Python sending email script not getting credentials from external file

Python sending email script not getting credentials from external file - python

import smtplib
import os
import time
def send_email(contacts):
try:
user= passw=""
with open("credentials.txt", "r") as f:
file = f.readlines()
user = file[0].strip()
passw = file[1].strip()
server = smtplib.SMTP('smtp.gmail.com:587')
server.ehlo()
server.starttls() # it is necessary to start this before login
server.login(user, passw) # login credentials
subject = "Assignment Task for Working student job"
msg = "This is a msg body of assignment. "
message = 'Subject: {}\n\n{}'.format(subject, msg)
for i in contacts:
server.sendmail(user, contacts, message)
print(f"successfully sent email to {i} and wait for 10 seconds" )
time.sleep(10)
server.quit()
print("Success: Email sent!")
except:
print("Email failed to send.")
if __name__ == "__main__":
#sender, password = read_creds()
contacts = ['editorawais#gmail.com', 'editorawais#yahoo.com', 'editorawais#live.com','techwpblog#gmail.com']
send_email(contacts)
I created this email script. But now i am getting error on login. My credentials.txt is just of two lines.
"Email address"
"Password"
Please can anybody help me where i am missing something. And the correct way possibly. Thanks

Lose the quotation marks if you indeed have those in the txt file. Python will try to plug in everything on the first and second line including the "" try just doing this in your .txt file.
email
password

Related

Python SMTP Email Message Body Showing

I have been trying to make the content or message body to appear in the emails but it doesn't appear to be working. It's mentioned that a empty line is needed before the message and with new line after subject. Also, each time I run the script it runs but gives this error "Task timed out after 3.01 seconds" but I get the email, however, the Lambda function is marked as Failed...not sure why?? Maybe that's not so much of a big deal but if it ran then I'm assuming it was successful which is confusing since it says failed. The biggest thing here is the content not showing up. Thank you for any assistance.
import smtplib
sender = 'example.org'
recipient = contact
try:
subject = str(instance_name) + ' Issues'
content="Hello World"
mail = smtplib.SMTP('smtp.office365.com', 587)
mail.ehlo()
mail.starttls()
mail.login('example.org','1234567890')
header = 'To:' + recipient + '\n' + 'From:' \
+sender+'\n'+'subject:' + subject + '\n'
content=header+content
mail.sendmail(sender, recipient, content)
except:
print ("Error: unable to send email")

This works perfectly for me, I hope it will help you out.
import os
import socket
import smtplib
from email.message import EmailMessage
from email.message import EmailMessage
message = EmailMessage()
# Recepients addresses in a list
message['To']=["recepient1#gmail.com","recepient2#gmail.com"]
message['Cc'] = ["cc_recepient#gmail.com"]
message['Bcc'] = ["bcc_recepient#gmail.com"]
message['From'] = "sender#gmail.com"
message['Subject'] = "Subject Matter"
message.set_content("I received the data you sent.")
# Attach a document.
with open("document.txt", "rb") as file:
message.add_attachment(file.read(), maintype="application", subtype="octet-stream",
filename=os.path.basename(file.name))
print(f'Document: {os.path.basename(file.name)} attached successfully.')
# Login in and send your email.
try:
with smtplib.SMTP_SSL("smtp.office365.com", 587) as smtp:
smtp.login('sender#gmail.com', 'password')
print('Sending email...')
smtp.send_message(message)
print(f'Email successfully sent.')
smtp.quit()
except (smtplib.SMTPRecipientsRefused, socket.gaierror):
print ("Error: unable to send email")

I changed this line of code "+sender+'\n'+'subject:' + subject + '\n\n' " and it appears to be working. As far as the timeout issue. I increased it to a minute and it works fine now.

