Curl requests in python - python

I have a curl request like this:
curl -X POST http://mdom-n-plus-1.nonprod.appsight.us:8081/mesmerdom/v3/getByImageAndDom -F "data=$DATA" -F "dom=#$DOM" -F "image=#$IMG"
I am trying to convert it to python by using something like this:
import requests
import json
url = "http://mdom-n-plus-1.nonprod.appsight.us:8081/mesmerdom/v1/getByScreen"
payload = {"data": json.dumps({"screen":["screen-id", "57675"]}), dom:"abc", image:"xyz"}
req = requests.post(url, data=payload)
print (req.text)
but it is not working.

Related

curl to python for post request

I would like to "translate" my curl request into python using request or urllib.
I try to post a file.
My curl request is :
curl -X POST -H "Content-Type: multipart/form-data" -H "Authorization: Bearer $1" -F "data=#$2;filename=$3" --cert certificateprivate.pem --cacert MyDigiCertSHA2.crt.pem <my_url>
I tried the code below ( doesn't work , response 400)
def upload_file(token,file_path):
ctx = ssl.create_default_context(ssl.Purpose.CLIENT_AUTH,cafile='MyDigiCertSHA2.crt.pem')
ctx.load_cert_chain(certfile='certificateprivate.pem')
url = <my_url>
hdr = {"Content-Type": "multipart/form-data","Authorization":"Bearer "+token}
data = '{"filterList":[{}]}'
with open(file_path, 'rb') as f:
from urllib import request, parse
data = parse.urlencode( {'filename':file_path,"data": f.read()}).encode()
req = request.Request( url, data = data,headers=hdr)
resp = request.urlopen(req, context=ctx)
content = resp.read()
data = json.loads(content.decode('utf-8'))
print(data)
The curl command has "Content-Type: multipart/form-data", but your python code has "Content-Type": "application/json".

POST of JSON data not working the same with requests as with curl

I have problem with post method of REST in python.
when i am invoking REST API post method from curl it is working but when i invoke same from python program i have bad request 400 error.
The following curl command works:
curl -k -d #data.json -H "Content-Type: application/json" -v https://dsp.corpo.t-mobile.pl/npitapi/pn/saveAll
Data id data.json file
[{
"msisdn": "483260321",
"date_from": "2019-04-25T18:30:00.000+0000",
"date_to": "2019-04-24T18:30:00.000+0000",
"opr_recpn_id": 5,
"date_last": "2019-04-21T18:30:00.000+0000"
}]
My python code:
import json
import httplib
import requests
from requests.packages.urllib3.exceptions import InsecureRequestWarning
requests.packages.urllib3.disable_warnings(InsecureRequestWarning)
url = 'https://dsp.corpo.t-mobile.pl/npitapi/pn/saveAll';
pay= {'msisdn': '483260329',
'date_from': '2019-04-25T18:30:00.000+0000',
'date_to': '2019-04-24T18:30:00.000+0000',
'opr_recpn_id': 5,
'date_last': '2019-04-21T18:30:00.000+0000'}
response = requests.post(url, json=pay,verify=False)
print(response)
output response:
<Response [400]>
Can somebody help me what is the issue in data ?
i think json data is correct and it is same what i have in curl command.
import json
import requests
url = 'https://dsp.corpo.t-mobile.pl/npitapi/pn/saveAll'
headers = {
'content-type': "application/json"
}
pay= [{'msisdn': '483260329',
'date_from': '2019-04-25T18:30:00.000+0000',
'date_to': '2019-04-24T18:30:00.000+0000',
'opr_recpn_id': 5,
'date_last': '2019-04-21T18:30:00.000+0000'}]
response = requests.post(url, data=json.dumps(pay), headers=headers)
print(response)
Can you try this?

Python post request returns 500

I am using requests to make a POST request to create a user. The request succeeds with 201 created when I use curl, however fails with a 500 response when I use requests. My curl command is
curl --user administrator:password -H "Content-Type: application/json" https://localhost:8080/midpoint/ws/rest/users -d #user.json -v
And my python script is:
import requests
import json
headers = {
'Content-Type': 'application/json',
}
with open('user.json') as j:
data = json.load(j)
response = requests.post('https://localhost:8080/midpoint/ws/rest/users', headers=headers, data=str(data), auth=('Administrator', 'password'))
print(response)
Can anyone see a reason why my python script would be failing? I am at a loss.
str(data) returns the Python representation of data, not its JSON representation. These two forms can differ in things like ' vs. ", True vs. true, and None vs. null. To properly JSONify data, call json.dumps() on it:
response = requests.post(..., data=json.dumps(data))
or let requests do the JSONification:
response = requests.post(..., json=data)
or use the JSON as it appears in user.json directly:
with open('user.json') as j:
data = j.read()
response = requests.post(..., data=data)

