I'm trying to send a simple mail with SendGrid which must contain one hyperlink.
I'm not doing anything fancy, just following the documentation example with some changes
import os
from sendgrid.helpers.mail import *
sg = sendgrid.SendGridAPIClient(api_key=os.environ.get('SENDGRID_API_KEY'))
from_email = Email("test#example.com")
to_email = To("test#example.com")
subject = "Sending with SendGrid is Fun"
content = Content("text/html", '<html>google</html>')
mail = Mail(from_email, to_email, subject, content)
response = sg.client.mail.send.post(request_body=mail.get())
It looks fine to me, but once I run the script and the mail is sent, it shows up like plain text I cannot click on.
I also tried many other combinations removing the <html> tag, using single and double quotes with the backslash, but nothing really worked. I even tried to do the same thing without the Mail Helper Class, but it didn't work.
Thanks very much for the help.
content = Content(
"text/html", "Hi User, \n This is a test email.\n This is to also check if hyperlinks work <a href='https://www.google./com'> Google </a> Regards Karthik")
This helped me. I believe you don't need to mention the html tags
Related
I've been trying to print email body using python(using imap_tools lib)but it's not really working for me. here is the code snippet.
from imap_tools import MailBox, A, AND, OR, NOT
with MailBox('outlook.office365.com').login('test#test.com', 'test') as mailbox:
for msg in mailbox.fetch(A(seen=False)):
print(msg.text)
but when I print the subject using msg.subject, it's working fine. I tried using msg.html and here is the output.
<body lang="EN-IN" link="blue" vlink="#954F72" style="word-wrap:break-word"><div class="WordSection1"><p class="MsoNormal">Hi, this is a test email to store body in file<o:p></o:p></p></div></body></html>
note: this is not the whole HTML output, but this is to show that the email has some data in the body.
Can anyone help me solve this problem?
I have a question related to last answer in How do I send HTML Formatted emails, through the gmail-api for python but unfortunately the answer does not work for me. If I attach both the 'plain' and 'html' parts, it only accepts the LAST 'attach' call I make. That is, if I attach as 'plain' AFTER 'html', it only sends as 'plain',(which looks unappealing on devices/apps with HTML rendering)., but if I attach the 'html' AFTER 'plain', it only sends the 'html' format (which looks bad on devices/apps without HTML rendering). Unlike the person who posted that question, I do need both parts because some of the devices/apps that receive my emails do not render HTML and need the plain text part.
This is not a problem if I used 'smtplib' instead of GMAIL-API, but I want to use gmail api for better security in my app.
Here is my code:
message = MIMEMultipart('alternative')
message['to'] = to_email
message['from'] = from_email
message['subject'] = subject
body_plain = MIMEText(email_body,'plain')
message.attach(body_plain)
body_html_format="<u><b>html:<br>"+email_body+"</b></u>"
body_html = MIMEText(body_html_format,'html')
message.attach(body_html) # PROBLEM: Will only send as HTML since this was added LAST.
raw_string = base64.urlsafe_b64encode(message.as_bytes()).decode()
request = service.users().messages().send(userId='my.email#gmail.com',body={'raw':raw_string})
message = request.execute()
Thanks and regards,
Doug
I am currently working on a project in Python that would be connecting to an email server and looking at the latest email to tell the user if there is an attachment or a link embedded in the email. I have the former working but not the latter.
I may be having troubles with the if any() part of my script. As it seems to half work when I test. Although it may be due to how the email string is printed out?
Here is my code for connecting to gmail and then looking for the link.
import imaplib
import email
word = ["http://", "https://", "www.", ".com", ".co.uk"] #list of strings to search for in email body
#connection to the email server
mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login('email#gmail.com', 'password')
mail.list()
# Out: list of "folders" aka labels in gmail.
mail.select("Inbox", readonly=True) # connect to inbox.
result, data = mail.uid('search', None, "ALL") # search and return uids instead
ids = data[0] # data is a list.
id_list = ids.split() # ids is a space separated string
latest_email_uid = data[0].split()[-1]
result, data = mail.uid('fetch', latest_email_uid, '(RFC822)') # fetch the email headers and body (RFC822) for the given ID
raw_email = data[0][1] # here's the body, which is raw headers and html and body of the whole email
# including headers and alternate payloads
print "---------------------------------------------------------"
print "Are there links in the email?"
print "---------------------------------------------------------"
msg = email.message_from_string(raw_email)
for part in msg.walk():
# each part is a either non-multipart, or another multipart message
# that contains further parts... Message is organized like a tree
if part.get_content_type() == 'text/plain':
plain_text = part.get_payload()
print plain_text # prints the raw text
if any(word in plain_text for word in word):
print '****'
print 'found link in email body'
print '****'
else:
print '****'
print 'no link in email body'
print '****'
So basically as you can see I have a variable called 'Word' which contains an array of keywords to search for in the plain text email.
