Develop Reference

fastest way to check a .rar file password - other than rarfile extractall

So i have written a little .rar password "cracker" based on tutorials, using the code underneath. It works fine, but is very slow when the file size is big. The best reason i could find is, that ever so often when you put in a wrong password, it extracts the whole file, before refusing the password. With small files that is not a big problem, but with big files it slows the process a lot.
Is there a way to just check a hashed version of the password against a iterated hash?
import itertools
import rarfile
import time
rarfile.UNRAR_TOOL = "path"
rar = rarfile.RarFile("path")
done = False
n = 0
inputList = ["A","B","1","2"]
class h():
startword = ""
rep = 1
start = 0
itrTot = 0
f = open("save.txt")
for x,each in enumerate(f):
if x == 0:
h.rep = int(each)
else:
h.start = int(each)-3
f.close()
if h.start < 0:
h.start = 0
h.itrTot = len(inputList)**h.rep
def pw_guess():
res = itertools.product(inputList, repeat=h.rep)
for guess in res:
yield guess
start_time = time.time()
while True:
guess_generator = pw_guess()
for guess in guess_generator:
n += 1
if h.startword == "":
h.startword = guess
else:
if guess == h.startword:
h.rep += 1
n = 0
h.itrTot = len(inputList)**h.rep
h.start = 0
print("next rotation, itr rep: "+str(h.rep))
h.startword = ""
break
if n < h.start:
continue
txt = f"({n}/{h.itrTot}, {round((100/h.itrTot)*n,2)}%) - {h.rep}: {''.join(guess)}"
print(txt)
try:
rar.extractall(path="path",members=None,pwd=''.join(guess))
print("Pass found!")
print(str(n) + " - " + str(h.rep) + ": " + str(''.join(guess)))
done = True
txt2 = f"({n}/{h.itrTot}, {round((100/h.itrTot)*n,2)}%) - {h.rep}: {''.join(guess)}\n"
f = open("pass.txt", "a")
f.write(txt2)
f.close()
break
except:
f = open("save.txt", "w")
f.write(str(h.rep) + "\n" + str(n))
f.close()
if done:
end_time = time.time()
break
print("End time: " + str(end_time-start_time))

John the ripper is the answer. +20k passwords checked in 2 minutes. But using parts of the script for wordlist generation, is still very fast and functional.
wordlist generator i used:
import itertools
inputList = ["A","B","C","D","1","2","3","4","5"]
itr = 7
WL_path = "path"
f = open(WL_path,"w")
f.write("")
f.close()
class h():
startword = ""
rep = 1
itrTot = 0
txt = ""
h.itrTot = len(inputList)**itr
print("Wordlist length: " + str(h.itrTot))
def pw_guess():
res = itertools.product(inputList, repeat=h.rep)
for guess in res:
yield guess
while True:
guess_generator = pw_guess()
for guess in guess_generator:
if h.startword == "":
h.startword = guess
else:
if guess == h.startword:
h.rep += 1
print("next rotation, itr rep: " + str(h.rep))
h.startword = ""
break
h.txt = ''.join(guess)
f = open(WL_path, "a")
f.write(h.txt+"\n")
f.close()
if h.rep > itr:
break

Identifying spaces between commas

I need to identify if theres a space between a number and comma then that number is invalid. So if the number has more or less than 2 decimal places and/or white spaces in between the commas then it is INVALID but if it has no whitespaces in between the commas and has 2 decimal places then it it a VALID number. That's why the first number in Line 1 is VALID
There's two methods, I prefer to work on method 2 but I thought if I put two methods it might help any of you to add on
#-----------Method 1------------------------------------------
res = 0
outfile = "output2.txt"
baconFile = open(outfile,"wt")
index = 0
invalid_string = "INVALID"
valid_string = "VALID"
with open('file.txt') as file:
for line in file:
carrera = ''
index = index + 1
print("Line {}: ".format(index), end='')
baconFile.write("Line {}: ".format(index))
number_list = line.strip().split(',')
for number in number_list:
if len(number.split('.')[-1]) == 2:
#res += 1
## print("VALID")
carrera = valid_string
if len(number.split('.')[-1]) != 2:
#res += 1
carrera = invalid_string
if len(number.split(',')[-1]) == " ": #checking for whitespace
carrera = invalid_string
print (carrera, end=' ')
baconFile.write(carrera + " ")
print('\n', end='')
baconFile.write('\n')
baconFile.close()
#-----------Method 2------------------------------------------
res = 0
outfile = "output2.txt"
baconFile = open(outfile,"wt")
index = 0
invalid_string = "INVALID"
valid_string = "VALID"
with open('file.txt') as file:
for line in file:
index = index + 1
o = "Line {}: ".format(index)
number_list = line.strip().split(',')
for x in number_list:
if len(x.split('.')[-1]) == 2:
o += valid_string + " "
if len(x.split('.')[-1]) != 2:
o += invalid_string + " "
if len(x.split(',')[-1]) == " ":
o += valid_string + " "
Here's my list of numbers in Text.file:
1,1.02, 123.0005
1.02, 1.02 , 1.02
Expected:
Line 1: INVALID VALID INVALID
Line 2: VALID INVALID INVALID (since there's spaces between the last number that's why it is INVALID)
ACTUAL:
Line 1: INVALID VALID INVALID
Line 2: VALID INVALID VALID

