This is all the further i've gotten.
import math
num_to_convert = int(input("Please enter any intger from 1 and 100:"))
while num_to_convert < 1 or num_to_convert > 100:
num_to_convert = int(input("Sorry that's not an integer from 1 to 100, try again:"))
else:
print("I'm lost!")
I found this but I don't understand whats going on. Maybe some explanation of what's going on would help.
def decimalToBinary(n):
if(n > 1):
# divide with integral result
# (discard remainder)
decimalToBinary(n//2)
print(n%2, end=' ')
It seems like you want to convert an integer which is not a decimal to binary from your code i would write
while True:
try:
value1=input("Integer you want to convert to binary: ")
binaryvalue=(bin(int(value1)))
print (binaryvalue[2:])
except:
print("I did not understand that")
pass
Valuetoconvert=int(input("Number to convert: "))
u = format(Valuetoconvert, "08b")
print(u)
Try this then
See Below:
def toBin(n):
if n < 2:
return str(n)
else:
if n % 2 == 0:
return toBin(n//2) + "0"
else:
return toBin(n//2) + "1"
Explanation:
This is my sollution which works similar to yours. I hope you know what recursion is otherwise this is going to be difficult to understand.
Anyway the algorithm is to devide the number repeatedly by 2 until the number is smaller than 2 cause then you have the sollution right away(base case).
When the current number is greater than 2 you check wether it is
divisible by 2. If it is even you append a 0 to your string else append a 1. You can try this out on paper to better understand it.
I need some help regarding calculating averages and ranges. I am using built-in functions such as sum(), len(), etc. and cannot seem to calculate the average or range. I am using it to write a small piece of code for fun but cannot seem to get it to work. any help is much appreciated. Thank you!
x = 1
number_list = []
while x == 1:
input_number = input("PLease input an integer")
if str.isdigit(input_number) == True:
number_list.append(input_number)
else:
print("Please input a valid integer only.")
continueornot = input("Would you like to continue adding data? PLease input 'Yes' to continue, and anything else to quit.")
if continueornot == 'Yes':
x = 1
else:
print("Here is the maximum number:", max(number_list))
print("Here is the minimum number:", min(number_list))
print("Here is the count:", len(number_list))
print("Here is the average:" + sum(number_list) / len(number_list))
print("Here is the range:", range(number_list))
quit()
Change
if str.isdigit(input_number) == True:
number_list.append(input_number)
to
if input_number.isdigit():
number_list.append(int(input_number))
The error is because you're trying to do those operations on a list of strings.
You can also remove the check against True since that is implicitly checking the truthiness and since input_number is already a str, you can call the isdigit() method directly.
The problem is that you are appending strings to the list rather than integers and then you are applying arithmetic operations on it. So first you should convert the input number to int type.
Secondly range function will not give you the range of a list rather then it returns a sequence.
x = 1
number_list = []
while x == 1:
input_number = input("PLease input an integer")
if str.isdigit(input_number) == True:
input_number=int(input_number)
number_list.append(input_number)
else:
print("Please input a valid integer only.")
continueornot = input("Would you like to continue adding data? PLease input 'Yes' to continue, and anything else to quit.")
if continueornot == 'Yes':
x = 1
else:
print("Here is the maximum number:", max(number_list))
print("Here is the minimum number:", min(number_list))
print("Here is the count:", len(number_list))
print("Here is the average:" , sum(number_list) / len(number_list))
print("Here is the range:", max(number_list)-min(number_list))
I am creating a math test program that creates random questions and I ask the user to input the answer and the answer is checked with the correct answer and the output is given.
import random
q = 1
live=3
operations = ("+" , "-")
for q in range(0,11):
while live>=1:
op=random.choice(operations)
num1=random.randint(0,10)
num2=random.randint(1,10)
if op =="+":
op=random.choice(operations)
num1=random.randint(0,10)
num2=random.randint(1,10)
correct = num1+num2
print("What is", " " +str(num1) + "+" +str(num2) + "?")
answer =input("\n Enter answer")
if answer==correct :
print("Correct answer")
q= q+1
else:
answer != correct
live= live - 1
print("The answer is incorrect. Try again mate!")
this is my incomplete code. The problem is even when there is a question with the addition mark and the user inputs the correct answer the programs still prints the wrong output (the output that should be printed if the user enters a wrong answer) Please, any help would be appreciated. Thanks in advance.
