Develop Reference

I need to print the specific part of a line in a txt file

I have this text file that reads ,,Janitors, 3,, ,,Programers, 4,, and ,,Secretaries, 1,, and all of these are on different lines. I need to print out Janitor seperate from the number 3, and this has to work for basicaly any word and number combo. This is the code I came up with and, of course, it doesnt work. It says ,,substring not found,,
File = open("Jobs.txt", "r")
Beg_line = 1
for lines in File:
Line = str(File.readline(Beg_line))
Line = Line.strip('\n')
print(Line[0: Line.index(',')])
Beg_line = Beg_line + 1
File.close()

Try running the following code:
file = open("Jobs.txt", "r")
lines = file.read().split('\n')
for line in lines:
print(line.split(' ')[0])
file.close()
This will give the following output:
Janitors
Programers
Secretaries

Is there any idea of deleting lines in python?

So,I have this problem,the code below will delete the 3rd line in a text file.
with open("sample.txt","r") as f:
lines = f.readlines()
del lines[2]
with open("sample.txt", "w+") as f2:
for line in lines:
f2.write(line)
How to delete all lines from a text file?

Why use loop if you want to have an empty file anyways?
f = open("sample.txt", "r+")
f.seek(0)
f.truncate()
This will empty the content without deleting the file!

I think you to need something like this
import os
def delete_line(original_file, line_number):
""" Delete a line from a file at the given line number """
is_skipped = False
current_index = 1
dummy_file = original_file + '.bak'
# Open original file in read only mode and dummy file in write mode
with open(original_file, 'r') as read_obj, open(dummy_file, 'w') as write_obj:
# Line by line copy data from original file to dummy file
for line in read_obj:
# If current line number matches the given line number then skip copying
if current_index != line_number:
write_obj.write(line)
else:
is_skipped = True
current_index += 1
# If any line is skipped then rename dummy file as original file
if is_skipped:
os.remove(original_file)
os.rename(dummy_file, original_file)
else:
os.remove(dummy_file)

How can we write a text file from variable using python?

I am working on NLP project and have extracted the text from pdf using PyPDF2. Further, I removed the blank lines. Now, my output is being shown on the console but I want to populate the text file with the same data which is stored in my variable (file).
Below is the code which is removing the blank lines from a text file.
for line in open('resume1.txt'):
line = line.rstrip()
if line != '':
file=line
print(file)
Output on Console:
Eclipse,
Visual Studio 2012,
Arduino IDE,
Java
,
HTML,
CSS
2013
Excel
.
Now, I want the same data in my (resume1.txt) text file. I have used three methods but all these methods print a single dot in my resume1.txt file. If I see at the end of the text file then there is a dot which is being printed.
Method 1:
with open("resume1.txt", "w") as out_file:
out_file.write(file)
Method 2:
print(file, file=open("resume1.txt", 'w'))
Method 3:
pathlib.Path('resume1.txt').write_text(file)
Could you please be kind to assist me in populating the text file. Thank you for your cooperation.

First of all, note that you are writing to the same file losing the old data, I don't know if you want to do that. Other than that, every time you write using those methods, you are overwriting the data you previously wrote to the output file. So, if you want to use these methods, you must write just 1 time (write all the data).
SOLUTIONS
Using method 1:
to_file = []
for line in open('resume1.txt'):
line = line.rstrip()
if line != '':
file = line
print(file)
to_file.append(file)
to_save = '\n'.join(to_file)
with open("resume1.txt", "w") as out_file:
out_file.write(to_save)
Using method 2:
to_file = []
for line in open('resume1.txt'):
line = line.rstrip()
if line != '':
file = line
print(file)
to_file.append(file)
to_save = '\n'.join(to_file)
print(to_save, file=open("resume1.txt", 'w'))
Using method 3:
import pathlib
to_file = []
for line in open('resume1.txt'):
line = line.rstrip()
if line != '':
file = line
print(file)
to_file.append(file)
to_save = '\n'.join(to_file)
pathlib.Path('resume1.txt').write_text(to_save)
In these 3 methods, I have used to_save = '\n'.join(to_file) because I'm assuming you want to separate each line of other with an EOL, but if I'm wrong, you can just use ''.join(to_file) if you want not space, or ' '.join(to_file) if you want all the lines in a single one.
Other method
You can do this by using other file, let's say 'output.txt'.
out_file = open('output.txt', 'w')
for line in open('resume1.txt'):
line = line.rstrip()
if line != '':
file = line
print(file)
out_file.write(file)
out_file.write('\n') # EOL
out_file.close()
Also, you can do this (I prefer this):
with open('output.txt', 'w') as out_file:
for line in open('resume1.txt'):
line = line.rstrip()
if line != '':
file = line
print(file)
out_file.write(file)
out_file.write('\n') # EOL

First post on stack, so excuse the format
new_line = ""
for line in open('resume1.txt', "r"):
for char in line:
if char != " ":
new_line += char
print(new_line)
with open('resume1.txt', "w") as f:
f.write(new_line)

Fetching a line which comes 2 lines after searched line from a text file in python

Text file contains below data:
InitialSearch='Searched data'
file = open("textfile.txt","r")
lines = file.readlines()
file.close()
fileOutput = open ('NewTextFile.txt', 'w')
for x,line in enumerate(lines):
if line.find(InitialSearch)>=0:
fileOutput.write(line)
fileOutput.close
Code is not properly working

You already have the index of the "matched" line in your for loop. Just add two to it, and you will have the row you want to add to the output file.
InitialSearch='Searched data'
file = open("textfile.txt","r")
lines = file.readlines()
file.close()
with open('NewTextFile.txt', 'w') as fileOutput
for x,line in enumerate(lines):
if line.find(InitialSearch)>=0:
fileOutput.write(lines[x+2])

How to delete a particular line from file in Python

def deleteEmployee(self,code,name):
with open("employee.data","r+") as file:
# data=file.readlines()
for num, i in enumerate(file,1):
print(i)
a=i[:len(i)-1]
if str(a)==str(code):
print("found at",num)
file.seek(num)
file.write("\n")
file.close()
I just want to write a file handling code. Here I define delete function where I want to delete particular code if exists inside the file but it's not working.

This code should achieve what you want:
def deleteEmployee(self,code,name):
with open("employee.data","r+") as file:
new_content = ""
for num, line in enumerate(file,1):
print(line)
a=line[:-1]
if str(a)==str(code):
print("found at ",num)
new_content += "\n" #Adds newline instead of 'bad' lines
else:
new_content += line #Adds line for 'good' lines
file.seek(0) #Returns to start of file
file.write(new_content) #Writes cleaned content
file.truncate() #Deletes 'old' content from rest of file
file.close()