Develop Reference

Split String based on multiple Regex matches

First of all, I checked these previous posts, and did not help me. 1 & 2 & 3
I have this string (or a similar case could be) that need to be handled with regex:
"Text Table 6-2: Management of children study and actions"
What I am supposed to do is detect the word Table and the word(s) before if existed
detect the numbers following and they can be in this format: 6 or 6-2 or 66-22 or 66-2
Finally the rest of the string (in this case: Management of children study and actions)
After doing so, the return value must be like this:
return 1 and 2 as one string, the rest as another string
e.g. returned value must look like this: Text Table 6-2, Management of children study and actions
Below is my code:
mystr = "Text Table 6-2: Management of children study and actions"
if re.match("([a-zA-Z0-9]+[ ])?(figure|list|table|Figure|List|Table)[ ][0-9]([-][0-9]+)?", mystr):
print("True matched")
parts_of_title = re.search("([a-zA-Z0-9]+[ ])?(figure|list|table|Figure|List|Table)[ ][0-9]([-][0-9]+)?", mystr)
print(parts_of_title)
print(" ".join(parts_of_title.group().split()[0:3]), parts_of_title.group().split()[-1])
The first requirement is returned true as should be but the second doesn't so, I changed the code and used compile but the regex functionality changed, the code is like this:
mystr = "Text Table 6-2: Management of children study and actions"
if re.match("([a-zA-Z0-9]+[ ])?(figure|list|table|Figure|List|Table)[ ][0-9]([-][0-9]+)?", mystr):
print("True matched")
parts_of_title = re.compile("([a-zA-Z0-9]+[ ])?(figure|list|table|Figure|List|Table)[ ][0-9]([-][0-9]+)?").split(mystr)
print(parts_of_title)
Output:
True matched
['', 'Text ', 'Table', '-2', ':\tManagement of children study and actions']
So based on this, how I can achieve this and stick to a clean and readable code? and why does using compile change the matching?

The matching changes because:
In the first part, you call .group().split() where .group() returns the full match which is a string.
In the second part, you call re.compile("...").split() where re.compile returns a regular expression object.
In the pattern, this part will match only a single word [a-zA-Z0-9]+[ ], and if this part should be in a capture group [0-9]([-][0-9]+)? the first (single) digit is currently not part of the capture group.
You could write the pattern writing 4 capture groups:
^(.*? )?((?:[Ll]ist|[Tt]able|[Ff]igure))\s+(\d+(?:-\d+)?):\s+(.+)
See a regex demo.
import re
pattern = r"^(.*? )?((?:[Ll]ist|[Tt]able|[Ff]igure))\s+(\d+(?:-\d+)?):\s+(.+)"
s = "Text Table 6-2: Management of children study and actions"
m = re.match(pattern, s)
if m:
print(m.groups())
Output
('Text ', 'Table', '6-2', 'Management of children study and actions')
If you want point 1 and 2 as one string, then you can use 2 capture groups instead.
^((?:.*? )?(?:[Ll]ist|[Tt]able|[Ff]igure)\s+\d+(?:-\d+)?):\s+(.+)
Regex demo
The output will be
('Text Table 6-2', 'Management of children study and actions')

you have already had answers but I wanted to try your problem to train myself so I give you all the same what I found if you are interested:
((?:[a-zA-Z0-9]+)? ?(?:[Ll]ist|[Tt]able|[Ff]igure)).*?((?:[0-9]+\-[0-9]+)|(?<!-)[0-9]+): (.*)
And here is the link to my tests: https://regex101.com/r/7VpPM2/1

