file name (in the form dict_of_df['filename.csv']). Such a dictionary can help you identify issues with heterogeneous data formats, when column names are not aligned for example.
Import modules and locate file paths:
import os
import glob
import pandas
from collections import OrderedDict
path =r'C:\DRO\DCL_rawdata_files'
filenames = glob.glob(path + "/*.csv")
Note: OrderedDict is not necessary, but it'll keep the order of files which might be useful for analysis.
Load CSV files into a dictionary. Then concatenate:
dict_of_df = OrderedDict((f, pandas.read_csv(f)) for f in filenames)
pandas.concat(dict_of_df, sort=True)
Keys are file names f and values are the data frame content of CSV files.
Instead of using f as a dictionary key, you can also use os.path.basename(f) or other os.path methods to reduce the size of the key in the dictionary to only the smaller part that is relevant.
import os
os.system("awk '(NR == 1) || (FNR > 1)' file*.csv > merged.csv")
Where NR and FNR represent the number of the line being processed.
FNR is the current line within each file.
NR == 1 includes the first line of the first file (the header), while FNR > 1 skips the first line of each subsequent file.
In case of an unnamed column issue, use this code for merging multiple CSV files along the x-axis.
import glob
import os
import pandas as pd
merged_df = pd.concat([pd.read_csv(csv_file, index_col=0, header=0) for csv_file in glob.glob(
os.path.join("data/", "*.csv"))], axis=0, ignore_index=True)
merged_df.to_csv("merged.csv")
You can do it this way also:
import pandas as pd
import os
new_df = pd.DataFrame()
for r, d, f in os.walk(csv_folder_path):
for file in f:
complete_file_path = csv_folder_path+file
read_file = pd.read_csv(complete_file_path)
new_df = new_df.append(read_file, ignore_index=True)
new_df.shape
Consider using convtools library, which provides lots of data processing primitives and generates simple ad hoc code under the hood.
It is not supposed to be faster than pandas/polars, but sometimes it can be.
e.g. you could concat csv files into one for further reuse - here's the code:
import glob
from convtools import conversion as c
from convtools.contrib.tables import Table
import pandas as pd
def test_pandas():
df = pd.concat(
(
pd.read_csv(filename, index_col=None, header=0)
for filename in glob.glob("tmp/*.csv")
),
axis=0,
ignore_index=True,
)
df.to_csv("out.csv", index=False)
# took 20.9 s
def test_convtools():
table = None
for filename in glob.glob("tmp/*.csv"):
table_ = Table.from_csv(filename, header=False)
if table is None:
table = table_
else:
table = table.chain(table_)
table.into_csv("out_convtools.csv", include_header=False)
# took 15.8 s
Of course if you just want to obtain a dataframe without writing a concatenated file, it will take 4.63 s and 10.9 s correspondingly (pandas is faster here because it doesn't need to zip columns for writing it back).
import pandas as pd
import glob
path = r'C:\DRO\DCL_rawdata_files' # use your path
file_path_list = glob.glob(path + "/*.csv")
file_iter = iter(file_path_list)
list_df_csv = []
list_df_csv.append(pd.read_csv(next(file_iter)))
for file in file_iter:
lsit_df_csv.append(pd.read_csv(file, header=0))
df = pd.concat(lsit_df_csv, ignore_index=True)
This is how you can do it using Colaboratory on Google Drive:
import pandas as pd
import glob
path = r'/content/drive/My Drive/data/actual/comments_only' # Use your path
all_files = glob.glob(path + "/*.csv")
li = []
for filename in all_files:
df = pd.read_csv(filename, index_col=None, header=0)
li.append(df)
frame = pd.concat(li, axis=0, ignore_index=True,sort=True)
frame.to_csv('/content/drive/onefile.csv')

Comparing multiple csv file names and group them accordingly

I have for example 4 csv files. I have many other files with the following naming convention with some other files that don't have 'kd' in their name. I want to select the files with 'kd' and do the follows:
kd_2020_2.csv
kd_2020_2_modified.csv
kd_2021_2.csv
kd_2021_2_modified.csv
pp_2012_2.csv
I want to group the two files that have the same name except for the 'modified' portion and then read those files and do some comparison (therefore, kd_2020_2.csv and kd_2020_2_modified.csv will be grouped together and so on).
So far, I got
import pandas as pd
import os
import glob
import difflib
os.chdir('C:\\New_folder')
FileList = glob.glob('*.csv')
print(FileList)
files=[f for f in FileList if 'kd' in f]
file_name =[files[i].split('.')[0] for i in range(len(files))]
for i in range(len(file_name)):
if difflib.ndiff(file_name[i], file_name[i+1]) == 'modified':
df[i] = pd.read_csv(FileList[i])
df[i+1] = pd.read_csv(FileList[i+1])
It is going out of range since I am doing (i+1). Also, this is not what I intend to do. I want to compare each file name with all the other file names and read only the two files with matching name except the part 'modified'. Thank you for your help.
You can use itertools``groupby to create groups based on the first 9 characters of the filenames:
from itertools import groupby
file_groups = [list(i) for j, i in groupby(FileList, lambda a: a[:9])]
This will output a list of pairs:
[['kd_2020_2.csv', 'kd_2020_2_modified.csv'], ['kd_2021_2.csv, kd_2021_2_modified.csv'], ['pp_2012_2.csv']]
You can then iterate the list and load the pairs and process them:
for i in file_groups:
df1 = pd.read_csv(i[0])
df2 = pd.read_csv(i[1])

