Converting a decimal number from str to float - python

I have the following number of type float:
1.019e-05
To convert it to a decimal number, i did this:
print("%.10f" % float(1.019e-05))
Which gives the following output: 0.0000101900
The problem is that 0.0000101900 is of type str, but i need to make some calculations with that number. How can i convert 0.0000101900 from string to a number again? if i use float()the decimal will be converted again to an exponential. Am i forced to use the exponential number here?

The number is a float and has the same value no matter how it looks - the scientific notation used is just a way of representing how the data looks in a more concise way. By doing your formatting string, you are formatting the number to look a certain way for output, but that creates a string representation of the number rather than "converting it to a decimal number". You can't change the way Python natively represents a float, but I'm not understanding why this matters to you because it doesn't change the actual value of the number, just how it looks when printed out

Related

Convert float to Decimal with fixed digits after decimal

I want to convert some floats to Decimal retaining 5 digits after decimal place regardless of how many digits before the decimal place. Is using string formatting the most efficient way to do this?
I see in the docs:
The significance of a new Decimal is determined solely by the number of digits input. Context precision and rounding only come into play during arithmetic operations.
So that means I need to add 0 to force it to use the specified prec but the prec is total digits not after decimal so it doesn't actually help.
The best thing I can come up with is
a=[1.132434, 22.2334,99.33999434]
[Decimal("%.5f" % round(x,5)) for x in a]
to get [Decimal('1.13243'), Decimal('22.23340'), Decimal('99.33999')]
Is there a better way? It feels like turning floats into strings just to convert them back to a number format isn't very good although I can't articulate why.
Do all the formatting on the way out from your code, inside the print and write statements. There is no reason I can think of to lose precision (and convert the numbers to some fixed format) while doing numeric calculations inside the code.

How to convert all floats to two decimal places regardless of number of decimal places float has without repeating convert code?

Goal
I want to convert all floats to two decimal places regardless of number of decimal places float has without repeating convert code.
For example, I want to convert
50 to 50.00
50.5 to 50.50
without repeating the convert code again and again. What I mean is explained in the following section - research.
Not what this question is about
This question is NOT about:
Only limiting floats to two decimal points - if there is less than two decimal points then I want it to have two decimal points with zeros for the unused spaces.
Flooring the decimal or ceiling it.
Rounding the decimal off.
This question is not a duplicate of this question.
That question only answers the first part of my question - convert floats to two decimal places regardless of number of decimal places float has, not the second part - without repeating convert code.
Nor this question.
That is just how to add units before the decimal place. My question
is: how to convert all floats to two decimal places regardless of
number of decimal places float has without repeating convert code.
Research
I found two ways I can achieve the convert. One is using the decimal module:
from decimal import *
TWOPLACES = Decimal(10) ** -2
print(Decimal('9.9').quantize(TWOPLACES))
Another, without using any other modules:
print(f"{9.9:.2f}")
However, that does not fully answer my question. Realise that the code to convert keeps being needed to repeat itself? I keep having to repeat the code to convert again and again. Sadly, my whole program is already almost completed and it will be quite a waste of time to add this code here and there so the format will be correct. Is there any way to convert all floats to two decimal places regardless of number of decimal places float has without repeating convert code?
Clarification
What I mean by convert is, something like what Dmytro Chasovskyi said, that I want all places with floats in my program without extra changes to start to operate like decimals. For example, if I had the operation 1.2345 + 2.7 + 3 + 56.1223183 it should be 1.23 + 2.70 + 3.00 + 56.12.
Also, float is a number, not a function.
The bad news is: there is no "float" with "two decimal places".
Floating point numbers are represented internally with a fixed number of digits in base 2. https://floating-point-gui.de/basic/ .
And these are both efficient and accurate enough for almost all calculations we perform with any modern program.
What we normally want is that the human-readable text representation of a number, in all outputs of a program, shows only two digits. And this is controlled at wherever your program is either writting the value to a text file, to the screen, or rendering it to an HTML template (which is "writing it to a text file", again).
So, it happens that the same syntaxes that will convert a number to text, embedded in another string, allows additionally to control the exact output of the number. You put as an example print(f"{9.9:.2f}"). The only thing that looks impractical there is due to you hardcoding your number along with its conversion. Typically, the number will be in a variable.
Them, all you have to do is writting, wherever you output the number:
print(f"The value is: {myvar:.02f}")
instead of
print(f"The value is: {myvar}")
Or in whatever function you are calling that will need the rendered version of the number instead of print. Notice that the use of the word "rendered" here is deliberate: while your program is running, the number is stored in an efficient way in memory, directly usable by the CPU, that is not human readable. At any point you want to "see" the number, you have to convert it into text. It is just that some calls to it implicitly, like print(myvar). Then, just resort to explicitly converting it in these places - `print(f"{myvar:.02f}").
really having 2 decimal places in memory
If you use decimal.Decimal, then yes, there are ways to keep the internal representation of the number with 2 decimal digits,
but them, instead of just converting the number on output, you must convert it into a "2 decimal place" value on all inputs as well
That means that whenever ingesting a number into your program, be it typed by the user, read from a binary file or database, or received via wire from a sensor, you have to apply a similar transform to the one used in the output as detailed above. More precisely: you convert your float to a properly formatted string, and then convert that to a decimal.Decimal.
And this will prevent your program of accumulating errors due to base conversion, but you will still need to force the format to 2 decimal places on every output, just like above.
Use this function.
def cvt_decimal(input):
number = float(input)
return ("%.2f" % number)
print(cvt_decimal(50))
print(cvt_decimal(50.5))
Output is :
50.00
50.50
** Process exited - Return Code: 0 **
Press Enter to exit terminal
you can modify the decimal precision, even if you do any operation between 2 decimal types
import decimal
from decimal import Decimal
decimal.getcontext().prec = 2
a = Decimal('0.12345')
b = Decimal('0.12345')
print(a + b)
Decimal calculations are precise but it takes more time to do calculations, keep that in mind.

