i have x-axis which is in terms of days (366 days Feb was taken as 29 days) but instead I want to convert it in terms of months (Jan - Dec). What should i do...
def plotGraph():
line, point = getXY()
plt.plot(line['xlMax'], c='orangered', alpha=0.5, label = 'Minimum Temperature (2005-14)')
plt.plot(line['xlMin'], c='dodgerblue', alpha=0.5, label = 'Minimum Temperature (2005-14)')
plt.scatter(point['xsMax'].index, point['xsMax'], s = 10, c = 'maroon', label = 'Record Break Minimum (2015)')
plt.scatter(point['xsMin'].index, point['xsMin'], s = 10, c = 'midnightblue', label = 'Record Break Maximum (2015)')
ax1 = plt.gca() # Primary axes
ax1.fill_between(line['xlMax'].index , line['xlMax'], line['xlMin'], facecolor='lightgray', alpha=0.25)
ax1.grid(True, alpha = 1)
for spine in ax1.spines:
ax1.spines[spine].set_visible(False)
ax1.spines['bottom'].set_visible(True)
ax1.spines['bottom'].set_alpha(0.3)
# Removing Ticks
ax1.tick_params(axis=u'both', which=u'both',length=0)
plt.show()
I think the quickest change might be to just set new ticks and tick labels at the starts of months; I found the conversion from day-of-the-year to month here, the first table:
import numpy as np
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
x = range(1,367)
y = np.random.rand(len(range(1,367)))
ax.plot(x,y)
month_starts = [1,32,61,92,122,153,183,214,245,275,306,336]
month_names = ['Jan','Feb','Mar','Apr','May','Jun',
'Jul','Aug','Sep','Oct','Nov','Dec']
ax.set_xticks(month_starts)
ax.set_xticklabels(month_names)
Note I assumed your days were numbered 1 to 366; if they are 0 to 365 you may have to change the range.
But I think usually a better approach is to get your days into some sort of datetime; this is more flexible and usually pretty smart. If say, your days were not confined to one year, it would be more complicated to associate day numbers with months.
This example uses datetime instead of integers. The dates are plotted on the x-axis directly, and then the DateFormatter and MonthLocator from matplotlib.dates are used to format the axis appropriately:
import datetime as dt
import matplotlib.pyplot as plt
import matplotlib.dates as mdates
import numpy as np
start = dt.datetime(2016,1,1) #there has to be a year given, even if it isn't plotted
new_dates = [start + dt.timedelta(days=i) for i in range(366)]
fig, ax = plt.subplots()
x = new_dates
y = np.random.rand(len(range(1,367)))
xfmt = mdates.DateFormatter('%b')
months = mdates.MonthLocator()
ax.xaxis.set_major_locator(months)
ax.xaxis.set_major_formatter(xfmt)
ax.plot(x,y)
Related
My question is if there is any way to use matplotlib date tick labels with a log xscale.
I find whenever I try to set_xscale('log') it just erases the labels and doesn't actually log the xscale...
Example code:
import datetime
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.dates as mdates
import matplotlib.cbook as cbook
years = mdates.YearLocator() # every year
months = mdates.MonthLocator() # every month
yearsFmt = mdates.DateFormatter('%Y')
# Load a numpy record array from yahoo csv data with fields date, open, close,
# volume, adj_close from the mpl-data/example directory. The record array
# stores the date as an np.datetime64 with a day unit ('D') in the date column.
with cbook.get_sample_data('goog.npz') as datafile:
r = np.load(datafile)['price_data'].view(np.recarray)