Pandas Python Regular Expression Assistance

I wasn't sure what to call this title, feel free to edit it if you think there is a better name.
What I am trying to do is find cases that match certain search criteria.
Specifically, I am trying to find sentences that contain the word "where" in them. Once I have identified that, I am trying to find cases where the word "SQL" command is also located within that same tag.
Let's say I have a dataframe that looks like this:
search_criteria = ['where']
df4
Q R
0 file.sql <sentence>dave likes stuff</sentence><properties>version = "2", description = "example" type="SqlCommand">select id, name, from table where criteria = '5'</property><sentence>dave hates stuff>
0 file.sql <sentence>dave likes stuff</sentence><properties>version = "2", description = "example">select id, name, from table where criteria = '5'</properties><sentence>dave hates stuff>
I am trying to return this:
Q R
0 file.sql <properties>version = "2", description = "example">select id, name, from table</properties>
This record should get returned because it contains both "where" and "sqlcommand".
Here is my current process:
regex_stuff = df_all_xml_mfiles_tgther[cc:cc+1].R.str.findall('(<[^<]*?' + 'where' + '[^>]*?>)', re.IGNORECASE)
sql_command_regex_stuff = df_all_xml_mfiles_tgther[cc:cc+1].R.str.findall('(<property[^<]*?' + 'sqlcommand' + '[^>]*?<\/property>)', re.IGNORECASE)
if not regex_stuff.empty: #if one of the search criteria is found
if not sql_command_regex_stuff.empty: #check to see if the phrase "sqlcommand" is found anywhere as well
(insert rest of code)
This does not return anything.
What am I doing wrong?
Edit #1:
It seems like I need to do something at the end, to make the regex look something like this:
<property[^<]*?SqlCommand[^(<\/property>)]*
I feel like this is the right direction, doesn't work, but I feel like this is the right step.

You could just filter with str.contains:
df[(df['R'].str.contains('where', flags=re.IGNORECASE) & df['R'].str.contains('sqlcommand', flags=re.IGNORECASE))]
Q R
0 file.sql <sentence>dave likes stuff</sentence><properti...
or use ~ to return the opposite: strings that do not contain 'sqlcommand' or 'where'
df[~(df['R'].str.contains('where', flags=re.IGNORECASE) & df['R'].str.contains('sqlcommand', flags=re.IGNORECASE))]
Q R
1 file.sql <sentence>dave likes stuff</sentence><properti...

First of all, you have to have proper XML and SQL content, so you should
make the following corrections:
As the opening tag is <properties>, the closing tag must also be
</properties>, not </property>.
version, description and type are attributes (after them
there is > closing the opening tag, so after properties there
should be a space, not >.
Remove , after version="2".
Remove , after name.
Remove ( before <properties and ) after </properties>.
To find the required rows, use str.contains as the filtering
expression.
Below you have an example program:
import pandas as pd
import re
df4 = pd.DataFrame({
'Q' : 'file.sql',
'R' : [
'<s>dave</s><properties type="SqlCommand">select id, name '
'from table where criteria=\'5\'</properties><s>dave</s>',
'<s>dave</s><properties>select id, name from table '
'where criteria=\'6\'</properties><s>dave</s>',
'<s>mike</s><properties type="SqlCommand">drop table "Xyz"'
'</properties><s>mike</s>' ]})
df5 = df4[df4.R.str.contains(
'<properties[^<>]+?sqlcommand[^<>]+?>[^<>]+?where',
flags=re.IGNORECASE)]
print(df5)
Note that the regex takes care about the proper sequence of
strings:
First match <properties.
Then a sequence of chars other than < and > ([^<>]+?).
so we are still within the just opened XML tag.
Then match sqlcommand (ignoring case).
Then another sequence of chars other than < and >
([^<>]+?).
Then >, closing the tag.
Then another sequence of chars other than < and >
([^<>]+?).
And finally where (also ignoring case).
An attempt to check for sqlcommand and where in two separate
regexes is wrong, as these words can be at other locations,
which do not meet your requirement.

Get only first two numbers from the numeric value in python.How?

I have output from the below code and from that output I need to get only the maj and minor of that value.Is there any way I can get only the first two numbers 1.1 not full value 1.1.73.4
for version in issue["fields"]["fixVersions"]:
cacheData = json.dumps(version)
jsonToPython = json.loads(cacheData)
#lines = jsonToPython.items()
if jsonToPython['name'][:8] == "Ciagana ":
matches = re.findall(r"\d+\.\d+\.\d+\.\d+", jsonToPython['name'])
print matches[0]
Below is the output of the code currently:
Retrieving list of issues
Processing CTPT-2
1.1.73.4
1.1.90.0
Processing CTPT-1
1.5.73.4
Below is the desired output
Retrieving list of issues
Processing CTPT-2
1.1
1.1
Processing CTPT-1
1.1

Regex would work, or a simple split:
short_version_string = '.'.join(version_string.split('.')[:2])
Or this, though it only works in Python 3:
major, minor, *_ = version_string.split('.')