You can split the strings with , and decide if the string is valid or invalid based on whether the string stars with a whitespace
#Open the files
with open('file.txt') as fp:
#Extract out non-empty lines from file
lines = [line for line in fp.readlines() if line.strip()]
res = []
#Iterate over the lines
for idx, line in enumerate(lines):
#Number is valid if it doesn't start with a whitespace, has a decimal part and the decimal part is two digits long
res = ['VALID' if not item.startswith(' ') and '.' in item and len(item.split('.')[1]) == 2 else 'INVALID' for item in line.split(',')]
#Print the result
print("Line {}: {}".format(idx+1, ' '.join(res)))
The output will be
Line 1: INVALID VALID INVALID
Line 2: VALID INVALID INVALID

try this:
line="1,1.02, 123.0005"
reslt=line.split(",")
Res=" "
for i in reslt:
if " "in i:
line1="INVALID "
else:
line1="VALID "
Res +="".join(line1)
print("line1:"+Res)
READ from file :
nbline
with open('file.txt') as f:
for line in f.readlines():
print(line)
reslt=line.split(",")
Res=" "
for i in reslt:
if " "in i:
line1="INVALID "
else:
line1="VALID "
Res +="".join(line1)
nbline = nbline+1
print("line {}:{}".format(nbline,Res))
output:
line1: VALID VALID INVALID

A list comprehension based on splitting on commas, and a little string trickery would be much simpler:
line="1,1.02, 123.0005"
result = " ".join("IN"*(" " in s)+"VALID" for s in line.split(","))
print(result) # VALID VALID INVALID

With decimal.Decimal object, you can retrieve the exponent, which somehow tells you the number of decimal places (see docs):
import decimal
o += " ".join(['INVALID' if x[0] == ' ' or decimal.Decimal(x).as_tuple().exponent != -2 else 'VALID' for x in line.split(',')])
Output
#with line = "1,1.02, 123.0005"
'Line 1: INVALID VALID INVALID'
#with line = "1.02, 1.02 , 1.02"
'Line 2: VALID INVALID INVALID'

How to read and write code output into a text file line by line

For example, my list looks like this from my text file:
1,2.12,3.123
Then it prints this to my output text file (decimal places from each number):
Line 1: INVALID VALID INVALID
However, if my list from my text file is like this:
1,2.12,3.123
1,1.00
Then it prints this to my output text file:
Line 1: Line 2: INVALID
VALID
INVALID
Line 3: Line 4: INVALID
VALID
INVALID
How do I get it to print this to my output text file:
Line 1: INVALID VALID INVALID
LINE 2: INVALID VALID
I tried to add an index = index +1 so it can add 1 to every line.
from functools import reduce
res = 0
outfile = "output2.txt"
baconFile = open(outfile,"wt")
index = 0
invalid_string = "INVALID"
valid_string = "VALID"
for line in open("file.txt"): # read file line-by-line
carrera = ''
index = index +1 # Count lines that contain what the command wants
print("Line {}: ".format(index))
baconFile.write("Line {}: ".format(index))
with open('file.txt') as file:
number_list = file.readline().strip().split(',')
for line in number_list:
if len(line.split('.')[-1]) == 2:
# res += 1
## print("VALID")
carrera = valid_string
if len(line.split('.')[-1]) != 2:
#res += 1
carrera = invalid_string
print (carrera)
baconFile.write(carrera + " ")
# print(res)
baconFile.close()
Expected:
Line 1: INVALID VALID INVALID
LINE 2: INVALID VALID
Actual:
Line 1: Line 2: INVALID
VALID
INVALID
Line 3: Line 4: INVALID
VALID
INVALID

Iterate over each line in a file with for line in file, and print without a newline with print('...', end=''). Don't open() it twice.
res = 0
outfile = "output2.txt"
baconFile = open(outfile,"wt")
index = 0
invalid_string = "INVALID"
valid_string = "VALID"
index = 1
with open('file.txt') as file:
for line in file:
print("Line {}: ".format(index), end='')
baconFile.write("Line {}: ".format(index))
number_list = line.strip().split(',')
for number in number_list:
if len(number.split('.')[-1]) == 2:
#res += 1
## print("VALID")
carrera = valid_string
if len(number.split('.')[-1]) != 2:
#res += 1
carrera = invalid_string
print (carrera, end='')
baconFile.write(carrera + " ")
print('\n', end='')
baconFile.write('\n')
index += 1
(To other answerers: I avoid enumerate because the code already has index in it.)