When I send a test email with an embedded link that is in the format of 'http://' or 'https://' - the email prints out the email body with the link in the text like this -
---------------------------------------------------------
Are there links in the email?
---------------------------------------------------------
Test Link <http://www.google.com/>
****
found link in email body
****
And I get my print message saying 'found link in email body' - which is the result I am looking for in my test phase, yet this will lead onto something else to happen within the final program.
Yet, if I add an embedded link in the email with no http:// such as google.com then the link doesn't print out and I don't get the result, even though I have an embedded link.
Is there a reason for this? I'm also suspecting maybe my if any() loops is not really the best. I didn't really understand it when I originally added it but it worked for http:// links. Then I tried just a .com and got my problem which I am having trouble finding a solution for.
To check if there are attachments to an e-mail you can search the headers for Content-Type and see if it says "multipart/*". E-mails with multipart content types may contain attachments.
To inspect the text for links, images, etc, you can try using Regular Expressions. As a matter of fact, this is probably your best option in my opinion. With regex (or Regular Expressions) you can find strings that match a given pattern. The pattern "<a[^>]+href=\"(.*?)\"[^>]*>(.*)?</a>", for example, should match all links in your email message regardless of whether they are a single word or a full URL. I hope that helps!
Here's an example of how you can implement this in Python:
import re
text = "This is your e-mail body. It contains a link to <a
href='http//www.google.com'>Google</a>."
link_pattern = re.compile('<a[^>]+href=\'(.*?)\'[^>]*>(.*)?</a>')
search = link_pattern.search(text)
if search is not None:
print("Link found! -> " + search.group(0))
else:
print("No links were found.")
For the "end-user" the link will just appear as "Google", without www and much less http(s)... However, the source code will have the html wrapping it, so by inspecting the raw body of the message you can find all links.
My code is not perfect but I hope it gives you a general direction... You can have multiple patterns looked up in your e-mail body text, for image occurences, videos, etc. To learn Regular Expressions you'll need to research a little, here's another link, to Wikipedia
I'm making an API using Python requests, and HTTP GET is working fine, but I'm having a little bit of trouble with HTTP POST. So, as with a lot of websites, you can read information, but in order to make a post request (such as following a user, or writing a post), you need to have an authenticated session. THIS website, uses google to log in. Normally, I would just pass the username:password into the POST request formdata to log in, but this google thing is pretty wonky (and quite frankly I'm not that experienced). Does anyone have a reference or an example to help me out? ;/
I do not know about python requests but to send an email its as easy as this
import yagmail
yagmail.SMTP(emailh).send(email, subject, body)
#emailh = your email (just username no #gmail.com)
#email = send to (full email including domain ***#gmail.com or ***#outlook.com)
#subject = subject of the message
#body = body of the message
Even better
emailh = raw_input('Your email: ')
email = raw_input('Send to: ')
subject = raw_input('Subject: ')
body = raw_input('Body: ')
yagmail.SMTP(emailh).send(email, subject, body)
print('Email Sent.')
If this is what you are talking about anyway.
This page might be useful link
I have a test.html file that I want to send via email(I am refering about the page content). Is there a way for getting the information from the html and sending it as a email? If you have any other ideas please share.
Here's a quick and dirty script I just wrote which might be what you're looking for.
https://gist.github.com/1790847
"""
this is a quick and dirty script to send HTML email - emphasis on dirty :)
python emailpage.py http://www.sente.cc
made to answer: http://stackoverflow.com/questions/9226719/sending-a-html-file-via-python
Stuart Powers
"""
import lxml.html
import smtplib
import sys
import os
page = sys.argv[1] #the webpage to send
root = lxml.html.parse(page).getroot()
root.make_links_absolute()
content = lxml.html.tostring(root)
message = """From: Stuart Powers <stuart.powers#gmail.com>
To: Stuart Powers <stuart.powers#gmail.com>
MIME-Version: 1.0
Content-type: text/html
Subject: %s
%s""" %(page, content)
smtpserver = smtplib.SMTP("smtp.gmail.com",587)
smtpserver.starttls()
smtpserver.login("stuart.powers#gmail.com",os.environ["GPASS"])
smtpserver.sendmail('stuart.powers#gmail.com', ['stuart.powers#gmail.com'], message)
There are many ways of reading files in python and there are also ways to send emails in python. Why don't you look up the documentation and come back with some coding error ?
Sending emails in python: http://docs.python.org/library/email-examples.html
Reading files in python: http://docs.python.org/tutorial/inputoutput.html