# Matplotlib works better with datetime.datetime than np.datetime64, but the
# latter is more portable.
date = r.date.astype('O')
fig, ax = plt.subplots()
ax.plot(date, r.adj_close)
# format the ticks
ax.xaxis.set_major_locator(years)
ax.xaxis.set_major_formatter(yearsFmt)
ax.xaxis.set_minor_locator(months)
datemin = datetime.date(date.min().year, 1, 1)
datemax = datetime.date(date.max().year + 1, 1, 1)
ax.set_xlim(datemin, datemax)
# format the coords message box
def price(x):
return '$%1.2f' % x
ax.format_xdata = mdates.DateFormatter('%Y-%m-%d')
ax.format_ydata = price
ax.grid(True)
# rotates and right aligns the x labels, and moves the bottom of the
# axes up to make room for them
fig.autofmt_xdate()
ax.set_xscale('log')
plt.show()
Try using ScalarFormatter:
from matplotlib.ticker import ScalarFormatter
ax.xaxis.set_major_formatter(ScalarFormatter())
This code plots the data exactly as I want with the dates on the x-axis and the times on the y-axis. However I want the y-axis to show every hour on the hour (e.g., 00, 01, ... 23) and the x-axis to show the beginning of every month at an angle so there's no overlap (the actual data being used spans over a year) and only once, since this code repeats the same months. How is this accomplished?
import pandas as pd
import matplotlib.pyplot as plt
import matplotlib.dates as mdates
data = ['2018-01-01 09:28:52', '2018-01-03 13:02:44', '2018-01-03 15:30:27', '2018-02-04 11:55:09']
f, ax = plt.subplots()
data = pd.to_datetime(data, yearfirst=True)
ax.plot(data.date, data.time, '.')
ax.set_ylim(["00:00:00", "23:59:59"])
days = mdates.DayLocator()
d_fmt = mdates.DateFormatter('%Y-%m')
ax.xaxis.set_major_locator(days)
ax.xaxis.set_major_formatter(d_fmt)
plt.show()
UPDATE: This fixes the x axis.
# Monthly intervals on x axis
months = mdates.MonthLocator()
d_fmt = mdates.DateFormatter('%Y-%m')
ax.xaxis.set_major_locator(months)
ax.xaxis.set_major_formatter(d_fmt)
However, this attempt to fix the y axis just makes it blank.
# Hourly intervals on y axis
hours = mdates.HourLocator()
t_fmt = mdates.DateFormatter('%H')
ax.yaxis.set_major_locator(hours)
ax.yaxis.set_major_formatter(t_fmt)
I'm reading these docs but not understanding my error: https://matplotlib.org/api/dates_api.html, https://matplotlib.org/api/ticker_api.html
Matplotlib cannot plot times without corresponding date. This would make is necessary to add some arbitrary date (in the below case I took the 1st of january 2018) to the times. One may use datetime.datetime.combine for that purpose.
timetodatetime = lambda x:dt.datetime.combine(dt.date(2018, 1, 1), x)
time = list(map(timetodatetime, data.time))
ax.plot(data.date, time, '.')
Then the code from the question using HourLocator() would work fine. Finally, setting the limits on the axes would also require to use datetime objects,
ax.set_ylim([dt.datetime(2018,1,1,0), dt.datetime(2018,1,2,0)])
Complete example:
import pandas as pd
import matplotlib.pyplot as plt
import matplotlib.dates as mdates
import datetime as dt
data = ['2018-01-01 09:28:52', '2018-01-03 13:02:44', '2018-01-03 15:30:27',
'2018-02-04 11:55:09']
f, ax = plt.subplots()
data = pd.to_datetime(data, yearfirst=True)
timetodatetime = lambda x:dt.datetime.combine(dt.date(2018, 1, 1), x)
time = list(map(timetodatetime, data.time))
ax.plot(data.date, time, '.')
# Monthly intervals on x axis
months = mdates.MonthLocator()
d_fmt = mdates.DateFormatter('%Y-%m')
ax.xaxis.set_major_locator(months)
ax.xaxis.set_major_formatter(d_fmt)
## Hourly intervals on y axis
hours = mdates.HourLocator()
t_fmt = mdates.DateFormatter('%H')
ax.yaxis.set_major_locator(hours)
ax.yaxis.set_major_formatter(t_fmt)
ax.set_ylim([dt.datetime(2018,1,1,0), dt.datetime(2018,1,2,0)])
plt.show()
I'm trying to build matplotlib charts whose x-axis is a dateIndex from a pandas dataframe. Trying to mimic some examples from matplotlib, I've been unsuccessful. The xaxis ticks and labels never appear.
I thought maybe matplotlib wasn't properly digesting the pandas index, so I converted it to ordinal with the matplotlib date2num helper function, but that gave the same result.
