Develop Reference

Regex : replace url inside string

i have
string = 'Server:xxx-zzzzzzzzz.eeeeeeeeeee.frPIPELININGSIZE'
i need a python regex expression to identify xxx-zzzzzzzzz.eeeeeeeeeee.fr to do a sub-string function to it
Expected output :
string : 'Server:PIPELININGSIZE'
the URL is inside a string, i tried a lot of regex expressions

Not sure if this helps, because your question was quite vaguely formulated. :)
import re
string = 'Server:xxx-zzzzzzzzz.eeeeeeeeeee.frPIPELININGSIZE'
string_1 = re.search('[a-z.-]+([A-Z]+)', string).group(1)
print(f'string: Server:{string_1}')
Output:
string: Server:PIPELININGSIZE

No regex. single line use just to split on your target word.
string = 'Server:xxx-zzzzzzzzz.eeeeeeeeeee.frPIPELININGSIZE'
last = string.split("fr",1)[1]
first =string[:string.index(":")]
print(f'{first} : {last}')
Gives #
Server:PIPELININGSIZE

The wording of the question suggests that you wish to find the hostname in the string, but the expected output suggests that you want to remove it. The following regular expression will create a tuple and allow you to do either.
import re
str = "Server:xxx-zzzzzzzzz.eeeeeeeeeee.frPIPELININGSIZE"
p = re.compile('^([A-Za-z]+[:])(.*?)([A-Z]+)$')
m = re.search(p, str)
result = m.groups()
# ('Server:', 'xxx-zzzzzzzzz.eeeeeeeeeee.fr', 'PIPELININGSIZE')
Remove the hostname:
print(f'{result[0]} {result[2]}')
# Output: 'Server: PIPELININGSIZE'
Extract the hostname:
print(result[1])
# Output: 'xxx-zzzzzzzzz.eeeeeeeeeee.fr'

Print only alphabetics in a string using Regular Expression

Goal : i want only alphabets to be printed in a string
#Input
#======
string = ' 529Wind3#. '
#Neededoutput
#============
'Wind'
I tried coding for this using the below code
import re
string=re.sub('[^a-z]+[^A-Z]',' ',string)
print(string)
The output i'm getting is
ind
But this code only applies for lowercase
Can you please tell me how to write code for both upper and lowercase

Try using a list comprehension to check if each character is in string.ascii_letters or not, if it is, it will be stored:
import string
String = ' 529Wind3#. '
print(''.join([i for i in String if i in string.ascii_letters]))
Output:
Wind

I agree with #U8-Forward's point but I think you may also want to know why your regular expression isn't working. This
[^a-z]+[^A-Z]
doesn't do what you want because W matches [^a-z]+ and so gets removed.
Put all of the characters you don't want in a single character class:
[^a-zA-Z]+

You need to write [^a-zA-Z] instead of [^a-z]+[^A-Z]. The + operator is for detecting repetitive characters and not to combine multiple conditions.
Try the below code for your requirement:
import re
string=re.sub('[^a-zA-Z]',' ',string)
print(string)

you can use re.findall
import re
String = ' 529Wind3#. '
string = re.findall('[a-zA-Z]+', String)
print(''.join(string))

print re.sub('[^a-zA-Z]','',string)

how to remove comma at the end from the below string in python code

input string
str = "(\"Cardinal\", \"Tom B. Erichsen\", \"Skagen 21\",)"
output string should look like:
("Cardinal", "Tom B. Erichsen", "Skagen 21")
The comma at the end should be removed, help me how to do this in python code.
I tried with str.rstrip(",") it dint work.

