I am parsing through two separate csv files with the goal of finding matching customerID's and dates to manipulate balance.
In my for loop, at some point there should be a match as I intentionally put duplicate ID's and dates in my csv. However, when parsing and attempting to match data, the matches aren't working properly even though the values are the same.
main.py:
transactions = pd.read_csv(INPUT_PATH, delimiter=',')
accounts = pd.DataFrame(
columns=['customerID', 'MM/YYYY', 'minBalance', 'maxBalance', 'endingBalance'])
for index, row in transactions.iterrows():
customer_id = row['customerID']
date = formatter.convert_date(row['date'])
minBalance = 0
maxBalance = 0
endingBalance = 0
dict = {
"customerID": customer_id,
"MM/YYYY": date,
"minBalance": minBalance,
"maxBalance": maxBalance,
"endingBalance": endingBalance
}
print(customer_id in accounts['customerID'] and date in accounts['MM/YYYY'])
# Returns False
if (accounts['customerID'].equals(customer_id)) and (accounts['MM/YYYY'].equals(date)):
# This section never runs
print("hello")
else:
print("world")
accounts.loc[index] = dict
accounts.to_csv(OUTPUT_PATH, index=False)
Transactions CSV:
customerID,date,amount
1,12/21/2022,500
1,12/21/2022,-300
1,12/22/2022,100
1,01/01/2023,250
1,01/01/2022,300
1,01/01/2022,-500
2,12/21/2022,-200
2,12/21/2022,700
2,12/22/2022,200
2,01/01/2023,300
2,01/01/2023,400
2,01/01/2023,-700
Accounts CSV
customerID,MM/YYYY,minBalance,maxBalance,endingBalance
1,12/2022,0,0,0
1,12/2022,0,0,0
1,12/2022,0,0,0
1,01/2023,0,0,0
1,01/2022,0,0,0
1,01/2022,0,0,0
2,12/2022,0,0,0
2,12/2022,0,0,0
2,12/2022,0,0,0
2,01/2023,0,0,0
2,01/2023,0,0,0
2,01/2023,0,0,0
Expected Accounts CSV
customerID,MM/YYYY,minBalance,maxBalance,endingBalance
1,12/2022,0,0,0
1,01/2023,0,0,0
1,01/2022,0,0,0
2,12/2022,0,0,0
2,01/2023,0,0,0
Where does the problem come from
Your Problem comes from the comparison you're doing with pandas Series, to make it simple, when you do :
customer_id in accounts['customerID']
You're checking if customer_id is an index of the Series accounts['customerID'], however, you want to check the value of the Series.
And in your if statement, you're using the pd.Series.equals method. Here is an explanation of what does the method do from the documentation
This function allows two Series or DataFrames to be compared against each other to see if they have the same shape and elements. NaNs in the same location are considered equal.
So equals is used to compare between DataFrames and Series, which is different from what you're trying to do.
One of many solutions
There are multiple ways to achieve what you're trying to do, the easiest is simply to get the values from the series before doing the comparison :
customer_id in accounts['customerID'].values
Note that accounts['customerID'].values returns a NumPy array of the values of your Series.
So your comparison should be something like this :
print(customer_id in accounts['customerID'].values and date in accounts['MM/YYYY'].values)
And use the same thing in your if statement :
if (customer_id in accounts['customerID'].values and date in accounts['MM/YYYY'].values):
Alternative solutions
You can also use the pandas.Series.isin function that given an element as input return a boolean Series showing whether each element in the Series matches the given input, then you will just need to check if the boolean Series contain one True value.
Documentation of isin : https://pandas.pydata.org/docs/reference/api/pandas.Series.isin.html
It is not clear from the information what does formatter.convert_date function does. but from the example CSVs you added it seems like it should do something like:
def convert_date(mmddyy):
(mm,dd,yy) = mmddyy.split('/')
return mm + '/' + yy
in addition, make sure that data types are also equal
(both date fields are strings and also for customer id)
I have a column (series) of values I'm trying to move characters around and I'm going nowhere fast! I found some snippets of code to get me where I am but need a "Closer". I'm working with one column, datatype (STR). Each column strings are a series of numbers. Some are duplicated. These duplicate numbers have a (n-) in front of the number. The (n) number will change based on how many duplicate numbers strings are listed. Some may have two duplicates, some eight duplicates. Doesn't matter, order should stay the same.
I need to go down through each cell or string, pluck the (n-) from the left of string, swap the two characters around, and append it to the end of the string. No number sorting needed. The column is 4-5k lines long and will look like the example given all the way down. No other special characters or letters. Also, the duplicate rows will always be together no matter where in the column.
