When we use flask function send_file, what is the actual encoding of the file sent on the REST body with mimetype image/jpeg? It is possible to send the file using a base64 enconding?
Line of code:
send_file("logo.jpg", mimetype='image/jpeg')
It's being sent as binary on the wire, e.g. the HTTP response will be
200 OK
Content-type: image/jpeg
Content-length: 1234
����JFIF��
ExifMM*
$���1�2��i��%�OnePlusONEPLUS A6013
etc.
You can manually base64 encode the data if your app requires it.
Related
I'm trying to decode a base64 pdf file and send it to another endpoint.
I used a python policy for the decoding part and here's the code
import base64
pdfB64 = flow.getVariable("request.content")
pdfFile = base64.b64decode(pdfB64)
flow.setVariable("pdfFileDecoded",pdfFile)
Now, when I send my http post request which is below
headers :
Accept : */*
boundary : --Boundaryy
--Boundaryy
Content-Disposition: form-data; name="testdu12janvier"; filename="testdu12janvier.pdf"
Content-Type: application/pdf
<< Heres is sensitive data which is basically a base64 encoded pdf file >>
--Boundaryy--
When I send this POST request and trace it in Apigee Edge, I notice that something else is encoded before the pdf file I think its either the boundary or one of the headers. This makes a corrupt pdf file which can't be read.
How do I isolate the pdf file from the request body without removing boundaries? as I'll need to send multiple in near future.
I have tested some requests inside the Postman app. First, I want to get the body information of an HTTP request inside Python (package requests used). The response appears positive with 200 OK.
response = session.request("POST", url, headers=headers, data=payload, verify ='custom-proxy-ca.crt')
Now I would like to get the body with
body = response.content
Print(body) delivers
b'\x83\x84\x01\x00\xc4\xff\xd4\xe9\xb4\xf6\xde,\x13\xa9\xc0(\xc7_\x8dL\x90\xf0\xb4K\xc4<\xe7\xb1M\x02)\xe0\x80z\xd0\xdf>\xcf\xd7\xd2\xec\x8d\x1e\xe4un\x0c\x83\xa1\x88g\xe7fah\x89\xbe\xca\xa8\x04_\xa2W\xbd\xfe]W\xd1\x06\x1f\xef~ZN\xa6\x0bq\xfa\x18\xc4\x1f\xb3\xf8\xc2\x9dF\xc5\xf0\xe6\x8d\xb6\xc1\xa0\xab\x7f\xfbyM\xe0\x88I\xb4\xd4\x82\xa1%\xd9R7Nt\xa4~<\x8c\x8e\xdb\xe7<xx-.\xab\xa7|16\xcb"\xba\x89\xbc\xe7\xcaF\xd1\xacV-u\xbf\xaa\x04\xf7\xa2\x88\xa1\x1bUI\xdfkI$`\x18:j\x7fU\x02\x0e\xcb\x97\x8em\xc6\x81\xe6\x85\xbe\xa5\xb9vbjQ$}M&n\xe0$A\xe0\xd9\xd2\xc6\x9aA\xf4\x12\x81/1\x0c\xf0(\x0cy\xf5\xaf\xca\x1bQ\x1082\xa1\xb4n4VRR\xbb7\xa5XO\x08\x0c\x13\xf2:\xc0-\x06\xa9\xda\xaeGX\x97B\x81!\x17\x87\xfa\xd1\x1b\xc0\xd0\x89|\xe8E\x0f\rp\xfd\x00\x96\xeaI\xbe\xda\xbb\xe3\x87\xc7\xdb\x9b\xfd\xab\xe8\xc7\xdd\x0cEL-x\xe0\x9bVhY\x0cT\x08\x95S\xa3\xfd\xdc\xe3\x81/1\x9d\x9e\'T\xf6\xe0pl\xd33#0,T}X%\x04\x0e\xd7r\xfd\x10\x0cs\xe90\x05\xe8\xe8\xf8\xea\xfc\xe5\xf8\xe1\xfd\xb9\xea\xe7\xe0\xc0\x9a!\xa1\\M\xa8\x9d\x9f\xe4\xa2\x07_\xae\xd7\x0c\xdd\xb8\xaa\xbf\xe9\xfc\x1a|\x89^\xf59\x81\xe3J\x91\xa4v(\xff7J1\x1ao\x9c\x89\xa1#0\xf4\xaa\xa0\xc7\xbc\xea\x9f\xae\xa6\xe8\xa9-T\xc9#\xd1\x81\x7f\xee\x9a\xbb\xfd\x87\xc3\xe3+|K\xe2\xfdPe\xa0\xaa\x9d\x18\xf0\xcc\xc0\xf10\x80\xca\xb0XuW\x9d\xcc\xc0\xa5\xc8;bP\xdd\x9d\x1aeC\xfd\xf84\xa6\x14yG\xeb\xb5\x01\x03'
Now I try to search a token in the body, but it seems to be encrypted.