How to recive an email with attachment

I was asked to recive an email using any coding language ( I know java and C but python will be much easier I think but I hope someone can help me choose) then look for the word "cat" inside the body of the email then run the python file attachment which is attached to the mail and send back the output of the file to the sender if the word cat is in the message ( if the word wasnt there or the file returned an exception then return the the problem ) here is what I did so far :
import email
import imaplib
import smtplib
from email.message import EmailMessage
def send_email():
sender_email = 'momo#gmail.com'
password = '123456789'
rec_email ="koko#gmail.com"
message = input(str("enter your message below : "))
server= smtplib.SMTP('smtp.gmail.com',587)
server.starttls()
server.login(sender_email, password )
print("login success")
server.sendmail(sender_email , rec_email, message )
print("Email has been sent to " , rec_email )
def recive_and_check():
EMAIL = 'nono#gmail.com'
PASSWORD = '123456789'
SERVER = 'imap.gmail.com'
# connect to the server and go to its inbox
mail = imaplib.IMAP4_SSL(SERVER)
mail.login(EMAIL, PASSWORD)
mail.select("inbox")
#I used several tutorials on youtube from here don't really understand what I wrote
status, data = mail.search(None, 'ALL')
inbox_item_list = data[0].split()
most_recent = inbox_item_list[-1]
oldest = inbox_item_list [0]
email_data = mail.fetch(most_recent,'(RFC822)')
raw_email = email_data[0][1].decode("utf-8")
email_message = email.message_from_string(raw_email)
email_message: EmailMessage = email.message_from_bytes(envelope, _class=EmailMessage)
for email_message_part in email_message.walk():
if email_message_part.is_attachment():
Run(email_message_part)

python3: Text file to email body

i have an output.txt which i want to send its content as an email body.
1.i want to remove specific lines from the content ( not delete from the file itself)
2.i want to be able to convert it to html and to desing some of specific lines size and maybe even color.
i have a working script which sends the mail.
there are some problems:
im not able to remove specific line when using file.read().
when trying readlines() the type is list and the email body is getting messed up.(join doesnt work on list with bytes type)
import smtplib
import email.message
def send_email(subject, msg):
try:
server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.ehlo()
ID = 'XXXX'
PASSWORD = 'XXXXXXX'
email_reciever = 'XXXXXX'
server.login(ID, PASSWORD)
message = 'Subject:{} \n\n {}'.format(subject, msg)
server.sendmail(ID, email_reciever, message)
print('Succes')
except Exception as e:
# Print any error messages to stdout
print(e)
finally:
server.quit()
filename = r".\Reports\Report.txt"
with open(filename, "rb") as filename:
text = filename.read()
msg = email.message.Message()
msg.add_header('Content-Type', 'text/plain')
msg.set_payload(text)
subject = "Report"
send_email(subject, msg)

SMTP works in Linux but not on Mac [duplicate]

I am trying to send email (Gmail) using python, but I am getting following error.
Traceback (most recent call last):
File "emailSend.py", line 14, in <module>
server.login(username,password)
File "/usr/lib/python2.5/smtplib.py", line 554, in login
raise SMTPException("SMTP AUTH extension not supported by server.")
smtplib.SMTPException: SMTP AUTH extension not supported by server.
The Python script is the following.
import smtplib
fromaddr = 'user_me#gmail.com'
toaddrs = 'user_you#gmail.com'
msg = 'Why,Oh why!'
username = 'user_me#gmail.com'
password = 'pwd'
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(username,password)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()

def send_email(user, pwd, recipient, subject, body):
import smtplib
FROM = user
TO = recipient if isinstance(recipient, list) else [recipient]
SUBJECT = subject
TEXT = body
# Prepare actual message
message = """From: %s\nTo: %s\nSubject: %s\n\n%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
try:
server = smtplib.SMTP("smtp.gmail.com", 587)
server.ehlo()
server.starttls()
server.login(user, pwd)
server.sendmail(FROM, TO, message)
server.close()
print 'successfully sent the mail'
except:
print "failed to send mail"
if you want to use Port 465 you have to create an SMTP_SSL object:
# SMTP_SSL Example
server_ssl = smtplib.SMTP_SSL("smtp.gmail.com", 465)
server_ssl.ehlo() # optional, called by login()
server_ssl.login(gmail_user, gmail_pwd)
# ssl server doesn't support or need tls, so don't call server_ssl.starttls()
server_ssl.sendmail(FROM, TO, message)
#server_ssl.quit()
server_ssl.close()
print 'successfully sent the mail'

You need to say EHLO before just running straight into STARTTLS:
server = smtplib.SMTP('smtp.gmail.com:587')
server.ehlo()
server.starttls()
Also you should really create From:, To: and Subject: message headers, separated from the message body by a blank line and use CRLF as EOL markers.
E.g.
msg = "\r\n".join([
"From: user_me#gmail.com",
"To: user_you#gmail.com",
"Subject: Just a message",
"",
"Why, oh why"
])
Note:
In order for this to work you need to enable "Allow less secure apps" option in your gmail account configuration. Otherwise you will get a "critical security alert" when gmail detects that a non-Google apps is trying to login your account.