My problem is the code below actually works and will step through each string, evaluate it for a dash, then process the numbers in the way I need. However, I have not learned how to get the changes back into my dataframe from a python for-loop. I was really hoping that somebody had a niffy lambda fix or a pandas apply function to address the whole column at once. But I haven't found anything that I can tweak to work. I know there is a better way than slowly traversing down through a series and I would like to learn.
Two possible fixes needed:
Is there a way to have the code below replace the old df.string value with the newly created df.string value? If so, please let me know.
I've been trying to read up on df.apply using the split feature so I can address the whole column at once. I understand it's the smarter play. Is there a couple of lines code that would do what I need?
Please let me know what you think. I appreciate the help. Thank you for taking the time.
import re
import pandas as pd
from pandas import DataFrame, Series
import numpy as np
df = pd.read_excel("E:\Book2.xlsx")
df.column1=df.column1.astype(str)
for r in df['column1']: #Finds Column
if bool(re.search('-', r))!=True: #test if string has '-'
continue
else:
a = [] #string holder for '-'
b = [] #string holder for numbers
for c in r:
if c == '-': #if '-' then hold in A
a.append(c)
else:
b.append(c) #if number then hold in B
t = (''.join(b + a)) #puts '-' at the end of string
z = t[1:] + t[:1] #picks up 1st position char and moves to end of string
r = z #assigns new created string to df.column1 value
print(df)
Starting File: Ending File:
column1 column1
41887 41887
1-41845 41845-1
2-41845 41845-2
40905 40905
1-41323 41323-1
2-41323 41323-2
3-41323 41323-3
41778 41778
You can use df.str.replace():
If we recreate your example with a file containing all your values and retain column1 as the column name:
import pandas as pd
df=pd.read_csv('file.txt')
df.columns=['column1']
df['column1']=df['column1'].str.replace('(^\d)-(\d+)',r'\2-\1')
print(df)
This will give the desired output. Replace the old column with new one, and do it all in one (without loops).
#in
41887
1-41845
2-41845
40905
1-41323
2-41323
3-41323
41778
#out
column1
0 41887
1 41845-1
2 41845-2
3 40905
4 41323-1
5 41323-2
6 41323-3
7 41778
My dataset looks like this:
Paste_Values AB_IDs AC_IDs AD_IDs
AE-1001-4 AB-1001-0 AC-1001-3 AD-1001-2
AE-1964-7 AB-1964-2 AC-1964-7 AD-1964-1
AE-2211-1 AB-2211-1 AC-2211-3 AD-2211-2
AE-2182-4 AB-2182-6 AC-2182-7 AD-2182-5
I need to compare all values in the Paste_values column with the all other three values in a row.
For Example:
AE-1001-4 is split into two part AE and 1001-4 we need check 1001-4 is present other columns or not
if its not present we need to create new columns put the same AE-1001-4
if 1001-4 match with other columns we need to change it inot 'AE-1001-5' put in the new column
After:
If there is no match I need to to write the value of Paste_values as is in the newly created column named new_paste_value.
If there is a match (same value) in other columns within the same row, then I need to change the last digit of the value from Paste_values column, so that the whole value should not be the same as in any other whole values in the row and that newly generated value should be written in new_paste_value column.
I need to do this with every row in the data frame.
So the result should look like:
Paste_Values AB_IDs AC_IDs AD_IDs new_paste_value
AE-1001-4 AB-1001-0 AC-1001-3 AD-1001-2 AE-1001-4
AE-1964-7 AB-1964-2 AC-1964-7 AD-1964-1 AE-1964-3
AE-2211-1 AB-2211-1 AC-2211-3 AD-2211-2 AE-2211-4
AE-2182-4 AB-2182-6 AC-2182-4 AD-2182-5 AE-2182-1
How can I do it?
Start from defining a function to be applied to each row of your DataFrame:
def fn(row):
rr = row.copy()
v1 = rr.pop('Paste_Values') # First value
if not rr.str.contains(f'{v1[3:]}$').any():
return v1 # No match
v1a = v1[3:-1] # Central part of v1
for ch in '1234567890':
if not rr.str.contains(v1a + ch + '$').any():
return v1[:-1] + ch
return '????' # No candidate found
A bit of explanation:
The row argument is actually a Series, with index values taken from
column names.
So rr.pop('Paste_Values') removes the first value, which is saved in v1
and the rest remains in rr.
Then v1[3:] extracts the "rest" of v1 (without "AE-")
and str.contains checks each element of rr whether it
contains this string at the end position.