I made some modifications for formatting:
res = 0
outfile = "output2.txt"
baconFile = open(outfile,"wt")
index = 0
invalid_string = "INVALID"
valid_string = "VALID"
with open('file.txt') as file:
for line in file:
index = index +1
o = "Line {}: ".format(index)
number_list = line.strip().split(',')
for x in number_list:
if len(x.split('.')[-1]) == 2:
o += valid_string + " "
if len(x.split('.')[-1]) != 2:
o += invalid_string + " "
print(o)
baconFile.write(o + "\n")
baconFile.close()
EDIT: accidentally left the 'carrera' variable there, thought I might edit it out, since it no longer serves a purpose

compare an exact word with the txt file

i am trying to get the exact word match from my file along with their line no.
like when i search for abc10 it gives me all the possible answers e.g abc102 abc103 etc
how can i limitize my code to only print what i commanded..
here is my code!
lineNo = 0
linesFound = []
inFile= open('rxmop.txt', 'r')
sKeyword = input("enter word ")
done = False
while not done :
pos = inFile.tell()
sLine = inFile.readline()
if sLine == "" :
done = True
break
if (sLine.find( sKeyword ) != -1):
print ("Found at line: "+str(lineNo))
tTuple = lineNo, pos
linesFound.append( tTuple )
lineNo = lineNo + 1
done = False
while not done :
command = int( input("Enter the line you want to view: ") )
if command == -1 :
done = True
break
for tT in linesFound :
if command == tT[0] :
inFile.seek( tT[1] )
lLine = inFile.readline()
print ("The line at position " + str(tT[1]) + "is: " + lLine)

"like when i search for abc10 it gives me all the possible answers e.g abc102 abc103 etc"
You split each record and compare whole "words" only.
to_find = "RXOTG-10"
list_of_possibles = ["RXOTG-10 QTA5777 HYB SY G12",
"RXOTG-100 QTA9278 HYB SY G12"]
for rec in list_of_possibles:
words_list=rec.strip().split()
if to_find in words_list:
print "found", rec
else:
print " NOT found", rec

Python - how to print amount of numbers, periods, and commas in file

def showCounts(fileName):
lineCount = 0
wordCount = 0
numCount = 0
comCount = 0
dotCount = 0
with open(fileName, 'r') as f:
for line in f:
words = line.split()
lineCount += 1
wordCount += len(words)
for word in words:
# ###text = word.translate(string.punctuation)
exclude = set(string.punctuation)
text = ""
text = ''.join(ch for ch in text if ch not in exclude)
try:
if int(text) >= 0 or int(text) < 0:
numCount += 1
# elif text == ",":
# comCount += 1
# elif text == ".":
# dotCount += 1
except ValueError:
pass
print("Line count: " + str(lineCount))
print("Word count: " + str(wordCount))
print("Number count: " + str(numCount))
print("Comma count: " + str(comCount))
print("Dot count: " + str(dotCount) + "\n")
Basically it will show the number of lines and the number of words, but I can't get it to show the number of numbers, commas, and dots. I have it read a file that the user enters and then show the amount of lines and words, but for some reason it says 0 for numbers commas and dots. I commented out the part where it gave me trouble. If i remove the comma then i just get an error. thanks guys

This code loops over every character in each line, and adds 1 to its variable:
numCount = 0
dotCount = 0
commaCount = 0
lineCount = 0
wordCount = 0
fileName = 'test.txt'
with open(fileName, 'r') as f:
for line in f:
wordCount+=len(line.split())
lineCount+=1
for char in line:
if char.isdigit() == True:
numCount+=1
elif char == '.':
dotCount+=1
elif char == ',':
commaCount+=1
print("Number count: " + str(numCount))
print("Comma count: " + str(commaCount))
print("Dot count: " + str(dotCount))
print("Line count: " + str(lineCount))
print("Word count: " + str(wordCount))
Testing it out:
test.txt:
Hello, my name is B.o.b. I like biking, swimming, and running.
I am 125 years old, and I was 124 years old 1 year ago.
Regards,
B.o.b
Running:
bash-3.2$ python count.py
Number count: 7
Comma count: 5
Dot count: 7
Line count: 6
Word count: 27
bash-3.2$
Everything makes sense here, except the lineCount the reason why this is 6 is because of newlines. In my editor (nano), it adds a newline to the end of any file by default. So just imagine the text file to be this:
>>> x = open('test.txt').read()
>>> x
'Hello, my name is B.o.b. I like biking, swimming, and running.\n\nI am 125 years old, and I was 124 years old 1 year ago.\n\nRegards,\nB.o.b \n'
>>> x.count('\n')
6
>>>
Hope this helps!

For the punctuations, why not just do:
def showCounts(fileName):
...
...
with open(fileName, 'r') as fl:
f = fl.read()
comCount = f.count(',')
dotCount = f.count('.')

You could use the Counter class to take care of it you:
from collections import Counter
with open(fileName, 'r') as f:
data = f.read().strip()
lines = len(data.split('\n'))
words = len(data.split())
counts = Counter(data)
numbers = sum(v for (k,v) in counts.items() if k.isdigit())
print("Line count: {}".format(lines))
print("Word count: {}".format(words))
print("Number count: {}".format(numbers))
print("Comma count: {}".format(counts[',']))
print("Dot count: {}".format(counts['.']))