I ran into a similar problem and stumbled on this question. I got an SMTP Authentication Error but my user name / pass was correct. Here is what fixed it. I read this:
https://support.google.com/accounts/answer/6010255
In a nutshell, google is not allowing you to log in via smtplib because it has flagged this sort of login as "less secure", so what you have to do is go to this link while you're logged in to your google account, and allow the access:
https://www.google.com/settings/security/lesssecureapps
Once that is set (see my screenshot below), it should work.
Login now works:
smtpserver = smtplib.SMTP("smtp.gmail.com", 587)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo()
smtpserver.login('me#gmail.com', 'me_pass')
Response after change:
(235, '2.7.0 Accepted')
Response prior:
smtplib.SMTPAuthenticationError: (535, '5.7.8 Username and Password not accepted. Learn more at\n5.7.8 http://support.google.com/mail/bin/answer.py?answer=14257 g66sm2224117qgf.37 - gsmtp')
Still not working? If you still get the SMTPAuthenticationError but now the code is 534, its because the location is unknown. Follow this link:
https://accounts.google.com/DisplayUnlockCaptcha
Click continue and this should give you 10 minutes for registering your new app. So proceed to doing another login attempt now and it should work.
UPDATE: This doesn't seem to work right away you may be stuck for a while getting this error in smptlib:
235 == 'Authentication successful'
503 == 'Error: already authenticated'
The message says to use the browser to sign in:
SMTPAuthenticationError: (534, '5.7.9 Please log in with your web browser and then try again. Learn more at\n5.7.9 https://support.google.com/mail/bin/answer.py?answer=78754 qo11sm4014232igb.17 - gsmtp')
After enabling 'lesssecureapps', go for a coffee, come back, and try the 'DisplayUnlockCaptcha' link again. From user experience, it may take up to an hour for the change to kick in. Then try the sign-in process again.

This Works
Create Gmail APP Password!
After you create that then create a file called sendgmail.py
Then add this code:
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
# =============================================================================
# Created By : Jeromie Kirchoff
# Created Date: Mon Aug 02 17:46:00 PDT 2018
# =============================================================================
# Imports
# =============================================================================
import smtplib
# =============================================================================
# SET EMAIL LOGIN REQUIREMENTS
# =============================================================================
gmail_user = 'THEFROM#gmail.com'
gmail_app_password = 'YOUR-GOOGLE-APPLICATION-PASSWORD!!!!'
# =============================================================================
# SET THE INFO ABOUT THE SAID EMAIL
# =============================================================================
sent_from = gmail_user
sent_to = ['THE-TO#gmail.com', 'THE-TO#gmail.com']
sent_subject = "Hey Friends!"
sent_body = ("Hey, what's up? friend!\n\n"
"I hope you have been well!\n"
"\n"
"Cheers,\n"
"Jay\n")
email_text = """\
From: %s
To: %s
Subject: %s
%s
""" % (sent_from, ", ".join(sent_to), sent_subject, sent_body)
# =============================================================================
# SEND EMAIL OR DIE TRYING!!!
# Details: http://www.samlogic.net/articles/smtp-commands-reference.htm
# =============================================================================
try:
server = smtplib.SMTP_SSL('smtp.gmail.com', 465)
server.ehlo()
server.login(gmail_user, gmail_app_password)
server.sendmail(sent_from, sent_to, email_text)
server.close()
print('Email sent!')
except Exception as exception:
print("Error: %s!\n\n" % exception)
So, if you are successful, will see an image like this:
I tested by sending an email from and to myself.
Note: I have 2-Step Verification enabled on my account. App Password works with this! (for gmail smtp setup, you must go to https://support.google.com/accounts/answer/185833?hl=en and follow the below steps)
This setting is not available for accounts with 2-Step Verification enabled. Such accounts require an application-specific password for less secure apps access.
Clarification
Navigate to https://myaccount.google.com/apppasswords and create an APP Password as stated above.

