I've tried to import bootstrap an archive but i've face this error:
"GET /bootstrap.css HTTP/1.1" 404
While when I use this tag link it works perfectly.
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css" integrity="sha384-9aIt2nRpC12Uk9gS9baDl411NQApFmC26EwAOH8WgZl5MYYxFfc+NcPb1dKGj7Sk" crossorigin="anonymous">
It is possible to import bootstrap as a file while using Flask? If don't, I would like to know why, please
html:
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="bootstrap.css">
<title>{% block title %}{% endblock %}</title>
</head>
<body>
<h1>Hello User</h1>
{% block content %}
{% endblock %}
</body>
</html>
python:
from flask import Flask, url_for, redirect, render_template
app = Flask(__name__)
#app.route("/")
def home():
return render_template("index.html")
if __name__ == "__main__":
app.run(debug=True)
You can try to link the bootstrap using the link tag that they give you in the docs instead of having a file.
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css" integrity="sha384-9aIt2nRpC12Uk9gS9baDl411NQApFmC26EwAOH8WgZl5MYYxFfc+NcPb1dKGj7Sk" crossorigin="anonymous">
First thing first, by answering your question: It is possible to import bootstrap as a file while using Flask? If don't, I would like to know why:
Yes it is, you just did it but you only have to link insert this css file in the right place and point it with the right command. Once is downloaded is just like any other CSS file.
For my understanding you have imported the bootstrap by downloading the 'Compiled CSS and JS' from this here ===> https://getbootstrap.com/docs/4.5/getting-started/download/
Assuming that your Boostrap file in within a 'Static' folder and then inside a 'style' as so:
/app
- app.py
/views
- view.py
/templates
- index.html
/static
/style
- bootstrap.css
This both will work for you:
(most common usage)
`<link rel="stylesheet" type="text/css" href="{{ url_for('static', filename='style/bootstrap.css') }}">`
Example number one depends where in the directory the .html is at, in this example it would be just below templates and is 'index.html
<link rel="stylesheet" type="text/css" href="../static/style/bootstrap.css">
The most important thing is that the css file is in the static folder and it must be correctly pointed at.
Some more reference of really good answer about this topic:
Application not picking up .css file (flask/python):
Note that you can override the static folder path:
app = Flask(__name__, static_url_path="/STATIC_FOLDER", static_folder='STATIC_FOLDER')
More regarding change static folder default
From Flask DOCS
Put bootstrap.css in your static directory, then:
<link rel="stylesheet" type="text/css" href="{{ url_for('static', filename='bootstrap.css') }}">
Related
To practise my Django skills, I want to try to host a game on my website. The game was made in Unity and packaged using WebGL.
I used the index.html created by WebGL as a Django template and created the URL path and view in the relevant locations. WebGL creates two folders, Build and TemplateData that are referenced in index.html.
I have tried putting these folders in with the html templates, and on every level in my Django folder structure.
The outcome is the same wherever I put the folders. The GET command is sent but a "Not Found: /TemplateData/filename...." is shown for a few files
Does anyone know how to see where the GET command is looking, or just where the folders should go?
Thanks,
Sophie
After some more messing about I found that you can just wham everything into the static folder and then reference it in index.html the same way you pick up css files in base.html
{% load static %}
.....some more code
<script>
var gameInstance = UnityLoader.instantiate("gameContainer", "{% static
'Build/Juno_WebGL.json' %}", {onProgress: UnityProgress});
</script>
Do this for every reference to the files in index.html
I ran into this same issue recently and came across this thread. Here was my solution for anyone who may come across this in the future.
take the index.html file generated and put it in your templates folder, create a link through to this template using the standard django, url, view, template flow e.g:
urls.py:
urlpatterns = [
path('', views.home, name='home'),
path('unity/', views.unity, name='unity'),
]
views.py:
def unity(request):
return render(request, template_name='mainapp/unity.html')
Take your WebGL build files and put them somewhere in your static folder. Finally edit your index.html so that it includes {% load static %} and look for any href's in the file and point these to your static folder, do the same for any scripts. E.g. My Unity builds WebGL application had a 'var buildUrl = "Build";' line which I had to point towards my static folder.
Example:
<!--block content etc.. -->
{% load static %}
<html lang="en-us">
<head>
<meta charset="utf-8">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Unity WebGL Player | UnityApp</title>
<link rel="shortcut icon" href="{% static 'unity/TemplateData/favicon.ico' %}">
<link rel="stylesheet" href="{% static 'unity/TemplateData/style.css' %}">
</head>
<!-- etc.. -->
<body>
<script>
var buildUrl = "../static/unity/Build";
var loaderUrl = buildUrl + "/Unity App.loader.js";
// etc..
</script>
</body>
</html>
I'm a beginner using Flask. My static files don't working, the root
I've this tree directories :
/ <-------------- launching (flask run) the site, here.
/static
/static/css
/static/js
/static/img
/flask_mysite
/flask_mysite/log
/flask_mysite/templates
The flask app variable :
$ echo $FLASK_APP
flask_mysite/__init__.py
To navigate in the root / folder, using an vagrant VM :
flask run --host=192.168.56.101
In the /flask_mysite/__init.py__ I've the jinjia config :
flask_mysite.jinja_env.globals['static'] = (
lambda filename: url_for('static', filename=filename)
)
from flask_mysiteimport views, models
if __name__ == '__main__':
flask_mysite.run(debug=True)
And, in the /flask_mysite/templates/base.html, for example :
<link rel="stylesheet" href="{{ static('css/main.css') }}">
And so, the html generated :
<link rel="stylesheet" href="/static/css/main.css">
Can anobody can help me please ? :)
Thanks.