Why does this Translation of Curl into Python requests fail? [duplicate]

I'm trying to convert the following working request in curl to a python request (using Requests).
curl --data 'query={"tags":["test1","test2"]}' http://www.test.com/match
(I've used a fake url but the command does work with the real url)
The receiving end (ran in Flask) does this:
#app.route("/match", methods=['POST'])
def tagmatch():
query = json.loads(request.form['query'])
tags = query.get('tags')
# ... does stuff ...
return json.dump(stuff)
In curl (7.30), ran on Mac OS X (10.9) the command above properly returns a JSON list that's filtered using the tag query.
My Python script is as follows, it returns a 400 Bad Request error.
import requests
payload = {"tags":["test1", "test2"]}
# also tried payload = 'query={"tags":["test1","test2"]}'
url = 'http://www.test.com/match'
r = requests.post(url, data=payload)
if __name__=='__main__':
print(r.text)
There is an open source cURL to Python Requests conversion helper at https://curlconverter.com/. It isn't perfect, but helps out a lot of the time. Especially for converting Chrome "Copy as cURL" commands. There is also a node library if you need to do the conversions programmatically
Your server is expecting JSON, but you aren't sending it. Try this:
import requests
import json
payload = {'query': json.dumps({"tags":["test1", "test2"]})}
url = 'http://www.test.com/match'
r = requests.post(url, data=payload)
if __name__=='__main__':
print r.text
Save your life
A simpler approach would be:
Open POSTMAN
Click on the "import" tab on the upper left side.
Select the Raw Text option and paste your cURL command.
Hit import and you will have the command in your Postman builder!
Hope this helps!
credit: Onkaar Singh
Try to use uncurl library. It is pretty nice to do its job. I've tried it.
u = uncurl.parse(
"curl -X GET 'https://mytesturl.com/' -H 'accept: application/json' -H 'Authorization: 1234567890'")
print(u)
It prints,
requests.get("https://mytesturl.com/",
headers={
"Authorization": "1234567890",
"accept": "application/json"
},
cookies={},
)
try this:
https://github.com/spulec/uncurl
import uncurl
print uncurl.parse("curl 'https://pypi.python.org/pypi/uncurl' -H
'Accept-Encoding: gzip,deflate,sdch'")
I wrote an HTTP client plugin for Sublime Text called Requester, and one of its features is to convert calls to cURL to Requests, and vice versa.
If you're using Sublime Text this is probably your fastest, easiest option. If not, here's the code that actually handles the conversion from cURL to Requests. It's based uncurl, but with various improvements and bug fixes.
import argparse
import json
try:
from urllib.parse import urlencode, parse_qsl
except ImportError: # works for Python 2 and 3
from urllib import urlencode
from urlparse import parse_qsl
if __name__ == "__main__":
parser = argparse.ArgumentParser()
parser.add_argument('command')
parser.add_argument('url')
parser.add_argument('-X', '--request', default=None)
parser.add_argument('-d', '--data', default=None)
parser.add_argument('-G', '--get', action='store_true', default=False)
parser.add_argument('-b', '--cookie', default=None)
parser.add_argument('-H', '--header', action='append', default=[])
parser.add_argument('-A', '--user-agent', default=None)
parser.add_argument('--data-binary', default=None)
parser.add_argument('--compressed', action='store_true')
parsed_args = parser.parse_args()
method = 'get'
if parsed_args.request:
method = parsed_args.request
base_indent = ' ' * 4
post_data = parsed_args.data or parsed_args.data_binary or ''
if post_data:
if not parsed_args.request:
method = 'post'
try:
post_data = json.loads(post_data)
except ValueError:
try:
post_data = dict(parse_qsl(post_data))
except:
pass
cookies_dict = {}
if parsed_args.cookie:
cookies = parsed_args.cookie.split(';')
for cookie in cookies:
key, value = cookie.strip().split('=')
cookies_dict[key] = value
data_arg = 'data'
headers_dict = {}
for header in parsed_args.header:
key, value = header.split(':', 1)
if key.lower().strip() == 'content-type' and value.lower().strip() == 'application/json':
data_arg = 'json'
if key.lower() == 'cookie':
cookies = value.split(';')
for cookie in cookies:
key, value = cookie.strip().split('=')
cookies_dict[key] = value
else:
headers_dict[key] = value.strip()
if parsed_args.user_agent:
headers_dict['User-Agent'] = parsed_args.user_agent
qs = ''
if parsed_args.get:
method = 'get'
try:
qs = '?{}'.format(urlencode(post_data))
except:
qs = '?{}'.format(str(post_data))
print(post_data)
post_data = {}
result = """requests.{method}('{url}{qs}',{data}\n{headers},\n{cookies},\n)""".format(
method=method.lower(),
url=parsed_args.url,
qs=qs,
data='\n{}{}={},'.format(base_indent, data_arg, post_data) if post_data else '',
headers='{}headers={}'.format(base_indent, headers_dict),
cookies='{}cookies={}'.format(base_indent, cookies_dict),
)
print(result)
You could make a script with this code, e.g. curl_to_request.py, and call this script from the command line like so. It will work for both Python 2 and Python 3.
python curl_to_request.py curl -X POST -d 'key2=value2&key1=value1' 'http://httpbin.org/post'
python curl_to_request.py curl -X POST -H 'Content-Type: application/json' -d '{"key2": "value2", "key1": "value1"}' 'http://httpbin.org/post'
python curl_to_request.py curl -X POST -H 'Content-Type: application/json' -d '[1, 2, 3]' 'http://httpbin.org/post'
python curl_to_request.py curl -X POST -H 'Content-Type: application/json' -d '{"name": "Jimbo", "age": 35, "married": false, "hobbies": ["wiki", "pedia"]}' 'http://httpbin.org/post'
python curl_to_request.py curl -X GET 'http://httpbin.org/get?key2=value2&key1=value1'
python curl_to_request.py curl -X GET -H 'key1: value1' -H 'key2: value2' 'http://httpbin.org/headers'
python curl_to_request.py curl -X GET -b 'key1=value1;key2=value2' 'http://httpbin.org/cookies'
From your code using requests and in Flask, it seems like you don't post the right data format. The payload should be like this:
payload = {'query': {'tags': ['test1', 'test2']},}
This seems not normal as post data when using requests.post(). So if you have posted the html form here, it may have been more clear to solve the problem.
Here is another similar question: Using Python Requests to pass through a login/password