# https://matplotlib.org/api/dates_api.html
# https://matplotlib.org/examples/api/date_demo.html
import datetime as dt
import matplotlib.dates as mdates
import matplotlib.cbook as cbook
import matplotlib.dates as mpd
years = mdates.YearLocator() # every year
months = mdates.MonthLocator() # every month
yearsFmt = mdates.DateFormatter('%Y')
majorLocator = years
majorFormatter = yearsFmt #FormatStrFormatter('%d')
minorLocator = months
y1 = np.arange(100)*0.14+1
y2 = -(np.arange(100)*0.04)+12
"""neither of these indices works"""
x = pd.date_range(start='4/1/2012', periods=len(y1))
#x = map(mpd.date2num, pd.date_range(start='4/1/2012', periods=len(y1)))
fig, ax = plt.subplots()
ax.plot(x,y1)
ax.plot(x,y2)
ax.xaxis.set_major_locator(years)
ax.xaxis.set_major_formatter(yearsFmt)
ax.xaxis.set_minor_locator(months)
datemin = x[0]
datemax = x[-1]
ax.set_xlim(datemin, datemax)
fig.autofmt_xdate()
plt.show()
The problem is the following. pd.date_range(start='4/1/2012', periods=len(y1)) creates dates from the first of April 2012 to the 9th of July 2012.
Now you set the major locator to be a YearLocator. This means, that you want to have a tick for each year on the axis. However, all dates are within the same year 2012. So there is no major tick to be shown within the plot range.
The suggestion would be to use a MonthLocator instead, such that the first of each month is ticked. Also if would make sense to use a formatter, which actually shows the months, e.g. '%b %Y'. You may use a DayLocator for the minor ticks, if you want, to show the small tickmarks for each day.
ax.xaxis.set_major_locator(mdates.MonthLocator())
ax.xaxis.set_major_formatter(mdates.DateFormatter('%b %Y'))
ax.xaxis.set_minor_locator(mdates.DayLocator())
Complete example:
import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.dates as mdates
y1 = np.arange(100)*0.14+1
y2 = -(np.arange(100)*0.04)+12
x = pd.date_range(start='4/1/2012', periods=len(y1))
fig, ax = plt.subplots()
ax.plot(x,y1)
ax.plot(x,y2)
ax.xaxis.set_major_locator(mdates.MonthLocator())
ax.xaxis.set_major_formatter(mdates.DateFormatter('%b %Y'))
ax.xaxis.set_minor_locator(mdates.DayLocator())
fig.autofmt_xdate()
plt.show()
You could use pd.DataFrame.plot to handle most of that
df = pd.DataFrame(dict(
y1=y1, y2=y2
), index=x)
df.plot()
I wanted to plot a data which has datetime values for the x axis and another set of values as y. As an example, I will use the example from matplotlib where y in this case are stock prices. Here is the code for that.
import matplotlib.pyplot as plt
from matplotlib.finance import quotes_historical_yahoo_ochl
from matplotlib.dates import YearLocator, MonthLocator, DateFormatter
import datetime
date1 = datetime.date(1995, 1, 1)
date2 = datetime.date(2004, 4, 12)
years = YearLocator() # every year
months = MonthLocator() # every month
yearsFmt = DateFormatter('%Y')
quotes = quotes_historical_yahoo_ochl('INTC', date1, date2)
if len(quotes) == 0:
raise SystemExit
dates = [q[0] for q in quotes]
opens = [q[1] for q in quotes]
fig, ax = plt.subplots()
ax.plot_date(dates, opens, '-')
# format the ticks
ax.xaxis.set_major_locator(years)
ax.xaxis.set_major_formatter(yearsFmt)
ax.xaxis.set_minor_locator(months)
ax.autoscale_view()
# format the coords message box
def price(x):
return '$%1.2f' % x
ax.fmt_xdata = DateFormatter('%Y-%m-%d')
ax.fmt_ydata = price
ax.grid(True)
fig.autofmt_xdate()
plt.show()
Now, what I want to do is color each value in the graph based on some criterion. For simplicity's sake, let's say that the criterion in the case of the example is based on the year. That is, prices belonging to the same year will be colored the same. How would I do that? Thanks!