If I want to get the result of the JSON parser with
json.loads(body)
it returns
UnicodeDecodeError: 'utf-8' codec can't decode byte 0x83 in position 0: invalid start byte`.
Okay, it seems that the encoding is done in a different way than expected. But how did the Postman app do the decoding of the body? For example, I can read it there parsed as JSON (see the figure below). What am I doing wrong in Python?
Request
Okay, the problem is solved, but I want to share with you how to deal with this kind of problem.
The initial problem is to call the HTTP POST request with the header parameter Accept-Encoding like
'Accept-Encoding': 'gzip, deflate, br'
This line of code means: Locally can receive data in compressed format.
The server compresses the large file and sends it back to the client during processing. After receiving the IE, the IE performs a local pressure on the file.
The reason for the error is: the program did not extract the file
Solution: delete this line of code and it works
How do I send an mtom message in python? I have tried using the requests library but I am getting an error from the server. The workflow is HTTP headers with a SOAP envelope and a binary attachment. I am using an MTOM template file which is structured as follows:
Content-Type: multipart/related;
boundary=boundary1234567890; type="application/xop+xml";
start="<0.urn:uuid:1FACEDB95C3509148F1570480012346#w3.org>"; start-info="text/xml"
Transfer-Encoding: chunked
SOAPAction: "soap-action"
--boundary1234567890
Content-Type: application/xop+xml; charset=UTF-8; type="text/xml"
Content-Transfer-Encoding: binary
Content-ID: <0.urn:uuid:1FACEDB95C3509148F1570480012346#w3.org>
set soap envelope here
--boundary1234567890
Content-Type: application/zip
Content-Transfer-Encoding: binary
Content-ID: <1.urn:uuid:1FACEDB95C3509148F1570480012347#w3.org>
set binary attachment here
I then send the message with the python requests library as follows:
import requests
data = open(template, 'rb').read()
response = requests.post(url, data=data, headers={})
However, I am getting an error from the server saying that my request was not able to be processed. I am probably doing something wrong, but I do not know how to send an MTOM message. Any help would be greatly appreciated.
I think the only real support for MTOM
is currently in Java and C#.You can use Axis2/C which I believe supports MTOM and
put a Python wrapper around it.
I would like to recreate a .png file sent from a Flask server.
If I GET in a browser the file downloads and I can view it.
If I GET it from python requests I have problems saving the file and I can never view it because the format seems to be broken.
Client:
req = requests.get(URL + "/image/file.png")
with open("recv.png", "wb") as f:
print(req.text)
f.write(req.text.encode())
Server:
#app.route("/image/<string:path>")
def get(path):
return send_from_directory("images", path, mimetype="image/png", as_attachment=True)
You can use a Base64 encoding with multipart http request:-
Content-Type: multipart/form-data;
I'm tying to write some simple app on python3 and tornado for server, and requests for client, and I'm getting some headers in 'self.request.body', which I can't dispose of. For instance, for file 'blahblahblah', I get:
--cb5f6ba84bdf42d382dfd3204f6307c7\r\nContent-Disposition: form-data; name="file"; filename="1.bin"\r\n\r\nblahblahblah\n\r\n--cb5f6ba84bdf42d382dfd3204f6307c7--\r\n
Files are sent by
f = {'file': open(FILE, 'rb')}
requests.post(URL_UPLOAD, files=f)
and received by
class UploadHandler(tornado.web.RequestHandler):
def post(self, filename):
with open(Dir + filename, 'wb') as f:
f.write(self.request.body)
My full code can be seen here
When I send the file by curl with curl -X POST -d $(cat ./1.bin) http://localhost:8080/upload/1.bin I get the correct file, but without \n.
There must be something I missed. Please can someone help me with that? Thank You.
There are two ways to upload files: simply using the file as the request body (usually, but not necessarily, with the HTTP PUT method), or using a multipart wrapper (usually with the HTTP POST method). If you upload the file from an HTML form, it will usually use the multipart wrapper. Your requests example is using a multipart wrapper and the curl one is not; your server is not expecting the wrapper.
To use a multipart wrapper: in requests, pass files= as you've done here. With curl, see this answer: Using curl to upload POST data with files. On the server, use self.request.files instead of self.request.body: http://www.tornadoweb.org/en/stable/httpserver.html#tornado.httpserver.HTTPRequest.files
To not use the multipart wrapper, use data=open(FILE, 'rb').read() from requests, and keep the other two components the same.
It is possible to support both styles simultaneously on the server: use self.requests.files when self.request.headers['Content-Type'] == 'multipart/form-data' and self.request.body otherwise.