Why do I get 'internal error' from Paypal using this call in Django?

I have a request that gets PayPal authentication. It is written in Curl and it works perfectly. Trying to rewrite it in Python leads to an error response(500000 internal error). Can anyone please direct me on how I would rewrite it or correct my existing code.
CURL
curl -s --insecure -H "X-PAYPAL-SECURITY-USERID: <user_id>" -H "X-PAYPAL-SECURITY-PASSWORD: <user_password>" -H "X-PAYPAL-SECURITY-SIGNATURE: <user_signature>" -H "X-PAYPAL-REQUEST-DATA-FORMAT: JSON" -H "X-PAYPAL-RESPONSE-DATA-FORMAT: JSON" -H "X-PAYPAL-APPLICATION-ID: APP-80W284485P519543T" https://svcs.sandbox.paypal.com/Permissions/RequestPermissions -d "{\"scope\":\"EXPRESS_CHECKOUT\", \"callback\":\"<callback_url>", \"requestEnvelope\": {\"errorLanguage\":\"en_US\"}}"
PYTHON
import settings
import urllib
import urllib2
from django.utils import simplejson
def home(request):
headers = {
"X-PAYPAL-SECURITY-USERID": settings.USERNAME,
"X-PAYPAL-SECURITY-PASSWORD": settings.PASSWORD,
"X-PAYPAL-SECURITY-SIGNATURE": settings.SIGNATURE,
"X-PAYPAL-REQUEST-DATA-FORMAT": "JSON",
"X-PAYPAL-RESPONSE-DATA-FORMAT": "JSON",
"X-PAYPAL-APPLICATION-ID": "APP-80W284485P519543T"
}
data = {"scope":"EXPRESS_CKECKOUT", callback":"http://www.example.com/success.html", "requestEnvelope": {"errorLanguage":"en_US"}}
req = urllib2.Request("https://svcs.sandbox.paypal.com/Permissions/RequestPermissions/", simplejson.dumps(data), urllib.urlencode(data), headers)
res = urllib2.urlopen(req).read()
typo in "EXPRESS_CKECKOUT" instead of "EXPRESS_CHECKOUT" and third argument urllib.urlencode(data) for urllib2.Request is not required.
data = {"scope":"EXPRESS_CHECKOUT", "callback":"http://www.example.com/success.html", "requestEnvelope": {"errorLanguage":"en_US"}}
req = urllib2.Request("https://svcs.sandbox.paypal.com/Permissions/RequestPermissions/", simplejson.dumps(data), headers)
res = urllib2.urlopen(req).read()

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