Another way, by modifying your regex pattern to have a look-ahead for another period:
text = ['4.4.73.4', '4.4.90.0', '4.5.73.4']
for version in text:
matches = re.findall(r"\d+\.\d+(?=\.)", version)
print matches[0]
#4.4
#4.4
#4.5
The pattern is:
\d+\.\d+: Any number of digits followed by a period followed by any number of digits
(?=\.): A non-capturing look-ahead for another period

Repeated regex groups of arbitrary number

I have this example text snippet
headline:
Status[apphmi]: blubb, 'Statustext1'
Main[apphmi]: bla, 'Maintext1'Main[apphmi]: blaa, 'Maintext2'
Popup[apphmi]: blaaa, 'Popuptext1'
and I want to extract the words within '', but sorted with the context (status, main, popup).
My current regex is (example at pythex.org):
headline:(?:\n +Status\[apphmi\]:.* '(.*)')*(?:\n +Main\[apphmi\]:.* '(.*)')*(?:\n +Popup\[apphmi\]:.* '(.*)')*
but with this I only get 'Maintext2' and not both. I don't know how to repeat the groups to an arbitrary number.

You can try with this:
r"(.*?]):(?:[^']*)'([^']*)'"g
Look here
Group1 and Group 2 for each match contains your key value pair
You can not merge the second match as one by using regex, once you get all the pairs... you can apply some programming here to merge duplicate keys as one.
Here I have used dictionary of list, if a key already exists in the dictionary then you should append the value to the list , otherwise insert a new key with a new list having the value.
This is how it should be done (tested in python 3+)
import re
d = dict()
regex = r"(.*?]):(?:[^']*)'([^']*)'"
test_str = ("headline: \n"
"Status[apphmi]: blubb, 'Statustext1'\n"
"Main[apphmi]: bla, 'Maintext1'Main[apphmi]: blaa, 'Maintext2'\n"
"Popup[apphmi]: blaaa, 'Popuptext1'")
matches = re.finditer(regex, test_str)
for matchNum, match in enumerate(matches):
if match.group(1) in d:
d[match.group(1)].append(match.group(2))
else:
d[match.group(1)] = [match.group(2),]
print(d)
Output:
{
'Popup[apphmi]': ['Popuptext1'],
'Main[apphmi]': ['Maintext1', 'Maintext2'],
'Status[apphmi]': ['Statustext1']
}

Python parsing

I'm trying to parse the title tag in an RSS 2.0 feed into three different variables for each entry in that feed. Using ElementTree I've already parsed the RSS so that I can print each title [minus the trailing )] with the code below:
feed = getfeed("http://www.tourfilter.com/dallas/rss/by_concert_date")
for item in feed:
print repr(item.title[0:-1])
I include that because, as you can see, the item.title is a repr() data type, which I don't know much about.
A particular repr(item.title[0:-1]) printed in the interactive window looks like this:
'randy travis (Billy Bobs 3/21'
'Michael Schenker Group (House of Blues Dallas 3/26'
The user selects a band and I hope to, after parsing each item.title into 3 variables (one each for band, venue, and date... or possibly an array or I don't know...) select only those related to the band selected. Then they are sent to Google for geocoding, but that's another story.
I've seen some examples of regex and I'm reading about them, but it seems very complicated. Is it? I thought maybe someone here would have some insight as to exactly how to do this in an intelligent way. Should I use the re module? Does it matter that the output is currently is repr()s? Is there a better way? I was thinking I'd use a loop like (and this is my pseudoPython, just kind of notes I'm writing):
list = bandRaw,venue,date,latLong
for item in feed:
parse item.title for bandRaw, venue, date
if bandRaw == str(band)
send venue name + ", Dallas, TX" to google for geocoding
return lat,long
list = list + return character + bandRaw + "," + venue + "," + date + "," + lat + "," + long
else
In the end, I need to have the chosen entries in a .csv (comma-delimited) file looking like this:
band,venue,date,lat,long
randy travis,Billy Bobs,3/21,1234.5678,1234.5678
Michael Schenker Group,House of Blues Dallas,3/26,4321.8765,4321.8765
I hope this isn't too much to ask. I'll be looking into it on my own, just thought I should post here to make sure it got answered.
So, the question is, how do I best parse each repr(item.title[0:-1]) in the feed into the 3 separate values that I can then concatenate into a .csv file?