Simply change this line:
answer = input("\n Enter answer")
To this:
answer = int(input("\n Enter answer"))
The reason being is that your comparing a str and an int.
For Example
In the case ofnum1 = 5 and num2 = 5
correct will be equal to 5+5 or 10.
However, answer will be equal to the string "10".
So when you go to test equality between correct and answer, you're comparing "10" == 10 which is of course False. Thus you need to typecast the string answer into an int because input always returns a string. This results in 10==10 which is True.
thanks for taking time to read this.
I have to create a program that generates 10 random maths questions based around =, - and *. I have the program working but everytime I run it after the main program it prints "none" even though that's not in my program.Any help at all would be much appreciated. Thank you.
import random
print ("Welcome")
name=input("What's your name?")
print("Nice to meet you", name, ",you will be given 10 multiplication, addition and subtraction questions.")
Num1 = random.randint(1,12)
Num2 = random.randint(1,12)
sign = random.randint(1,3)
if sign == 1: # If the random number generated is 1
question = Num1 + Num2
rightanswer1 = Num1 + Num2
answer1=input(print("What is", question ,"?"))
if answer1 == rightanswer1:
print("Well Done!")
if answer1 != rightanswer1:
print("Sorry, that's incorrect, the answer was", rightanswer1)
if sign == 2:
question = Num1 - Num2
rightanswer2 = Num1 - Num2
answer2=input(print("What is", Num1, "-", Num2 ,"?"))
if answer2 == rightanswer2:
print("Well done!")
elif answer2 != rightanswer2:
print("Sorry, that's incorrect, the answer was", rightanswer2)
if sign == 3:
question = Num1 * Num2
rightanswer3 = Num1 * Num2
answer3=input(print("What is", Num1, "x", Num2 ,"?"))
if answer3 == rightanswer3:
print("Well done!")
elif answer3 != rightanswer3:
print("Sorry, that's incorrect, the answer was", rightanswer3)`
> Welcome
> What's your name? John
> Nice to meet you John ,you will be given 10 multiplication, addition and subtraction questions.
> What is 12 x 3 ?
> None 36
> Sorry, that's incorrect, the answer was 36
I think you are using python 3. In python 3 input is like raw_input in python 2. So you get the string as input. So convert it into int
var = int(input("Enter a number: "))
So in your code make it as
print("What is", Num1, "x", Num2 ,"?")
answer3 = input()
answer3 = int(answer3)
See this:
whats-the-difference-between-raw-input-and-input-in-python3-x
I'm reluctant to just give you an answer that just does it for you, so instead i'll provide you with a few hints to improve things. (i.e. this isn't an answer, just too large of a comment - and more like a codereview answer)
First off, you use a structure like this:
if x == 1:
#do something
if x == 2:
#do something else
...
In this case, which it makes no difference, it is easier to read if you use the if syntax as intended:
if <condition>:
#do this if the above test is true.
elif <more conditions>:
#do this only if the first test is false and this one is true
elif <more conditions>:
#same as above, except for the second test must be false too
else:
#do this if all the above tests are false
So you could use this something like:
if sign == 1:
...
elif sign == 2:
...
elif sign == 3:
...
else:
# something weird happened...
Which would make that section of the program easier to follow.
The same thing can be done with the if answer1 == rightanswer1: sections;
if answer1 == rightanswer1:
#correct!
else:
#incorrect.
That would be a clearer was to do it. You seem to have used the if...elif style in a couple of them, but not the first one.
Once you have this, it will be a little clearer.
The next way you could improve things is by removing duplicated code. You don't need separate branches for each sign, you can just roll it all into one:
number1 = randint(1,12)
number2 = randint(1,12)
op = randint(1,3)
question_string = "%d %s %d = ?" % (number1, number2, ["+", "-", "*"][op])
result = None
if op == 1:
result = number1 + number2
elif op == 2:
result = number1 - number2
elif op == 3:
result = number1 * number2
This will do most of the logic for you, and generate the strings you want, without duplicating all of the other code.