With this explanation, the rest of this function should be quite
understandable. If not, execute each individual instruction and
print their results.
And the only thing to do is to apply this function to your DataFrame,
substituting the result to a new column:
df['new_paste_value'] = df.apply(fn, axis=1)
To run a test, I created the following DataFrame:
df = pd.DataFrame(data=[
['AE-1001-4', 'AB-1001-0', 'AC-1001-3', 'AD-1001-2'],
['AE-1964-7', 'AB-1964-2', 'AC-1964-7', 'AD-1964-1'],
['AE-2211-1', 'AB-2211-1', 'AC-2211-3', 'AD-2211-2'],
['AE-2182-4', 'AB-2182-6', 'AC-2182-4', 'AD-2182-5']],
columns=['Paste_Values', 'AB_IDs', 'AC_IDs', 'AD_IDs'])
I received no error on this data. Perform a test on the above data.
Maybe the source of your error is in some other place?
Maybe your DataFrame contains also other (float) columns,
which you didn't include in your question.
If this is the case, run my function on a copy of your DataFrame,
with this "other" columns removed.
I have a dataframe in Pandas with a column called 'Campaign' it has values like this:
"UK-Sample-Car Rental-Car-Broad-MatchPost"
I need to be able to pull out that the string contains the word 'Car Rental' and set another Product column to be 'CAR'. The hyphen is not always separating out the word Car, so finding the string this way isn't an possible.
How can I achieve this in Pandas/Python?
pandas as some sweet string functions you can use
for example, like this:
df['vehicle'] = df.Campaign.str.extract('(Car).Rental').str.upper()
This sets the column vehicle to what is contained inside the parenthesis of the regular expression given to the extract function.
Also the str.upper makes it uppercase
Extra Bonus:
If you want to assign vehicle something that is not in the original string, you have to take a few more steps, but we still use the string functions This time str.contains .
is_motorcycle = df.Campaign.str.contains('Motorcycle')
df['vehicle'] = pd.Series(["MC"] * len(df)) * is_motorcycle
The second line here creates a series of "MC" strings, then masks it on the entries which we found to be motorcycles.
If you want to combine multiple, I suggest you use the map function:
vehicle_list = df.Campaign.str.extract('(Car).Rental|(Motorcycle)|(Hotel)|(.*)')
vehicle = vehicle_list.apply(lambda x: x[x.last_valid_index()], axis=1)
df['vehicle'] = vehicle.map({'Car':'Car campaign', 'Hotel':'Hotel campaign'})
This first extracts the data into a list of options per line. The cases are split by | and the last one is just a catch-all which is needed for the Series.apply function below.
The Series.map function is pretty straight forward, if the captured data is 'Car', we set 'Car campaign', and 'Hotel' we set 'Hotel campaign' etc.
My problem: I have a pandas dataframe and one column in particular which I need to process contains values separated by (":") and in some cases, some of those values between ":" can be value = value, and can appear at the start/middle/end of the string. The length of the string can differ in each cell as we iterate through the row, for e.g.
clickstream['events']
1:3:5:7=23
23=1:5:1:5:3
9:0:8:6=5:65:3:44:56
1:3:5:4
I have a file which contains the lookup values of these numbers,e.g.
event_no,description,event
1,xxxxxx,login
3,ffffff,logout
5,eeeeee,button_click
7,tttttt,interaction
23,ferfef,click1
output required:
clickstream['events']
login:logout:button_click:interaction=23
click1=1:button_click:login:button_click:logout
Is there a pythonic way of looking up these individual values and replacing with the event column corresponding to the event_no row as shown in the output? I have hundreds of events and trying to work out a smart way of doing this. pd.merge would have done the trick if I had a single value, but I'm struggling to work out how I can work across the values and ignore the "=value" part of the string
Edit for to ignore missing keys in Dict:
import pandas as pd
EventsDict = {1:'1:3:5:7',2:'23:45:1:5:3',39:'0:8:46:65:3:44:56',4:'1:3:5:4'}
clickstream = pd.Series(EventsDict)
#Keep this as a dictionary
EventsLookup = {1:'login',3:'logout',5:'button_click',7:'interaction'}
def EventLookup(x):
list1 = [EventsLookup.get(int(item),'Missing') for item in x.split(':')]
return ":".join(list1)
clickstream.apply(EventLookup)
Since you are using a full DF and not just a series, use:
clickstream['events'].apply(EventLookup)
Output:
1 login:logout:button_click:interaction
2 Missing:Missing:login:button_click:logout
4 login:logout:button_click:Missing
39 Missing:Missing:Missing:Missing:logout:Missing...