You can use numpy arrays with masks over the range you want (in this case a year). In order to use the inbuilt YearLocator function from your example, you need to plot the graph first and set the ticks, then remove and replace with the range per year, from your example,
import matplotlib.pyplot as plt
from matplotlib.finance import quotes_historical_yahoo_ochl
from matplotlib.dates import YearLocator, MonthLocator, DateFormatter
import datetime
import numpy
date1 = datetime.date(1995, 1, 1)
date2 = datetime.date(2004, 4, 12)
years = YearLocator() # every year
months = MonthLocator() # every month
yearsFmt = DateFormatter('%Y')
quotes = quotes_historical_yahoo_ochl('INTC', date1, date2)
if len(quotes) == 0:
raise SystemExit
dates = np.array([q[0] for q in quotes])
opens = np.array([q[1] for q in quotes])
fig, ax = plt.subplots()
l = ax.plot_date(dates, opens, '-')
# format the ticks
ax.xaxis.set_major_locator(years)
ax.xaxis.set_major_formatter(yearsFmt)
ax.xaxis.set_minor_locator(months)
ax.autoscale_view()
l[0].remove()
py = years()[0]
for year in years()[1:]:
mask = (py < dates) & (dates < year)
ax.plot_date(dates[mask], opens[mask], '-')
py = year
# format the coords message box
def price(x):
return '$%1.2f' % x
ax.fmt_xdata = DateFormatter('%Y-%m-%d')
ax.fmt_ydata = price
ax.grid(True)
fig.autofmt_xdate()
plt.show()
which gives,
The way I typically do this is by using a for loop to plot different sections of the data, coloring each section as I go. In your example, this section:
fig, ax = plt.subplots()
ax.plot_date(dates, opens, '-')
becomes:
# import the colormaps
from maplotlib import cm
fig, ax = plt.subplots()
for y in years:
y_indices = [i for i in range(len(dates)) if dates[i].year==y]
# subset the data, there are better ways to do this
sub_dates = [dates[i] for i in y_indices]
sub_opens = [opens[i] for i in y_indices]
# plot each section of data, using a colormap to change the color for
# each iteration.
ax.plot_date(sub_dates, sub_opens, '-', linecolor=cm.spring((y-2000)/10.0)
My matplotlib pyplot has too many xticks - it is currently showing each year and month for a 15-year period, e.g. "2001-01", but I only want the x-axis to show the year (e.g. 2001).
The output will be a line graph where x-axis shows dates and the y-axis shows the sale and rent prices.
# Defining the variables
ts1 = prices['Month'] # eg. "2001-01" and so on
ts2 = prices['Sale']
ts3 = prices['Rent']
# Reading '2001-01' as year and month
ts1 = [dt.datetime.strptime(d,'%Y-%m').date() for d in ts1]
plt.figure(figsize=(13, 9))
# Below is where it goes wrong. I don't know how to set xticks to show each year.
plt.xticks(ts1, rotation='vertical')
plt.xlabel('Year')
plt.ylabel('Price')
plt.plot(ts1, ts2, 'r-', ts1, ts3, 'b.-')
plt.gcf().autofmt_xdate()
plt.show()
Try removing the plt.xticks function call altogether. matplotlib will then use the default AutoDateLocator function to find the optimum tick locations.
Alternatively if the default includes some months which you don't want then you can use matplotlib.dates.YearLocator which will force the ticks to be years only.
You can set the locator as shown below in a quick example:
import matplotlib.pyplot as plt
import matplotlib.dates as mdate
import numpy as np
import datetime as dt
x = [dt.datetime.utcnow() + dt.timedelta(days=i) for i in range(1000)]
y = range(len(x))
plt.plot(x, y)
locator = mdate.YearLocator()
plt.gca().xaxis.set_major_locator(locator)
plt.gcf().autofmt_xdate()
plt.show()
You can do this with plt.xticks.
As an example, here I have set the xticks frequency to display every three indices. In your case, you would probably want to do so every twelve indices.
import numpy as np
import matplotlib.pyplot as plt
x = np.arange(10)
y = np.random.randn(10)
plt.plot(x,y)
plt.xticks(np.arange(min(x), max(x)+1, 3))
plt.show()
In your case, since you are using dates, you can replace the argument of the second to last line above with something like ts1[0::12], which will select every 12th element from ts1 or np.arange(0, len(dates), 12) which will select every 12th index corresponding to the ticks you want to show.