You down with OOP?
#!/usr/bin/env python
import smtplib
class Gmail(object):
def __init__(self, email, password):
self.email = email
self.password = password
self.server = 'smtp.gmail.com'
self.port = 587
session = smtplib.SMTP(self.server, self.port)
session.ehlo()
session.starttls()
session.ehlo
session.login(self.email, self.password)
self.session = session
def send_message(self, subject, body):
''' This must be removed '''
headers = [
"From: " + self.email,
"Subject: " + subject,
"To: " + self.email,
"MIME-Version: 1.0",
"Content-Type: text/html"]
headers = "\r\n".join(headers)
self.session.sendmail(
self.email,
self.email,
headers + "\r\n\r\n" + body)
gm = Gmail('Your Email', 'Password')
gm.send_message('Subject', 'Message')

Here is a Gmail API example. Although more complicated, this is the only method I found that works in 2019. This example was taken and modified from:
https://developers.google.com/gmail/api/guides/sending
You'll need create a project with Google's API interfaces through their website. Next you'll need to enable the GMAIL API for your app. Create credentials and then download those creds, save it as credentials.json.
import pickle
import os.path
from googleapiclient.discovery import build
from google_auth_oauthlib.flow import InstalledAppFlow
from google.auth.transport.requests import Request
from email.mime.text import MIMEText
import base64
#pip install --upgrade google-api-python-client google-auth-httplib2 google-auth-oauthlib
# If modifying these scopes, delete the file token.pickle.
SCOPES = ['https://www.googleapis.com/auth/gmail.readonly', 'https://www.googleapis.com/auth/gmail.send']
def create_message(sender, to, subject, msg):
message = MIMEText(msg)
message['to'] = to
message['from'] = sender
message['subject'] = subject
# Base 64 encode
b64_bytes = base64.urlsafe_b64encode(message.as_bytes())
b64_string = b64_bytes.decode()
return {'raw': b64_string}
#return {'raw': base64.urlsafe_b64encode(message.as_string())}
def send_message(service, user_id, message):
#try:
message = (service.users().messages().send(userId=user_id, body=message).execute())
print( 'Message Id: %s' % message['id'] )
return message
#except errors.HttpError, error:print( 'An error occurred: %s' % error )
def main():
"""Shows basic usage of the Gmail API.
Lists the user's Gmail labels.
"""
creds = None
# The file token.pickle stores the user's access and refresh tokens, and is
# created automatically when the authorization flow completes for the first
# time.
if os.path.exists('token.pickle'):
with open('token.pickle', 'rb') as token:
creds = pickle.load(token)
# If there are no (valid) credentials available, let the user log in.
if not creds or not creds.valid:
if creds and creds.expired and creds.refresh_token:
creds.refresh(Request())
else:
flow = InstalledAppFlow.from_client_secrets_file(
'credentials.json', SCOPES)
creds = flow.run_local_server(port=0)
# Save the credentials for the next run
with open('token.pickle', 'wb') as token:
pickle.dump(creds, token)
service = build('gmail', 'v1', credentials=creds)
# Example read operation
results = service.users().labels().list(userId='me').execute()
labels = results.get('labels', [])
if not labels:
print('No labels found.')
else:
print('Labels:')
for label in labels:
print(label['name'])
# Example write
msg = create_message("from#gmail.com", "to#gmail.com", "Subject", "Msg")
send_message( service, 'me', msg)
if __name__ == '__main__':
main()

Not directly related but still worth pointing out is that my package tries to make sending gmail messages really quick and painless. It also tries to maintain a list of errors and tries to point to the solution immediately.
It would literally only need this code to do exactly what you wrote:
import yagmail
yag = yagmail.SMTP('user_me#gmail.com')
yag.send('user_you#gmail.com', 'Why,Oh why!')
Or a one liner:
yagmail.SMTP('user_me#gmail.com').send('user_you#gmail.com', 'Why,Oh why!')
For the package/installation please look at git or pip, available for both Python 2 and 3.

You can find it here: http://jayrambhia.com/blog/send-emails-using-python
smtp_host = 'smtp.gmail.com'
smtp_port = 587
server = smtplib.SMTP()
server.connect(smtp_host,smtp_port)
server.ehlo()
server.starttls()
server.login(user,passw)
fromaddr = raw_input('Send mail by the name of: ')
tolist = raw_input('To: ').split()
sub = raw_input('Subject: ')
msg = email.MIMEMultipart.MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = email.Utils.COMMASPACE.join(tolist)
msg['Subject'] = sub
msg.attach(MIMEText(raw_input('Body: ')))
msg.attach(MIMEText('\nsent via python', 'plain'))
server.sendmail(user,tolist,msg.as_string())