Fabrice
You're using wrong the static files: http://exploreflask.com/en/latest/static.html
<link rel="shortcut icon"
href="{{ url_for('static', filename='img/favicon.ico') }}">
This is the code that Flask documentation uses for static files, the way are you using it seems to be the Django way
EDIT:
Your flaskapp.py
app = Flask(__name__)
#app.route("/")
def home():
return render('template.html')
Your template.html
<!doctype html>
<html>
<head>
<link href="{{ urlfor('static' , filename='css/yourcss.css'}}">
<script src="{{ urlfor('static' , filename='js/yourjs.js'}}"></script>
</head>
<body>
<!-- the rest of your html -->
</body>
</html>
Assuming that you have "static/css/yourcss.css" and "static/js/yourjs.js" and the .py file is in the root of the folder with the static folder
I am pretty new to web programming and Flask. I'm trying to link a .css file to the head of my base.html file. I can render the content of the website but not the styles from the .css file. This is my directory:
app
templates
base.html
index.html
views.py
static
style.css
In the head of base.html i wrote:
<head>
...
<link rel="stylesheet" type="text/css" href="/static/style.css">
</head>
I also tried this one:
<head>
...
<link rel="stylesheet" type="text/css" href="{{ url_for('static', filename='style.css') }}">
</head>
And also some variations copying the .css file around my directory. Still no formatting on the website.
Some further information: By running the views.py I render the index.html which extends the base.html - I don't know if this might be relevant.
Please try this . It may help
in .py file
from flask import Flask, request, send_from_directory
# set the project root directory as the static folder, you can set others.
app = Flask(__name__, static_url_path='')
#app.route('/static/<path:path>')
def send_css(path):
return send_from_directory('static', path)
in .html file
**
<head>
...
<link rel="stylesheet" type="text/css" href="../../../static/style.css">
</head>
**
edit :
<head>
...
<link rel="stylesheet" type="text/css" href="../../../static/style.css">
</head>
I got it! My directory division was wrong. I put the static folder outside of the app folder - I do not know why but Python could not link outside of the app folder. Thank you for your help, everyone!
please try this and please give path to static_folder correct means it must point to the 'static' directory.
import os
from flask import Flask, request, send_from_directory
app = Flask(__name__, static_folder = 'path/to/folder/of/staticfiles')
#in your case it is 'static' directory.
#app.route('/static/<path:path>/<filename>')
#app.route('/static/<filename>')
def send_css(**kwargs):
filename = kwargs.get('filename')
path = kwargs.get('path')
if path:
return send_from_directory(os.path.join(static_folder,path), filename)
else:
return send_from_directory(static_folder, filename)
This will also read .css files from any subdirectory of your 'static' directory.
just keep this in your index.html.
<head>
...
<link rel="stylesheet" type="text/css" href="/static/style.css">
</head>
I hope your are Extending base.html in index.html
and rendering index.html from flask.
And Did you understand what path you have to give in your static_folder in app = Flask(__name__, static_folder = 'path/to/folder/of/staticfiles') ????
You have to add path of your directory where .css file is kept means your's path of 'static' folder.
I am new to Tornado. I am trying to link a CSS file to the html template. I am using jinja2 with Tornado. But due to some unknown reasons the CSS file is not loading up.
EDIT: I have created my custom render_template function which is working fine.
Directory structure:
app.py
static
css
custom.css
templates
index.html
Here is my Request Handler's Class:
class Index(RequestHandler):
def get(self):
path = os.path.join('static/css/', 'custom.css')
return self.write(render_template('index.html', path = path))
and here is my index.html template:
<!Doctype html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="{{path}}"/>
</head>
<body>
<div>
<div class="header">
asdasdasd
</div>
</div><!--wrapper-->
</body>
</html>
but the browser is returning the 404-NotFound error for the css file with the correct url, that is http://localhost/static/css/custom.css
Here is a guide on how to link static files in tornado:
http://tornado.readthedocs.org/en/latest/guide/running.html#static-files-and-aggressive-file-caching
Important is the 'static_path' setting in your settings dictionary:
settings = {
"static_path": os.path.join(os.path.dirname(__file__), "static")
}
Now you should be able to use it.
I've searched for answer for this question, but i havent found any solution for my problem. I want to link css to my project, but just cant handle how STATIC_URL work
<head>
{% load static from staticfiles %}
<link rel="stylesheet" type="text/css" href="{% static "css/style.css" %}">
</head>
it's to much code to post here so here are the links:
settings.py: http://pastebin.com/9Bsg3u1h
And I render with context_instance=RequestContext(request) parameter of course.
I got files structure like this:
Django_project
...
appname
templates
static
I tried also to place static directory in many project, in appname, and even in templates.
Can someone explain me how should it look for my project?
Use the builtin static, not static from staticfiles:
<head>
{% load static %}
<link rel="stylesheet" type="text/css" href="{% static "css/style.css" %}">
</head>
https://docs.djangoproject.com/en/dev/ref/templates/builtins/#static
Django ships with a static template tag. You can use this regardless if you’re using RequestContext or not.
Note
The staticfiles contrib app also ships with a static template tag which uses staticfiles' STATICFILES_STORAGE to build the URL of the given path. Use that instead if you have an advanced use case such as using a cloud service to serve static files...