I'm a Python beginner and am trying out JupyterLab. I tried a simple line of code but keep getting an error a NameError message: name 'val' is not defined. I'm using JupyterLab 2.1.3 on a localhost (Win 10 Enterprise). Any help?
In the picture, the [] beside your code cell indicates that the cell defining val = ... has not been executed. If you run the cell, [] would change to [2] based on your picture.
Simply put, run the cell above first before running the cell you are having error in now.
Or, you can simply combine them:
val = 4+2+4
val
Run this and it will give you what you want.
Thank you everyone for helping. I found out that my original line of code was written in Raw mode that's why it showed an error. Setting it to Code mode fixed it. Sorry I didn't capture the entire screen.
Related
I have python code which keeps giving below error. To the surprise it keeps coming in one environment (QA) but does not happen in another (DEV) inspite of using exact same code and input file
"TypeError","evalue":"'list' object is not callable"
I have below lines related to python list in my code -
country_list = list(input_df.select('country').distinct().toPandas()['country'])
country_list = list(filter(None, country_list))
country_code = str(country_list).strip('[]')
Which looks fine to me and works in DEV environment without any issue. What could be the possible reason for this. Can this be something to with python versions?
Thanks in advance
I've been working on some dataframes with Python. I load them in using readCSV(filename, index=0) and it's all fine. The files also open fine in Excel. I also opened them in notepad, and the seem alright; below is an example line:
851,1.218108787,0.636454978,0.269719611,-0.849476404,-0.143909689,0.050626813,-0.094248374,-0.3096134,-0.131347142,0.671271112,0.167593329,0.439417259,-0.198164647,-0.031552824,-0.215189948,-0.1791156,0.092648696,-0.107840318,-0.162596466,0.019324121,0.040572892,-0.008307331,-0.077819297,-0.023809355,-0.148229913,-0.041082835,0.138234498,-0.070986117,0.024788437,-0.050982962,0.24689969,0
The first column is as I understand it an index column. Then there's a bunch of Principal Components, and at the end is a 1/0.
When I try and load the file into WEKA, however, it gives me a nasty error and urges me to use the converter, saying:
Reason:
32 Problem encountered on line: 2
When I attempt to use the converter with the default settings, it states a new error:
Couldn't read object file_name.csv invalid stream header: 2C636F6D
Could anyone help with any of this? I can't provide the entire data file but if requested I can try and maybe cut out a few rows and only paste those if the error still occurs. Are there any flags I need to specify when saving a file to CSV in python? At the moment I just use a .toCSV('x.csv').
I think the index column not having an issue would prevent weka from reading it, when you write using pandas.to_csv() set the index = False
df.to_csv(index = False)
As the title says, i am trying to create a vm on opennebula with the python api. (this is my first time working with one and i have zero clue of anythings, so plz be not too hard with me)
#!/usr/bin/python3
import oca
client = oca.Client('username:passwd', 'ip:2633/RPC2')
oca.VirtualMachine.allocate(client, 'test')
#'test' is the name of the template i want to use
it gives me this error:
oca.exceptions.OpenNebulaException: [VirtualMachineAllocate] Error allocating a new virtual machine. Parse error: syntax error, unexpected $end, expecting EQUAL or EQUAL_EMPTY at line 1, columns 1:5
anyone an idea how to fix this?
thanks in advance.
ok.. i am stupid and have searched only after 4h trying in the right place --> the git repository and the 'issues' tab.
vm_templ = oca.VmTemplatePool(client)
vm_templ.info()
for templ in vm_templ:
if templ.name == "Ubuntu 14.04 - KVM":
templ.instantiate("oca-test")
that is a way you can create a vm of an existing template via python.
(the connection part is missing, but that is trivial).
i don't delete this question, perhaps somebody out there will have a hard time too with this.
Why do I receive this warning message every time I run my code? (below). Is it possible to get rid of it? If so, how do I do that?
My code:
from openpyxl import load_workbook
from openpyxl import Workbook
wb = load_workbook('NFL.xlsx', data_only = True)
ws = wb.active
sh = wb["Sheet1"]
ptsDiff = (sh['J127'].value)
print ptsDiff
The code works but I get this warning message:
Warning (from warnings module):
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/openpyxl/reader/worksheet.py", line 320
warn(msg)
UserWarning: Unknown extension is not supported and will be removed
This error happens when openpyxl cannot understand/read an extension (source). Here is the list of built-in extensions openpyxl currently knows that is doesn't support:
Conditional Formatting
Data Validation
Sparkline Group
Slicer List
Protected Range
Ignored Error
Web Extension
Slicer List
Timeline Ref
Also see the Worksheet extension list specification.
Try to add single quotes to your data_only parameter like this:
wb = load_workbook('NFL.xlsx', data_only = **'True'**)
This works for me.
Using python 3.5 under Anaconda3, Excel 2016, Windows10 -- I had the same problem initially with an xlsx file. Tried to make it into a csv and did not work. What worked was: select the entire spreadsheet, copy on a Notepad, select the notepad text, paste in a new spreadsheet, save as xslx. It looks like any extra formatting would result in a warning.
It is already listed in the first answer what is wrong with it If you only want to get rid of the error that is given in red for some reason. You can go to the file location of the error and # the line where is says warn(msg) this will stop the error being displayed the code still works fine in my experience.I am not sure if this will work after compiled but this should work in the same machine.
PS:I had the same error and this is what I did because I though it could be confusing for the end user
PS:You can use a try and except error catcher too but this is quicker.
I'm trying to read a file using python and I keep getting this error
ERROR: Line magic function `%user_vars` not found.
My code is very basic just
names = read_csv('Combined data.csv')
names.head()
I get this for anytime I try to read or open a file. I tried using this thread for help.
ERROR: Line magic function `%matplotlib` not found
I'm using enthought canopy and I have IPython version 2.4.1. I made sure to update using the IPython installation page for help. I'm not sure what's wrong because it should be very simple to open/read files. I even get this error for opening text files.
EDIT:
I imported traceback and used
print(traceback.format_exc())
But all I get is none printed. I'm not sure what that means.
Looks like you are using Pandas. Try the following (assuming your csv file is in the same path as the your script lib) and insert it one line at a time if you are using the IPython Shell:
import pandas as pd
names = pd.read_csv('Combined data.csv')
names.head()