Dec, 2022 Update:
You need to use an app password to allow your app to access your google account.
Sign in with App Passwords:
An App Password is a 16-digit passcode that gives a less secure app or
device permission to access your Google Account. App Passwords can
only be used with accounts that have 2-Step Verification turned on.
In addition, google hasn't allowed your app to access your google account with username(email address) and password since May 30, 2022. So now, you need username(email address) and an app password to access your google account.
Less secure apps & your Google Account:
To help keep your account secure, from May 30, 2022, Google no
longer supports the use of third-party apps or devices which ask you
to sign in to your Google Account using only your username and
password.
How to generate an app password:
First, click on Account from 9 dots:
Then, click on App passwords from Security. *Don't forget to turn on 2-Step Verification before generating an app password otherwise you cannot generate an app password:
Then, click on Other (Custom name):
Then, put your app name, then click on GENERATE:
Finally, you could generate the app password xylnudjdiwpojwzm:
So, your code with the app password above is as shown below:
import smtplib
fromaddr = 'user_me#gmail.com'
toaddrs = 'user_you#gmail.com'
msg = 'Why,Oh why!'
username = 'user_me#gmail.com'
password = 'xylnudjdiwpojwzm' # Here
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(username,password)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()
In addition, settings.py with the app password above in Django is as shown below:
# "settings.py"
EMAIL_BACKEND = 'django.core.mail.backends.smtp.EmailBackend'
EMAIL_HOST = 'smtp.gmail.com'
EMAIL_PORT = 587
EMAIL_USE_TLS = True
EMAIL_HOST_USER = 'myaccount#gmail.com'
EMAIL_HOST_PASSWORD = 'xylnudjdiwpojwzm' # Here

Realized how painful many of the things are with sending emails via Python thus I made an extensive library for it. It also has Gmail pre-configured (so you don't have to remember Gmail's host and port):
from redmail import gmail
gmail.user_name = "you#gmail.com"
gmail.password = "<YOUR APPLICATION PASSWORD>"
# Send an email
gmail.send(
subject="An example email",
receivers=["recipient#example.com"],
text="Hi, this is text body.",
html="<h1>Hi, this is HTML body.</h1>"
)
Of course you need to configure your Gmail account (don't worry, it's simple):
Set up 2-step-verification (if not yet set up)
Create an Application password
Put the Application password to the gmail object and done!
Red Mail is actually pretty extensive (include attachments, embed images, send with cc and bcc, template with Jinja etc.) and should hopefully be all you need from an email sender. It is also well tested and documented. I hope you find it useful.
To install:
pip install redmail
Documentation: https://red-mail.readthedocs.io/en/latest/
Source code: https://github.com/Miksus/red-mail
Note that Gmail don't allow changing the sender. The sender address is always you.

Enable less secure apps on your gmail account and use (Python>=3.6):
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
gmailUser = 'XXXXX#gmail.com'
gmailPassword = 'XXXXX'
recipient = 'XXXXX#gmail.com'
message = f"""
Type your message here...
"""
msg = MIMEMultipart()
msg['From'] = f'"Your Name" <{gmailUser}>'
msg['To'] = recipient
msg['Subject'] = "Subject here..."
msg.attach(MIMEText(message))
try:
mailServer = smtplib.SMTP('smtp.gmail.com', 587)
mailServer.ehlo()
mailServer.starttls()
mailServer.ehlo()
mailServer.login(gmailUser, gmailPassword)
mailServer.sendmail(gmailUser, recipient, msg.as_string())
mailServer.close()
print ('Email sent!')
except:
print ('Something went wrong...')

There is a gmail API now, which lets you send email, read email and create drafts via REST.
Unlike the SMTP calls, it is non-blocking which can be a good thing for thread-based webservers sending email in the request thread (like python webservers). The API is also quite powerful.
Of course, email should be handed off to a non-webserver queue, but it's nice to have options.
It's easiest to setup if you have Google Apps administrator rights on the domain, because then you can give blanket permission to your client. Otherwise you have to fiddle with OAuth authentication and permission.
Here is a gist demonstrating it:
https://gist.github.com/timrichardson/1154e29174926e462b7a

great answer from #David, here is for Python 3 without the generic try-except:
def send_email(user, password, recipient, subject, body):
gmail_user = user
gmail_pwd = password
FROM = user
TO = recipient if type(recipient) is list else [recipient]
SUBJECT = subject
TEXT = body
# Prepare actual message
message = """From: %s\nTo: %s\nSubject: %s\n\n%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
server = smtplib.SMTP("smtp.gmail.com", 587)
server.ehlo()
server.starttls()
server.login(gmail_user, gmail_pwd)
server.sendmail(FROM, TO, message)
server.close()