PYTHON - Changing very small numbers as string to float (scientific notation)

i have a string like '0.00008400' and i just want to turn it 0.00008400 (float). But python changes it to scientific notation type and it is looking like 8.4e-05,
float('0.00008400') = 8.4e-05 #as float
I saw some formatting answers but they are turning it to string instead of float.
format(8.4e-05, '.8f') = 0.00008400 #as string
and of course I can't turn this string value into float again...
#stupid alert
float(format(8.4e-05, '.8f')) = 8.4e-05
I just want to my string type input to turn float exactly...
'0.00008400' => 0.00008400 #string to float
Thanks in advance...
Edit:
there is a function that I want to use gets float value but can't understand scientific notion format of float. So this is why I want to show this float normal.
SORRY:
string format is okay too. Sorry.
The scientific representation is "just" a representation of your float, that does not change the real value of the float, whatever how python display it.
So I don't understand what you want to do. Could you send more informations ?

Converting Binary Number of List integer Type into Decimal Number?

I know this is kind of weird question. I was developing a program, and suddenly I got stuck a bit strange issue. Let me explain the portion, where I am having an issue:
I have int type list variable, where I stored binary values like
Now I want to take as it is and to convert into Decimal format. How should I do it?
You first need to turn the integer to string than again to int using base 2.
Here is an example:
x = 111000111100000
dec = int(str(x), 2)
print(dec) # --> 29152

How can I convert a string to a float and always show 2 decimal places?

I've managed to get 2dp format for a number, however, it returns a string. Is there any way to keep float and always have 2dp regardless if there are instances of .00?
average = "{:.2f}".format(10.0)
print(average)
Outputs
'10.00'
However, if I try to convert this to a float using the following
average = float("{:.2f}".format(10.0))
It outputs the following float:
10.0
I've seen other threads that say to use Decimal, but i'm uncertain of how to do this without importing library.
Is there anyway to achieve this without importing any libraries?
Keep it as a float the entire time, at the last step when you want to show it covert it to string with two decimal points. This is not the perfect answer but it will work.

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