You can use some regex for example you can replace (.*),([^,]+)$ with \1\2
result = re.sub(r"(.*),([^,]+)$", r"\1\2", yourstring)
here is a regex demo

Check this code
str = str.replace('",)', '")')

you can chain different str.replace()
str.replace(", )",")").replace(",)",")")
That will work for your string

You can do this in following way
str = "(\"Cardinal\", \"Tom B. Erichsen\", \"Skagen 21\",)"
str = str[:len(str)-2] + str[len(str)-1]

You could use the regex module:
import re
s = "INSERT INTO Customers (CustomerName, ContactName, Address, ) VALUES (\"Cardinal\", \"Tom B. Erichsen\", \"Skagen 21\",)"
print re.sub(r',(\s+)*\)', ')', s)

How to get sub string from a string in python using split or regex

I have a str in python like below. I want extract a substring from it.
table='abc_test_01'
number=table.split("_")[1]
I am getting test as a result.
What I want is everything after the first _.
The result I want is test_01 how can I achieve that.

Here is the code as already given by many of them
table='abc_test_01'
number=table.split("_",1)[1]
But the above one may fail in situations when the occurrence is not in the string, then you'll get IndexError: list index out of range
For eg.
table='abctest01'
number=table.split("_",1)[1]
The above one will raise IndexError, as the occurrence is not in the string
So the more accurate code for handling this is
table.split("_",1)[-1]
Therefore -1 will not get any harm because the number of occurrences is already set to one.
Hope it helps :)

To get the substring (all characters after the first occurrence of underscore):
number = table[table.index('_')+1:]
# Output: test_01

You could do it like:
import re
string = "abc_test_01"
rx = re.compile(r'[^_]*_(.+)')
match = rx.match(string).group(1)
print(match)
Or with normal string functions:
string = "abc_test_01"
match = '_'.join(string.split('_')[1:])
print(match)

Nobody mentions that the split() function can have an maxsplit argument:
str.split(sep=None, maxsplit=-1)
return a list of the words in the string, using sep as the delimiter string. If maxsplit is given, at most maxsplit splits are done (thus, the list will have at most maxsplit+1 elements).
So the solution is only:
table.split('_', 1)[1]

You can try this:
Edit: Thanks to #valtah's comment:
table = 'abc_test_01'
#final = "_".join(table.split("_")[1:])
final = table.split("_", 1)[1]
print final
Output:
'test_01'
Also the answer of #valtah in the comment is correct:
final = table.partition("_")[2]
print final
Will output the same result

Python : How to ignore a delimited part of a sentence?

I have the following line :
CommonSettingsMandatory = #<Import Project="[\\.]*Shared(\\vc10\\|\\)CommonSettings\.targets," />#,true
and i want the following output:
['commonsettingsmandatory', '<Import Project="[\\\\.]*Shared(\\\\vc10\\\\|\\\\)CommonSettings\\.targets," />', 'true'
If i do a simple regex with the comma, it will split the value if there's a value in it, like i wrote a comma after targets, it will split here.
So i want to ignore the text between the ## to make sure there's no splitting there.
I really don't know how to do!

http://docs.python.org/library/re.html#re.split
import re
string = 'CommonSettingsMandatory = #toto,tata#, true'
splitlist = re.split('\s?=\s?#(.*?)#,\s?', string)
Then splitlist contains ['CommonSettingsMandatory', 'toto,tata', 'true'].

While you might be able to use split with a lookbehind, I would use the groups captured by this expression.
(\S+)\s*=\s*##([^#]+)##,\s*(.*)
m = re.Search(expression, myString). use m.group(1) for the first string, m.group(2) for the second, etc.

If I understand you correctly, you're trying to split the string using spaces as delimiters, but you want to also remove any text between pound signs?
If that's correct, why not simply remove the pound sign-delimited text before splitting the string?
import re
myString = re.sub(r'#.*?#', '', myString)
myArray = myString.split(' ')
EDIT: (based on revised question)
import re
myArray = re.findall(r'^(.*?) = #(.*?)#,(.*?)$', myString)
That will actually return an array of tuples including your matches, in the form of:
[
(
'commonsettingsmandatory',
'<Import Project="[\\\\.]*Shared(\\\\vc10\\\\|\\\\)CommonSettings\\.targets," />',
'true'
)
]
(spacing added to illustrate the format better)