Seems like problem of the old smtplib. In python2.7 everything works fine.
Update: Yep, server.ehlo() also could help.

import smtplib
fromadd='from#gmail.com'
toadd='send#gmail.com'
msg='''hi,how r u'''
username='abc#gmail.com'
passwd='password'
try:
server = smtplib.SMTP('smtp.gmail.com:587')
server.ehlo()
server.starttls()
server.login(username,passwd)
server.sendmail(fromadd,toadd,msg)
print("Mail Send Successfully")
server.quit()
except:
print("Error:unable to send mail")
NOTE:https://www.google.com/settings/security/lesssecureapps that should be enabled

import smtplib
server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.login("fromaddress", "password")
msg = "HI!"
server.sendmail("fromaddress", "receiveraddress", msg)
server.quit()

howto get arguments parsed into send email in python3

since mailutils is not available I am trying to write a simple python script that sends email like:
echo text | mail -s "some subject" -r jo#do.com
I have succeeded catching arguments and printing them, but I do not know howto get these arguments into an email header part.
The script runs like this
./m2.py -s "dag mijnheer" -r hanscees#hanscees.con
The script runs, but this fails very much.. In the script below the email headers are empty, although it arrives as an email.
I also tried using smtpObj.sendmail(sender, RECIPIENT, message2)
But that doesn't work.
How do I get these headers filled with text and variables?
#!/usr/bin/python3
import argparse
import smtplib
## get commandline arguments
def commandLineSetup():
commandParser = argparse.ArgumentParser(description="Sends email "
"to email server by smtp")
commandParser.add_argument("-s", "--subject", help="Subject of email")
commandParser.add_argument("-r", "--recipient", help="emailaddress of recipient")
args = commandParser.parse_args()
return args.subject, args.recipient
def main():
SUBJECT, RECIPIENT = commandLineSetup()
# Check that proper inputs were provided
if not SUBJECT or not RECIPIENT:
print ("Insufficient inputs provided")
exit()
sender = "docker79#hanscees.con"
print ("sendto adress is", RECIPIENT)
#built list with text message
message2 = 'FROM: '+sender+'\n'+'TO: '+RECIPIENT+'\n'+'SUBJECT: ',SUBJECT,'\n'
print ("messages2 is", message2)
message = """From: sender
To: RECIPIENT
Subject: SUBJECT
This is a test e-mail message.
"""
try:
smtpObj = smtplib.SMTP('192.168.0.111')
smtpObj.sendmail(sender, RECIPIENT, message)
print ("Successfully-sent-email")
except smtplib.SMTPException:
print ("Error-unable-to-send-email")
if __name__ == "__main__":
main()

Well, found an answer combining several places.
Here is a python3 script for sending email that actually works fine.
Didn't find this anywhere on the internet to my amazement.
Any improvements are welcome. Because it will probably crash your computer if you cat /dev/null into it :(
use it like this
echo some text | pymail3.py -s "how are you " -r somebody#somewhere.com
Be advised you must manually add your mailserver and from address in the script. It will send email to port 25 only.
pymail3.py
#!/usr/bin/python3
import argparse
import smtplib
from email.message import EmailMessage
from email.headerregistry import Address
from email.utils import make_msgid
## get commandline arguments
def commandLineSetup():
commandParser = argparse.ArgumentParser(description="Sends email piped in "
"to email server by smtp")
commandParser.add_argument("-s", "--subject", help="Subject of email")
commandParser.add_argument("-r", "--recipient", help="emailaddress of recipient")
args = commandParser.parse_args()
return args.subject, args.recipient
def main():
SUBJECT, RECIPIENT = commandLineSetup()
# Check that proper inputs were provided
if not SUBJECT or not RECIPIENT:
print ("Insufficient inputs provided")
exit()
sender="dockerdaemon79#hanscees.con"
msg = EmailMessage()
msg["Subject"] = SUBJECT
msg["From"] = Address("dockershost", addr_spec=sender)
msg["To"] = Address("whomwever", addr_spec=RECIPIENT)
#lets get text from stdin
data = ""
for line in sys.stdin:
data += line
msg.set_content (data)
server = smtplib.SMTP('192.168.0.254', 25)
try:
server.send_message(msg)
server.quit()
except smtplib.SMTPException:
print ("Error-unable-to-send-email")
if __name__ == "__main__":
main()

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Python is a programming language that lets you work quickly and integrate systems more effectively.