Small changes like this can make things much more readable.
It's printing None because the print() function returns None and you're passing that value of None from print() as the prompt to your input() functions. Eg,
answer3=input(print("What is", Num1, "x", Num2 ,"?"))
So print("What is", Num1, "x", Num2 ,"?") prints its stuff, and returns None, which then gets printed as the prompt by input().
A simple way to fix this is to just move your print() function calls out of your input() functions.
Eg,
print("What is", Num1, "x", Num2 ,"?")
answer3=input()
However, there's another major problem with your program: the rightanswer variables are ints, but the inputted answers are strings. To compare them properly they need to be the same type. So you should either convert the inputted answers to int, or alternatively, convert the rightanswers to str.
There are two problems with how you use the input function:
You misuse the prompt argument
You forget to convert the result
First, have a better look at the reference of the input function
The prompt argument
input takes a string as argument that will be displayed ("prompted") to the user to indicate that the program is waiting an input. The print function also displays a string to the user, but it doesn't return anything. It does its job and that's all (and in Python a function that returns nothing, returns None). That's what input gets to display, so it displays None. You should use format instead. It will format and return the formatted string that input can display:
answer1_as_str=input("What is {} ?".format(question))))
or
answer2_as_str=input("What is {:d} - {:d} ?".format(Num1, Num2)))
The return value
input returns the user input as a string contrary to python 2 (i.e. exactly as entered). So you have to convert the input to the desired type if you need it. If you type 10 for example, the input will return "10". If you need an int, you have to convert it yourself.
answer1 = int(answer1_as_str)
It looks like you don't really understand how input() works. You might also want to review the different datatypes and conditional statements. Other than that, it was a very good attempt. Here's my solution:
from random import randint
print("Welcome")
name = input("What's your name?\n")
print("Nice to meet you " + name + ", you will be given 10 multiplication, addition and subtraction questions.")
for i in range(10):
print("\nProblem " + str(i+1))
num1 = randint(1,12)
num2 = randint(1,12)
sign = randint(1,3)
if sign == 1:
question = str(num1) + " + " + str(num2)
answer = num1 + num2
elif sign == 2:
question = str(num1) + " - " + str(num2)
answer = num1 - num2
else:
question = str(num1) + " x " + str(num2)
answer = num1 * num2
user_answer = input("What is " + question + "? ")
if user_answer == str(answer):
print("Well done!")
else:
print("Sorry, that's incorrect, the answer was", answer)
How do I add numbers in between two numbers the user inputted in Python 2.7. So a person would input 75 and 80 and I want my program to add the numbers in between those two numbers. I am very new to programming and python so any help would be awesome!
This example excludes 75 and 80. If you need to include them replace with print sum(range(n1,n2+1))
n1=input('Enter first number ')
n2=input('Enter second number ')
print sum(range(min(n1,n2)+1,max(n1,n2)))
#DSM is right!
n1=input('Enter first number ')
n2=input('Enter second number ')
print (n2-n1+1)*(n2+n1)/2
to capture user input use number1 = raw_input('Input number'). From there I'm not exactly sure what you mean from adding numbers between the two? If you want 76+77+78+79 in that example
number1 = raw_input('Input number')
number2 = raw_input('Second number')
result = 0
for n in range(int(number1)+1, int(number2)):
result+=n
print result
Here's a quick sample that should handle a few different situations. Didn't go that in-depth since I don't know the scope of the situation. Realistically you should do some form of type-checking and loop until valid input is entered. However this should get you started:
def sumNums(a, b):
total = 0
if a < b:
total = sum(range(a+1, b))
elif b < a:
total = sum(range(b+1, a))
return total
num1 = int(raw_input("First Number: "))
num2 = int(raw_input("Second Number: "))
print sumNums(num1, num2)
However I'm sure there's a more comprehensive way using lists and sum() but it seems like you only need a basic working example.
easy you just go
def add(x,y):
if True:
return add(x, y)
else:
return None
add([1,2,3,4][0], [1,2,3,4][2])