Iterate through folders and find a file to put into a dataframe

I have a directory ../customer_data/* with 15 folders. Each folder is a unique customer.
Example: ../customer_data/customer_1
Within each customer folder there is a csv called surveys.csv.
GOAL: I want to iterate through all the folders in ../customer_data/* and find the surveys.csv for each unique customer and create a concatenated dataframe. I also want to add a column in the dataframe where it has the customer id which is the name of the folder.
import glob
import os
rootdir = '../customer_data/*'
dataframes = []
for subdir, dirs, files in os.walk(rootdir):
for file in files:
csvfiles = glob.glob(os.path.join(rootdir, 'surveys.csv'))
# loop through the files and read them in with pandas
# a list to hold all the individual pandas DataFrames
df = pd.read_csv(csvfiles)
df['customer_id'] = os.path.dirname
dataframes.append(df)
# concatenate them all together
result = pd.concat(dataframes, ignore_index=True)
result.head()
This code is not giving me all 15 files. Please help
You can use the pathlib module for this.
from pathlib import Path
import pandas as pd
dfs = []
for filepath in Path("customer_data").glob("customer_*/surveys.csv"):
this_df = pd.read_csv(filepath)
# Set the customer ID as the name of the parent directory.
this_df.loc[:, "customer_id"] = filepath.parent.name
dfs.append(this_df)
df = pd.concat(dfs)
Let's try pathlib with rglob which will recursively search your directory structure for all files that match a glob pattern. in this instance survey.
import pandas as pd
from pathlib import Path
root_dir = Path('/top_level_dir/')
files = {file.parent.parts[-1] : file for file in Path.rglob('*survey.csv')}
df = pd.concat([pd.read_csv(file).assign(customer=name) for name,file in files.items()])
Note you'll need Python 3.4+ for pathlib.

Efficient ways to combine multiple .csv files using python

I currently have about 700 '.csv' files and want to combine them into one. Each file has three columns: 'date', 'time' and 'var'. I have to combine them based on two columns: date and name. I currently read them as dataframe. After combining them, the final file should have columns of date, name, var1, var2,var3...var700. I currently use pandas merge function, but it is supper slow, as the data is large. Is there any efficient way to combine the files? My current code is as follows:
for filename in os.listdir(signal_path):
filepath=os.path.join(signal_path,filename)
_temp = pd.read_pickle(filepath)
data.merge(_temp, how = 'left', on=['date','name'])
I have attached a
sample data , each file has different length.
this code will combine all the csv files if the files in the same path.
import pandas as pd
from pathlib import Path
dir = Path("../relevant_directory")
df = (pd.read_csv(f) for f in dir.glob("*.csv"))
df = pd.concat(df)
use this:
import pandas as pd
import os
dir = '../relevant_directory/'
first = True
for folder, subfolders, files in os.walk(dir):
for f in files:
file = str(folder)+str(f)
if file.split('.')[-1] == 'csv':
if first:
data = pd.read_csv(file)
first = False
else:
df = pd.read_csv(file)
data = pd.merge(data, df, on=['date', 'name'])

Merge files with similar name in to one dataframe

I have a list of files stored in directory such as
filenames=[
abc_1.txt
abc_2.txt
abc_3.txt
bcd_1.txt
bcd_2.txt
bcd_3.txt
]
pattern=[abc]
I want to read multiple txt files into one dataframe such that all files starting with abc will be in one dataframe then all all filename starting with bcd etc.
My code:
filenames = os.listdir(file_path)
expnames=[]
for files in filenames:
expnames.append(files.rsplit('_',1)[0])
## expnames=[abc, bcd]
dfs = []
for exp in expnames:
for files in filenames:
if files.startswith(exp):
dfs.append(pd.read_csv(file_path+files,sep=',',header=None))
big_frame = pd.concat(dfs, ignore_index=True)
My output contain duplicate rows due to multiple for loops
Output:
Can someone help wih this?
This will store your desired outputs in a list of dataframes called list_of_dfs and then create a MultiIndex dataframe final from them with the file prefixes (e.g. ['abc','bcd']) as the keys for the outermost index level:
import pandas as pd
import os
filenames = os.listdir(file_path)
prefixes = list(set(i.split('_')[0] for i in filenames))
list_of_dfs = [pd.concat([pd.read_csv(os.path.join(file_path, file), header=None) for file in filenames if file.startswith(prefix)], ignore_index=True) for prefix in prefixes]
final = pd.concat(list_of_dfs, keys=prefixes)
file_path = '/home/iolie/Downloads/test/'
filenames = os.listdir(file_path)
prefixes = list(set(i.split('_')[0] for i in filenames))
for prefix in prefixes:
for file in filenames:
if file.startswith(prefix):
list_of_dfs= [ pd.concat( [pd.read_csv (os.path.join(file_path, file)], header=None ),ignore_index=True)]
final=pd.concat(list_of_dfs)

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