Don't let regex scare you off... it's well worth learning.
Given the examples above, you might try putting the trailing parenthesis back in, and then using this pattern:
import re
pat = re.compile('([\w\s]+)\(([\w\s]+)(\d+/\d+)\)')
info = pat.match(s)
print info.groups()
('Michael Schenker Group ', 'House of Blues Dallas ', '3/26')
To get at each group individual, just call them on the info object:
print info.group(1) # or info.groups()[0]
print '"%s","%s","%s"' % (info.group(1), info.group(2), info.group(3))
"Michael Schenker Group","House of Blues Dallas","3/26"
The hard thing about regex in this case is making sure you know all the known possible characters in the title. If there are non-alpha chars in the 'Michael Schenker Group' part, you'll have to adjust the regex for that part to allow them.
The pattern above breaks down as follows, which is parsed left to right:
([\w\s]+) : Match any word or space characters (the plus symbol indicates that there should be one or more such characters). The parentheses mean that the match will be captured as a group. This is the "Michael Schenker Group " part. If there can be numbers and dashes here, you'll want to modify the pieces between the square brackets, which are the possible characters for the set.
\( : A literal parenthesis. The backslash escapes the parenthesis, since otherwise it counts as a regex command. This is the "(" part of the string.
([\w\s]+) : Same as the one above, but this time matches the "House of Blues Dallas " part. In parentheses so they will be captured as the second group.
(\d+/\d+) : Matches the digits 3 and 26 with a slash in the middle. In parentheses so they will be captured as the third group.
\) : Closing parenthesis for the above.
The python intro to regex is quite good, and you might want to spend an evening going over it http://docs.python.org/library/re.html#module-re. Also, check Dive Into Python, which has a friendly introduction: http://diveintopython3.ep.io/regular-expressions.html.
EDIT: See zacherates below, who has some nice edits. Two heads are better than one!

Regular expressions are a great solution to this problem:
>>> import re
>>> s = 'Michael Schenker Group (House of Blues Dallas 3/26'
>>> re.match(r'(.*) \((.*) (\d+/\d+)', s).groups()
('Michael Schenker Group', 'House of Blues Dallas', '3/26')
As a side note, you might want to look at the Universal Feed Parser for handling the RSS parsing as feeds have a bad habit of being malformed.
Edit
In regards to your comment... The strings occasionally being wrapped in "s rather than 's has to do with the fact that you're using repr. The repr of a string is usually delimited with 's, unless that string contains one or more 's, where instead it uses "s so that the 's don't have to be escaped:
>>> "Hello there"
'Hello there'
>>> "it's not its"
"it's not its"
Notice the different quote styles.

Regarding the repr(item.title[0:-1]) part, not sure where you got that from but I'm pretty sure you can simply use item.title. All you're doing is removing the last char from the string and then calling repr() on it, which does nothing.
Your code should look something like this:
import geocoders # from GeoPy
us = geocoders.GeocoderDotUS()
import feedparser # from www.feedparser.org
feedurl = "http://www.tourfilter.com/dallas/rss/by_concert_date"
feed = feedparser.parse(feedurl)
lines = []
for entry in feed.entries:
m = re.search(r'(.*) \((.*) (\d+/\d+)\)', entry.title)
if m:
bandRaw, venue, date = m.groups()
if band == bandRaw:
place, (lat, lng) = us.geocode(venue + ", Dallas, TX")
lines.append(",".join([band, venue, date, lat, lng]))
result = "\n".join(lines)
EDIT: replaced list with lines as the var name. list is a builtin and should not be used as a variable name. Sorry.