This question already has an answer here:
NumPy: Logarithm with base n
(1 answer)
Closed 2 years ago.
How can i convert the following code to log base 2?
df["col1"] = df["Target"].map(lambda i: np.log(i) if i > 0 else 0)
I think you just want to use np.log2 instead of np.log.
Related
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The tilde operator in Python
(9 answers)
Closed 1 year ago.
pd_selftest = pd_selftest[pd_selftest['SICCD'] != 0]
pd_selftest = pd_selftest[~pd_selftest['SICCD'].isnull()]
I'd like to know what the function of the ~ is in the above code.
That's the bit-wise invert or not operator. So, it returns only those lines where the SICCID column is not null. I would probably use the word not in this case.
This question already has answers here:
Why is exponentiation applied right to left?
(4 answers)
Closed 2 years ago.
print (2**3**2)
Answer is 512.
Why 512 is answer not 64? Because ((2^3)^2) = 64
I want to know the inside math operation of print (2** 3**2)
The order of operations for exponentiation is right-to-left, not-left-to right. So:
2**3**2
is interpretted as:
2**(3**2) = 2**(9) = 512
This question already has answers here:
What does & mean in python [duplicate]
(5 answers)
Closed 3 years ago.
I mistakenly wrote the line of code, I expected it to give me an error but it returned an answer.
Codx = [num for num in range(1,9) if num & 2 = 0]
Print (codx)
I got the answer
[1,4,5,8]
Then I did
Print(3&2)
Answer was 2
Print(5&2)
Answer was 0
What’s the role of the ampersand?
That's the bitwise-and operator: For the official documentation, it does a "bitwise and". Each bit of the output is 1 if the corresponding bit of x AND of y is 1, otherwise it's 0.
This question already has answers here:
Math operations from string [duplicate]
(8 answers)
Closed 6 years ago.
I have a string with a formula 5 - 3, and I need to get the result in integer. How could I do that?
use eval function:
eval("5 - 3") # 2
test = "5-3"
print(eval(test))
Gives 2
This question already has answers here:
Why does integer division yield a float instead of another integer?
(4 answers)
Closed 6 years ago.
In Python 3 vs Python 2.6, I've noticed that I can divide two integers and get a float. How do you get the Python 2.6 behaviour back?
Is there a different method to get int/int = int?
Try this:
a = 1
b = 2
int_div = a // b