I am a n00b programmer and I have a python program that reads a text file in the same folderas itself. PyCharm can't seem to find that text file. Does anyone know why?
My program:
password_file = open('passwords.txt', 'r')
print(password_file.read())
password_file.close()
PyCharm can't seem to find the text file - the error message:
C:\Users\User\AppData\Local\Programs\Python\Python38-32\python.exe C:/Users/User/PycharmProjects/password_test/password.py
Traceback (most recent call last):
File "C:/Users/User/PycharmProjects/password_test/password.py", line 1, in <module>
password_file = open('passwords.txt', 'r')
FileNotFoundError: [Errno 2] No such file or directory: 'passwords.txt'
Process finished with exit code 1
Like I said, the python program (password.py) is located in the same folder as the text file (passwords.txt). The main reason I find this strange is because I have set a program up like this before and it worked just fine. However, when I use a full path, like so:
password_file = open('C:/Users/User/PycharmProjects/password_test/passwords.txt', 'r')
print(password_file.read())
password_file.close()
my program prints the text file just fine.
What's going on and, more importantly, how do I fix it?
Thank you in advance and have a nice night.
File is opened relative to your working directory. It doesn't matter where your "password.py" is, it only matters where are you running your "python.exe" from. If you use command line to start it, then you should navigate into directory with that file. If you're using PyCharm - you can set "Working directory:" inside "Run/Debug Configurations" window from "Run -> Edit Configurations...".
Related
I am very new on this platform and I need help reading a file in python. First, it was a docx file because I am using Mac, I converted it into a txt file ,but still have file not found error.
Here is some code:
opdoc = open('PRACT.txt')
print(opdoc.readline())
for each in opdoc :
print(each)
and this the error output: FileNotFoundError: [Errno 2] No such file or directory: 'PRACT.txt'
Unless your file is in the exact same directory as your python file, you'll get this error. Even then, it's best practice to include some sort of relative filepath, like "./PRACT.txt". In general, your issue stems from the fact that Python doesn't know where to look for your file, and where it does know to look, the file isn't there. You need to provide the full path to the file, like:
with open("path/to/file/PRACT.txt", "rb") as f:
# read file etc
Make a new folder and put the txt file in it and also the programme itself. Or just put them in the same directory.
As you have this error ( No such file or directory: 'PRACT.txt') your code couldn't find the file because they were not in the same directory. When you use open("README.txt") the programme is assuming that the text is in the same directory as your code. If you don't want them in the same directory you could also try open(f"[file_path]") and that should work.
Abstract:
I am analysing a pcap file, with live malware (for educational purposes), and using Wireshark - I managed to extract few objects from the HTTP stream and some executables.
During my Analysis, I found instances hinting Fiestka Exploit Kit used.
Having Googled a ton, I came across a GitHub Rep: https://github.com/0x3a/tools/blob/master/fiesta-payload-decrypter.py
What am I trying to achieve?
I am trying to run the python fiesta-payload-decrypter.py against the malicious executable (extracted from the pcap).
What have I done so far?
I've copied the code onto a plain text and saved it as malwaredecoder.py. - This script is saved in the same Folder (/Download/Investigation/) as the malware.exe that I want to run it against.
What's the Problem?
Traceback (most recent call last):
File "malwaredecoder.py", line 51, in <module>
sys.exit(DecryptFiestaPyload(sys.argv[1], sys.argv[2]))
File "malwaredecoder.py", line 27, in DecryptFiestaPyload
fdata = open(inputfile, "rb").read()
IOError: [Errno 2] No such file or directory: '-'
I am running this python script in Kali Linux, and any help would be much appreciated. Thank you.
The script expects two args... What are you passing it?
Looks like it expects the args to be files and it sees a -, (dash), as the input file.
https://github.com/0x3a/tools/blob/master/fiesta-payload-decrypter.py#L44 Here it looks like the first arg is the input file and second is the output file.
Try running it like this:
python malewaredecoder.py /Download/Investigation/fileImInvestigating.pcap /Download/Investigation/out.pcap
All that said, good luck, that script looks pretty old and was last modified in 2015.
This question already has answers here:
open() gives FileNotFoundError / IOError: '[Errno 2] No such file or directory'
(8 answers)
Closed 3 months ago.
For some reason I am unable to open my .txt file within python.
I have the .py and .txt file within a folder. Both files are stored Workspace -> Folder(Crash Course) -> Folder(Lessons) -> Folder(Ch 10)-> both files within this Ch 10 Folder.
I am getting
FileNotFoundError: [Errno 2] No such file or directory: 'pi_digits.txt'
With the code:
with open('pi_digits.txt') as file_object:
contents = file_object.read()
print(contents)
This is less for the person that asked the question but more for people like myself that come here from Python Crash Course with the same question and don't get the answer they were looking for:
If, like me, you were running the code from your text editor (in my case VS Code), it's possible that the terminal window within the editor wasn't in the proper directory. I didn't realize myself, because I was thinking that because I opened the .py file from the correct working directory in the terminal that everything should work as planned. It wasn't until I realized that the terminal in the editor is a separate instance (thus making the present working directory home instead of my folder for PCC work) that I was able to get the program to run as intended.
In short, navigate to the proper directory in your editor's terminal instance and the program should run as intended.
Hope this helps!
image with terminal open on desktop and in text editor to show working directory difference
I used full path of the file along with r, which is for raw string. Worked for me.
example:
filename = **r**'C:\Python\CrashCourse\pi_digits.txt'
with open(filename) as file_object:
content = file_object.read()
print(content)
The path to the file is relative to where you run the python file from, not from where the python file is located.
Either run your code from the same directory as the files, or make the file path absolute, based on the python file's location.
import os
with open(os.path.join(os.path.dirname(__file__), 'pi_digits.txt')) as file_object:
contents = file_object.read()
print(contents)
Hope that helps
Try this:
with open('c:\\Workspace\\Crash Course\\Lessons\\Ch 10\\pi_digits.txt') as file_object:
contents = file_object.read()
print(contents)
You can try getting the full path to the file
import os
dir_path = os.path.dirname(os.path.realpath(__file__))
pi_digits = os.path.join(dir_path, 'pi_digits.txt')
with open(pi_digits, r) as file_object:
print(file_object.read())
You might have to enable "Execute in file dir"
vscode setting
I'm trying to access the .txt file in my project folder (in the same folder). But I am kept getting FileNotFoundError: [Errno 2] No such file or directory: '\u200e\u2068useragents.txt' error.
Code is;
USER_AGENT_LIST = "useragents.txt"
it seems like you have a control character in your file name value. erase and write the file name again. Check if your editor or IDE has the feature to show invisible control characters. you will be able to see it.
I have a Python script that runs properly on my laptop, but when running on my raspberry pi, the following code does not seem to be working properly. Specifically, "TextFile.txt" is not being updated and/or saved.
openfile = open('/PATH/TextFile.txt','w')
for line in lines:
if line.startswith(start):
openfile.write(keep+'\n')
print ("test 1")
else:
openfile.write(line)
print ("test 2")
openfile.close()
I am seeing "test 1" and "test 2" in my output, so I know that the code is being reached, paths are correct, etc
It may be due to a permissions problem. I am running the script from the terminal by using:
usr/bin/python PATH/script.py
Python is owned by "root" and script.py is owned by "Michael".
My first guess:
Does the file exist? If it does not exist then you cannot write to it. Try this to create the file if it does not exist: file = open('myfile.dat', 'w+')
Additionally manually opening and closing file handles is bad practice in python. The with statement handles the opening and closing of the resource automatically for you:
with open("myfile.dat", "w+") as f:
#doyourcalculations with the file object here
for line in f:
print line
All, thank you for your input. I was able to figure out that it was writing to the new file, but it was overwriting with the same text. The reason was because ".startswith" was returning false when I expected true. The misconception was due to the difference between how Windows and Unix treat new line characters (/n /r).
Since your code is running, there should be a file somewhere.
You call "PATH/script.py", but there is "/PATH/TextFile.txt" in your program. Is the slash before PATH a mistake? Have you checked the path in your program is really where you are looking for the output file?